It might be a good idea to sticky this thread, just like the Methods and Specialist ones.Done.
Does anyone have any experience with Networks? I had a look over some exams and didn't seem to like it. The other two Modules are Graphs & Relations and Matrices. I'm considering taking up Number Patterns instead.I'm not that great at Math but Networks is my jam.
Does anyone have any experience with Networks? I had a look over some exams and didn't seem to like it. The other two Modules are Graphs & Relations and Matrices. I'm considering taking up Number Patterns instead.If you did sequences and series in GMA then would basically understand most of the module already. You'd definitely be better off doing number patterns instead of networks if that was the case.
Is it necessary to do EVERY single question in the textbook?
Is it necessary to do EVERY single question in the textbook? My teacher seems to think so ::)
What modules is everyone doing?
I'm doing:
1) Number Patterns
2) Graphs and Relations
3) Matrices
What modules is everyone doing?
I'm doing:
1) Number Patterns
2) Graphs and Relations
3) Matrices
Can past students give some tips on how to minimise mistakes in Graphs & Relations?
I find it quite straightforward, but it is easy to slip up in linear programming (especially when writing the constraints). Any suggestions to address this issue?
Well, I don't know how effective this will be for you, but whenever the question provided information in worded form and asked us to create a constraint, I would check my answer by substituting random values to make sure that the constraint was right.
eg. 2012 Exam 1: Graphs and Relations q 8
at least 5 loves of white bread will be made for ever loaf of brown bread that is made
w= white bread made per day
b= brown bread made per day
I'd first write up my constrain: w ≥ 5b
I'd then check this by subbing in random values for b. So, if I made 1 brown bread, I'd made 5 white bread. If this matches the constraint they provided originally in words, you'd know you have the right answer.
Hope that makes sense. :P
I have my first SAC this Wednesday (my school divides the CORE Sac into Univariate and Bivariate data). Does anyone have any tips for the univariate section?
No, you've probably covered every single little thing in univariate data really thoroughly (just like I did). So now, just relax and make sure you don't do something stupid in your first SAC (just like I did). :P
Random sampling hardly ever comes up. Might be something to watch out for though!
For seasonal, it reappears every Q4. Therefore if there is a max at Q1, then a max will occur at each Q4 after. Eg. Q1, Q5, Q9
Cyclic has peaks etc but it doesnt always follow the same pattern.
An example a teacher use to tell us was:
Seasonal- ice cream sales; they would peak during summer
cyclic; apple company; they release a product, lots of people buy it, they wait until there are less sales, then release their next product
Well as long as it reoccurs at the same period
Wow thats soo much better!!
I had to do it all within 1 week class time. Was one massive SAC.
For seasonal, it reappears every Q4. Therefore if there is a max at Q1, then a max will occur at each Q4 after. Eg. Q1, Q5, Q9
Cyclic has peaks etc but it doesnt always follow the same pattern.
An example a teacher use to tell us was:
Seasonal- ice cream sales; they would peak during summer
cyclic; apple company; they release a product, lots of people buy it, they wait until there are less sales, then release their next product
Does it have to be every Q4? Because if you were investigating a 36-month period, it could be at every 12th month, or, end of every year, a trough would exist..
The main difference between a seasonal and a cyclic trend is that in a seasonal trend, the repetition is constant and the 'cycle' is less than one year in duration. Cyclic trends are generally more varied and are more than one year in duration.
Any other differences?
Bar charts are seperated. Each bar is separated, where as histograms are all touching each other, there is no break
1C: Did you standardise the years in the x-axis? It says to make 1992 the number 1 and go onwards from there. Also, make sure that you determine the right number for the year 2008. You might be one number off, so quickly make a little list.Yep I did this, but my answer was still off :S
2A: Work through the the quarters (in order) of year 1, then year 2, then year 3. Don't do something silly like taking the average.I'm not sure what you mean by this :S
Calculator: Not sure what calculator you use, but I just stopped defining the lists because I had a similar issue. Why do you have to label them? :PI use the grey CAS. So you don't have to label them? What do you do then, if you need to draw a graph using the data? Don't you have to name them then?
Yep I did this, but my answer was still off :S
I'm not sure what you mean by this :S
I use the grey CAS. So you don't have to label them? What do you do then, if you need to draw a graph using the data? Don't you have to name them then?
Thanks for the help :)
And one more thing that's unrelated to the questions above but still bugs the crap out of me, how do I 'clear history' on lists and spreadsheets? Like I'll be doing a question and naming column A 'x' for example, and then when I open a new lists and spreadsheets, it's still defined as the previous x. My teacher said to just 'clear a-z' in the calculator page, but is there no other way?I think you may have to start a new document, I've been bugged by it also... I just try keeping my label's as unique as possible so I don't come across it twice, then I start a new document once I'm done.
Thanks
Thanks,
There is a question that is 2 marks and asks us to comment on the features of the time series plot. Would saying that it has a positive/upward cyclic trend be enough for the 2 marks?
Hey,
In what type of time series plots would it not be appropriate to use a least squares regression line?
I have a question that wants me to say if it is appropriate to use a least squares regression line is appropriate to model an increasing seasonal trend. I know that the answer would be no, but not sure how to explain (as it's 2 marks).
thanks
I always went for the median because it works every time, regardless of the shape of the distribution. :)
Hey can someone please explain how to do:Hi,
- q13 from http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2009furmath1-w.pdf
- q9 from http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2008furmath1-w.pdf
Thanks!
