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March 28, 2024, 10:32:08 pm

Author Topic: VCE Chemistry Question Thread  (Read 2313066 times)  Share 

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lzxnl

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Re: VCE Chemistry Question Thread
« Reply #900 on: May 21, 2014, 10:21:24 pm »
+1
Probably a silly question, but just wanted to clarify something that only occured to me then...

are haloalkanes (eg chloroalkane) part of the alkane homologous series or are haloalkanes a completely separate homologous series? Going by the chemistry definition of homologous series:having the same functional group but differing in composition by a fixed group of atoms. This would suggest that chloroalkanes are a homologous series itself, and then say, bromoalkanes are another one...

They would be, yes.

Our school is only up to mass spec lol. But we did organics (aos 2) first.

Thushan how would you rate unit 4? Smaller in length? Larger? Harder? Easier? Than unit 3.

I have all my unit 4 sacs in the same term.

Much less rote learning hahahaha
And much more fun for me

Haha my school just finished unit 3. I'm up to area of study 2 now! V-textbook is AWESOME!

I really just find spare time (i.e. when I don't have SACs) to just go ahead. I'm aiming to finish the VCAA Chem course by the start of term 3, and dedicate all of term 3 to prac exams/revision of units 3 and 4 of Chem.

Finishing VCAA Chem course by start of term 3? Keen eh xP
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Yacoubb

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Re: VCE Chemistry Question Thread
« Reply #901 on: May 21, 2014, 10:30:20 pm »
+2
Finishing VCAA Chem course by start of term 3? Keen eh xP

LOL I just want to do well in Chemistry. A lot of you guys are geniuses! I need LOTs of time to reach your standards :P

swagsxcboi

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Re: VCE Chemistry Question Thread
« Reply #902 on: May 21, 2014, 10:31:39 pm »
0
when performing the bromine test to see if the hydrocarbon is saturated or unsaturated, the Bromine is aqueous...I thought the first four alkanes were gas at room temperature? Could someone explain this?
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darklight

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Re: VCE Chemistry Question Thread
« Reply #903 on: May 21, 2014, 10:35:23 pm »
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Qn 2 should be an easy question.. but I keep getting none of the options  :-[
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Yacoubb

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Re: VCE Chemistry Question Thread
« Reply #904 on: May 21, 2014, 10:39:00 pm »
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Qn 2 should be an easy question.. but I keep getting none of the options  :-[

Okay so at an absorbance of 24, the concentration is 13.7 ug/L. This, however, is not the concentration of copper ions in the original solution; this is the concentration of Cu2+ ions in the 'diluted' solution. So, we must calculate the concentration of the original solution by multiplying 13.7ug/L by the dilution factor, which is 100 (100mL/1mL), giving us 1370ug/L, which is C.

darklight

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Re: VCE Chemistry Question Thread
« Reply #905 on: May 21, 2014, 10:42:55 pm »
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Okay so at an absorbance of 24, the concentration is 13.7 ug/L. This, however, is not the concentration of copper ions in the original solution; this is the concentration of Cu2+ ions in the 'diluted' solution. So, we must calculate the concentration of the original solution by multiplying 13.7ug/L by the dilution factor, which is 100 (100mL/1mL), giving us 1370ug/L, which is C.

Thanks Yacoubb, I understand that, but that's q1 not 2 :P
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swagsxcboi

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Re: VCE Chemistry Question Thread
« Reply #906 on: May 21, 2014, 10:47:38 pm »
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Thanks Yacoubb, I understand that, but that's q1 not 2 :P

is the answer C?
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darklight

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Re: VCE Chemistry Question Thread
« Reply #907 on: May 21, 2014, 10:48:42 pm »
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is the answer C?

Yes! How did you get that?  :D
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swagsxcboi

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Re: VCE Chemistry Question Thread
« Reply #908 on: May 21, 2014, 10:50:33 pm »
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mass of Cu2+ ions = 1370ug/L
in sample, mass of Cu2+ ions = 1.37 ug
n=m/m n=1.37x10-3 / 63.5
n(Cu2+) = 0.000022
n(Cu) = n(CuCl2)

n=m x M
m(CuCl2) = 0.002902g = 2.90 ug
« Last Edit: May 21, 2014, 11:12:02 pm by swagsxcboi »
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Yacoubb

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Re: VCE Chemistry Question Thread
« Reply #909 on: May 21, 2014, 11:06:55 pm »
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Thanks Yacoubb, I understand that, but that's q1 not 2 :P

Oh woops, sorry! I thought you didn't get q1. swagsxcboi explained q2, so hopefully you got it !

psyxwar

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Re: VCE Chemistry Question Thread
« Reply #910 on: May 21, 2014, 11:17:26 pm »
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when performing the bromine test to see if the hydrocarbon is saturated or unsaturated, the Bromine is aqueous...I thought the first four alkanes were gas at room temperature? Could someone explain this?
can't you bubble gas through solution?
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Rod

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Re: VCE Chemistry Question Thread
« Reply #911 on: May 22, 2014, 07:34:50 am »
+1
LOL I just want to do well in Chemistry. A lot of you guys are geniuses! I need LOTs of time to reach your standards :P
50 in chem right there :D

Hey Yacoubb, when you go ahead in chem, do you watch vtextbook, make detailed notes, and then finish of all the textbook questions? That's what I've been doing

Or do you do checkpoint/exam style questions instead after watching videos and making detailed notes?

Thanks :)
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Yacoubb

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Re: VCE Chemistry Question Thread
« Reply #912 on: May 22, 2014, 09:25:13 am »
+1
50 in chem right there :D

Hey Yacoubb, when you go ahead in chem, do you watch vtextbook, make detailed notes, and then finish of all the textbook questions? That's what I've been doing

Or do you do checkpoint/exam style questions instead after watching videos and making detailed notes?

Thanks :)

What I do is read up on the concepts, watch V-textbook and basically write up my own notes. Once I've familiarised myself with the theory, I begin doing the textbook questions. After this, I do checkpoints for more complex questions. I find that this really worked for me.


Rod

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Re: VCE Chemistry Question Thread
« Reply #913 on: May 22, 2014, 03:46:43 pm »
+1
What I do is read up on the concepts, watch V-textbook and basically write up my own notes. Once I've familiarised myself with the theory, I begin doing the textbook questions. After this, I do checkpoints for more complex questions. I find that this really worked for me.
I do the exact same thing except I tend to save the checkpoint questions for SAC prep.

Thanks Yacoubb :). Keep up the great work!
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Re: VCE Chemistry Question Thread
« Reply #914 on: May 22, 2014, 05:46:48 pm »
0
How does one write an equation illustrating fragmentation?
C5H12
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