Login

Welcome, Guest. Please login or register.

March 28, 2024, 08:19:35 pm

Author Topic: Quick complex number question  (Read 723 times)  Share 

0 Members and 1 Guest are viewing this topic.

GodlyOne

  • Adventurer
  • *
  • Posts: 12
  • Respect: 0
Quick complex number question
« on: September 27, 2017, 12:47:28 am »
0
Hi,

So if given the quadratic equation, the roots are 5i and -i however when factorising this equation over the complex field, I thought u put these roots into the assumed form of so it would be but the solution says the signs are switched which i am confused about because i thought linear complex factors can be formed by roots like usual 3u polynomials

jamonwindeyer

  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 10150
  • The lurker from the north.
  • Respect: +3108
Re: Quick complex number question
« Reply #1 on: September 27, 2017, 07:05:52 am »
+3
Hey! I think you may have mixed up the signs of your roots?



It definitely does work just as you expect once the roots are correct ;D


RuiAce

  • ATAR Notes Lecturer
  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 8814
  • "All models are wrong, but some are useful."
  • Respect: +2575
Re: Quick complex number question
« Reply #2 on: September 27, 2017, 09:17:23 am »
+3

« Last Edit: September 27, 2017, 09:18:54 am by RuiAce »

GodlyOne

  • Adventurer
  • *
  • Posts: 12
  • Respect: 0
Re: Quick complex number question
« Reply #3 on: September 27, 2017, 09:28:57 pm »
0
Thanks, I just realised that I forgot about the Sum of roots being negative which is why i got the wrong signs.