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April 24, 2024, 12:08:26 pm
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Author Topic: Mathematics - a new basis  (Read 33328 times)  Share 

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Jenny_2108

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Re: Mathematics - a new basis
« Reply #105 on: March 11, 2013, 04:18:42 am »
+6
Quote from: ms.srki on February 12, 2013, 10:56:08 pm
TEST
(2.8 )
a)3/.5/4/.23/4s.=?
b)44/.45/21/.3/33/.4/1s.=?
c)?={2/.34/2 , ? }
(2.10)
a)3/.4/12s.+ [.5] 6/.5/2s.=?
b)32s.+ [.20] 2/.20/1=?
c)3/.12/2/.4/2s. +[15]2/.8/3s.=?
(2.12)
a)3/.5/2s. - [.3] 4/.1/5s.=?
b)8/.8/8s. -[10] 4/.75s.=?
c)4/.40/20s.-[.30] 7/.1/1/.1/4=?
(2.13)
a) 5/.5/5s. [.4] 3/.3/3/.3/3s.=?
b)4/.4/4[5]6/.6/6=?
c)10 [.6]15=?

I know its not mathematically correct, I just attempt based on what I read your posts and your formula (I dunno where you get those evidence without proving though)

(2.8 )
a) 3/.5/4/.23/4s = {3/.5/4/.23/4, 0/.3/5/.4/23/.4/0}
b) 44/.45/21/.3/33/.4/1s = {44/.45/21/.3/33/.4/1, 0/.44/45/.21/3/.33/4/.1/0}
c) ?={2/.34/2 , ? }
2/.34/2s = {2/.34/2, 0/.2/34/.2/0}

(2.10)
a) 3/.4/12s.+ [.5] 6/.5/2s
= 0/.3/4/.12/0 + [.5] 0/.6/5/.2/0 (from 2.8 )
= 0+[.0]4+[.0]0+[.5] (0+[.0]5+[.0]0) (from 2.11)
= 4+[.5]5
= 4+[0]5=5

b) 32s.+ [.20] 2/.20/1
= 0/.32/0+[.20]2/.20/1 (from 2.8 )
= 0+[.0]0+[.20] (2+[.0]1) (from 2.11)
= 0+[.20]3
= 0+[-17]3=-14

c) 3/.12/2/.4/2s. +[15]2/.8/3s
= 0/.3/12/.2/4/.2/0+[15]0/.2/8/.3/0 (from 2.8 )
= 16+[15]8=23

(2.12)
a) 3/.5/2s. - [.3] 4/.1/5s
= 0/.3/5/.2/0-[.3]0/.4/1/.5/0 (from 2.8 )
= 5-[.3]1=-2

b) 8/.8/8s-[10]4/.75s
= 0/.8/8/.8/0-[10]0/.4/75/0 (from 2.8 )
= 8-[10]75=10

c) 4/.40/20s-[.30]7/.1/1/.1/4
= 0/.4/40/.20/0-[.30]0/.7/1/.1/1/.4/0 (from 2.8 )
= 40-[.30]2=-28

(2.13)
a) 5/.5/5s. [.4] 3/.3/3/.3/3s
= 0/.5/5/.5/0 [.4] 0/.3/3/.3/3/.3/0
= 5 [.4]6=4

b) 4/.4/4[5]6/.6/6
= 0/.4/4/.4/0 [5]0/.6/6/.6/0
= 4 [5]6
= 4 [.1]6=1

c) 10 [.6]15=6
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ms.srki

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Re: Mathematics - a new basis
« Reply #106 on: March 12, 2013, 01:47:16 am »
0
Quote from: Jenny_2108 on March 11, 2013, 04:18:42 am
(2.8 )
a) 3/.5/4/.23/4s = {3/.5/4/.23/4, 0/.3/5/.4/23/.4/0}
b) 44/.45/21/.3/33/.4/1s = {44/.45/21/.3/33/.4/1, 0/.44/45/.21/3/.33/4/.1/0}
c) ?={2/.34/2 , ? }
2/.34/2s = {2/.34/2, 0/.2/34/.2/0}
This is true, (s) need (s.)
----
2(10)
3/.4/12s.+ [.5] 6/.5/2s.
first  solution 3/.4/12+[.5]6/.5/2=3/.4/13/.5/2
second solution 3/.4/12+[.5]0/.6/5/.2/0=3/.4/12/.1/5
third solution 0/.3/4/.12/0+[.5]6/.5/2=4/.7/6/.5/2
fourth solution 0/.3/4/.12/0+[.5]0/.6/5/.2/0=4/.13/5
3/.4/12s.+ [.5] 6/.5/2s.={3/.4/13/.5/2 , 3/.4/12/.1/5 , 4/.7/6/.5/2 , 4/.13/5}
see (k1-k8) if you follow the procedure you will get solutions
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ms.srki

