Login

Welcome, Guest. Please login or register.

March 30, 2024, 01:44:57 am

Author Topic: VCE Specialist 3/4 Question Thread!  (Read 2164699 times)  Share 

0 Members and 2 Guests are viewing this topic.

pi

  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 14348
  • Doctor.
  • Respect: +2376
Re: Specialist 3/4 Question Thread!
« Reply #225 on: February 03, 2012, 12:01:19 pm »
0
(refer to the attached image).

We can't :P

b^3

  • Honorary Moderator
  • ATAR Notes Legend
  • *******
  • Posts: 3529
  • Overloading, just don't do it.
  • Respect: +631
  • School: Western Suburbs Area
  • School Grad Year: 2011
Re: Specialist 3/4 Question Thread!
« Reply #226 on: February 03, 2012, 05:29:41 pm »
+1
(refer to the attached image).

We can't :P
Sorry guys, mustn't have attached it, it's attached in the original post now.

Moderator action: removed real name, sorry for the inconvenience
« Last Edit: January 02, 2017, 09:47:40 pm by pi »
2012-2016: Aerospace Engineering/Science (Double Major in Applied Mathematics - Monash Uni)
TI-NSPIRE GUIDES: METH, SPESH

Co-Authored AtarNotes' Maths Study Guides


I'm starting to get too old for this... May be on here or irc from time to time.

HERculina

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1209
  • To ∞ and beyond
  • Respect: +11
  • School: St. Trinians
  • School Grad Year: 2012
Re: Specialist 3/4 Question Thread!
« Reply #227 on: February 04, 2012, 03:06:47 pm »
0
If w= -(1/3) - ((square root 3)/3)i, express w^(-4) in polar form :D
------------------------------------------------------> :D <-----------------------------------------------------

Mr. Study

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 494
  • Onion Knight
  • Respect: +18
Re: Specialist 3/4 Question Thread!
« Reply #228 on: February 04, 2012, 03:15:53 pm »
0
Just this question for me:

Find the tangent to the curve x=2-3y^2, at point x=-1.

I saw the worked solution to it but it's still very confusing.
ᕕ( ᐛ )ᕗ

TrueTears

  • TT
  • Honorary Moderator
  • Great Wonder of ATAR Notes
  • *******
  • Posts: 16363
  • Respect: +667
Re: Specialist 3/4 Question Thread!
« Reply #229 on: February 04, 2012, 03:17:57 pm »
0
find dx/dy, flip it to get dy/dx, sub in x = -1 to find gradient, then just use general equation of a linear line
PhD @ MIT (Economics).

Interested in asset pricing, econometrics, and social choice theory.

paulsterio

  • ATAR Notes Legend
  • *******
  • Posts: 4803
  • I <3 2SHAN
  • Respect: +430
Re: Specialist 3/4 Question Thread!
« Reply #230 on: February 04, 2012, 03:21:37 pm »
+1

If w= -(1/3) - ((square root 3)/3)i, express w^(-4) in polar form :D

ugh, i wish i knew latex, but this will have to be sufficient :)


b^3

  • Honorary Moderator
  • ATAR Notes Legend
  • *******
  • Posts: 3529
  • Overloading, just don't do it.
  • Respect: +631
  • School: Western Suburbs Area
  • School Grad Year: 2011
Re: Specialist 3/4 Question Thread!
« Reply #231 on: February 04, 2012, 03:28:04 pm »
+3
If w= -(1/3) - ((square root 3)/3)i, express w^(-4) in polar form :D

(base angle is but is in the 3rd quadrant







Now we want so we flip the r and the angle will become postive since

So we end up with

Beaten but there is your LaTeX Paul.
2012-2016: Aerospace Engineering/Science (Double Major in Applied Mathematics - Monash Uni)
TI-NSPIRE GUIDES: METH, SPESH

Co-Authored AtarNotes' Maths Study Guides


I'm starting to get too old for this... May be on here or irc from time to time.

paulsterio

  • ATAR Notes Legend
  • *******
  • Posts: 4803
  • I <3 2SHAN
  • Respect: +430
Re: Specialist 3/4 Question Thread!
« Reply #232 on: February 04, 2012, 03:30:34 pm »
+1
Find the tangent to the curve x=2-3y^2, at point x=-1.

