2007 u3 projectile question

[jaydee]

can someone please explain question 14? i resolve the projectile horizontally and get 3.50s (correct answer) but I also resolved it vertically and got an answer of 3.38 seconds. someone please clarify

[Phy124]

The Exam writers made a mistake and either the angle of release should be less or the horizontal distance travelled should be greater.

The Assessment report said that both answers were accepted for the questions following.

edit: This coincides with what the Australian Institute of Physics (Vic Branch) has said;

Note 1: The use of 9.8 m/s2 gives the same answer to two significant figures. 
Note 2: The data in the question is inconsistent.  The time of flight can also be determined from the range;

Ref: http://www.vicphysics.org/documents/teachers/VCEJune2007Solutions.doc (thanks to laseredd)

[jaydee]

thanks! thought something didnt feel right! no mention of 2 answers on the official assessor's report though...

[Phy124]

No worries and I was referring to;

Applying one of the constant acceleration formulae to the vertical motion gave a height of 14.3 m. 
The answer here varied depending on the particular approach used and whether the student used 9.8 or 10 for the
gravitational field strength.

Ref: http://www.vcaa.vic.edu.au/vce/studies/physics/assessreports/2007/physics1_assessrep_07.pdf, page 3