ATAR Notes: Forum

VCE Stuff => VCE Science => VCE Mathematics/Science/Technology => VCE Subjects + Help => VCE Physics => Topic started by: Matt89 on November 12, 2007, 08:11:13 pm

Title: Synchrotron question
Post by: Matt89 on November 12, 2007, 08:11:13 pm

Could someone help me with Question 6 in Synchrotron on the 2006 Exam?

(The exam can be found here: http://www.vcaa.vic.edu.au/vce/studies/physics/pastexams/2006/2006physics2-w.pdf)

According to itute, the solution is found using this formula:

Wavelength Shift ∆λ = (1 - cosϴ)h/mc[/b]

I've NEVER seen this formula before. Could someone give me a brief explanation of it and where you would use it PLEASE

Title: Synchrotron question
Post by: Daniel15 on November 12, 2007, 08:21:18 pm

Me neither, I don't think I've ever seen that formula before O.o

Title: Synchrotron question
Post by: Ninox on November 13, 2007, 05:20:56 pm

Quote from: "Daniel15"

Me neither, I don't think I've ever seen that formula before O.o

I haven't seen it either. Neither me nor my teachers could get it using, so we let it be an open question to the class. The most logical explanation we could find was simply: more deflection, more energy lost and longer subsequent wavelength. We've already got 0 and 90deg, so 135deg is the answer.

Title: Synchrotron question
Post by: Galelleo on November 13, 2007, 05:23:54 pm

Daniel, lol, you probably arent doing detailed study - synchotron and applications.

Im doing sound, so i cant help you, sorry  matt

Title: Synchrotron question
Post by: Daniel15 on November 13, 2007, 05:49:55 pm

Quote from: "Galelleo"

Daniel, lol, you probably arent doing detailed study - synchotron and applications.

Im doing sound, so i cant help you, sorry  matt

Nope, that's the detailed study I am doing, which was why I was concerned with not seeing that formula.

Title: Synchrotron question
Post by: Galelleo on November 13, 2007, 06:03:31 pm

dw i just had a similar experience on diffraction