A few questions once again!
- Balanced equation for the conversion of CH3CHO to CH3COOH in the presence of NAD+
- The type of reaction of this would be?
- How does the omission of coenzymes and cofactors effect on the enzyme's activity?
Thanks!
Ok first one.
CH3CHO to CH3COOH? NAD+ just goes to NADH, so the half reaction is NAD+ + H+ + 2e- => NADH for the reduction
As for the oxidation, CH3CHO => CH3COOH Balance oxygens by adding water
CH3CHO + H2O => CH3COOH Balance hydrogens
CH3CHO + H2O => CH3COOH + 2H+ + 2e- See how I added electrons to balance the charge?
Put the two equations together to give NAD+ + CH3CHO => CH3COOH + H+ + H2O
This is a redox reaction
Omitting coenzymes and cofactors means the enzyme can't work. They're a crucial part of the enzyme's function. For example, the zinc cation in carbonic anhydrase is what facilitates the entire catalysis of H2CO3 formation.
Thanks so much! SO much clearer now. :
However how does the accumulation affect the production of CO2?
I'm taking a wild guess that it increases it?
What happens is that by consuming ethanol and requiring the use of the oxidant NAD+, your body has less NAD+. Remember how the Krebs/citric acid cycle requires 3 lots of NAD+ and 1 lot of FAD per molecule of acetyl CoA? If you run low on NAD+, the Krebs cycle can't run as fast and less CO2 is produced.