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March 29, 2024, 04:52:45 am

Author Topic: VCE Physics Question Thread!  (Read 603318 times)  Share 

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Phenomenol

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Re: VCE Physics Question Thread!
« Reply #585 on: September 02, 2014, 09:34:51 pm »
+2
Is the yield strength the same as the elastic limit of a material? If not what is the difference?  8) :-\

I believe they mean the same thing.
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Re: VCE Physics Question Thread!
« Reply #586 on: September 04, 2014, 04:58:59 pm »
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We don't have to know about incandescent light for L&M, right?
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Rishi97

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Re: VCE Physics Question Thread!
« Reply #587 on: September 08, 2014, 08:53:02 pm »
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Hey everyone

In the physics exam, can we use formulas that are not in the study design? Because my tutor said we can only use formulas if we know how to derive them :/

Thanks
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Phenomenol

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Re: VCE Physics Question Thread!
« Reply #588 on: September 08, 2014, 09:00:43 pm »
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Hey everyone

In the physics exam, can we use formulas that are not in the study design? Because my tutor said we can only use formulas if we know how to derive them :/

Thanks

Don't use obscure ones - use ones that the examiner can clearly see are rearrangements of a formula on the formula sheet, or when very simple substitutions are made. For example, e = hc/lambda is completely acceptable. (substituting f = c/lambda into the photon energy equation)
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lzxnl

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Re: VCE Physics Question Thread!
« Reply #589 on: September 08, 2014, 09:09:28 pm »
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Hey everyone

In the physics exam, can we use formulas that are not in the study design? Because my tutor said we can only use formulas if we know how to derive them :/

Thanks

Which formulas would you even want to use? I never felt the need to use extra formulas explicitly.
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Rishi97

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Re: VCE Physics Question Thread!
« Reply #590 on: September 08, 2014, 09:32:57 pm »
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Which formulas would you even want to use? I never felt the need to use extra formulas explicitly.

just ones for projectile motion such as quicker formulas to find range and time
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lzxnl

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Re: VCE Physics Question Thread!
« Reply #591 on: September 08, 2014, 10:13:22 pm »
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You sure those aren't on the formula sheet? Maybe my memory isn't working properly for me here but I swear the range is at least.
In any case, deriving it wouldn't take you more than half a minute.
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speedy

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Re: VCE Physics Question Thread!
« Reply #592 on: September 08, 2014, 10:17:33 pm »
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You sure those aren't on the formula sheet? Maybe my memory isn't working properly for me here but I swear the range is at least.
In any case, deriving it wouldn't take you more than half a minute.

It's not - that's all the motion ones:
Spoiler

I always thought that if you used a different formula, and got the answer wrong, you wouldn't get any marks for working. May be wrong though, but I would say always derive it first.
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Rishi97

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Re: VCE Physics Question Thread!
« Reply #593 on: September 08, 2014, 10:32:17 pm »
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You sure those aren't on the formula sheet? Maybe my memory isn't working properly for me here but I swear the range is at least.
In any case, deriving it wouldn't take you more than half a minute.



Nope not on there. Could you by any chance give me tips on how to derive? And from what formula?
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lzxnl

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Re: VCE Physics Question Thread!
« Reply #594 on: September 08, 2014, 10:38:10 pm »
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That is really weird.

Anyway, I'm assuming you mean the formula for no change in height projectile motion.

In the vertical direction, y=0. So ut + 1/2 at^2 = 0
We don't want t=0 = 2u + at = 0
Letting up be positive, a = -g
t = 2u/g. But u = v sin theta => t = 2v sin theta / g

Distance travelled = v cos theta * t = 2v sin theta cos theta v /g = v^2 sin(2 theta)/g by trig identity
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Re: VCE Physics Question Thread!
« Reply #595 on: September 17, 2014, 10:39:05 pm »
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any help is greatly appreciated :)

an object, projected vertically upwards with a speed U, returns with a speed V. Assuming constant gravity and air resistance proportional to the square of the speed, find the total time taken.

Yacoubb

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Re: VCE Physics Question Thread!
« Reply #596 on: September 17, 2014, 10:50:52 pm »
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any help is greatly appreciated :)

an object, projected vertically upwards with a speed U, returns with a speed V. Assuming constant gravity and air resistance proportional to the square of the speed, find the total time taken.

V= u -10t
t = -(v-u)/10
t = u-v/10 *2
t= u-v/5

Not sure if this is your answer but that's my jab! :-)

lzxnl

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Re: VCE Physics Question Thread!
« Reply #597 on: September 17, 2014, 10:59:12 pm »
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any help is greatly appreciated :)

an object, projected vertically upwards with a speed U, returns with a speed V. Assuming constant gravity and air resistance proportional to the square of the speed, find the total time taken.

What's the proportionality constant?
You'd have to break this question up into two parts as the air resistance changes direction, and even then it's a question involving calculus which wouldn't be asked for a VCE physics student.

V= u -10t
t = -(v-u)/10
t = u-v/10 *2
t= u-v/5

Not sure if this is your answer but that's my jab! :-)

Not constant acceleration; there's air resistance here
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Re: VCE Physics Question Thread!
« Reply #598 on: September 17, 2014, 11:04:50 pm »
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Not constant acceleration; there's air resistance here

Would this be right if we were told to ignore air resistance?

lzxnl

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Re: VCE Physics Question Thread!
« Reply #599 on: September 17, 2014, 11:47:11 pm »
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Your working missed a nuance in the question. The question says 'speed v'. But it's returning downwards, so its final velocity is actually -v, not v.
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