ATAR Notes: Forum

HSC Stuff => HSC Maths Stuff => HSC Subjects + Help => HSC Mathematics Advanced => Topic started by: miaconway_05 on July 31, 2021, 10:02:50 pm

Title: Expected Value Probability
Post by: miaconway_05 on July 31, 2021, 10:02:50 pm

I've tried using the standard procedure of multiplying each outcome by 1/n and adding the results. Also I'm using an expected value table, with the rows 1,2 and 3 being x,p(x),xp(x). Any help would be appreciated! *the q is 3d

Title: Re: Expected Value Probability
Post by: fun_jirachi on August 01, 2021, 12:52:29 am

The question implies you have a binomial distribution. The expected value for a binomial is \(np\) where \(p\) is the chance of 'success', and \(n\) is the number of trials. Here, you want to find the expected number of faulty cars given 3 trials and the chance of 'success' being \(\frac{1}{1000}\); hence, \(E(X) = \frac{3}{1000}\).

Hope this helps :)