Upon observing the results with the 5-point smoothing, a trend appears. Take the data from the 5-point moving average smoothing and fit a straight line using the least-squares method. Put the first smoothed point at t = 3 and then centre the time data. State the y-intercept and gradient. Compare this trend line with that from question 3.
i'm confused on how to centre the time data or what is meant by that, can someone please explain this to me?
You'd only centre the data during (even number)-pt moving mean smoothing such as 2-pt, 4pt etc.
This is because when you initially find the mean, the centre of the points is not actually belonging to the original series (or original time value). We then have to 'centre' the means through finding the 2-pt moving mean again of the already smoothed values in order to allow them to line up with their original time values.
This is would be better demonstrated using a visualised table, so perhaps try drawing one out!
However, in your case of a 5-pt moving mean or any (odd number)-pt moving mean, centring would definitely not be required. Perhaps it was a trick or a typo in the question that was provided to you so don't stress!
Hope I helped :)
I'm having a SAC on time series soon but there's one thing bugging me.
I find it hard to differentiate between seasonal and seasonal with trend. For example, if you're given a graph and you see that there are peaks and troughs, how do you determine if it is indeed seasonal only and not with trend or the other way around?
I'm having a SAC on time series soon but there's one thing bugging me.
I find it hard to differentiate between seasonal and seasonal with trend. For example, if you're given a graph and you see that there are peaks and troughs, how do you determine if it is indeed seasonal only and not with trend or the other way around?
Okay so the first thing you need to understand is that when you're analysing a time series plot, there are two main features:
(a) Trend - increasing (upward) or decreasing downward
(b) Variation - seasonal (pattern), cyclical (pattern) or random.
Seasonal variation can easily be identified by looking at a period of one year or less and observing evidently regular fluctuations (i.e. troughs and peaks occur at consistent time intervals over the time frame under analysis.
Now its one thing to identify seasonal variation, and another to determine trend. I had a TIME SERIES SAC today and my time series plot showed a decreasing (downward) trend with seasonal variation. Just note that in order to calculate seasonal indices, you MUST have a seasonal component (i.e. seasonal variation). Just a tip if you're stuck with what type of variation you've got.
Trend can be identified two ways. Firstly, sometimes its extremely easy to see a visible trend simply by looking at the graph, usually if you have a fair few plotted points (i.e. 8 points +). However, sometimes you have insufficient points to see any visible trend, and a tip would be to simply use your calculator to find the regression line of your time series plot; if the gradient/slope is (+), you're looking at an increasing trend, and (-) slope/gradient corresponds to a decreasing downward trend. Sometimes, there is no trend. It is possible to have seasonal variation with NO trend (i.e. over many years, you're having consistency in the seasonal component and the DV does not decrease/increase over the timeframe).
If there is a trend, you can use your rule to see a visible trend simply by looking at the overall trend of the graph, or as mentioned, using your calculator. But if no trend is visible, you practically see that there is no increase/decrease in DV over the timeframe. You can also look at the raw data; if the values of the data decrease over the quarters/months/terms, etc, there is probably going to be a decreasing (downward) trend.
Hope this helped, and best of luck!
As far as I can tell, most people seem to have already finished core. Have you guys also done a module, or did you start with core?
Just finished the time series SAC. I think I did pretty well. Thanks for your help Yacoubb.
We're now starting on Trig.
Can someone explain how to "comment on histograms" and "compare histograms A and B" ?
Cheers
Can someone explain how to "comment on histograms" and "compare histograms A and B" ?
Cheers
Hey, I am really stuck on Question 8 and 10. I answered 8a fine and got it right but 8b doesn't make sense to me. I keep getting 5.99 and the answer is 5.53 cm.
As for Question 10, I got 10a right too but I'm also having trouble with the second part to the question.
The answer to 10b is 67.7 cm.
http://cambridge.edu.au/go/interactive_book/books/vce_further_maths/images/chapter/inline-405.gif <-- The questions are there. 8 and 10.
Hey, I am really stuck on Question 8 and 10. I answered 8a fine and got it right but 8b doesn't make sense to me. I keep getting 5.99 and the answer is 5.53 cm.Here's my working for your questions, have the picture by your side so you know all of the angles and the side lengths that I am referring to.
As for Question 10, I got 10a right too but I'm also having trouble with the second part to the question.
The answer to 10b is 67.7 cm.
http://cambridge.edu.au/go/interactive_book/books/vce_further_maths/images/chapter/inline-405.gif <-- The questions are there. 8 and 10.
Bump! I need help.
Here's my working for your questions, have the picture by your side so you know all of the angles and the side lengths that I am referring to.
edits: fixing messy working
Thanks Yacouub. Will there be different expectations if the question asked to describe a boxplot? (Besides the fact that a BP provdes 5 simmaru statistics)
hi all, im in search of a further math study guide on matrices, ive searched in the notes section of the forum but there is nothing on it, i understand it it an easy section for some, but couple of bits are hard. thank you
hello, cant wait to ask to my teacher so just going to ask here hehe, matrices module 6
question is
RS=T
s= 2 4 t= 0 2 find matrix r, cant find it in my book either
1 3 2 0
Hi,
Can someone please explain and work out this question
An equilateral triangle has altitudes of 20cm . Find the length of one side.
thanks
An equilateral triangle as three same sides and angles, with the angles being 60 degrees equally. For more detail, see : http://au.answers.yahoo.com/question/index?qid=20081011170708AAg8pyQ and here is a diagram to help you: http://free-test-online.com/Content/equilateral%20triangle.jpg
How did you cope with the time constraint in the exam? Did you feel rushed for time?
