Hello, how do solve find the volume of solid of revolution rotated about the x axis or the y axis.
For example, how do I solve area bounded by y=x^2, y=-x(x-2)
Area bounded by y=x^1/2, y=4 and the y-axis
Area bounded by x=y^2, y=-1, y=1 and the y axis.
The volume when rotated around the y axis is
and when rotated around the x axis is
So if the graph of y=x
1/2 between y=4 and the y axis is rotated around the y axis, we know the boundaries are y=4 (given), and y=0 as the y axis is where x=0, so y=0
1/2=0
From there it's just standard integrals. The other questions should follow a similar format.
If you want to find the volume where the area
between two graphs is rotated, you subtract one volume from the other. That is:
The volume when rotated around the y axis is
Note f(y) is just like the x from before, basically x in terms of y.
and when rotated around the x axis is
Note: drawing it out is
very useful