Question 9: The answer should be I and III as already said above, this seems to be an error of the book you are working from.
I would like to add that for question 10, the given answer is correct (it should be D). Have a read of this (from my notes):
Changing pressure/volume (with regards to gases only)
- If pressure decreases, then volume increases (reaction will move to the side that makes the most particles in the products)
- If pressure increases, then volume decreases (reaction will move to the side that makes the least particles in the products)
Changing pressure by adding inert gas has no effect on Kc (all gases will always have the same partial pressures)
So, when there is a 'sharp decrease in volume', this means the there is a sharp increase in pressure (since volume and pressure are inversely proportional). As a result, the reaction will try to move to the side that produces the least amount of particles (since there is less volume).
The given equation in the question is hydrogen + iodine ---> hydrogen iodide (all gases)
AKA it is in the form:
A + B ---> C
Since the products side has fewer particles than the reactants side, the forward reaction will speed up. The suggested solutions are correct, but the explanations are wrong. You are probably better off referring to the examiners report.