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April 20, 2024, 07:07:07 pm

Author Topic: Increasing versus strictly increasing  (Read 3040 times)  Share 

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Massimooo123

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Increasing versus strictly increasing
« on: November 05, 2019, 08:12:56 pm »
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I've done a bit of searching on this, but I'm just looking for a straight answer here that doesn't delve into the very deep specifics of the definitions.

The function f(x) = -(x-1)(x+1)^2 has stationary points at x=-1 and x=1/3. f'(x)>0 for -1<x<1/3, and f'(x)≥0 for -1≤x≤1/3.

For what interval of x is f(x) increasing?

For what interval of x is f(x) strictly increasing?

That's all I want to know. Everyone seems to dance around the question for some reason, but just answering this example will make me very happy.

KiNSKi01

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Re: Increasing versus strictly increasing
« Reply #1 on: November 05, 2019, 08:20:52 pm »
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Strictly increasing means as long as it isn't decreasing (so turning points included)
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Tau

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Re: Increasing versus strictly increasing
« Reply #2 on: November 05, 2019, 08:41:49 pm »
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This is VCAA’s definition per their FAQ for Maths:

When is a function strictly increasing or strictly decreasing over an interval?
A function f is said to be strictly increasing over an interval when a < b implies f(a) < f(b) for all a and b in that interval. Similarly, a function f is said to be strictly decreasing over an interval when a < b implies f(a) > f(b) for all a and b in that interval.
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Massimooo123

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Re: Increasing versus strictly increasing
« Reply #3 on: November 05, 2019, 10:52:31 pm »
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Thank you both. Tau, that was the definition I was thinking of when I was talking about dancing around the question, but now that you've said it here it actually makes perfect sense and I don't know why I was confused haha.

Does increasing include stationary points?