absolute legend lad, nice to see someone else doing IPT
Project Management:
COASPTD
Collecting
Organizing
Analyzing
Storing and Retrieving
Processing
Transmitting and Receiving
Displaying
Waterfall Method:
Understanding The Problem
Planning
Designing
Implementing
Testing, Evaluating and Maintenance
Information Systems and Databases:
Freedom of Information Act (Commonwealth and NSW) not sure on the copy right one
A distributed database can offer increased speeds when accessing data, due to the the databases being spread out (cant really explain this right its just congestion and distance when accessing data). It also offers increased reliability in the event of error the database may still be accessible as opposed to the centralized database.
175 x 64 = 11200 Bytes, 11200 Bytes divided by 1024 into Kilobytes = 10.9375 KB ( im probably wrong)
Asymmetric and Symmetric
Metadata? This questions pre hard
Data Warehouses can be used for electronic storage of information which can be accessed later in the future
Communication Systems:
Application Level. Communication Control and Addressing Level, Transmission Level
A protocol is a set of rule that governs the transfer of data?
Handshaking is establishing a communication link and determining or agreeing on which protocol to use when transferring data.
Simple Mail Transfer Protocol
No clue on the bandwith one
Can Someone Please supply me a link or tell me about the roles of Administrators such as database Admins, System Admin and all the others. I know that one of those roles involve assigning users to printers or something[/size]
Can Someone Please supply me a link or tell me about the roles of Administrators such as database Admins, System Admin and all the others. I know that one of those roles involve assigning users to printers or something[/size]
Describe the functionality provided by a network interface card.
I'll post up the answer tomorrow if no one answers :)
Hey there!
The syllabus only requires us to know the tasks of a network administrator & are listed there...don't think you need to go into it in detail, judging from the past 10 years of the HSC papers (they have only ever asked about the network admin's tasks in multiple choice or just relating their tasks to the given scenario (found in HSC 2008 paper question 22b)).
This website could be useful to you if you just want to know extra information: https://www.google.com/support/enterprise/static/postini/docs/admin/en/admin_ee_cu/auth_admins.html
Hope this helped!
Its a phiscal component in a computer or device allowing the user to access the internet which is connected through a protocol like agreement between the card and the router. Basically uses handshaking.
Was I correct or way off? I never check my answers as I like learning, not looking at answers and forgetting
You're right! Just make sure you also mention that it allows computers to connect to a network and can be installed as an expansion card if it's not a part of the computer. :)
You're right! Just make sure you also mention that it allows computers to connect to a network and can be installed as an expansion card if it's not a part of the computer. :)By the way do you know how to work out binary code? I am lost and I also looked at Freddie Woo's explanation but I still cant get it
oh god, im such a nugget. i replied to the thread and never came back to check on it....
anyways arent network interface cards mainly installed on motherboards now? (not even on topic just a random thought)
*Physcial
Thanks so much!! I had no idea.
Question:With out looking at answers, answer a) and c) as b) is easy.
(http://i64.tinypic.com/11bu58w.png)
By the way do you know how to work out binary code? I am lost and I also looked at Freddie Woo's explanation but I still cant get it
Question:With out looking at answers, answer a) and c) as b) is easy.
(http://i64.tinypic.com/11bu58w.png)
Btw where is this question from? And do you have answers?
Binary code? Do you mean you don't understand how to turn a decimal to a binary?
No worries! Glad it helped! :)
Also, the answers to your questions:
a) Cyclic redundancy check (CRC) is a method used to detect errors in transmission – a method 99.99% more effective than check sum. Hence, in this information system, it could be used when the details of the customer when they are applying for a loyalty card are transmitted to the department store.
Note: I don’t think I wrote an adequate amount…and if I did this correctly….
c) In this information system:
- Internet would be used to access the online department store for shopping and applying for a loyalty card. It would also be used when the customers receive advertising emails from the business partners of the online department store.
- Intranet would be used when the store shares information with its employees.
- Extranet would be used for when the store shares information with its business partners.
Note: Not too sure about this question either…… :’(
I dont get changing the value at the end... look at every multiple choice Question, its usually the last.How to convert decimal to binary (I think that's your question?):
How to convert decimal to binary (I think that's your question?):
For example, how is 72 represented as a binary?
Answer: 1001000 (working out in the picture attached)
Hope this answered your question!
hes talking about parity bits, which are 001011 0 with the parity set to odd or even.
hes talking about parity bits, which are 001011 0 with the parity set to odd or even.
Yep :P
LoL bro, I know how to do binary ahahah and you screwed up your method.. its 0-1-2-4-8-16-32-64-128Note: the "0-1-2-4-8-16-32-64-128" method is only used for converting binary to decimal not decimal to binary. I did the method where you convert decimal to binary (i.e. 72 is converted to 1001000)
I mean a question that says like pick the wrong message. Shows different codes. Its either odd even and you have to pick which code it is
Ah, right.
