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VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: droodles on December 03, 2007, 10:36:01 pm

Title: solve for the following equation
Post by: droodles on December 03, 2007, 10:36:01 pm
(http://img99.imageshack.us/img99/3259/27176368le8.png) DOMAIN x [0,2]

sin (2∏x)=-1/2
-sin (2∏x) = ∏/6

???
Title: Re: solve for the following equation
Post by: Collin Li on December 03, 2007, 10:41:44 pm
2sin(2pix) = -1, dom: [0,2]

period = 2pi/2pi = 1

=> sin(2pix) = -1/2

Negative solution: Q3 and Q4
=> 2pix = 7pi/6, 11pi/6
=> x = 7/12, 11/12

Add/subtract periods to get all solutions for x from [0,2]:
x = 7/12, 11/12, 19/12, 23/12
Title: Re: solve for the following equation
Post by: Neobeo on December 03, 2007, 10:51:05 pm
LaTeX test. Also, wondering if it was possible to insert a linebreak.

Solve for x in the domain [0,2]:



Solution by coblin:

, dom:

Period =


Negative solution: Q3 and Q4



Add/subtract periods to get all solutions for x from [0,2]:
Title: Re: solve for the following equation
Post by: Ahmad on December 04, 2007, 04:34:52 pm
Neobeo, using \sin rather than just sin is preferred when using   :)

Compare:
rather than