Welcome, Guest. Please login or register.

December 15, 2019, 10:12:49 pm

Author Topic: solve for the following equation  (Read 909 times)  Share 

0 Members and 1 Guest are viewing this topic.

droodles

  • Guest
solve for the following equation
« on: December 03, 2007, 10:36:01 pm »
0
DOMAIN x [0,2]

sin (2∏x)=-1/2
-sin (2∏x) = ∏/6

???

Collin Li

  • VCE Tutor
  • Victorian
  • ATAR Notes Legend
  • *******
  • Posts: 4966
  • Respect: +17
Re: solve for the following equation
« Reply #1 on: December 03, 2007, 10:41:44 pm »
0
2sin(2pix) = -1, dom: [0,2]

period = 2pi/2pi = 1

=> sin(2pix) = -1/2

Negative solution: Q3 and Q4
=> 2pix = 7pi/6, 11pi/6
=> x = 7/12, 11/12

Add/subtract periods to get all solutions for x from [0,2]:
x = 7/12, 11/12, 19/12, 23/12

Neobeo

  • Victorian
  • Trendsetter
  • **
  • Posts: 188
  • 反逆 の Neobeo
  • Respect: +3
Re: solve for the following equation
« Reply #2 on: December 03, 2007, 10:51:05 pm »
0
LaTeX test. Also, wondering if it was possible to insert a linebreak.

Solve for x in the domain [0,2]:



Solution by coblin:

, dom:

Period =


Negative solution: Q3 and Q4



Add/subtract periods to get all solutions for x from [0,2]:
Mathematics Coach: Tuition and Enrichment // Email/MSN:

If you remember the flying birds, they died D=

Ahmad

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1296
  • *dreamy sigh*
  • Respect: +15
Re: solve for the following equation
« Reply #3 on: December 04, 2007, 04:34:52 pm »
0
Neobeo, using \sin rather than just sin is preferred when using   :)

Compare:
rather than
Mandark: Please, oh please, set me up on a date with that golden-haired angel who graces our undeserving school with her infinite beauty!

The collage of ideas. The music of reason. The poetry of thought. The canvas of logic.