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April 18, 2024, 11:37:41 pm

Author Topic: VCE Chemistry Question Thread  (Read 2322751 times)  Share 

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Scooby

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Re: VCE Chemistry Question Thread
« Reply #465 on: March 10, 2014, 12:56:11 pm »
+1
Thanks for clarifying that Scooby. :)

No problem :)


Help pls :)
1-propylamine may be produced by a reaction between 1-chloropropane and one other molecular compound. When 2.17g of 1-chloropropane is completely converted to 1-propylamine, what mass of the other compound would be expected to react?

To produce propan-1-amine from 1-chloropropane we need to react it with ammonia. Use the mass of 1-chloropropane given and its molar mass to find the number of moles of it that reacted. From that determine the number of moles of ammonia that reacted. Since you have the number of moles of ammonia reacted and its molar mass, you can work out the mass that reacted as well
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Blondie21

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Re: VCE Chemistry Question Thread
« Reply #466 on: March 10, 2014, 03:27:22 pm »
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is 0.025mg/L of Ca2+ equal to 6.25x10-7mol L
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Yacoubb

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Re: VCE Chemistry Question Thread
« Reply #467 on: March 10, 2014, 03:45:45 pm »
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is 0.025mg/L of Ca2+ equal to 6.25x10-7mol L

Yes.

0.025 mg/L (or ppm) / 1000 = 0.000025 g/L
0.000025 g/L divided by 40.1 (Mr of Ca) = 6.25 x 10-7 mol/L or M.

Blondie21

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Re: VCE Chemistry Question Thread
« Reply #468 on: March 10, 2014, 03:52:33 pm »
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Yes.

0.025 mg/L (or ppm) / 1000 = 0.000025 g/L
0.000025 g/L divided by 40.1 (Mr of Ca) = 6.25 x 10-7 mol/L or M.

Wooo!! Thanks
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Rishi97

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Re: VCE Chemistry Question Thread
« Reply #469 on: March 11, 2014, 07:39:47 pm »
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Can anyone name and similarities or differences between IR spec, AAS and UV-visible spectroscopy?
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bonappler

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Re: VCE Chemistry Question Thread
« Reply #470 on: March 11, 2014, 10:12:49 pm »
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Yeah I need help with this
Grains of fine California beach sand are approximately spheres with an average radius of 50 μm and are made of silicon dioxide, which has a density of 2.8 × 103 kg/m3. What mass of sand grains would have a total surface area (the total area of all the individual spheres) equal to the surface area of a cube 0.9 m on an edge?


Aurelian

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Re: VCE Chemistry Question Thread
« Reply #471 on: March 12, 2014, 06:32:03 pm »
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Yeah I need help with this
Grains of fine California beach sand are approximately spheres with an average radius of 50 μm and are made of silicon dioxide, which has a density of 2.8 × 103 kg/m3. What mass of sand grains would have a total surface area (the total area of all the individual spheres) equal to the surface area of a cube 0.9 m on an edge?

Lol what a bizarre question. Okay so, firstly think about what the surface area of that cube is going to be. Then think about what the surface area of an individual grain of sand is going to be. Then figure out how many grains of sand you're going to need.

Then think about what the mass of an individual grain of sand is going to be (hint: use the density). Then, the mass of sand you'll need will just be the number of grains required multiplied by the mass of each grain...!

Does that help? =)
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bonappler

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Re: VCE Chemistry Question Thread
« Reply #472 on: March 13, 2014, 11:41:48 am »
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Actually, I got an answer but I'm not sure if it is correct

Rishi97

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Re: VCE Chemistry Question Thread
« Reply #473 on: March 13, 2014, 07:01:29 pm »
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Has anyone had a chemistry sac on spectroscopy?
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soNasty

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Re: VCE Chemistry Question Thread
« Reply #474 on: March 15, 2014, 11:21:06 am »
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this may sound stupid but whats the difference between Mol/L and Molarity (concentration)

just say you had a substance and it was 6.5mol/L and you wanted to find the mass...
would you go m(substance)=6.5 x (molar mass of substance)   ?


RKTR

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Re: VCE Chemistry Question Thread
« Reply #475 on: March 15, 2014, 12:03:07 pm »
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For your first question,those two are the same.

Concentration(g/L)=molarity (mol/L) x molar mass (g/mol)

Then you need the volume to find the mass

Sometimes if you can't remember the formula, try using the units to help you
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soNasty

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Re: VCE Chemistry Question Thread
« Reply #476 on: March 15, 2014, 12:31:01 pm »
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Can someone give me the half equation of the oxidation of ethanol to ethanal?
Or, if that's not possible, the full equation of ethanol being oxidised to ethanal using an excess of potassium dichromate, please.

lzxnl

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Re: VCE Chemistry Question Thread
« Reply #477 on: March 15, 2014, 02:00:44 pm »
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Can someone give me the half equation of the oxidation of ethanol to ethanal?
Or, if that's not possible, the full equation of ethanol being oxidised to ethanal using an excess of potassium dichromate, please.

Ethanol is C2H5OH
Ethanal is C2H4O

So really it's just C2H5OH => C2H4O + 2H+ + 2e-
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Snorlax

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Re: VCE Chemistry Question Thread
« Reply #478 on: March 15, 2014, 04:25:13 pm »
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Why is a fine layer of powder (Alumina) spread on a glass/plastic plate in Thin-Layer Chromatography?
Is it to increase surface area for components to be adsorbed into the stationary phase more effectively?

Also in chromatography, when it says you need an appropriate solvent/mobile phase what does that mean? - So, say my sample is a polar compound, would I want a polar solvent, or what? (polar-attracts-polar rule?)

Also! Does the degree of adsorption to the stationary phase depend on the: chemical structure of the stationary phase? or is it the chemical structure of the component?

Thanks,
« Last Edit: March 15, 2014, 10:14:52 pm by Snorlax »
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Rishi97

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Re: VCE Chemistry Question Thread
« Reply #479 on: March 15, 2014, 08:06:04 pm »
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In chromatography, are the Rf values and the Rt value, inversely proportional?  ???
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