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December 14, 2019, 02:49:18 am

Author Topic: VCE Further Maths Question Thread!  (Read 336148 times)  Share 

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ashmi

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Re: VCE Further Maths Question Thread!
« Reply #2535 on: November 03, 2019, 08:06:19 pm »
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Can someone please explain Q3 from matrices module NHT exam 2019?

I'm going to assume you are talking about Exam 2 Matrices?
For this question, it tells you that there will always be 600 Gillen residents watching C3 whereas the remaining 1400 will not be watching C3. They give you a 2 by 2 matrix with row 2, column one already filled which is 0.35 (C3 to Not C3).

The first thing you can do off the bat is find V by doing 1 - 0.35 = 0.65 because we know that in a transition matrix, all the columns must equal 1.
The next thing to do is that now you know that 0.35 (the number given) times by 600 (your original Gillen residents watching C3), you get 210 which means the amount of not watching C3 (That moved from C3).

With this, all that is left to do is 210/1400 (Original not watching C3) and you get the proportion 0.15 for w. To find x just do 1 - 0.15 = 0.85.  ;D
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Sherlock.Holmes

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Re: VCE Further Maths Question Thread!
« Reply #2536 on: November 03, 2019, 08:38:03 pm »
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Thank you so much
Makes sense 👍🏼

Em.C11

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Re: VCE Further Maths Question Thread!
« Reply #2537 on: December 11, 2019, 02:50:57 pm »
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How do I find the centre/median for a skewed histogram? A symmetric one is fine but I am unsure for a skewed, if someone could explain it to me it would be well appreciated. Thanks.

NomotivationF

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Re: VCE Further Maths Question Thread!
« Reply #2538 on: December 11, 2019, 03:06:38 pm »
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How do I find the centre/median for a skewed histogram? A symmetric one is fine but I am unsure for a skewed, if someone could explain it to me it would be well appreciated. Thanks.

You would do the same as you would for any normal histogram. Just count from each side until you reach the middle number
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Em.C11

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Re: VCE Further Maths Question Thread!
« Reply #2539 on: December 11, 2019, 03:16:10 pm »
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You would do the same as you would for any normal histogram. Just count from each side until you reach the middle number
Even if their are higher frequency values on one side compared to the other? If you count to the middle number it's not necessarily even on both sides?

NomotivationF

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Re: VCE Further Maths Question Thread!
« Reply #2540 on: December 11, 2019, 03:55:18 pm »
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Even if their are higher frequency values on one side compared to the other? If you count to the middle number it's not necessarily even on both sides?

Is there any chance you can upload a picture of the question? I like to think of the histogram as a dot plot when finding medians. If you look at q3 from NHT 2018 Exam two for example, you would count the frequency of each bird weight if you wanted to find the median. Since there are 143 birds, and the weight of 0-1000 has a frequency of over 100, the median would be 0-1000 if you understand what I mean?
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Em.C11

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Re: VCE Further Maths Question Thread!
« Reply #2541 on: December 11, 2019, 04:09:47 pm »
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Is there any chance you can upload a picture of the question? I like to think of the histogram as a dot plot when finding medians. If you look at q3 from NHT 2018 Exam two for example, you would count the frequency of each bird weight if you wanted to find the median. Since there are 143 birds, and the weight of 0-1000 has a frequency of over 100, the median would be 0-1000 if you understand what I mean?
This is a question from the further textbook, it is asking to find the "approximate location of the centre"
« Last Edit: December 11, 2019, 04:11:30 pm by Em.C11 »

Sine

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Re: VCE Further Maths Question Thread!
« Reply #2542 on: December 11, 2019, 04:57:31 pm »
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This is a question from the further textbook, it is asking to find the "approximate location of the centre"
I think you should manually count the total number of whatever is on this histogram and then go from either the left or right-hand side of the graph to find the certain point that there is 50% of the data above and 50% of the data below that point. This will find the median.

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Re: VCE Further Maths Question Thread!
« Reply #2543 on: December 11, 2019, 05:06:56 pm »
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This is a question from the further textbook, it is asking to find the "approximate location of the centre"

We can read this and see that the frequencies are:
13,15,12,11,8,6,5,4,4,2,1 (I'm doing this visually but for an assessment I'd use a ruler)
1+2+4+4+5+6+8+11 = 41   (summing from right to left)
13+15+12= 40                    (summing from left to right)

Thus the median value will be contained in the column with a frequency of 11 (the fourth column from the left)
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TheEagle

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Re: VCE Further Maths Question Thread!
« Reply #2544 on: December 11, 2019, 07:39:55 pm »
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This is a question from the further textbook, it is asking to find the "approximate location of the centre"

I remember having trouble with that earlier this year. In that specific question, the textbook is seemingly asking for an approximate median, hence I'd just see the "middle-ish" value as the median. However, for an exact median calculation, I'd do choose the (n+1)/2th value as the median (remember to add the frequencies in ascending order) :)

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Re: VCE Further Maths Question Thread!
« Reply #2545 on: December 13, 2019, 12:10:15 pm »
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Hey, everyone, I've been searching google but I can't seem to find anything

Could someone explain to me what this means

50 < 55 seconds

thanks
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MEH0010

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Re: VCE Further Maths Question Thread!
« Reply #2546 on: December 13, 2019, 12:29:29 pm »
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Hey, everyone, I've been searching google but I can't seem to find anything

Could someone explain to me what this means

50 < 55 seconds

thanks

Hello,
This means 50 seconds to less than 55 seconds
This includes 50 seconds but not 55 seconds
For example, 53 is a number between 50 < 55 seconds.
Hope this helps
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