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April 19, 2024, 05:23:49 am

Author Topic: VCAA 2009 exam 2, q5  (Read 721 times)  Share 

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02315

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VCAA 2009 exam 2, q5
« on: November 03, 2010, 05:58:56 pm »
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i understand which direction the current is but i dont understand where to point the magnetic field while doing the right hand rule, can someone please kindly explain? :)

Whatlol

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Re: VCAA 2009 exam 2, q5
« Reply #1 on: November 03, 2010, 10:42:11 pm »
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Ok when you have two magnets such as in that diagram, the field always goes from NORTH to SOUTH so position your fingers to the left, with your thumb forward. hope that helps
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02315

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Re: VCAA 2009 exam 2, q5
« Reply #2 on: November 04, 2010, 08:34:39 pm »
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would you be able to also explain question 14 and 15 for the electric power section?

Whatlol

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Re: VCAA 2009 exam 2, q5
« Reply #3 on: November 04, 2010, 08:39:24 pm »
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would you be able to also explain question 14 and 15 for the electric power section?

ill do it tommorow after methods
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3Xamz

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Re: VCAA 2009 exam 2, q5
« Reply #4 on: November 06, 2010, 03:43:08 pm »
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would you be able to also explain question 14 and 15 for the electric power section?

14)
=> Power Lost = (Current^2)*Resistance
=> P=VI, therefore I=P/V
=> I=10,000watts/5000volts
=> I=2A
=> Ploss = [(2amps)^2)]*10ohms
=> Ploss = 4*10 = 40 Watts.

15)
=> P=VI
=> 9960Watts = Voltage * 20A
=> V = 9960/20 = 498V
NOTE: P = 9960W; as we have P(available) = P(generated) - P(loss) = 10,000W - 40W = 9960Watts.