HSC Physics Marathon[NEW SYLLABUS]

[DrDusk]

My solution, I think it may be easier to see, but bit longer to do

Spoiler

i) Out of page (using rhpr but flipped hand because electrons)

ii) Using mass spectomrtry equation
i.e. qvB=mv²/r
r = mv/qB
rearranging v = rqB/m .............. (1)

Now Consider:
K = (1/2)mv²
rearrange to make v subject: v = sqrt(2K/m) ............... (2)

Equating (1) and (2)
sqrt(2K/m) = rqB/m
2K/m = (r²q²B²)/m²
Just rearrange to make B² subject
B² > 2Km/qr
B > sqrt((2Km/qr))
(Now: q=e and r=d)
B > sqrt((2Km/e²d²))
There may be lots of errors because it is too messy to read with this crap formatting.

Well done on this attempt!




Well done on getting this far! You've almost got it

[DrDusk]

UPDATE:
Now that the HSC has happened we know what level of questions to expect.
With my finals finishing in the next 2/3 weeks. I will be releasing a whole papers worth of questions!

Coincidentally a question that appeared in the HSC was one of the questions that I uploaded here!

[Coolmate]

UPDATE:
Now that the HSC has happened we know what level of questions to expect.
With my finals finishing in the next 2/3 weeks. I will be releasing a whole papers worth of questions!

Coincidentally a question that appeared in the HSC was one of the questions that I uploaded here!

Thanks DrDusk!
This is very exciting, I can't wait to complete some questions!

Coolmate

[mani.s_]

Question 1:

This one is quite easy. Make sure to set your working and equations out clearly.

What does it mean by far the ball has dropped when it strikes the hill???

[DrDusk]

What does it mean by far the ball has dropped when it strikes the hill???

It means what is it's 'y' displacement from where it was launched.

[mani.s_]

It means what is it's 'y' displacement from where it was launched.

So its height at the marked point? or are you talking about its range for the launch position?

[DrDusk]

So its height at the marked point? or are you talking about its range for the launch position?

It's how far it as fallen so (the height of the building) - (it's height at that point)

[mani.s_]

It's how far it as fallen so (the height of the building) - (it's height at that point)

ohhhh ok. Thank you so much!!!

[mani.s_]

Question 3:

This is a good question. You will need to think!

A very good question for the new syllabus!

Let me add just in case, you may make the assumption that the effect of gravity on the electron is negligible

Also typo. The time spent between the plates should be 2.6 times 10^{-9} in the 2nd last line!

Hi, for this question I was wondering why won't be 0. The electron gun causes the electron to have a initial velocity but isn't that velocity in the horizontal direction? So the initial velocity in the y direction be 0?