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May 11, 2021, 07:06:11 am

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#### keltingmeith

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##### Re: VCE Methods Question Thread!
« Reply #18765 on: September 06, 2020, 09:41:56 pm »
+4
True. I'm specifically referring to chapter 14C from the Cambridge textbook. It's pretty much all CAS work but my friend is saying it has been removed from the course for this year.

In this case - there's nothing that has been removed from the study design relating to the binomial distribution. So technically, no, it hasn't been removed. I'm going to be honest, I don't remember having seen these types of questions being asked for a while (although S_R_K is probably a better judge of that than me), so if you're that worried, feel free to take the gamble. However, they're also not that hard, it's just different thinking - so could be worth learning that section so you get the new way of thinking.

how would i convert an equation from slope-intercept form (y=mx+c) to standard form (ax+by=c) using ONLY cas (tinspire specifically)? i know it's often easier to do this by-hand but....just in case

I don't know of a CAS function that can do this, but I cannot think of a single instance you'll be required to do this on a CAS and not in your head or on the page. All you do is multiply both sides by the denominator of m, then by the denominator of c, then move the x term to the other side. TBH, if the question asked (and I can promise you - VCAA will never ask this) you, "Convert y=(5/6)x + (2/3) into standard form using only your CAS", you should be able to do that in your head and just write, "by CAS, 18y-15x = 12". It's not like you submit your calculator for inspection after the exam, so.

Perchance there's a situation you imagined in your head you might need it for, and I might be able to help assuage those fears?

#### p0kem0n21

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##### Re: VCE Methods Question Thread!
« Reply #18766 on: September 07, 2020, 09:32:03 am »
0
haha nah im not scared, it's just that we have a ti-nspire assignment (im in year 10) and one of the things asked of us to do is to convert slope-intercept to standard form but...... i guess i can pretend i used cas xD

#### TheEagle

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##### Re: VCE Methods Question Thread!
« Reply #18767 on: September 08, 2020, 01:00:18 am »
0
Anyone know if continuous random variables are still in the course or not (i.e ch 15 of Cambridge)?

#### The Cat In The Hat

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##### Re: VCE Methods Question Thread!
« Reply #18768 on: September 08, 2020, 09:08:53 am »
+1
What's in the 2020 probability curriculum: 13AB, Ch 14, Ch 16, understanding of the importance of shape (positive and negative skew & symmetry), centre (mean = µ = average = long term expected value), spread (std dev = √var = sigma)

So, no.
VCE 20
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Mildly terrified that I've missed something important!
I hope I don't fail....
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#### Umar but with O

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##### Re: VCE Methods Question Thread!
« Reply #18769 on: September 08, 2020, 02:53:08 pm »
0
Is the study of matrices in units 1/2 required for units 3/4 (methods)?

#### Sine

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##### Re: VCE Methods Question Thread!
« Reply #18770 on: September 08, 2020, 03:07:27 pm »
0
Is the study of matrices in units 1/2 required for units 3/4 (methods)?
I think most schools go into matrices in more depth in units 1/2 than what is actually required for 3/4.

For 3/4 the importance of matrices lie with transformations however it is probably safer to revise addition/mutiplication/inverse of matrices as well.

#### eloisegrace

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##### Re: VCE Methods Question Thread!
« Reply #18771 on: September 08, 2020, 03:13:45 pm »
+1
Anyone know if continuous random variables are still in the course or not (i.e ch 15 of Cambridge)?
Nope, only discrete, binomial and normal variables. No stats either
2020 - mathematical methods [42] | further mathematics [45]
2021 - english language | chemistry | french | physical education
my vce journey !

#### The Cat In The Hat

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##### Re: VCE Methods Question Thread!
« Reply #18772 on: September 08, 2020, 04:43:45 pm »
+1
Hi Guys,

Could someone please help me with the attached questions, im so clueless with how to do them.

