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April 16, 2024, 07:42:57 pm

Author Topic: Mole  (Read 1716 times)  Share 

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ally1784

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Mole
« on: January 05, 2021, 10:02:00 pm »
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Guys, why is part a 5 and part b 2.5
n = m/M

Sine

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Re: Mole
« Reply #1 on: January 05, 2021, 10:11:02 pm »
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Guys, why is part a 5 and part b 2.5
n = m/M

I think you need to consider an alternative formula for n

n = N/Na

where
n = moles
N = number of particles (e.g. particles of H2)
Na = avagadro's constant which is 6.02 x 10^23

Edit: misread the q (didnt see the "in mol" part. See below for the correct answer.
« Last Edit: January 05, 2021, 10:46:40 pm by Sine »

Bri MT

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Re: Mole
« Reply #2 on: January 05, 2021, 10:40:44 pm »
+5
A H2 molecule has twice the mass of one H atom.

You then do:
n(H2) = m/M = 5/2 = 2.5   and n(H) = m/M = 5/1 = 5


Hope this helps :)

ally1784

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Re: Mole
« Reply #3 on: January 05, 2021, 11:06:37 pm »
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How do I know that I'm looking for just one H atom (part a) because at the start I thought I was looking for H2, and that's how I got the answer 2.5?

Chocolatepistachio

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Re: Mole
« Reply #4 on: January 05, 2021, 11:48:09 pm »
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Part a it’s H2 so you just do n=m/M and then x the answer by 2 because there are 2 atoms of H . B it’s just H so you don’t need to x 2

ally1784

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Re: Mole
« Reply #5 on: January 07, 2021, 12:43:35 am »
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how do I solve this?

Bri MT

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Re: Mole
« Reply #6 on: January 07, 2021, 09:57:50 am »
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how do I solve this?


First you find the number of mols using n=m/M
Get M from the periodic table.

Then you use n*Na = N   (look at Sine's post)