How did everyone go?!
Note: If NESA requests this to be taken down, I'll be forced to comply. Mostly gonna go backwards for now, but I'm also gonna juggle MX2. Please point out any mistakes.Thanks so much Rui!!!Question 16(https://i.imgur.com/C5MXirb.png)
Thanks so much Rui!!!Oh yikes haha definitely \( \frac\pi{12}\)! Thanks :D will edit that later
For 16 b, would the height be pi/4 or pi/2? And hence it would be pi/12(y0 + ylast 4yodd) ? cause I got 1.53 rip pls tell me I didn't make a big oopsie xD
Isn’t question 13 part (a) = sinx(cosx-1) as opposed to how you factorised it?
I could be wrong though
Isn’t question 13 part (a) = sinx(cosx-1) as opposed to how you factorised it?It's fine as written :)
I could be wrong though
Yeah I saw that! Also for part b) it should be minus 2 × 20 ×20That's either okay, or since been corrected :)
Also wouldn’t the final answer to the financial question be 24 not 25? Because the question asks how many times can a FULL withdrawal of $80000 be made. So instead of rounding up the final answer for n, shouldn’t it be rounded down?Yes, you're right here! Definitely should be 24, not 25.
Thanks for the solutions!For 12Ciii. I also left my answer as 54.29, in brackets I wrote (about 54 days later). The question just asked for what value of t is there 100 leaves, not on which day it become a 100 so I reckon what we have done is correct.
fun_jirachi I think you may have made an error for Q12 Ciii and Q 12 d
Q12 C iii)
Shouldn't it be 54 days, subbing this into L(t) gives 119 leaves, whereas subbing 55 days gives 91 leaves
EDIT: Is this because there is 100 trees at 54.3 days. Thus it needs to be day 55 for there to be less than 100 leaves. If so I wrote 54 in the exam (I had the decimal places above, do you think I will lose a mark?). Although there aren't 100 leaves for either 54 or 55 so shouldn't it have been left as a decimal?
Q 12d
The answer should be (3/2)In(10)
Thanks for the solutions!
fun_jirachi I think you may have made an error for Q12 Ciii and Q 12 d
Q12 C iii)
Shouldn't it be 54 days, subbing this into L(t) gives 119 leaves, whereas subbing 55 days gives 91 leaves
EDIT: Is this because there is 100 trees at 54.3 days. Thus it needs to be day 55 for there to be less than 100 leaves. If so I wrote 54 in the exam (I had the decimal places above, do you think I will lose a mark?). Although there aren't 100 leaves for either 54 or 55 so shouldn't it have been left as a decimal?
Q 12d
The answer should be (3/2)In(10)
Yep, you’re right for 12d): somehow read that as just ln|x+1| for some reason. I’ll make the correction when I’m more free.It is the 55th day, agreed. But the question Just says "find the value of t for which there are 100 leaves", not on which day it becomes 100
As for 12c, it is the 55th day. Consider if we were in the over 6.5 of a cricket match or something; it’s denoted and is the seventh over.
Thanks for pointing these out!
Even then I was told by my teachers and tutors to round to the nearest whole number. i.e. 54Yeah. Another tutoring company uploaded their solutions and they also wrote 54 days (nearest whole number), so we are good I'm pretty sure
So IDK, tbh as long as you have the decimal answer I think they would be leniant.
So what do you guys think the band 6 cut off will be?
No idea, would 85 be too high for a B6 cutoff?It wasn’t an overly difficult paper in my opinion. But after having done the questions I do believe there are some noteworthy challenging ones. I’d be inclined to say 82-84?
Honestly i'm thinking around low 80s....although someone more experienced should comment
It wasn’t an overly difficult paper in my opinion. But after having done the questions I do believe there are some noteworthy challenging ones. I’d be inclined to say 82-84?
How does it compare with 2018? I also agree, the paper was definitely doable, albeit a bit tricky.Can't say for sure; I never actually did solutions to the 2018 paper :/
Hey I just have a quick question regarding the hsc exam marks. Are the marks we receive the aligned marks? As in the ones where our marks are boosted up based off of the band cut offs or does that type of scaling happen in the atar mark?You're reported an aligned mark.
You're reported an aligned mark.
You don't get to see your raw mark by default. Raw marks need to be purchased off NESA.
Ah okay makes sense, thank you for the quick response. Is there any way of finding out what the band cut offs were for previous years?NESA never publicly discloses this information to my knowledge. Usually people use the raw marks database to infer where the cut-off would most likely be.