Thanks, also, did you feel well prepared before sitting the exam? I know it was your only 3/4 so you wouldn't have had as much workload compared to year 12.
Thanks, also, did you feel well prepared before sitting the exam? I know it was your only 3/4 so you wouldn't have had as much workload compared to year 12.
Hell yes. I was doing trial exams in July because that's when our class finished the course. My goal by the exams was essentially to cover every single type of question possible so that nothing could catch me out on the exams (hence the 80+ practice exams). And still, there were some questions unlike anything I'd ever seen before. XD Like McFleurry, I also had a minor panic attack in Exam 1 over six multiple choice questions - use the time provided to calm yourself down and move onto something that's a bit easier to tackle, let your subconscious work on it for a bit and come back to it later.Re: practice exams, where'd the 80+ come from, or do you mean 40 sets of exam 1 and 2? Which companies did you get your exams from, and did you end up repeating any exam more than once because you ran out or?
The extent that I went to last year in order to feel prepared is not a luxury that I have this year. I guess the major difference between Year 11 and Year 12 for me is that I really just don't have the time to go that little bit further in all my subjects and use extra supplementary material. A lot of my study is really based on doing the 'standard' thing, but doing it really thoroughly. I'm hoping my doubts will be (somewhat) addressed by the end of the term 3 holidays, when I know I'll be pumping out the trial exams.
I lost count in the end - my teacher just told me 80+ and that's what I've stuck with. Only now can I truly marvel at just how many resources my teacher had. Even when I thought I had run out of practice papers, he managed to find 20 more for me. :S That's not something I know my teachers this year are able to match.Did your teacher correct these ~80 exams? Or did the come with solutions?
The actual time you do VCAA exams is really not as big an issue as what everyone makes it out to be, because a lot of company papers (with the exception of Kilbaha >_<) are at a fairly relevant standard. As long as you make sure that you mix them up to get a variety of difficulties, you'll be fine.
Re: practice exams, where'd the 80+ come from, or do you mean 40 sets of exam 1 and 2? Which companies did you get your exams from, and did you end up repeating any exam more than once because you ran out or?
I'm thinking of doing some practice exams for the CORE and 1st module before school starts, and I'm looking towards VCAA. I'll do them knowing that I'll actually end up doing the same questions again closer to the actual exam, but under proper, timed exam conditions (i.e. once the whole course is finished). Do you think it's okay to repeat the VCAA exams or is it better to just do other company exams now and not expose myself to the VCAA questions until later?
I lost count in the end - my teacher just told me 80+ and that's what I've stuck with. Only now can I truly marvel at just how many resources my teacher had. Even when I thought I had run out of practice papers, he managed to find 20 more for me. :S That's not something I know my teachers this year are able to match.Hey, could you clarify if this was 80 exam 1's and exam 2's (therefore 160 papers), or 40 sets? Just wonderin.
i need help with question 16b in chapter 21F. Im getting the answer as $123716.47 but in the back it is $143716.47. is it me thats wrong or is it the back of the book that is wrong?
help me out cuz.
btw its financial maths.
1. Yes, technically you are wrong. :( The ratio is to be stated with the map value on the left.Thanks for your response Stick :P
Just had a linear sac, and there was a m.c question which i wasn't quite sure about.
Hi,
Just had a linear sac, and there was a m.c question which i wasn't quite sure about.
Mr Newcomer and Mrs latecomer leave the car park at the same time. If Mr newcomer arrives at the car park at 10:00 am, and Mrs latecomer is charged $24, what is the latest time Mrs latecomer can arrive at the car park?
There was graph in the question, although i can't upload a pic of it as the file is to big, so i will write it out.
- After 0 minutes up until 60 minutes the charge is $10.
- After 60 minutes up until 120 minutes the charge is $24.
- After 120 minutes the charge is $35.
a) 10:01 am
b) 10:59 am
c) 11:01 am
d) 11:59 am
e) the same time as Mr Newcomer
Both Mr Newcomer and Mrs Latecomer arrive at the same time. If Mr. Newcomer arrives at 10AM, and Mrs. Latecomer pays $24, that means she would have had to have been there between 1 and 2 hours (excluding 2 hours) after 10 (i.e. 11:59). Hence, the answer is D.
ok, but where did it say they arrived at the same time. It only said that they left at the same time.
Does anybody know how i can get my hands on copious amounts of further exams? not the VCAA ones as i already have them but all the other ones from various companies?
for instance a link to download exams? or where can i find them???
Please help!
cheers :)
Now I'm fine with normal inequalities but I have trouble understanding what it means when they use the words a is at least twice as b.
thanks for that. I get it now but I think I'll have to read the question four times before I really get the hang of it.
'At least' means that it must either be greater than or equal to.
So, if the number of dogs clipped is at least twice the number of dogs washed
x = number of dogs washed
y = number of dogs clipped
y is at least 2 x
y must be either equal to or greater than 2x
y>(greater than or equal to) 2x
i need help:total depreciation = 13000-4000=9000
Question one:
equipment is brought for $13000. In 5 years time it will depreciate in value to $4000. Assuming it depreciates by the straight line method, it depreciates annually by how much?
