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June 25, 2021, 01:19:03 am

Author Topic: Help with calculus question  (Read 703 times)  Share 

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Albertenouttaten

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Help with calculus question
« on: May 08, 2021, 09:03:44 pm »
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Hi all,
This question really confused me. Would really appreciate any help on this and also some guidance on how to break down the meaning of the "dx/dt" component to tackle future questions that look similar.

Thanks!

fun_jirachi

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Re: Help with calculus question
« Reply #1 on: May 08, 2021, 09:31:07 pm »
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\(\frac{dx}{dt}\) just means differentiate \(x\) with respect to \(t\). It's not dissimilar (in fact, the same!) to \(\frac{dy}{dx}\) when differentiating a function \(y = f(x)\) - if you've seen this notation, which is highly likely.
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Albertenouttaten

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Re: Help with calculus question
« Reply #2 on: May 08, 2021, 09:36:23 pm »
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So would the answer to this question therefore be:
differentiate x= 12/t
thus, dx/dt = -12/t^2
and then sub in t = 2
Thus dx/dt = -3 ?

fun_jirachi

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Re: Help with calculus question
« Reply #3 on: May 08, 2021, 09:44:27 pm »
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Yes, that is correct
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HSC 2018: Mod Hist [88] | 2U Maths [98]
HSC 2019: Physics [92] | Chemistry [93] | English Adv [87] | 3U Maths [98] | 4U Maths [97]
ATAR: 99.05

UCAT: 3310 - VR [740] | DM [890] | QR [880] | AR [800]
Guide Links:
Subject Acceleration (2018)
UCAT Question Compilation/FAQ (2020)
Asking good questions