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March 29, 2024, 07:00:36 pm

Author Topic: VCE Specialist 3/4 Question Thread!  (Read 2164585 times)  Share 

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Phy124

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Re: Specialist 3/4 Question Thread!
« Reply #300 on: February 13, 2012, 02:40:07 am »
+1
Thanks b^3, i know how to write pi in LaTeX now ;D

(quoted your post) :P
Too bad you don't know the correct formula for the volume of a cylinder...

Kidding! (Don't take that the wrong way ;))
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Hutchoo

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Re: Specialist 3/4 Question Thread!
« Reply #301 on: February 13, 2012, 04:04:25 pm »
0
Thanks b^3, i know how to write pi in LaTeX now ;D

(quoted your post) :P
Too bad you don't know the correct formula for the volume of a cylinder...

Kidding! (Don't take that the wrong way ;))
LOL!

ahh.liz

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Re: Specialist 3/4 Question Thread!
« Reply #302 on: February 13, 2012, 09:02:55 pm »
0
Hello Specialist Mathematics friends, it would seem that I require some mathematical assistance. How would one simplify the following expression?

cos(3x)cos(x) + sin(3x)sin(x)

Thank you :)
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TrueTears

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Re: Specialist 3/4 Question Thread!
« Reply #303 on: February 13, 2012, 09:04:39 pm »
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think about compound angle formula :P

or
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ahh.liz

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Re: Specialist 3/4 Question Thread!
« Reply #304 on: February 13, 2012, 09:09:30 pm »
+1
OOh! Haha, greatly appreciated! That's my homework done - time for some Restaurant City! :DDD
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Re: Specialist 3/4 Question Thread!
« Reply #305 on: February 14, 2012, 06:45:52 pm »
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Too bad you don't know the correct formula for the volume of a cylinder...

Kidding! (Don't take that the wrong way ;))

my baaaaaad!

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Re: Specialist 3/4 Question Thread!
« Reply #306 on: February 14, 2012, 10:03:17 pm »
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Could someone help me with this question? (:

Find 'x' for 4sinxo= secxo, x E [0,2pi]

Answer: 15o, 75o, 195o, 255o

b^3

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Re: Specialist 3/4 Question Thread!
« Reply #307 on: February 14, 2012, 10:15:43 pm »
0

So



« Last Edit: February 14, 2012, 10:18:19 pm by b^3 »
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Fishyiscool

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Re: Specialist 3/4 Question Thread!
« Reply #308 on: February 15, 2012, 09:58:16 pm »
0
Hmmm question:
Find z^(-3) if z= 1 - i
(I've tried this twice and too tired to reatttempt it, would be grateful if someone could show me how to solve this.)
Happy enough after one hell of a year.

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rife168

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Re: Specialist 3/4 Question Thread!
« Reply #309 on: February 15, 2012, 10:48:25 pm »
+1
Hmmm question:
Find z^(-3) if z= 1 - i
(I've tried this twice and too tired to reatttempt it, would be grateful if someone could show me how to solve this.)
Converting to polar form we have:
Then, using De Moivre's theorem:
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abd123

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Re: Specialist 3/4 Question Thread!
« Reply #310 on: February 15, 2012, 11:06:12 pm »
+1
Hmmm question:
Find z^(-3) if z= 1 - i
(I've tried this twice and too tired to reatttempt it, would be grateful if someone could show me how to solve this.)
Hmmm question:
Find z^(-3) if z= 1 - i
(I've tried this twice and too tired to reatttempt it, would be grateful if someone could show me how to solve this.)
Converting to polar form we have:
Then, using De Moivre's theorem:


,

Fourth quadrant, ,

, Sub it in.

Than you get, .

Using De Moivre's Theorem, .


Results as,

Don't rush the questions your having trouble with take it slow and steady you might get an answer out of it.

This is not a sac.

« Last Edit: February 15, 2012, 11:10:30 pm by abd123 »

motocross53

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Re: Specialist 3/4 Question Thread!
« Reply #311 on: February 15, 2012, 11:19:44 pm »
0
could someone please show me how to do this,
4.4 Q5a of essential book:

show that sin(theta)+cos(theta)i=cis(pi/2-theta)

thanks

Fishyiscool

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Re: Specialist 3/4 Question Thread!
« Reply #312 on: February 15, 2012, 11:22:00 pm »
0
Hmmm question:
Find z^(-3) if z= 1 - i
(I've tried this twice and too tired to reatttempt it, would be grateful if someone could show me how to solve this.)
Hmmm question:
Find z^(-3) if z= 1 - i
(I've tried this twice and too tired to reatttempt it, would be grateful if someone could show me how to solve this.)
Converting to polar form we have:
Then, using De Moivre's theorem:


,

Fourth quadrant, ,

, Sub it in.

Than you get, .

Using De Moivre's Theorem, .


Results as,

Don't rush the questions your having trouble with take it slow and steady you might get an answer out of it.

This is not a sac.


Thanks fletch-j and abd123, but the part I got stuck on was after all that... Like I have no idea what to do with the 3pi on 4 when I expand it to try to get it back to Cartesian form... :s
Happy enough after one hell of a year.

<3 Life goal: ---->  Prosthetics and Orthotics
2013 - bachelor of health sciences/master of clinical prosthetics and orthotics at La trobe :))

Mi piacerebbe aiutare gli altri studenti che studiano l'italiano quest' anno. Mi mandi un messaggio e possiamo chiacchierare x)

tony3272

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Re: Specialist 3/4 Question Thread!
« Reply #313 on: February 15, 2012, 11:25:46 pm »
+1
could someone please show me how to do this,
4.4 Q5a of essential book:

show that sin(theta)+cos(theta)i=cis(pi/2-theta)

thanks




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Re: Specialist 3/4 Question Thread!
« Reply #314 on: February 15, 2012, 11:26:30 pm »
+1
Hmmm question:
Find z^(-3) if z= 1 - i
(I've tried this twice and too tired to reatttempt it, would be grateful if someone could show me how to solve this.)
Hmmm question:
Find z^(-3) if z= 1 - i
(I've tried this twice and too tired to reatttempt it, would be grateful if someone could show me how to solve this.)
Converting to polar form we have:
Then, using De Moivre's theorem:


,

Fourth quadrant, ,

, Sub it in.

Than you get, .

Using De Moivre's Theorem, .


Results as,

Don't rush the questions your having trouble with take it slow and steady you might get an answer out of it.

This is not a sac.


Thanks fletch-j and abd123, but the part I got stuck on was after all that... Like I have no idea what to do with the 3pi on 4 when I expand it to try to get it back to Cartesian form... :s

Just remember that 3pi/4 = pi-pi/4 = pi/4. So it's just root2/4 x cos(pi/4) + root2/4 x isin(pi/4) .

edit: that is, sin(pi-x)=sin(x) and cos(pi-x)=cos(-x). What I said above is just applicable in the context of sin/cos/tan etc :P.
« Last Edit: February 15, 2012, 11:32:17 pm by teewreck »
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