Question two:
equipment is brought for $2250. If for every use it depreciates by 0.08 cents, how many uses will it take to depreciate it to a value of $1000?
total depreciation = 13000-4000=9000
annual=9000/5=1800
depreciation=2250-1000=1250
depreciation per use =0.08
number of uses =1250/0.08 =15625 uses
In linear programming, when do we use points within the feasible region as opposed to the vertices of the feasible region? I mean, I was stumped when I looked at a question in Checkpoints like that, and especially because I've never come across it.
On the bright side, 1 SAC left for Further (well, practically 2, but my Graphs+Relations SAC will be finished early next week). Then its on to practice exams!
I got the same answer for question 1. but for question two i think by 0.08 cents, it means $0.0008. Just clarify this part.oops i didnt look at that part carefully
Thank you friend.
This is really common (it came up last year). Basically, you use points within the feasible region if the vertices don't give integer values and you're dealing with discrete variables. I hated these questions because you have to trial a lot of points, so it's time consuming.
Asking a question for a friend of mine :)form a triangle ..the three vertices are A,B and top of tower ..
From a point, A, due north of a tower, the angle of elevation to the top of the tower is 45◦.
From a point, B, 100 m on a bearing of 120◦ from A, the angle of elevation is 26◦. Find the
height of the tower.
Is 33 degrees an acceptable alternate of 033 degrees for a bearing?
033 is safer.People from my school have claimed that they were penalised for not including a 0. I don't see the difference between 033 and 33 anyway. 0 is null.
People from my school have claimed that they were penalised for not including a 0. I don't see the difference between 033 and 33 anyway. 0 is null.
People from my school have claimed that they were penalised for not including a 0. I don't see the difference between 033 and 33 anyway. 0 is null.The Study Design refers to "three figure bearings". Writing 033 meets this requirement.
linear programming having trouble with constaints and which inequalite to use ? please help my sac is tomorrow
The Study Design refers to "three figure bearings". Writing 033 meets this requirement.Haha now I'm worried about this a little.
Haha now I'm worried about this a little.
Is writing this enough?
I generally keep all my bearings in true? I hope that's sufficient o.o
Asking a question for a friend of mine :)
From a point, A, due north of a tower, the angle of elevation to the top of the tower is 45◦.
From a point, B, 100 m on a bearing of 120◦ from A, the angle of elevation is 26◦. Find the
height of the tower.
can someone help with this question?
Hi,
I need help with this question.
I have been given the matrix q and the matrix qrx and the question asks me to solve for x. How would I do this? I know that I have to use the inverse somewhere but if X and R are unsolved, how would I do this?
Here's the actual question.
Given Q (2x2) no from left to right, first row then second is -2,4,3 and -2. and QRX is (2x1) top to bottom -24 and 32.
Hi,
I need help with this question.
I have been given the matrix q and the matrix qrx and the question asks me to solve for x. How would I do this? I know that I have to use the inverse somewhere but if X and R are unsolved, how would I do this?
Here's the actual question.
Given Q (2x2) no from left to right, first row then second is -2,4,3 and -2. and QRX is (2x1) top to bottom -24 and 32.
They look good to me.
The only thing that i might've added is for the Coefficient of determination you could also say in the next sentence, "12.46% of the variation in arm span can be explained by other factors such as ......."
Not sure if it's necessary though.
Y-intercept:Wow, never seen a question asking to describe the y-intercept of a graph like that, but nonetheless could be useful to set out how you want to answer a question.
On average, Jane's final weight at the start of the weight-loss program, is 96kg.
^ Are these templates for such questions okay? Thanks!
Would the following explanations be appropriate (they're for linear regression): i've just used example figures.
Coefficient of determination
87.56% of the variation in arm span can be explained by variation in height.
Describing a relationship:
From the scatterplot, it can be seen that there is a strong, negative linear relationship between number of errors on a test and the period of time spent studying, with no outliers.
Gradient:
On average, the final weight of Jane decreases by 1.44kg for every additional day spent working out.
Y-intercept:
On average, Jane's final weight at the start of the weight-loss program, is 96kg.
^ Are these templates for such questions okay? Thanks!
Wow, never seen a question asking to describe the y-intercept of a graph like that, but nonetheless could be useful to set out how you want to answer a question.
If you don't like the term 'on average', you can use 'expected' for the gradient and y-intercept (I preferred and used these):
Gradient: The final weight of Jane is expected to decrease by 1.44kg for every increase in days working out by 1.
y-intercept: When Jane spends no days working out, the final weight is expected to be 96kg.
This is actually really important.
Just a quick questions relating to the further core, I got this in a practice exam and had no idea how to work it out:
"A set of bivariate data involves the independent variable x. The mean of x is 31.38 and the standard deviation is 5.38.
The other variable is y and the mean of y is 19.46 and the standard deviation is 5.46.
Pearson's correlation coefficient is -0.813.
The least squares regression line for this data would have an equation closest to:"
A) y=45.4-0.8x
B) y=0.8+43.2x
C) y=9.9-0.8x
D) y=0.8+9.6x
E) y=44.6-0.8x
The know the answer couldn't be B or C and apparently it is A but how do I work it out?
