Author Topic: Extension 1 Parametrics help (Read 730 times) Tweet Share

88siege · « **on:** May 01, 2018, 08:36:44 pm »

Part (iii) and (iv) please.

For Part (iii) I've gotten for V(-7at, -a(t^2 +3)) But it doesn't look correct because it says that V is on the bottom left of the graph, while in the diagram it shows its in the top right?

?

RuiAce · « **Reply #1 on:** May 01, 2018, 08:45:39 pm »

$\text{If I divide }T(2at, -at^2)\text{ and }U(-at, -at^2-3a)\\ \text{in the ratio }-2:3$
(noting the external division)
$\text{then I arrive at the point}\\ \left( \frac{2at + 6at}{-2+3}, \frac{(2at^2+6a) - 3at^2}{-2+3} \right)$

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Author Topic: Extension 1 Parametrics help (Read 730 times) Tweet Share

88siege

Extension 1 Parametrics help

RuiAce

Re: Extension 1 Parametrics help

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