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Re: Mathematics - a new basis
« Reply #107 on: March 13, 2013, 11:48:40 pm »
0
k9-gap addition - 0 u a or u b there does not exist in the current mathematics
2/.4/2 [1]3/.3/2=0/.5/0
9p.png
9pp.png
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ms.srki

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Re: Mathematics - a new basis
« Reply #108 on: March 17, 2013, 01:21:01 am »
0
k10-gap subtraction - 0 there exists u a (b-no) or u b (a-no), does not exist in the current mathematics
2/.4/2 [1]3/.3/2=0/.2/2/.1/0
9oo.png
« Last Edit: March 17, 2013, 01:23:09 am by ms.srki »
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ms.srki

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Re: Mathematics - a new basis
« Reply #109 on: March 20, 2013, 04:00:41 am »
0
k11-gap opposite subtraction - 0 exists in a and b does not exist in the current mathematics
2/.4/2 [1]3/.3/2=0/.2/0
8o.png
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enwiabe

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Re: Mathematics - a new basis
« Reply #110 on: March 24, 2013, 07:06:50 pm »
+6
Quote from: ms.srki on March 20, 2013, 04:00:41 am
k11-gap opposite subtraction - 0 exists in a and b does not exist in the current mathematics
2/.4/2 [1]3/.3/2=0/.2/0
8o.png

This is building up to a hilarious apex on April 1st, isn't it?
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ms.srki

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Re: Mathematics - a new basis
« Reply #111 on: April 09, 2013, 03:53:45 am »
0
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ShortBlackChick

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Re: Mathematics - a new basis
« Reply #112 on: April 09, 2013, 02:35:27 pm »
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I didnt click on the link, but isnt a 'new base/is' what you've been trying to show in the last 8 pages of this thread, and as specified in the title?

You are incredibly determined. Or demented?
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ms.srki

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Re: Mathematics - a new basis
« Reply #113 on: October 28, 2013, 05:17:19 am »
+1
Here I am again,
I'll give you an example that challenges sets of numbers (rational, irrational, real)
question is whether a real number can be written as a fraction (rational number)

,


See you again!!
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excal

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Re: Mathematics - a new basis
« Reply #114 on: October 28, 2013, 10:00:27 am »
+6
This is still going on???
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alondouek

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Re: Mathematics - a new basis
« Reply #115 on: October 28, 2013, 11:00:44 am »
+8
Are you telling me that ? And that ?

Mind. Blown.
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BubbleWrapMan

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Re: Mathematics - a new basis
« Reply #116 on: October 28, 2013, 02:43:19 pm »
0
I think they're saying all reals are rational because you can write them as fractions - which works, provided you ignore the standard definition of "rational number".
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alondouek

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Re: Mathematics - a new basis
« Reply #117 on: October 28, 2013, 03:14:34 pm »
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Quote from: http://en.wikipedia.org/wiki/Rational_number
In mathematics, a rational number is any number that can be expressed as the quotient or fraction of two integers, with the denominator not equal to zero. Since may be equal to 1, every integer is a rational number.

At least this "new basis" makes more sense than the last one lol
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TheAspiringDoc

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Re: Mathematics - a new basis
« Reply #118 on: April 30, 2015, 05:37:03 pm »
-1
Please tell me the AN's brightest didn't just turn down that Japanese guy who wrote 512 pages of online papers trying to prove the ABC Conjecture?

Moderator action: Can we not bump threads with nothing to add? /locked
« Last Edit: June 13, 2015, 11:15:17 am by pi »
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