Hi,
In Matrices, if you are trying to find for example the number of people living in Town A after 3 years (against the number of people living in Town B, where there originally 100 in each town), so you calculate s(3) = T^3 * s(0), and say this comes to a matrix where there is exactly 95.5 living in town A and 105.5 living in Town B, how do you round?
thanks
Hi can someone work out this Number Patterns question and provide the working out? Will be grateful.
The sum of the first three terms of a geometric series is 57 while the infinite sum is 81.
The common ratio is
A. 1/3
B. 2/3
C. 1
D. 3/2
E. 12
Set up two equations:Thanks a lot.
1: Sum to Infinity -
2: Sum of 3 terms -
Solve these two equation simultaneously, for further just use your calculator.
and
I hoped that it didnt come to this, but i just am attempting to do practice exams on the modules i did at the start of the year matrices and networks, im all good with graphs and relations because i just completed it last week at school lol, however if i have forgotten around 50% of the module should i go over it again or just attempt practice exams and try and find the example in the textbook? OMFG its annoying when this happensI would go an try some challenging questions from your textbook related to your module, a refresher to the module, and then reinforce that revision with practice exams (which I personally think is good for trying different types of questions). If you do go and just attempt practice exams you may just end not learning as effectively if your foundation of the module isn't too strong, that's just what I think, find out what works best and stick with it and you'll remember the modules in no time =p
I've probably asked this question before somewhere, but now that I've finished the further course and it's the holidays, I might as well ask again. Do you think it's stupid to self-learn a module? I did business maths, and while it wasn't the worst module, I definitely struggled trying to identify what some questions were asking me, leading to confusion and marks lost. I've always wanted to study matrices, and I'm willing to spend some time these holidays on teaching myself matrices. I'm already familiar with basic concepts, with transition matrices being the main thing I need to properly learn. I'm also thinking of going to connect education for further, so if I do decide to study matrices instead I'll be going for matrices instead of business maths and using those notes to help me. Do you guys think this is a good idea? I just don't wanna risk majorly screwing up on the actual VCAA exam, which I feel will happen if I do business maths (because I've lost quite a number of marks in this module while doing past VCAA exams, and I can't afford for that to actually happen in the exam!)Haha, it always seems to be matrices that people want to switch into. =p
Thanks :)
I've probably asked this question before somewhere, but now that I've finished the further course and it's the holidays, I might as well ask again. Do you think it's stupid to self-learn a module? I did business maths, and while it wasn't the worst module, I definitely struggled trying to identify what some questions were asking me, leading to confusion and marks lost. I've always wanted to study matrices, and I'm willing to spend some time these holidays on teaching myself matrices. I'm already familiar with basic concepts, with transition matrices being the main thing I need to properly learn. I'm also thinking of going to connect education for further, so if I do decide to study matrices instead I'll be going for matrices instead of business maths and using those notes to help me. Do you guys think this is a good idea? I just don't wanna risk majorly screwing up on the actual VCAA exam, which I feel will happen if I do business maths (because I've lost quite a number of marks in this module while doing past VCAA exams, and I can't afford for that to actually happen in the exam!)
Thanks :)
Can someone please help me with this question?
I would say answer A.
We can see the median is roughly 22, and we know that about 68% of all variables lie within +/- 1 standard deviation. You can immediately cross out answers C-E as they are too far away from the median. Then out of A and B, A seemed the most likely.
Yeah, I agree with answer A.
It's because most of the values in a normal distribution lie within 3 standard deviations of the mean, and since the values in this case seem to end at 20 and 24, and the mean appears to be 22, we can approximate 3 standard deviations to be equal to 2 (22-20 = 24-22 = 2). Therefore, one standard deviation is equal to 2/3 (roughly 0.67). And then, since 68% lies within one standard deviation of the mean, subtract the standard deviation from the mean to get the lower boundary (22-0.67 = 21.33) and add it to the mean to get the upper boundary (22+0.67 = 22.67), so you get 21.33 to 22.67.
Thanks for the help, but just to clarify something, don't all values lie within 4 standard deviations of the mean? so why approximate 3?
And there's a formula for predicting the standard deviation in the essentials textbook; Sx=Range/4, in this case it equals 1.
Are we meant to use this formula? o_o
B as it says the first year it's $100,000 so we know the second is $108,000 third is $116,640 etc fourth is $125,971.2 etc... 13th is over $250,000
In Core,
If you are asked to describe the shape, would you say for example: positively skewed with a possible outlier - if you know it isn't an outlier, do you still say 'possible', and likewise if you know it is an outlier?
thanks
In Core,
If you are asked to describe the shape, would you say for example: positively skewed with a possible outlier - if you know it isn't an outlier, do you still say 'possible', and likewise if you know it is an outlier?
thanks
doesn't "possible outlier" suggest that it may not be an outlier?
If you can actually load your data onto the calculator and get a boxplot, it'll actually show whether an upper our lower outlier exists.
So, you'd say (if outliers present)
The distribution is positively skewed with an apparent outlier.
OR
if no outliers are present:
The distribution is positively skewed with no apparent oulier.
That would take up too much time in my opinion. Obviously, depends on how fast your are, but my guess is the average student won't have time to input data onto their calculator.
