Hello, could someone help me how to answer this:
10.5 grams of Ba(NO3)2 will dissolve into 100 grams of water to make a saturated solution at 25 Cº. Calculate the Ksp of Ba(NO3)2 at 25Cº.
The answer to this question is 2.59 x 10^-1
Hey there!
The equation for this reaction is Ba(NO
3)
2(s) ⇌ Ba
2+(aq) + 2NO
3-(aq). This indicates that K
sp = [Ba
2+][NO
3-]
2, and since these concentrations are equal at equilibrium, K
sp can be expressed in terms of the solubility s by K
sp=4s
3. Now, the solubility is given by c = n/V, or m / (MM*V), which is just 10.5/(261.337*0.1). Sub this into the above expression and you should get the K
sp value for barium nitrate.
Hope this helps
