Hi again.
So I have another question which is from the same attachment.
I am trying to do question c with intervals of pi/3. I drew the graph with intervals of pi/3 with the amplitude of 2. So, the range is -3 to 3.
When you sub in pi/3 into the equation how do you solve it to get the y value. ?
How do you do it on cas? It keeps saying missing) .
Can you post exactly what your CAS is saying?
I used the CAS and did it by hand and got the same answer.
I'm assuming it says "missing (" because you put it in like this into the CAS:
The calculator wont recognise this form you have to put in the 3 thats being multiplied inside the bracket like this:
@Evolio
I can also help you figure out the way to do it by hand if you would like.
Furthermore, the range is only [-2, 2] because only the 2 at the front alters the amplitiude which is two,
The 3 being multiplied inside the bracket changes the period.