(Again, sorry for no LATEX :P)


HERculina

  • Victorian
  • Part of the furniture
  • *****
  • Posts: 1209
  • To ∞ and beyond
  • Respect: +11
  • School: St. Trinians
  • School Grad Year: 2012
Re: Specialist 3/4 Question Thread!
« Reply #233 on: February 04, 2012, 03:33:00 pm »
0
Ah i seee! Thanks paulsterio + b^3 :)
------------------------------------------------------> :D <-----------------------------------------------------

b^3

  • Honorary Moderator
  • ATAR Notes Legend
  • *******
  • Posts: 3529
  • Overloading, just don't do it.
  • Respect: +631
  • School: Western Suburbs Area
  • School Grad Year: 2011
Re: Specialist 3/4 Question Thread!
« Reply #234 on: February 04, 2012, 03:33:43 pm »
+1
Find the tangent to the curve x=2-3y^2, at point x=-1.

(Again, sorry for no LATEX :P)

(Image removed from quote.)
But it feels and looks sooo much better! :P

EDIT: THAT WASN'T MEANT TO BE A PUN........
« Last Edit: February 04, 2012, 03:35:45 pm by b^3 »
2012-2016: Aerospace Engineering/Science (Double Major in Applied Mathematics - Monash Uni)
TI-NSPIRE GUIDES: METH, SPESH

Co-Authored AtarNotes' Maths Study Guides


I'm starting to get too old for this... May be on here or irc from time to time.

paulsterio

  • ATAR Notes Legend
  • *******
  • Posts: 4803
  • I <3 2SHAN
  • Respect: +430
Re: Specialist 3/4 Question Thread!
« Reply #235 on: February 04, 2012, 03:37:31 pm »
0
But it feels and looks sooo much better! :P

EDIT: THAT WASN'T MEANT TO BE A PUN........

It's Microsoft Word Equation Editor, or something like that, basically it's like LaTeX, except you have like drag-and-drop templates - I don't know syntax D:

Mr. Study

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 494
  • Onion Knight
  • Respect: +18
Re: Specialist 3/4 Question Thread!
« Reply #236 on: February 04, 2012, 03:45:07 pm »
0
Hey, thanks for the explanation.

Heres another question.

Find the argument for 1-(i x square root of 3), in [0, 2 pi].

ᕕ( ᐛ )ᕗ

paulsterio

  • ATAR Notes Legend
  • *******
  • Posts: 4803
  • I <3 2SHAN
  • Respect: +430
Re: Specialist 3/4 Question Thread!
« Reply #237 on: February 04, 2012, 03:57:43 pm »
0
Find the argument for 1-(i x square root of 3), in [0, 2 pi].


Edit: Whoops, sorry you wanted [0, 2pi]


« Last Edit: February 04, 2012, 04:00:56 pm by paulsterio »

Mr. Study

  • Victorian
  • Forum Obsessive
  • ***
  • Posts: 494
  • Onion Knight
  • Respect: +18
Re: Specialist 3/4 Question Thread!
« Reply #238 on: February 04, 2012, 04:08:06 pm »
0
Hey, thanks Paul.

Just this one last question on Complex numbers. (Yay!)

Simplify 4cis(2pi/3)/32cis(-pi/3).

(Also: How do you get that Microsoft Word Equation Editor?)
ᕕ( ᐛ )ᕗ

monkeywantsabanana

  • Victorian
  • Forum Leader
  • ****
  • Posts: 638
  • An eye for an eye will make us all blind.
  • Respect: +55
  • School Grad Year: 2012
Re: Specialist 3/4 Question Thread!
« Reply #239 on: February 04, 2012, 04:14:06 pm »
0
Hey, thanks Paul.

Just this one last question on Complex numbers. (Yay!)

Simplify 4cis(2pi/3)/32cis(-pi/3).

(Also: How do you get that Microsoft Word Equation Editor?)

4cis(2pi/3)/32cis(-pi/3)

4/32 cis(2pi/3 -(-pi/3))
=1/8 cis (2pi/3+pi/3)
=1/8 cis (3pi/3)
=1/8(cis pi)
=-1/8

I hope that's right...
« Last Edit: February 04, 2012, 04:16:09 pm by monkeywantsabanana »

Bachelor of Commerce (Economics & Finance)