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April 24, 2024, 07:56:00 am

Author Topic: Mathematics Question Thread  (Read 1306010 times)  Share 

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msimo4

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Re: Mathematics Question Thread
« Reply #3810 on: October 13, 2018, 10:07:42 pm »
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Just a question about physical apps: is there a specific way/rule to find the limiting velocity? Like for example, how when you need to find the maximum velocity you let acceleration = 0. Is there a similar thing for limiting velocity? Or is it only a question that they'll give us as a lead in after previous questions, the answers of which we have to use to solve the limiting velocity?

RuiAce

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Re: Mathematics Question Thread
« Reply #3811 on: October 13, 2018, 10:16:04 pm »
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Examine the limit as \(t\to \infty\).

That's what "limiting" means in the applications topic. It means to consider the eventual behaviour of your particle, which is what happens as your \(t\) gets very large.

jamonwindeyer

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Re: Mathematics Question Thread
« Reply #3812 on: October 14, 2018, 09:52:28 am »
+4
Ily Rui <3

RuiAce

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Re: Mathematics Question Thread
« Reply #3813 on: October 14, 2018, 10:08:51 am »
+3
Ily Rui <3
This is a miracle. Did Jamon just make my life complete <3

jamonwindeyer

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Re: Mathematics Question Thread
« Reply #3814 on: October 14, 2018, 01:29:37 pm »
+1
This is a miracle. Did Jamon just make my life complete <3

I was demoing the forums, but if it completes you I am happy to have played a part ;)

saige_abigail

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Re: Mathematics Question Thread
« Reply #3815 on: October 14, 2018, 03:51:59 pm »
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The correct answer was 48.2% ? In the textbook


Permit k to be negative in your working out.




This is the question that I'm struggling with. Why 0.9 instead of 0.1? And what happens to the M0? These questions might sound stupid but I'm just trying to understand.

RuiAce

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Re: Mathematics Question Thread
« Reply #3816 on: October 14, 2018, 04:21:15 pm »
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This is the question that I'm struggling with. Why 0.9 instead of 0.1? And what happens to the M0? These questions might sound stupid but I'm just trying to understand.
10% is just how much of it has decayed. But that’s not gonna help us measure anything easily.

Because how else can we measure what percentage decays in the next year? Or the year after that? (Note that in fact, in the second year what’s decayed is 90% * 10%, i.e. 9%. And in fact, another 8.1% decays in the third year.)

This is because the amount that decays per year is not dependent on how much has decayed last year, but rather how much from last year has not decayed. The problem is then that to figure out the total decay, we need to keep a running record of how much decays only in the n-th year, and then do the sum of a GP.

It turns out it is much easier to just resort to keeping track of how much is there still left, as opposed to what’s already decayed. This simplified the computations a lot more.

The M0 simply gets cancelled out on both sides of the equation. We don’t need to know what M0 is to complete the question

Also note that the post had a mistake, which was addressed a bit further down
« Last Edit: October 14, 2018, 04:25:15 pm by RuiAce »

saige_abigail

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Re: Mathematics Question Thread
« Reply #3817 on: October 14, 2018, 04:32:40 pm »
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10% is just how much of it has decayed. But that’s not gonna help us measure anything easily.

Because how else can we measure what percentage decays in the next year? Or the year after that? (Note that in fact, in the second year what’s decayed is 90% * 10%, i.e. 9%. And in fact, another 8.1% decays in the third year.)

This is because the amount that decays per year is not dependent on how much has decayed last year, but rather how much from last year has not decayed. The problem is then that to figure out the total decay, we need to keep a running record of how much decays only in the n-th year, and then do the sum of a GP.

It turns out it is much easier to just resort to keeping track of how much is there still left, as opposed to what’s already decayed. This simplified the computations a lot more.

The M0 simply gets cancelled out on both sides of the equation. We don’t need to know what M0 is to complete the question

Also note that the post had a mistake, which was addressed a bit further down

So to clarify: if the substance decays by 10% - 90% is what's left?

RuiAce

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Re: Mathematics Question Thread
« Reply #3818 on: October 14, 2018, 07:06:11 pm »
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So to clarify: if the substance decays by 10% - 90% is what's left?
Yeah.

Because 100% minus 10% is 90%.

skisso

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Re: Mathematics Question Thread
« Reply #3819 on: October 15, 2018, 06:25:49 pm »
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Helloo :) having trouble with HSC paper 2009, Question 10 e).
I dont understand the answers online or the answers in the excel book i have.
« Last Edit: October 15, 2018, 06:30:25 pm by skisso »

clovvy

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Re: Mathematics Question Thread
« Reply #3820 on: October 15, 2018, 06:34:57 pm »
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Helloo :) having trouble with HSC paper 2009, Question 10 e).
I dont understand the answers online or the answers in the excel book i have.
Hey, what they did is simply using product rule for (1+x)ln(1+x).... If you still don't understand feel free to reply and I'll try to explain further as best as I can..
2018 HSC: 4U maths, 3U maths, Standard English, Chemistry, Physics

fun_jirachi

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Re: Mathematics Question Thread
« Reply #3821 on: October 15, 2018, 06:37:42 pm »
+2

« Last Edit: October 15, 2018, 06:41:11 pm by fun_jirachi »
Spoiler
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HSC 2019: Physics [92] | Chemistry [93] | English Adv [87] | 3U Maths [98] | 4U Maths [97]
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skisso

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Re: Mathematics Question Thread
« Reply #3822 on: October 15, 2018, 06:53:56 pm »
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Hey, what they did is simply using product rule for (1+x)ln(1+x).... If you still don't understand feel free to reply and I'll try to explain further as best as I can..

Ohh i see. I had interpreted the question wrong and though that you had to integrate or something, but I got in now. Thanks!!

SebastianHabibi

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Re: Mathematics Question Thread
« Reply #3823 on: October 17, 2018, 06:02:05 pm »
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HELP!!!!
The focal chord that cuts the parabola x^2 = -6y at (6,-6) cuts the parabola again at X. Find the coordinates of X

fun_jirachi

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Re: Mathematics Question Thread
« Reply #3824 on: October 17, 2018, 06:11:03 pm »
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You can see that from the equation focal length=1.5, and that the focus is (0, -1.5) since the vertex is at (0,0) (from x=-b/2a, after converting to the form y=ax^2+bx+c) and the parabola is upside down from the minus sign in front of the 6y. From there, find the equation of the line that passes through both points, by first finding the gradient then subbing into the point gradient form of a line (the gradient and any of the points), then solve simultaneously with the parabola for the solution, which shouldnt be too difficult. I got, (-3/2, -3/8), tell me if the answer was different :)

Hope I helped :)
Spoiler
HSC 2018: Mod Hist [88] | 2U Maths [98]
HSC 2019: Physics [92] | Chemistry [93] | English Adv [87] | 3U Maths [98] | 4U Maths [97]
ATAR: 99.05

UCAT: 3310 - VR [740] | DM [890] | QR [880] | AR [800]
Guide Links:
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UCAT Question Compilation/FAQ (2020)
Asking good questions