Guys just doing Networks, and this question is one that i always hate, Constructing a network
(http://i39.tinypic.com/jgi8wg.jpg)
those are the questions
but i never understand how to set out the vertices and where and how long to draw the edges,
haha damn you couldnt post the pic, what ya needa do is to go on tinypic through google and upload the photo and then just use the IMG link after you upload it and copy and paste it here, i have a few more pics to upload as i am struggling them with aswell lol.
thanks bro
haha damn you couldnt post the pic, what ya needa do is to go on tinypic through google and upload the photo and then just use the IMG link after you upload it and copy and paste it here, i have a few more pics to upload as i am struggling them with aswell lol.
thanks bro
hehe, ive got another question when drawing a network, from a Matrix representation, are you allowed to have edges crossing each other when drawing it out,
I have B->M thats one edges then it goes P->K which looks like a big X, is this allowed, i thought edges were not allowed to cross when drawing out networks?, because if they are allowed to cross i am gonna be pissed thinking all this time you were not allowed too
Wat the heck?, i was so convinced they were not allowed to cross and i didnt even know you were allowed to hack Vertices 2 go around 3 and end up joining to 4, this is why i had so much difficulty with this module, omfg omfg.
Hi if someone can help me to understand the answers and how to get there for the following questions from the VCAA exam, I'd be extremely grateful. The worked solutions are on Itute by the way. I know I'm going to look like an idiot since I've got a long list of what I don't understand but I think it's better to ask than just keep quiet so no judging. hahah. (I'm an arts kid so anything maths related is not my forte.)
VCAA 2010 Exam 1
Geo & Trig
Question 6 I got the first part 7.106 but I don't get how they got the value for TM.
Draw a triangle DTM where DT = 7.106 and DM = 5.5 since M is the midpoint of DC which is 11 long. Now, if you can calculate the angle TDM, you could use the cosine rule on triangle DTM.
Angle ATM + Angle ADT = 90 degrees. So, if you calculate the angle ADT using tan(ADT) = , you can then find Angle TDM and hence the length of side TM.
Question 7 I didn't know how to solve this. I think it was because I was looking for another measurement. Can someone explain how they got 38.8 degrees?
Angle CBD is on the right triangle CBD where CD id the side opposite angle CBD and CB is the adjacent side. Therefore you could use tan(angle CBD) = .
To do this, you must calculate the length BC from the right triangle ABC using the given angle and the given length AB.
Question 9 Why is the volume of water in the cylinder equal to the volume of water in the cone?
When full, the volume of water in the cylinder = where r = 30 and h = 24. This gives a volume of 22619.46…
If this is water is all poured into the cylinder, the water will reach a certain height, assuming that the cylinder is high enough and the water does not overflow. Use the formula for the volume of a cylinder to find the depth (or height) of water. Since you know the values of V, r and , solve the resulting equation.
Question 8 in graphs in relations I forgot how to do this. Can someone refresh my mind?
Let’s use a letter “w” replace for the time being. You can then think of the equation being like .
If we were to draw a graph of , we would have a vertical axis labeled “y” and a horizontal axis labeled “w”. On such a graph, if “y” = 27, then “w” would equal 9.
So look for such a graph among the five present, remembering that “w” really stands for . The graphs A, B, C and D all have (or “w”) on the horizontal axis but only graph A has a point where “y” = 27 when “w” or = 9.
VCAA 2011 Exam 1
Geo & Trig
Question 7 Why is QC double PB? Is there any other method of solving this? Would similar triangles work?
Triangles AQC and APB are similar. Since the length AC in the larger triangle is double the length of the corresponding side AB in the smaller triangle, then all lengths in the larger triangle will be double the corresponding length in the smaller triangle.
Question 8 Why is x/0.8? I know the addition part but I don't know how they got 0.5818.
You need to first identify similar TRIANGLES rather than similar trapeziums. Do this by taking a horizontal line from P across to cross the line TU at a point we’ll call V and then continue to meet the line TU at right angles at a point we’ll call W. You now have two similar triangles PVU and PXS to which you can apply similar triangle ratios. You cannot apply such ratios to similar trapeziums.
Question 9 Again I thought that I needed another measurement. Didn't think it was similar triangles. How did they conclude that?
Angles ABD and ACB are equal. Both triangles ABD and ACB share the same angle at point A. Since these two triangles have a pair of equal angles, then they must have all three angles equal and the triangles must similar. It is now a matter of seeing that side BD = 24cm on triangle ABD is opposite to angle A and must correspond with side BC = 40cm on triangle ABC.
Therefore, each side of larger triangle is times larger than the corresponding side of the small triangle and its area must be times that of the smaller one.
Question 9 in graphs and relations Why is it 5x-5y? Why does it have to be the same gradient as AB? How do you work the gradient for this?
It is not 5x-5y .
The answer is (E) M = 5x + 5y. This line will have the same gradient as AB with a gradient of -1.
By rearrangement, M – 5x = 5y and so which is a straight line with a gradient of -1 and a y intercept of . We need the maximum value of (greatest y-intercept of a line that touches any and all points of the feasible region along the line AB.
Finally if you have any suggestions on how I can understand questions better, feel free to shoot them at me. (:
Practice, practice and practice. Not only in doing many questions but trying to figure out how what you have learnt can relate to the question at hand.
You need to first identify similar TRIANGLES rather than similar trapeziums. Do this by taking a horizontal line from P across to cross the line TU at a point we’ll call V and then continue to meet the line TU at right angles at a point we’ll call W. You now have two similar triangles PVU and PXS to which you can apply similar triangle ratios. You cannot apply such ratios to similar trapeziums.You can't use the trapeziums because they aren't similar, not because similar trapeziums can't be used. In this case the trapeziums both share the same angles, but the ratios of the sides aren't equal, hence they aren't similar.
