ATAR Notes: Forum
HSC Stuff => HSC Maths Stuff => HSC Subjects + Help => HSC Mathematics Advanced => Topic started by: Albertenouttaten on May 08, 2021, 09:03:44 pm
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Hi all,
This question really confused me. Would really appreciate any help on this and also some guidance on how to break down the meaning of the "dx/dt" component to tackle future questions that look similar.
Thanks!
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\(\frac{dx}{dt}\) just means differentiate \(x\) with respect to \(t\). It's not dissimilar (in fact, the same!) to \(\frac{dy}{dx}\) when differentiating a function \(y = f(x)\) - if you've seen this notation, which is highly likely.
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So would the answer to this question therefore be:
differentiate x= 12/t
thus, dx/dt = -12/t^2
and then sub in t = 2
Thus dx/dt = -3 ?
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Yes, that is correct