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April 19, 2024, 03:18:43 pm

Author Topic: VCE Specialist 3/4 Question Thread!  (Read 2171264 times)  Share 

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motocross53

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Re: Specialist 3/4 Question Thread!
« Reply #315 on: February 15, 2012, 11:43:27 pm »
0
could someone please show me how to do this,
4.4 Q5a of essential book:

show that sin(theta)+cos(theta)i=cis(pi/2-theta)

thanks




as required

sorry mate,
i still dont really following you,
could you please give a longer explanation

nubs

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Re: Specialist 3/4 Question Thread!
« Reply #316 on: February 16, 2012, 12:28:28 am »
+1


as required

To do a 'show that' question, you need to pick a side, and adjust it and manipulate it so that it equals the other side. so pick the left hand side, or right hand side (whichever you think is easier to manipulate and work on). Tony picked the RHS, which he then manipulated to = the LHS, so he did this:
RHS = (He then proceed to expand this)

Remember:


So

Also remember that, and

So, = LHS
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rife168

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Re: Specialist 3/4 Question Thread!
« Reply #317 on: February 16, 2012, 10:11:13 pm »
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Complex number question: (From VCAA 2006 Exam 1)

Solve the quadratic equation , expressing your answers in exact cartesian form.
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abd123

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Re: Specialist 3/4 Question Thread!
« Reply #318 on: February 17, 2012, 07:06:38 am »
+1
Complex number question: (From VCAA 2006 Exam 1)

Solve the quadratic equation , expressing your answers in exact cartesian form.










In polar form:

Hence,

Let

Therefore,

let

.

Thus, .

You can also use , Where a, b holds r.

Hoped I Helped :).
« Last Edit: February 17, 2012, 07:38:51 am by abd123 »

kensan

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Re: Specialist 3/4 Question Thread!
« Reply #319 on: February 19, 2012, 03:48:06 pm »
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Must be a gap in my knowledge here, but from

and when you square rooted doesn't the argument change?
I'm confused because when you subbed in k=0, you got
but wouldn't it be   because 
If that makes sense haha
Also I was looking through my textbook and couldn't find any examples of this type of question, is this assumed after all knowledge learnt?
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rife168

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Re: Specialist 3/4 Question Thread!
« Reply #320 on: February 19, 2012, 03:58:24 pm »
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Must be a gap in my knowledge here, but from

and when you square rooted doesn't the argument change?
I'm confused because when you subbed in k=0, you got
but wouldn't it be   because 
If that makes sense haha
Also I was looking through my textbook and couldn't find any examples of this type of question, is this assumed after all knowledge learnt?
When he wrote
the next line should have been

Hope that clears it up. Also, this is a VCAA past exam question, so it would be good to make sure you understand it fully.
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kensan

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Re: Specialist 3/4 Question Thread!
« Reply #321 on: February 19, 2012, 04:09:56 pm »
+1
Ah I see, opposite of De Moivre's theorem.
Thanks man :)
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monkeywantsabanana

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Re: Specialist 3/4 Question Thread!
« Reply #322 on: February 24, 2012, 05:23:22 pm »
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Why is this invalid?

= =

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nubs

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Re: Specialist 3/4 Question Thread!
« Reply #323 on: February 24, 2012, 05:56:18 pm »
+1
Let a = 2i+j-k
Let b = i+j+k

Using these values, find ((a-b).(a-b))^(1/2)

Now find (a-b)

What does that tell you?

Remember that a.a doesn't equal a^2, it equals |a|^2

Similarly, (a-b).(a-b) doesn't equal (a-b)^2, it equals |a-b|^2
So ((a-b).(a-b))^(1/2) = |a-b|
« Last Edit: February 24, 2012, 05:59:16 pm by Nirbaan »
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paulsterio

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Re: Specialist 3/4 Question Thread!
« Reply #324 on: February 25, 2012, 07:13:34 pm »
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= =

Nirbaan explained it, but in simple terms, DOES NOT EQUAL

in fact, =

TrueTears

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Re: Specialist 3/4 Question Thread!
« Reply #325 on: February 25, 2012, 07:34:41 pm »
+2
Why is this invalid?

= =
Well firstly consider this statement

Is "squaring" defined for a vector? There is no distinct "multiplication" operation defined for a vector in your usual sense.
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monkeywantsabanana

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Re: Specialist 3/4 Question Thread!
« Reply #326 on: February 26, 2012, 12:02:44 am »
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Ah ok thanks!


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Re: Specialist 3/4 Question Thread!
« Reply #327 on: February 26, 2012, 12:04:49 pm »
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Hi, I'm having a bit of trouble with De Moivre's...

If W = 54rt2 cis (3pi/4), find solutions to cuberootW

I only got one solution which is 3rt2cis pi/4

Can someone help please? There's 2 more..
« Last Edit: February 26, 2012, 12:12:12 pm by powerrrr »

trinh

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Re: Specialist 3/4 Question Thread!
« Reply #328 on: February 26, 2012, 01:52:20 pm »
+1

, k ∈ Z
, k ∈ Z

Sub in k=-1, 0 and 1 to get:


You pretty much just forgot to add on the in step 2, hence missing out on the other two solutions

claireb

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Re: Specialist 3/4 Question Thread!
« Reply #329 on: March 04, 2012, 07:09:55 pm »
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Having a mental block and can't seem to work out these questions (tech free) :(

edit:
- cos^2(x)/sin(x) + sin(x)  answer=cosec(x)

- Simplify tan((pi/2)-y)    answer= cot(y)

thanks fletch-j :)

- If sin(x)=4/5 for x E [0,pi/2] and tan(y)=5/12 for y E [pi,3pi/2], find:
-tan(x) answer=4/3
-sec(x) answer=5/3
-sin(x+y) answer=-63/65
-tan(x+2y) answer=-836/123

- If tan(x)=2 and x E [0,pi/2], use trigonometric identities to find the exact values for:
-sin(2x)  answer=4/5
-cos(2x)  answer=-3/5

- Simplify the expression tan(x/2)/(1-tan^2(x/2))
« Last Edit: March 04, 2012, 08:07:54 pm by claireb »