Wat the heck?, i was so convinced they were not allowed to cross and i didnt even know you were allowed to hack Vertices 2 go around 3 and end up joining to 4, this is why i had so much difficulty with this module, omfg omfg.I feel your frustration.
Business Maths - Do we round up to keep a situation logical or round down numerically?
For example:
The number of years required for $9,000 to double in value when invested at 6.3% compound interest, where interest is paid monthly is closest to -
A: 8
B: 9
C: 10
D: 11
E: 12
So I chose E. Solving for n in the compound interest formula will give you n=132.374 [months]. Converting this to years will give 11.0312 years. If only 11 years past, there will be slightly less than 18,000 so therefore there has to be 12 years for there to be 18,000.
So, in a VCAA exam, should I be rounding up or down? I know they are written a lot better than a lot of other companies, so how should I go about it logically? (Kilbaha said I was wrong in this particular question, I've had a few Neap like this which I've gotten wrong because they rounded down.)
Hey I was just looking through the key knowledge in the further study design for Core and I saw this dot point: Random numbers and their use to draw simple random samples from a population -
display, appropriately summarise and describe these samples.. What exactly does it refer to and how would it crop up in a question?
Hey what do you guys think about doing the VCAA exams pre-2006? I was thinking of doing those as well, since they're VCAA standard as well. For anyone that's already done further did you do these exams or just do other company exams? Also, do you think it's worth re-doing the VCAA exams? I'm doing/have done some VCAA exams already, from 2009-2012 and I was thinking of re-doing them closer to the exams under strict timed conditions and all. Is that a good idea or should I just expose myself to new exams instead?I started at 2006 and worked my way up to 2011 and that was enough. I did a minimal amount of company but I think if you learn from exams properly you'll have near no improvement to make by the time you're done with the VCAA ones and a few company ones. (Why did you start at 2009?)
Thanks :D
Fair enough :).. I started doing that in reverse so maybe that wasn't a good idea. I stopped at 2009 because I was doing from 2012 backwards in preparation for my internal exam at the end of the term.
Hi all, This relates to matrices on 2012 exam 2 last question 3)
here is the question, the question is at the bottom of the image. its really getting annoying to realise the last question is always the hardest lmfao.
(http://i43.tinypic.com/27wyq34.jpg)
When we are asked for a difference equation, how do we know when the initial value is t1, or t0?
For example
for this question i got, t(n+1)=0.95(tn)+30,000 t0=200,000
Just expanding on what Horacio said:
I like to just write down next to the question if the term they are giving you is like the first term of the sequence or the initial term before the sequence starts.
For example, from a VCAA exam a question was:
"A crystal measured 12cm in length at the beginning of a chemistry experiment. Each day it increased in length by 3%, the length after 14 days of growth is?"
I write down that initally the length is 12cm before any days have past, so the equation will be:SpoilerPersonally for this question, I wrote next to the question "after 1 day of growth, it will 12.36".
as you want the growth to happen 14 times (after 14 days), so in this case you don't use "n-1" as the 12cm is like the initial term before the first day of growth.
An example of the case in which you use "n-1" is:
"In the first month, the gardeners worked 625 hours. In the second month, the gardeners worked 500 hours. How many hours did they work in the fifth month.
Now we know the first term of the sequence is 625, so we have to use "n-1" or else we will generate a sequence after the first month. I wrote next to the wording there.
Hopefully that made some sense, I get so annoyed by the wording we get in some of the questions like "during", "after", "more". Or the questions when they want you to find how much "n" until one sequence reaches over a certain value.
For exam 2, is it required to show full workings + full worded sentences?For questions worth more than 1 mark, appropriate working out should be shown. If the question is one mark, then a correct answer will suffice (but working out is always useful).
When we are asked for a difference equation, how do we know when the initial value is t1, or t0?I get it from reading the question. It's really tricky, especially when they say "at the end of the 8th day", "at the beginning of the 11th day".
For example
for this question i got, t(n+1)=0.95(tn)+30,000 t0=200,000
Hi guys this relates to module 6 - matricesAll you need to find is the number of people who are expected to change their votes. 25% of the people who initially plan to vote for Rob say they are going to change their vote and 24% of the people who initially plan to vote for Anna will also change their vote. Rob has 5692 voters initially, but 25% will change and vote for Anna. Anna has 3450 votes initially, but 24% will change and vote for Rob. So in total, the number of people who change their vote is (0.25 x 5692) + (0.24 x 3450) = 2251.
could i get a solution to this please.
(http://i39.tinypic.com/34nodjk.jpg)
Pretty much I find the given information is the start of a sequence (like the first week, or first hour) then it will be t1. If the information gives information before a sequence takes place (like "initially" or "at the start") then it will be t0 - so in the question you showed, I would use t0.
Have a look at what I wrote here a few months ago:For questions worth more than 1 mark, appropriate working out should be shown. If the question is one mark, then a correct answer will suffice (but working out is always useful).Spoiler
Hey guys :)
Is anyone going to check their MC answers online on Friday Nov 1 after the exam. I have no idea whether I want to or not. I feel like its going to just kill me if I find I've made a multitude of errors, and ruin it for me, and that if I don't look up the answers, I'm going to CONSTANTLY be worried.
