Methods Exam 2 Paper (PDF)

[Floatzel98]

I'm not gonna say it's the best scan ever, but it should all be there.

https://drive.google.com/file/d/0B_H88JlKMMdvbU5FMXBTZlJ2YTQ/view?usp=sharing

Everyone should be able to access it but let me know if you can't.

[wobblywobbly]

My answers: AACBECCDBDAEEDBDDACBDB

[Maths Forever]

Thanks so much! 

[Adiamond]

My multiple choice answers;
1. A
2. A
3. C
4. B
5. E
6. C
7. C
8. D
9. B
10. D
11. A*
12. E
13. E
14. D
15. B
16. A
17. D
18. A
19. C
20. B
21. D
22. B
(These answers are not checked, just my multiple choice answers)
*Editing in right answers as i get them
Can someone please help me with question 3? I don't know if it's A or C

[lolattack]

i got basically the same as you except for a few exceptions:

3. C
8. D
11. A
15. B
18. A

[Swagadaktal]

ans to q 16 is correct? Is it A?

[Deshouka]

My answers: AACBECCDBDAEEDBDDACBDB

I think all your answers are correct

[jammin]

ans to q 16 is correct? Is it A?

16 was A

[Swagadaktal]

16 was A

damn educated guess works
praise Jesus

[byCrypt]

I'm pretty sure 16 was D. 

[Deshouka]

It's not A because using trial and error if you let f(x)= 3x^5
                                            Then f'(x)= 15x^4
                                            Therefore G(x)=15x^4
                                            Hence g(x)= 60x^3
  5/3 is not an integer?
Lol can any1 confirm  answer is D

[Escobar]

from memory, i got D for 16 because b/a=m or something, and m is an integer

[LoadedWithPotatoes]

Yeah given that m-n = 2, if you sub a few values in m/n won't always be integers, so it can't be A.

edit; and yeah eventually you can find out that b/a = mn + m, given that m and n are positive integers, b/a will be a positive integer as well. hence, D is correct.

[zsteve]

How I did 16:
Since f'(x) is an antiderivative of g(x), thus g(x) = f''(x).
f'(x) = amx^(m-1)
f''(x) = am(m-1)x^(m-2)
But f''(x)=g(x)
So am(m-1)x^(m-2) = bx^n.
Hence m-2 = n so n-m = -2, so E isn't it.
Equating coeffs: am(m-1) = b hence b/a = m(m-1), but
m-2 = n, and n is a positive integer, so m>=3, hence m(m-1) is an integer, D