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Homer

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« Reply #30 on: May 02, 2013, 09:36:09 pm »
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Thanks
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jono88

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« Reply #31 on: May 03, 2013, 05:47:40 pm »
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What is the difference between tensile strength and yield strength?

Phy124

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« Reply #32 on: May 03, 2013, 07:31:31 pm »
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Ultimate tensile strength is the maximum stress a material can withstand before failing under tension.

Yield strength is the maximum stress which a material can withstand before it begins to deform plastically, rendering it unable to return to its original state.
« Last Edit: May 03, 2013, 07:33:07 pm by 2/cos(c) »
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Homer

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« Reply #33 on: May 13, 2013, 06:56:42 pm »
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How to?

EDIT: I actually figured out a way to do this now, but not sure if right or not

$\frac{2}{m^2}\times 16mm^2$

$\frac{2}{(1000mm)^2}\times 16mm^2$

$\frac{32mm^2}{(1000mm)^2}$

$\frac{32mm^2}{1000000mm^2}$

$=\frac{32}{1000000}$

$32\mu W$
« Last Edit: May 13, 2013, 07:12:28 pm by Homer »
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jono88

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« Reply #34 on: May 13, 2013, 08:06:24 pm »
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I was wondering if anyone has had there EPI yet for physics. What topics are involved?

Professor Polonsky

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« Reply #35 on: May 15, 2013, 08:17:33 pm »
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Can anyone explain why the net force (if there is no side friction) for a banked then is $mg\times\tan\theta$?
« Last Edit: May 16, 2013, 12:46:34 am by Polonius »

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« Reply #36 on: May 15, 2013, 10:50:24 pm »
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Anyone mind helping me out with my circuit question (topic link below)

circuit question

Robert123

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« Reply #37 on: May 22, 2013, 04:45:08 pm »
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Question about the 'gain' in amplifiers
First off, can you have a negative gain? Does that occur when the gradient is negative?
Secondly, my interpretation of the gain is the factor in which the input voltage is multiplied to get the output voltage. However, in Qs 3a in Test 2 on electronic & photonics part in the atar notes book, it doesn't work because the gradient is negative.
Also, my original understanding with circuits, if you have two resistors in a circuit, the resistor with the highest resistance will have the highest power output. But this doesn't seem the case with resistors in parallel. Could someplease please confirm this and try to explain it a bit.
Thanks

EspoirTron

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« Reply #38 on: May 22, 2013, 09:50:53 pm »
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Question about the 'gain' in amplifiers
First off, can you have a negative gain? Does that occur when the gradient is negative?
Secondly, my interpretation of the gain is the factor in which the input voltage is multiplied to get the output voltage. However, in Qs 3a in Test 2 on electronic & photonics part in the atar notes book, it doesn't work because the gradient is negative.
Also, my original understanding with circuits, if you have two resistors in a circuit, the resistor with the highest resistance will have the highest power output. But this doesn't seem the case with resistors in parallel. Could someplease please confirm this and try to explain it a bit.
Thanks

Remember that the formula for gain is constituted by 'change in' vout and vin. The reason you may get a 'negative' gain is that the amplifier is inverting and since the gradient of the graph is negative, you will get a negative answer. To my knowledge gain is only concerned with a magnitude; therefore, while using it to calculate vout it you simply multiply by the gain value.
To address your second question. The reason why in series that a resistor with a higher resistance will output more power is because that it will have a higher potential across it, if you recall in a series circuit each component has the same amount of current flowing through it; hence, to maintain the ratio of v2/v1 = r2/r1 the resistor with the high resistance must have a higher potential across it and consequently a higher power output. The reason why this isn't the case for resistors in parallel is that in parallel the resistors will have the same potential but varying current based on their resistance. Therefore, I believe the lower the resistance the higher the current; thus, the resistor with the lowest resistance will have the highest power output (in the parallel component).
I hope that helped you out!
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sin0001

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« Reply #39 on: May 22, 2013, 11:25:07 pm »
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Just a made-up example for help:
E.g. Suppose there's a circuit involving 2 resistors (2 and 6 ohms) in parallel, the battery supplies, let's say, 8 V. Current would be 1.5 A, the 2 ohm resistor would receive 3/4 of the total current, so 9/8 A. Whereas the 6 ohm resistor would get 1/4 of the total current, so 3/8 A.
P(2 ohm)= I^2 x R = (9/8)^2 x 2 = 2.53 W
P(6 ohm) = (3/8)^2 x 6 = 0.84 W
So it can be seen that the resistor with the lowest resistance, in a parallel circuit, would have the highest power output.
Hope this helps!
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~T

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« Reply #40 on: May 27, 2013, 04:51:31 pm »
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^^ just getting resistance and current mixed up...

$\frac{1}{R_{T}} = \frac{1}{2} + \frac{1}{6} = \frac{2}{3}$

therefore $R_{T} = \frac{3}{2}$, not $I$

Current is thus given  $I_{T} = \frac{V}{R_{T}} = \frac{8}{1.5} = 5.33A$

The point still stands of course, but none of that calculation is even required.
The smaller resistor will receive $I_{2} = \frac{V_{T}}{R} = \frac{8}{2} = 4A$
The larger resistor will receive $I_{2} = \frac{V_{T}}{R} = \frac{8}{6} = 1.33A$

As $V$ is the same for both resistors (parallel circuit), the current will be greater for less resistance as $I=\frac{V}{R}$ and then the power will be greater because $P=VI$
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Homer

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« Reply #41 on: May 27, 2013, 07:54:53 pm »
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with question 6 in the vcaa 2011 exam 1, how do we know that the switch it attached across the resistor or thermistor?
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FlorianK

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« Reply #42 on: May 27, 2013, 08:38:44 pm »
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When the temperatur increases the resistance goes down and the voltage across the thermistor goes down, hence the voltage across the resistor goes up. If we would have a 500 Ohm resistor and the 1500Ohm Thermistor (at 20°) and the circuit switch across the thermistor then the circuit would switch when the temperature falls below 20° and not when it goes above 20°

tote.moore

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« Reply #43 on: May 28, 2013, 06:24:46 pm »
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from memory the question was...

If a certain amount of Power is transmitted through power lines into a house, why does the voltage of an appliance go up when another appliance is turned off?

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