Year 10 maths mhs

[plsbegentle]

Hey, was just wondering if the mhs math test would include these type of questions ( pls answer them if possible:
The digits 5, 6, 7, 8 and 9 can be arranged to form even five-digit numbers. The
tens digit in the largest of these numbers is

Four consecutive odd numbers add up to 48. What is the largest of these numbers?

In the diagram, triangles PQR and LMN are
both equilateral and QSM = 20◦. What is the
value of x?

How many different positive numbers are equal to the product of two odd one-digit
numbers?

[SMOKIE]

Ahhh, in the year 9 one. Heaps of these questions! They are pretty easy if you've done them a few times and know the correct formulas. Ill do a few and let others do some aswell.

Question 2
I would just work it as 4x+12=48 48-12/4=9( im amusing this is the smallest number) 9,11,13,15. A=15

Question 4
Bro, you dont even have the numbers there Imao. But take example 1,3,5,7,9
1x(1,3,5,7,9)=1,3,5,7,9, so 5 possible numbers: 1,3,5,7,9
3x(1,3,5,7,9)=3,9,15,21,27, but 3 and 9 are duplicates, so there are 3 additional numbers:15,21,27
5x(1,3,5,7,9)=5,15,25,35,45, but 5 and 15 are duplicates, so there are 3 additional numbers: 25,35,45
7x(1,3,5,7,9)=7,21,35,49,63, but 7, 21, and 35 are duplicates, so there are 2 additional numbers: 49,63
9x(1,3,5,7,9)=9,27,45,63,81, but 9, 27, 45, and 63 are duplicates, so there is 1 additional number: 81

So there are (5+3+3+2+1)=14 different possible numbers.

[plsbegentle]

is there any fast methods or forumlas in solving these. And if possible can someone post more of these questiosns so i can try asnwering them

[SMOKIE]

These questions are all about practice. What i did in the exam was just make good educated guess if they were 2 difficult and move on to more easier ones. And thb these arent even that hard, might worth knowing some basic year 9 algebra questions.
Ill try to dig some of those questions out from the internet or on books

[keltingmeith]

For the first two:

You can arrange these 5 numbers to make one big number, and they want the biggest. Intuitively, this is when you list them biggest to smaller - 98765. But, we want the number to be even, so we change it by swapping numbers as far right as possible. This gives 98756, which is even, so we're done. The number in the tens column is 5, so the answer is 5.

You can use algebra, but I prefer this method: You want 4 numbers, so divide the number they give by 4. This gives 12. Next, we want consecutive odd numbers, so move up and down 12 until you have four odd numbers. Moving up once gives 13, then down once gives 11. Doing this again to the next odd number gives 15 and 9. 9 + 11 + 13 + 15 = 48, so the largest number is 15.

If you give me a bit, I can find worked solutions for the next two (unless someone beats me to it )

EDIT: we need the diagram for question 3, and SMOKIE's method for 4 is the best you're going to get.

[SMOKIE]

Try this website, alot of questions relating to year 9ish maths
http://www.chiuchang.org.tw/download/docu/AMC/AMC_INT_2008.pdf ( they might be easy so if they are, try the senior version.)
might worth knowing quadratic equations, surd, geometry and probability. Cover all these topics and brush up ur algebra and linear equations, you should be good to go.

EDIT:Euler, the diagram is on the website, cbs working it out.