ATAR Notes: Forum
VCE Stuff => VCE Mathematics => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Mathematical Methods CAS => Topic started by: droodles on December 03, 2007, 10:36:01 pm
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(http://img99.imageshack.us/img99/3259/27176368le8.png) DOMAIN x [0,2]
sin (2∏x)=-1/2
-sin (2∏x) = ∏/6
???
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2sin(2pix) = -1, dom: [0,2]
period = 2pi/2pi = 1
=> sin(2pix) = -1/2
Negative solution: Q3 and Q4
=> 2pix = 7pi/6, 11pi/6
=> x = 7/12, 11/12
Add/subtract periods to get all solutions for x from [0,2]:
x = 7/12, 11/12, 19/12, 23/12
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LaTeX test. Also, wondering if it was possible to insert a linebreak.
Solve for x in the domain [0,2]:
Solution by coblin:
, dom:
Period =
Negative solution: Q3 and Q4
Add/subtract periods to get all solutions for x from [0,2]:
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Neobeo, using \sin rather than just sin is preferred when using :)
Compare:
rather than