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March 29, 2024, 02:09:19 am

Author Topic: VCE Specialist 3/4 Question Thread!  (Read 2164251 times)  Share 

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paulsterio

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Re: Specialist 3/4 Question Thread!
« Reply #150 on: January 03, 2012, 02:35:47 pm »
+1
pi, your way would have worked reasonably, except it's extremely long :P

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« Last Edit: January 02, 2017, 09:44:31 pm by pi »

dc302

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Re: Specialist 3/4 Question Thread!
« Reply #151 on: January 03, 2012, 02:36:08 pm »
0







Yeah, you know how to do that :)

(do it the long way, and not multiply by the identity btw)



Since when do you know how to do that in year 12?

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« Last Edit: January 02, 2017, 09:44:54 pm by pi »
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pi

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Re: Specialist 3/4 Question Thread!
« Reply #152 on: January 03, 2012, 02:38:55 pm »
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Since when do you know how to do that in year 12?

Our SACs... :(

pi, your way would have worked reasonably, except it's extremely long :P

Yeah, I see that, samad's way was much better, should've seen that (I'm really out of it lol)

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« Last Edit: January 02, 2017, 09:46:18 pm by pi »

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Re: Specialist 3/4 Question Thread!
« Reply #153 on: January 03, 2012, 02:39:25 pm »
+1
Hey, that question involves partial fractions:
express the integral:

Now:

Using standard partial fractions techniques
now the integral is:


as required
pi's appraoch very valid as well but not on course

Thank you! You're a legend :)

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« Last Edit: January 02, 2017, 09:46:41 pm by pi »
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dc302

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Re: Specialist 3/4 Question Thread!
« Reply #154 on: January 03, 2012, 02:40:51 pm »
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Since when do you know how to do that in year 12?

Our SACs... :(

pi, your way would have worked reasonably, except it's extremely long :P

Yeah, I see that, samad's way was much better, should've seen that (I'm really out of it lol)

Ah I see, I didn't know cause I don't remember ever seeing that (1/cosx) in vce :P

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« Last Edit: January 02, 2017, 09:47:07 pm by pi »
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paulsterio

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Re: Specialist 3/4 Question Thread!
« Reply #155 on: January 03, 2012, 02:43:22 pm »
+1
Yeah, I see that, samad's way was much better, should've seen that (I'm really out of it lol)

LOL! same here, I can't believe I didn't recognise the difference of squares when I first looked at it either!

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« Last Edit: January 02, 2017, 09:47:54 pm by pi »

pi

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Re: Specialist 3/4 Question Thread!
« Reply #156 on: January 03, 2012, 02:45:00 pm »
+1
Yeah, I see that, samad's way was much better, should've seen that (I'm really out of it lol)

LOL! same here, I can't believe I didn't recognise the difference of squares when I first looked at it either!

Yeah same! Can't believe I saw the trig way first... That's pretty damn slow.

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« Last Edit: January 02, 2017, 09:48:09 pm by pi »

paulsterio

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Re: Specialist 3/4 Question Thread!
« Reply #157 on: January 03, 2012, 02:46:26 pm »
+1
Hmm, the log should have given it away though, like you always get logs with partial fractions, I guess this is what happens when you don't do this stuff for 2 months, I wonder if I'll have anything left in the tank at the end of 2012, I was really looking forward to doing the 2012 spesh exam (A)!! :D


Btw, Year 12s, Tip: - If you see logs, think partial fractions

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Re: Specialist 3/4 Question Thread!
« Reply #158 on: January 03, 2012, 02:52:11 pm »
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Btw, Year 12s, Tip: - If you see logs, think partial fractions

Thanks. I'll remember that.
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Re: Specialist 3/4 Question Thread!
« Reply #159 on: January 05, 2012, 02:16:23 pm »
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Find all z satisfying:

z^8+1=0

Express your answers in polar form.

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Re: Specialist 3/4 Question Thread!
« Reply #160 on: January 05, 2012, 02:31:25 pm »
+3



let w=












EDIT: beaten :/
« Last Edit: January 05, 2012, 02:40:47 pm by abd123 »

dc302

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Re: Specialist 3/4 Question Thread!
« Reply #161 on: January 05, 2012, 03:35:56 pm »
+1
I don't really know why you have introduced a 'w' that you never used, but in any case, you should have z^8 = cis(pi + 2kpi) from the beginning, not 3 lines later as this is inconsistent.
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paulsterio

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Re: Specialist 3/4 Question Thread!
« Reply #162 on: January 06, 2012, 10:51:19 am »
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Btw, if you intend to write k = 4, you'll have to say that z = cis(9pi/8) = cis(-7pi/8) otherwise your answer wouldn't make much sense

Alternatively, you can let k = 0, 1, 2, 3, -1, -2, -3, -4 instead

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Re: Specialist 3/4 Question Thread!
« Reply #163 on: January 07, 2012, 02:51:54 pm »
+1
Is there supposed to be a picture attached?
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Re: Specialist 3/4 Question Thread!
« Reply #164 on: January 07, 2012, 05:48:43 pm »
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you guys are so ahead! takes me forever to do one exercise  :o
anyway i don't understand part b of the last question in exercise 1E (essentials, if anyone has done it yet):
10. a)Find an expression for the infinite geometric sum 1 + sintheta + sin^2*theta + ...
b)Find the values of theta for which the infinite geometric sum is 2.
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