PLZZ help Asap Arg(z-1+i)=alpha

[nick7862]

how do i get Arg(z-1+i)=alpha into cartesian form, plzz help asap

[exit]

Is this your school SAC or do you not have answers?

[de]

I believe this is the correct thinking; the argument of a non-zero complex number z, sometimes called angle of z or the phase of z is;

z = x + iy = r(cos θ + isin θ)

By that logic, Arg(z-1+i)=α Is saying that the angle of z is (z-1+i)= α ; Meaning that z-1+i=0 Furthermore z=1-i

So 1-i is the cartesian form.

I'm sorry, but this is wrong.
The correct way is to put z in cartesian form, say
then
If we picture a graph then the angle of this complex number from the real axis is given by (using tan to be equal to opposite over adjacent). Then taking the tangent of both sides we get isolating y, since a cartesian form is wanted we have