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March 30, 2024, 12:55:44 am

Author Topic: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions  (Read 64749 times)

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S200

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #225 on: November 09, 2018, 12:50:59 am »
0
My teacher said that a difficult exam 1 normally means an easier exam 2...
Show how muc he know bout normal distribution! :P
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crouchie

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #226 on: November 09, 2018, 07:50:18 am »
+4
VCAA 2018 Methods Exam 2 Provisional Solutions
Solutions by Daniel Traicos at TWM Publications

Interesting exam! Definitely some difficult ones!

Well done Dan. I'm sure the community appreciates your effort.
So sorry I wasn't able to do mine in time, I'll work on mine over today/the weekend and put CAS screenshots (TI CX) for those using that.
Thanks again, you're a champ.

integrationbyrecognition

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #227 on: November 09, 2018, 08:00:50 am »
0
My teacher said that a difficult exam 1 normally means an easier exam 2...
Show how muc he know bout normal distribution! :P
How did you find yesterday's exam in terms of difficulty?
The people that wrote these exams legit make them harder each year

DinWell

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #228 on: November 09, 2018, 08:03:22 am »
+1
Well done Dan. I'm sure the community appreciates your effort.
So sorry I wasn't able to do mine in time, I'll work on mine over today/the weekend and put CAS screenshots (TI CX) for those using that.
Thanks again, you're a champ.
Wow, you two are absolute legends. Can’t thank you both enough.
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Lear

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #229 on: November 09, 2018, 08:19:15 am »
0

Wow, you two are absolute legends. Can’t thank you both enough.


Ditto.
Jazzycab, Crouchie and Dantraicos. Great work guys.
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AlphaZero

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #230 on: November 09, 2018, 09:15:49 am »
+1
Well done Dan. I'm sure the community appreciates your effort.
So sorry I wasn't able to do mine in time, I'll work on mine over today/the weekend and put CAS screenshots (TI CX) for those using that.
Thanks again, you're a champ.

Haha, exam 2s are just a killer to write up nicely. The CAS screenshots I think will really benefit people. Looking forward to reading your solutions soon. See you at spesh E1 :D
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Sean_G

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #231 on: November 09, 2018, 09:34:17 am »
0
How did you guys get 1/8 for the question (on the second last page I think?) finding area? I got a different answer although 1/8 was one of the answers I got using a method.

And for the three-mark question finding distance PQ, was there any other method that was less time-consuming than finding the coordinates of Q than using the distance formula? The distance formula felt like it has been used so much in these two exams.

For the distance PQ you had the angle pi/90 and the hypotenuse distance which was something I can't remember, but you could just use regular trig and solve for the missing length

crouchie

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #232 on: November 09, 2018, 09:45:16 am »
+1
Haha, exam 2s are just a killer to write up nicely. The CAS screenshots I think will really benefit people. Looking forward to reading your solutions soon. See you at spesh E1 :D
Agreed. Very hard to write up nicely as the algebra can sometimes get so gnarly. And then the CAS screenshots can take up heaps of space, so have to find efficient ways to show steps (such as solve(derivative(f(x))=0,x) which is 1 step which normally takes 2).
See you at Spesh E1!

Alexmaths

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #233 on: November 09, 2018, 04:18:34 pm »
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Can somebody please explain how you were supposed to do question 5 on the short answer? I remember it saying something about an inverse of g, and when I put it in my calculator it gave me a strange result, the answers I've seen have just been basic integrals and such. How we're you meant to go about solving it? I got that 2a/3 x g(2a/3) was equal to 2, but I can't see how this helps. Thanks

DinWell

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #234 on: November 09, 2018, 05:29:44 pm »
0
Can somebody please explain how you were supposed to do question 5 on the short answer? I remember it saying something about an inverse of g, and when I put it in my calculator it gave me a strange result, the answers I've seen have just been basic integrals and such. How we're you meant to go about solving it? I got that 2a/3 x g(2a/3) was equal to 2, but I can't see how this helps. Thanks
Here's how I thought about it:
Imagine the graph of g(x). The graph along the y axis is the inverse of g(x) right? In other words, if we rotated the graph of g(x) by 90 degrees counterclockwise and flipped it about the x axis (which is now vertical), we'd get the graph of the inverse of g(x). Then  the line x=g(3a/2) can instead by changed to y=g(3a/2) when looking at g(x). So what we really want is the area that g(x) makes with the y axis from y=0 to y=g(3a/2). We find this by taking the area of a rectangle that encloses g(x), and minus the area that g(x) makes with the x axis from x=0 to x=3a/2. The previous question helped you because it made you find, just the area of a rectangle with length 3a/2 and height g(3a/2). It was a subtle hint imo.
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integrationbyrecognition

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #235 on: November 10, 2018, 02:31:04 pm »
0
For the question where we had to find the distance (3 marks), I was only able to work out the gradient of the perpendicular line (using m1*m2 = -1)
Am I likely to get 1/3?
For some reason, under exam pressure, I wasn't even able to make the simple link that when I have the gradient of the perpendicular line, I just had to sub the coordinates of "P" and then I have the equation of the line, then equate the line to the original line, and then find the distance. True example of exam pressure haha
Does anyone have a prediction of the a+ cutoff for exam 1 and exam 2 respectively?
Thanks

AlphaZero

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #236 on: November 10, 2018, 07:19:36 pm »
0
Does anyone have a prediction of the a+ cutoff for exam 1 and exam 2 respectively?
Thanks

I predict the cutoffs will be:
Exam 1: 33-34 / 40
Exam 2: 67-68 / 80
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Worm

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #237 on: November 11, 2018, 06:45:30 pm »
+1
I predict the cutoffs will be:
Exam 1: 33-34 / 40
Exam 2: 67-68 / 80

Hi dantraicos...

Solutions look good. The only one you buggered up is 3f... You can't use trig rule as it is not a triangle, as the angle pi/90 is with the horizontal, not the point P... Otherwise everything else looks correct.

cheers,
Worm

AlphaZero

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #238 on: November 11, 2018, 07:19:40 pm »
+1
Hi dantraicos...

Solutions look good. The only one you buggered up is 3f... You can't use trig rule as it is not a triangle, as the angle pi/90 is with the horizontal, not the point P... Otherwise everything else looks correct.

cheers,
Worm

Oh my!!! I can't believe I fell for that :( Thanks mate
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Lear

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Re: Maths Methods (Exam 2): Discussion, Questions & Potential Solutions
« Reply #239 on: November 11, 2018, 07:26:35 pm »
0
Hi dantraicos...

Solutions look good. The only one you buggered up is 3f... You can't use trig rule as it is not a triangle, as the angle pi/90 is with the horizontal, not the point P... Otherwise everything else looks correct.

cheers,
Worm

Wait....crap. If a person used the triangle method do you think all 3 marks would be taken off?
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