Well then,
For parity checks, you choose to transmit the data with an odd parity bit or an even one.
E.g. the binary to be transmitted is 0110101 and you choose odd parity. Choosing odd parity means that the number of 1's must be odd - if it's not, then you make it odd by making the parity bit 1. However, if it is, then the parity bit would be 0 in order to leave the number of 1's odd.
In this case, the number of 1's in the binary are 4. We have chosen odd parity hence the parity bit has to be 1 to make the number of 1's odd. As a result, the transmitting data would read as: 0110101 1
On the other hand, if even parity was chosen, the parity bit would be zero and the data to be transmitted would read as: 0110101 0
Hope this helped!
Answer's B.
Here's why, the first bye there 3 0's and 5 1's this makes it an odd parity as the parity bit is 1 to make the 1's odd. Whilst in the 2nd and 3rd byte there are even amounts of 1's and 0's. As state before the first byte's parity is ODD, whilst the second byte and third byte have even parities. Therefor the Parity is odd and the corrupted data bytes are second and third
OMFG, I love you!!! Thank you so much... I get it now!!!! do you have a similar question that you could ask me on this binary thing and I answer it and you tell me if Im right?
Have a go at these two :)
Have a go at these two :)
Have a go at these two :)
Im guessing a) for 1, I dont know its odd and a 1, all the rest are even
Im guessing a) for 1, I dont know its odd and a 1, all the rest are even
Guys I sorta get it but not completely now... is there a slow and basic way you can explain to me because I know every other element of IPT except for this and its pis*ing me off
Guys I sorta get it but not completely now... is there a slow and basic way you can explain to me because I know every other element of IPT except for this and its pis*ing me off
- The message I want to send is: 01001101
- Which parity do I want? Odd or even?
- I choose even.
- I count the number of ones in my message.
- There are 4 number of ones - therefore, it is even.
- To make it stay even, the parity bit that I add is 0.
- Just to check, I count the number of ones again in my modified message: 01001101 0. There are still 4 number of ones.
- If the receiver gets this message: 01001101 0 or 01111010 1, it says it is correct.
- This is because the receiver and the sender agreed upon even parity. The receiver counted the number of ones and they were even. Hence, it accepted this message and did not detect an error.
- If however the receiver gets this message: 01101101 0, it would request a resend as the number of ones are odd (there are 5 number of ones in that message). This is because the receiver and the sender had agreed upon even parity and not odd.
If you still don't get it, say exactly which step makes you confused and I can expand on it
Hope this helped!
It makes sense now.. i didnt know you choose even or add.. i was like where the fu*k are they getting this from ahaha -_-
Is the first one d) what i did was select odd and there are 3 1's if i add a zero there are still 3 1's
1st one is C right?
Do you want to test yourself?
Try these questions
You're getting there....think about it and read the question properly - it's asking you which one of the options will require you to resend the message? ie, which one of the options are wrong?
For option d), the message looks exactly the same as the transmitted one - hence, we would not request for a resend.
Think about which parity is chosen for the message to be sent correctly. Odd or Even? Then, for the message to be wrong, look for the option that uses opposite parity to the correct one.
I'm pretty sure you'll get there - try again :)
How long should each question take, can you guys do it instantly!
Do you guys have any videos I can watch on this... We had to self teach our selfs this
Yeah it did aha ill try the questions now
First one is c right because it was odd transmission and that is the only even oneYup!
I'll be posting up the answers to the questions tomorrow :)
Would you mind posting them tonight and some more questions of any type!
So with first attachment you rule out c) and d) because they are not commercial and are not businesses. A) is ruled out because an atm does not look at sale data, it is simply used for getting money out. Therefore b)
Let me think about second one
Third one is b) because all the other answers have a surname as a primary key, when primary keys can only be like an id number. For example s7170 or just 011837 cant be words like ford, opal.. cant be any type of word
Is the last one b) or a)?
Second one is c) am i right?
Seller needs to post ad and login to idiskok. Shopper searches for a tag in the product description which comes back as details then the shopper wants to buy so add to cart
Anymore man😅
D) the where is agent no. Only meaning no name required. The 342 is probs an ID
C) for last one because i cant see optic fibre running for 260kms
Moderator edit: Merged double post. Again, stop double posting.
You're right for the first one but it's B for the second one. Because the distance is so big, optic fibre is needed so that there is faster transmission at segment 3. The last segment is more likely to be a twisted-pair cable than a coaxial cable because it's mainly used for audio and visual purposes (very short distances) e.g. connecting your VCR to your TV. You can read more about it at https://www.techwalla.com/articles/what-is-a-coaxial-cable-used-for
What paper is the second one?