A solution was prepared by dissolving 4.680g of sodium chloride and 1.705g of sodium sulfate in water, so the total volume of the solution was 500ml. what is the sodium ion concentration.
so far I have done and
so what do I do from here? Am I able to add the 2 mols together then divide by 0.5L even though the substances were different?
I will continue from your step since it looks good. Just make sure u use the VCAA data booklet (download from vcaa website or ask your teacher for a nice copy).
From Na2SO4: n(Na+) = n(Na2SO4) x 2 (as there a 2 sodium atoms present in each molecule)
= 0.0204 mol
From NaCl: n(Na+)= n(NaCl)= 0.0801 mol
So now we have all the number of moles of sodium ion from 2 solution.
Add them up. n(Na+)total= 0.0801mol+0.0204mol= 0.1005mol
Finally divide by the total volume. c(Na+)= 0.1005mol/0.500L = 0.201 M
Hope it is right. ** Yawn **