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April 25, 2024, 02:16:30 am

Author Topic: pH  (Read 950 times)  Share 

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sav07

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pH
« on: January 23, 2019, 08:04:38 pm »
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Hey! The question says:
HA has Ka 1.6 x 10^-5
Calculate the pH of a 0.001 ml L solution of HA
I was just wondering how I can calsulate the pH from the Ka

kauac

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Re: pH
« Reply #1 on: January 23, 2019, 08:08:41 pm »
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Hey! The question says:
HA has Ka 1.6 x 10^-5
Calculate the pH of a 0.001 ml L solution of HA
I was just wondering how I can calsulate the pH from the Ka

Hi, would you be able to clarify your acronyms? :)

HA = hydrochloric acid?
Ka = ??
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sav07

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Re: pH
« Reply #2 on: January 23, 2019, 08:11:01 pm »
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HA is just an acid it doesn't specify which one, and Ka is the equilibrium constant for the acid dissociation

david.wang28

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Re: pH
« Reply #3 on: January 23, 2019, 09:17:21 pm »
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HA is just an acid it doesn't specify which one, and Ka is the equilibrium constant for the acid dissociation
Hi Sav! If this is HA, then you would want to write H^+ + A^- as your dissociation reaction. Then you would want to write the Ka reaction (products over reactants). You should find the concentration of HA (c= n/v) and once you have done that, draw up an ICE table (I'm sure you can work this out for yourself). Then, find the concentration of H^+, and sub that number into pH = -log(H^+), and you should get the answer! :)
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