trial exams??

[joechan521]

which one do you reckon is the most challenging?
?
?

[avogarbro]

kilbaha

[joechan521]

i found itutes questions are non-relevant

[BenBenMan]

TSSM is testing but okay except for this one question:

Question 8
Use the change of variable u=sin(3x) to evaluate the integral of dx / cos(3x). Express your answer in the form a ln f(x) + C

This isn't supposed to be an easy question is it? It's still got me screwed

[Markos]

I tried the iTute exams and many of the questions I'd never covered before. Even my teacher had trouble with it

[Ahmad]

TSSM is testing but okay except for this one question:

Question 8
Use the change of variable u=sin(3x) to evaluate the integral of dx / cos(3x). Express your answer in the form a ln f(x) + C

This isn't supposed to be an easy question is it? It's still got me screwed

Although I could quote that integral from memory (I don't encourage memorising..), you can solve it by noticing that you can transform it into an integral in the form 1/(1 - u^2) which can be solved by partial fractions.

[bilgia]

tsfx ones are long and tough at the same time...not much room for mistakes..
they tend to drag out questions way too far and end up screwing over people who haventt made it past part c)

[bilgia]

TSSM is testing but okay except for this one question:

Question 8
Use the change of variable u=sin(3x) to evaluate the integral of dx / cos(3x). Express your answer in the form a ln f(x) + C

This isn't supposed to be an easy question is it? It's still got me screwed

Although I could quote that integral from memory (I don't encourage memorising..), you can solve it by noticing that you can transform it into an integral in the form 1/(1 - u^2) which can be solved by partial fractions.

that is interesting...but yeah i arrived at that stage as well and wondered wat the....

[joechan521]

TSSM is testing but okay except for this one question:

Question 8
Use the change of variable u=sin(3x) to evaluate the integral of dx / cos(3x). Express your answer in the form a ln f(x) + C

This isn't supposed to be an easy question is it? It's still got me screwed

Although I could quote that integral from memory (I don't encourage memorising..), you can solve it by noticing that you can transform it into an integral in the form 1/(1 - u^2) which can be solved by partial fractions.

 1 / cos(3x) need to be changed to cos(3x)/cos^2(3x)

and get to
the form 3/(1 - u^2)  

then  u can solve it easily.

[Ahmad]

Yep. That was my suggestion.

[joechan521]

those are fun anti-s to try:

1/(1+x^3)



1/sqrt(1+x^2)

[Ahmad]

First is partial fractions.

Second is inverse sinh i.e. log[sqrt[1+x^2]+x] if i recall correctly

I have a pretty fun one in the univ maths section, be sure to check out

[joechan521]

First is partial fractions.

Second is inverse sinh i.e. log[sqrt[1+x^2]+x] if i recall correctly

I have a pretty fun one in the univ maths section, be sure to check out

i dont think 2nd is inverse sin? how come i got differently

[Ahmad]

You misinterpreted me. I wrote inverse sinh. That's inverse hyperbolic sine

[joechan521]

You misinterpreted me. I wrote inverse sinh. That's inverse hyperbolic sine

right.... no idea what it is lol... i dont expect thats specialist knowledge?