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August 02, 2021, 12:00:12 pm

Author Topic: Maths Graphs  (Read 363 times)  Share 

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biology1234

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Maths Graphs
« on: June 15, 2021, 10:56:07 pm »
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Use a graph to show the solution to the following pair of simultaneous inequalities.
y > 3x-3
3y +5x =15 < or equal to 0

Could someone attach the final solution graph, to guide me. Thanks

fun_jirachi

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Re: Maths Graphs
« Reply #1 on: June 15, 2021, 11:27:11 pm »
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Attaching the graph with the solution is a little redundant if you actually want to learn. Here are a few hints you can use to construct your own graph instead:

- Instead of graphing the inequality, graph the equality first. For example, if you had \(y > 3x-3\), graph \(y = 3x-3\).
- Test some points on either side of the curve. For example, we could test the point \((0, 3)\). Here, we can clearly see that \(y\) is indeed greater than \(3x-3\). This means that the side of the curve that contains \((0, 3)\) is the side where the inequality holds true. Shade this area in. Conversely, a point such as \((0, -4)\) would not work - implying that the inequality does not hold true for that side of the curve.

Repeat for the other curve; the intersection of the two shaded areas is the final shaded area that should be left. Note that for strict inequalities the convention is that the curve is marked by a dotted line (to show exclusion), while for non-strict inequalities, the convention is that the curve is marked by a solid line (to show inclusion).
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