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March 29, 2024, 07:43:49 am

Author Topic: VCE Specialist 3/4 Question Thread!  (Read 2164365 times)  Share 

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AlphaZero

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9405 on: February 23, 2019, 09:52:11 pm »
0
Why is the body in the first diagram accelerating upwards, but in the second diagram, downwards? Shouldn’t it be the other way around as the friction is moving with the pulley in the second diagram?
https://m.imgur.com/CAAH3du

Friction is a force that opposes intended motion.

So, if the body is accelerating up the plane, then the friction force on the body is acting down the plane.

If the body is accelerating down the plane then the friction force on the body is acting up the plane.

Please also note that the concept of coefficient of friction is not in the course anymore. It was removed after 2015 for the 2016-2020 study design.
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schoolstudent115

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9406 on: February 23, 2019, 10:00:12 pm »
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Friction is a force that opposes intended motion.

So, if the body is accelerating up the plane, then the friction force on the body is acting down the plane.

If the body is accelerating down the plane then the friction force on the body is acting up the plane.

Please also note that the concept of coefficient of friction is not in the course anymore. It was removed after 2015 for the 2016-2020 study design.
Thanks that makes sense now. I was just looking through a textbook a friend gave me. I’m not doing the subject yet but just a question, are vector proofs in exams and sacs?
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AlphaZero

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9407 on: February 23, 2019, 10:44:11 pm »
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Thanks that makes sense now. I was just looking through a textbook a friend gave me. I’m not doing the subject yet but just a question, are vector proofs in exams and sacs?

Proving results regarding vectors is not really a big focus in the exam. If present, they are usually in the Exam 1, or will be in the Exam 2 as a multiple-choice question (where for example you have to select a necessary and sufficient condition for a statement to hold). The last time the vectors area of study (AOS4) had its own extended response question was back in the 2014 Exam 2.

As for SACs however, they will most certainly appear there.
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schoolstudent115

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9408 on: February 24, 2019, 11:53:27 am »
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Proving results regarding vectors is not really a big focus in the exam. If present, they are usually in the Exam 1, or will be in the Exam 2 as a multiple-choice question (where for example you have to select a necessary and sufficient condition for a statement to hold). The last time the vectors area of study (AOS4) had its own extended response question was back in the 2014 Exam 2.

As for SACs however, they will most certainly appear there.
In the sac's, how difficult would you expect the questions to get. For example, proving sides are equal (very easy), proving that sides are perpendicular or parallel (easy-average), question involving bisections or difficult colinearity (which I find difficult so far).
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S_R_K

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9409 on: February 24, 2019, 12:07:29 pm »
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In the sac's, how difficult would you expect the questions to get. For example, proving sides are equal (very easy), proving that sides are perpendicular or parallel (easy-average), question involving bisections or difficult colinearity (which I find difficult so far).

SACs vary from school to school, so ask your teacher.

In principle, because SACs present an opportunity to investigate topics in more depth, you *could* get a more difficult vector proof than would ever appear on an exam. But it is up to your teacher, so ask them for advice on how to best prepare.

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9410 on: February 25, 2019, 09:35:54 pm »
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can someone help me with this question

im in spec 1/2 btw
When all eight factors of 30 are multiplied together, the product is 30k. What is the value of k?
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DBA-144

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9411 on: February 25, 2019, 10:09:41 pm »
+2
can someone help me with this question

im in spec 1/2 btw
When all eight factors of 30 are multiplied together, the product is 30k. What is the value of k?

Given you're in spec 1/2 this question should have been directed at the spec 1/2 question thread.

Basically, list out all the other 7 factors of 30 (there are 8, but don't include 30).

That is, that k= 1 x 2 x 15 x 3 x 10 x 6 x 5 = 30 x 30 x 30 = 27000.

Is that right? Again, please direct 1/2 questions to the 1/2 questions thread.

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lzxnl

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9412 on: February 26, 2019, 10:05:47 pm »
+3
srry dad ill post questions in the right thread...but than again the 1/2 thread looks dead
and no btw ur wrong...the answer is 30 to the power of 4

Mate, if someone helps you out, even if they're wrong, there's no need to be so rude and passive-aggressive. No one here owes you anything.
Given you're in spec 1/2 this question should have been directed at the spec 1/2 question thread.

Basically, list out all the other 7 factors of 30 (there are 8, but don't include 30).

That is, that k= 1 x 2 x 15 x 3 x 10 x 6 x 5 = 30 x 30 x 30 = 27000.

Is that right? Again, please direct 1/2 questions to the 1/2 questions thread.


It's actually convenient to use 30. You have 8 factors of 30, which means you can form four pairs of factors that multiply to give 30. Thus, the product of all factors is 304. Divide out 30 to give the correct answer.
« Last Edit: February 28, 2019, 09:34:49 pm by lzxnl »
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Re: VCE Specialist 3/4 Question Thread!
« Reply #9413 on: February 26, 2019, 10:27:39 pm »
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alright can someone help me out with this beefy composite function (attached)

find the implied domain and range of h(x)

I found the domain which turned out to be x is a subset of (-inf,(2-sqrt6)/2) union ((2-sqrt2)/2,(2+sqrt2)/2) union ((2+sqrt6)/2,+inf) and have no idea how to sub that back into the original equation to find the range.

cheers
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Re: VCE Specialist 3/4 Question Thread!
« Reply #9414 on: February 26, 2019, 10:47:13 pm »
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alright can someone help me out with this beefy composite function (attached)

find the implied domain and range of h(x)

I found the domain which turned out to be x is a subset of (-inf,(2-sqrt6)/2) union ((2-sqrt2)/2,(2+sqrt2)/2) union ((2+sqrt6)/2,+inf) and have no idea how to sub that back into the original equation to find the range.

cheers

If we intersect the range of 1/(2x^2 – 4x) with [–1, 1] (maximal domain of arccos), we get [–1, –0.5] U (0, 1]. Now find the range of –(1/2)arccos(y), where y is in [–1, –0.5] U (0, 1]. This gives [–pi/2, –pi/3) U (–pi/4, 0].

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9415 on: February 26, 2019, 10:47:55 pm »
0
alright can someone help me out with this beefy composite function (attached)

find the implied domain and range of h(x)

I found the domain which turned out to be x is a subset of (-inf,(2-sqrt6)/2) union ((2-sqrt2)/2,(2+sqrt2)/2) union ((2+sqrt6)/2,+inf) and have no idea how to sub that back into the original equation to find the range.

cheers

Since its a composite function, isn't it just the domain of the inner function?
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Re: VCE Specialist 3/4 Question Thread!
« Reply #9416 on: February 27, 2019, 02:00:26 pm »
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Hey, I was wondering if anyone knows whether we could get complex number questions like these on the exam?

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Re: VCE Specialist 3/4 Question Thread!
« Reply #9417 on: February 27, 2019, 02:26:06 pm »
+1
Hey, I was wondering if anyone knows whether we could get complex number questions like these on the exam?

I don't think so, but you would likely be required to make use of these ideas.

Hope this helps.
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Re: VCE Specialist 3/4 Question Thread!
« Reply #9418 on: February 27, 2019, 06:09:59 pm »
+1
Hey, I was wondering if anyone knows whether we could get complex number questions like these on the exam?

They're actually really easy. If it's addition or subtraction, use Cartesian. If it's multiplication or division, use polar. You just need to know how to use Cartesian vs polar and how to take conjugates in each.
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Re: VCE Specialist 3/4 Question Thread!
« Reply #9419 on: February 27, 2019, 07:17:32 pm »
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Thanks that does help :)