Cheers
Hi and welcome to AN! Could you please put the question/s up in full? All I see is a short sentence and no context.
VCE 20
HHD 19 (26.83) MM (39.16) Revs (F/R) (30.96) Eng (39.26) T&T (34.19)
ATAR: 85.00
Uni 21-24: BNursing/BMidwifery @ Deakin
Y1T1:
HNM101
HNN112
HNN120
HBS109
Mildly terrified that I've missed something important!
I hope I don't fail....
~English - PM for P&P/creatives help~
Creative excerpts
Nur/Mid uni journal

For Narnia and for Aslan!

she/her

#### The Cat In The Hat

• MOTM: NOV 20
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##### Re: VCE Methods Question Thread!
« Reply #18773 on: September 08, 2020, 05:22:51 pm »
0
Since we have no idea about what programs these are, they cannot be answered. Could you put in the entire question please?
VCE 20
HHD 19 (26.83) MM (39.16) Revs (F/R) (30.96) Eng (39.26) T&T (34.19)
ATAR: 85.00
Uni 21-24: BNursing/BMidwifery @ Deakin
Y1T1:
HNM101
HNN112
HNN120
HBS109
Mildly terrified that I've missed something important!
I hope I don't fail....
~English - PM for P&P/creatives help~
Creative excerpts
Nur/Mid uni journal

For Narnia and for Aslan!

she/her

#### The Cat In The Hat

• MOTM: NOV 20
• Posts: 900
• Do all to the glory of God. - 1 Corinthians 10:31
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##### Re: VCE Methods Question Thread!
« Reply #18774 on: September 08, 2020, 05:47:33 pm »
0
Quote
The probability that a new puppy qualifies for the scent training program is 1/3 and the probability that it qualifies for the guide dog program is 1/4.
g) If a puppy cannot qualify for both programs, what is the mathematical term that represents this situation?
It can qualify for one or the other, so they are mutually exclusive.
VCE 20
HHD 19 (26.83) MM (39.16) Revs (F/R) (30.96) Eng (39.26) T&T (34.19)
ATAR: 85.00
Uni 21-24: BNursing/BMidwifery @ Deakin
Y1T1:
HNM101
HNN112
HNN120
HBS109
Mildly terrified that I've missed something important!
I hope I don't fail....
~English - PM for P&P/creatives help~
Creative excerpts
Nur/Mid uni journal

For Narnia and for Aslan!

she/her

#### Sine

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##### Re: VCE Methods Question Thread!
« Reply #18775 on: September 14, 2020, 04:00:50 pm »
0
Hi Guys,

Was wondering if anyone would please show me how to do this question and provide solutions.

What aspect of the question are you having difficulty with? What have you tried so far?

Also, please try to refrain from double posting in the future.

#### Sine

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##### Re: VCE Methods Question Thread!
« Reply #18776 on: September 14, 2020, 05:01:52 pm »
+3
The whole question, i am very unsure. My methods skills are pretty bad. Thanks so much for your time Sine.

The questions says the time to complete the workout is normally distributed with a mean of 30 minutes and a standard deviation of 2 minutes.

This should be a very clear sign that you need to define the random variable T.

So, T ~ N(30,22) or T ~ N(30, 4). Is this notation familiar?

If you want to find the probability that she takes less than 25 minutes to finish her work out use the random variable T.

Pr(T < 25)
To solve this you convert it to a standard normal distribution with a mean of 0 and standard deviation of 1 (Z ~ (0,1))
Pr(T < 25) = Pr (Z < (25-30)/2)) = Pr(Z < -2.5)

#### rukayabal

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##### Re: VCE Methods Question Thread!
« Reply #18777 on: September 15, 2020, 01:44:27 pm »
0
Hi all,
I would like to know whether combinatorics and permutations and all the factorial skills need to be known for the current study design as I am completely clueless about them. I saw a question in the 2019 nht exam 1 and seems incredibly complicated. Here it is. I have attached it.

I would really appreciate a reply.

« Last Edit: September 15, 2020, 01:46:10 pm by rukayabal »

#### S_R_K

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##### Re: VCE Methods Question Thread!
« Reply #18778 on: September 15, 2020, 01:48:15 pm »
+1
That exam question is from the current study design, so yes.

#### keltingmeith

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##### Re: VCE Methods Question Thread!
« Reply #18779 on: September 15, 2020, 02:03:17 pm »
+1
Hi all,
I would like to know whether combinatorics and permutations and all the factorial skills need to be known for the current study design as I am completely clueless about them. I saw a question in the 2019 nht exam 1 and seems incredibly complicated. Here it is. I have attached it.

I would really appreciate a reply.

Just adding on to what S_R_K has said - these questions also aren't too difficult, don't be scared just because they're technically in the realm of combinatorics. Remember - this is just a binomial distribution problem, all you need to do is apply the binomial distribution material as you were taught it in class.