VCE Methods Question Thread!

[darkz]

For the last part, would it have been acceptable to use limits? As in, limit of A(k) as k --> 1 from the negative/left direction is equal to 2 and the limit of A(k) as k --> 0 from the positive direction is equal to 0 ... If it is, do you have to actually evaluate the limit by hand or is it sufficient to say lim k --> +infinit --- is that calc syntax btw?

Limits would've been fine

[Uhhhh1204]

Hey guys, so on yesterday's exam 2 when it asked for the gradient at point A I accidentally subbed 'a' into f(x) instead of f(x) + 3 and hence I got an incorrect gradient. Although for part ii), I used the correct method and got the correct answer BASED on my original gradient. I know I'd lose 1 mark for the initial part but would I get 2/3 marks for part ii)? Also, just wondering if you needed to include something like '+ 12k', k ∈ Z when it asked for the 'c' value in the transformation matrix? I just did c = 6...

Thanks in advance

[Amnilauv]

Could anyone predict study score please?
Rank four in moderate cohort

SACS: 55%
Exam One: 45%
Exam two: 25%

Maybe around 25?
A bit of an unreliable comparison but I know someone who got all D+ for the graded assessments (and also failed a SAC) and got a 26.

[pat0029]

does anyone have hard tests from selective schools,

thanks

[Ionic Doc]

Hey everyone
This is a simple question but I'm sorta stumped so
Could someone please explain to me how the -2 changed to a -4.
Thanks

[Tau]

Hey everyone
This is a simple question but I'm sorta stumped so
Could someone please explain to me how the -2 changed to a -4.
Thanks

The two on the inside of the squared bracket can be evaluated by squaring it so 2^2=4 and this now comes out of the bracket. The sign outside the bracket status the same, hence you get -4 outside.

[lastapasta]

hi,
i just had a question in my textbook i wasn't really sure how to do so it would be great if someone could help me out on how to approach this problem.

8e^-x - e^x = 2
Solve for x.

thanks!

[Tau]

hi,
i just had a question in my textbook i wasn't really sure how to do so it would be great if someone could help me out on how to approach this problem.

8e^-x - e^x = 2
Solve for x.

thanks!

The trick with these questions is to multiply both sides by \(e^x\), then you get a quadratic in terms of \(e^x\) and you can apply the quadratic formula. Make sure to reject solutions if they don't make sense with respect to the original equation

[lastapasta]

The trick with these questions is to multiply both sides by \(e^x\), then you get a quadratic in terms of \(e^x\) and you can apply the quadratic formula. Make sure to reject solutions if they don't make sense with respect to the original equation

thank you so much! so whenever i get a problem with e^-x in it should i just multiply the whole thing by e^x?

Also, I just had a couple of other questions:

1. Find a transformation that takes the graph of y=3^x to the graph of y=e^x
2. Find a transformation that takes the graph of y=e^x to the graph of y=2^x

again, thank you so much

[sk2000]

thank you so much! so whenever i get a problem with e^-x in it should i just multiply the whole thing by e^x?

Also, I just had a couple of other questions:

1. Find a transformation that takes the graph of y=3^x to the graph of y=e^x
2. Find a transformation that takes the graph of y=e^x to the graph of y=2^x

again, thank you so much

In my opinion, it's much more simple and straight forward to substitute e^x with a pronumeral such as a.

[Tau]

thank you so much! so whenever i get a problem with e^-x in it should i just multiply the whole thing by e^x?

Also, I just had a couple of other questions:

1. Find a transformation that takes the graph of y=3^x to the graph of y=e^x
2. Find a transformation that takes the graph of y=e^x to the graph of y=2^x

again, thank you so much

Using properties of exponentials we can rewrite as so all exponentials of different bases can be rewritten as a dilation from the y-axis of the natural exponential. You should be able to apply this to the second question.

[lastapasta]

In my opinion, it's much more simple and straight forward to substitute e^x with a pronumeral such as a.

thank you, that makes a lot of sense!

[lastapasta]

Using properties of exponentials we can rewrite as so all exponentials of different bases can be rewritten as a dilation from the y-axis of the natural exponential. You should be able to apply this to the second question.

which property of an exponential is that? also, how did you get from y=3^x to the second line? i am still a little bit confused on what exactly to do there

[MB_]

which property of an exponential is that? also, how did you get from y=3^x to the second line? i am still a little bit confused on what exactly to do there

The property is \( e^{\ln(x)}=x\)

[colline]

which property of an exponential is that? also, how did you get from y=3^x to the second line? i am still a little bit confused on what exactly to do there