I was thinking of maybe checking one of the exams (possibly checking answers for exam 1). If I do well, it will be a MASSIVE confidence boost for exam 2; it sort of works out both ways.
Inputs would be great :)
I checked it after completing Exam 1. But the one mistake that one of my friends made, was wasting time circling it on the booklet that you get to keep as well as the MC Sheet at the same time. He should have done the whole exam first, and then copied it out, not at the same time - Otherwise you are wasting time and will not finish. He ended up guessing about 2 or 3 at the end (which isn't too bad), but its still costly marks. =/
So do the whole exam first, and if you have time at the end, then copy it over to your question booklet. :)
This is probably a really easy question, but how to you work out the std deviation from a histogram. Do i just count the percentages from around the median up to 68% and take an educated estimate?
For example Q3- http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2010furmath1-w.pdf
Also in Q2- Looking off the box plot it looks as though the IQR is 2, is there a mathematical approach to getting 2.7
Thank you in advance
Hello, I have a few questions:
1. Number Patterns
i) For the difference equation tn+1 = 2tn - 1, if t4=5, then t3= (my answer was 5, just unsure whether it is 1)
Is there a reason why the answer's E instead of A? Is it because Adjacency matrixes count degrees? I thought it was only for edges.
Loops count as 2, not 1. It's because you can go clockwise (which counts as one), and anti-clockwise (which also counts as one). But I remember my teacher last year saying something about Loops counting as 1. =/ Looking at the font, it I'm guessing its a past VCAA Exam question - what year is it from?
Great, now I feel mentally challenged. It's from Kilbaha 2011 exam 1.
Can anyone take me through question 9 for geo and trig
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2009furmath1-w.pdf
and can someone show me how shelley was right in question 9 for geo and trig
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2007furmath1.pdf
A square pyramid has a volume of 25m^3 (with a height of 3m).
The square pyramid is filled with foam insulation to a depth of one metre.
What percentage of the original roof space is now filled with foam insulation? Write your answer correct to the nearest whole number.
Thank you
edit; height is actually 3m ._.
quick question: Are Itute practice exams meant to be a kick in the face, similar to the Kilbaha ones?
Another one: Is it best to revisit some previously done exams, or best if you find/do other ones and struggle with them?
Yeah, iTute ones are a bit hard, especially for Geometry and Trig.
Yes, you should revisit past exams that you have already done, and re-do the questions you got wrong. Anything that you're still getting wrong should be revised thoroughly and may be added to your bound reference.
I haven't made and don't plan to make a bound reference. Is this an issue for me? I really, really don't think I need one.
Is it normal to struggle over their core questions as well? These Itute ones, golly they hurt my pride.
Redoing questions I've got wrong, thanks for the tips on that one. Thanks.
For Methods, its not really a big thing to have a reference, because I never look at it. However, for Further you will probably need to look at it.Geo/Trig, Number Patterns, Networks
What three modules are you doing?
Geo/Trig, Number Patterns, Networks
Nope.. never had to look at my textbook. I know all the number patterns formulas and same with trig (unless there are more that I haven't encountered yet). With networks.. there aren't really any formulas its mainly just applying logic. Oh I know where everything is in the textbook.
I should be ok without a bound reference.
Yeah I can apply them all well. I'm definitely taking my textbook, of course, I'm just uncertain about bound references. I tried making one but it's really, really.. really..... untidy, I think I'd spend majority of the time looking for formulas than actually applying them, so I think I'll probably just stick to my textbook.
I'm on my iPad right now so this isn't going to work too well, but I'll try anyway. :)My teacher said its 30%.. but I really don't think so, I (and another classmate) worked it out to be 70% too.
So you have a pyramid of height 3m and this "smaller" pyramid of height 2m. That gives you a k value of 2/3. Cube that (for volume) and you'll get 8/27.
So 8/27 of the pyramid is not filled up with foam. That means that 19/27 of the pyramid has been filled with foam. (19/27)*100 = 70% to the nearest whole number.
Maybe you'll see this a bit better with a diagram too. I hope this helps, and I'm sorry that my help has been a bit limited.
I had during 1996, as the result for the start of 1997 was 22106.81
Hey guys I've got a question!
I want to know how do you guys go over your mistakes and make sure you don't make the same ones again? (Silly question I know). I've been doing a number of practice exams and I find that it's always bearings and contour maps (trig) are the areas that I need to work on. Do you guys a) keep doing more exams b) look at the textbook c) do more questions from other resources e.g. Checkpoints, A+ notes and focus on those areas
I've been schooling for 13 years and I still don't know how to study properly....sigh :(
Hey guys I've got a question!
I want to know how do you guys go over your mistakes and make sure you don't make the same ones again? (Silly question I know). I've been doing a number of practice exams and I find that it's always bearings and contour maps (trig) are the areas that I need to work on. Do you guys a) keep doing more exams b) look at the textbook c) do more questions from other resources e.g. Checkpoints, A+ notes and focus on those areas
I've been schooling for 13 years and I still don't know how to study properly....sigh :(
Can I get some clarification on this question?0.5 * 32 * 10 * 6 = 960cm^3
I used 2 different methods and got different answers.
Question: A right angle triangular prism has a volume of 160cm^3. A second right angle triangular prism is made with the same width, twice the height and three times the length of the prism shown. Find the volume of the second prism.
Method 1:
0.5*h*w*l=160
hwl=320
new prism: 2h*w*3l=6hwl
6*hwl=960cm^3 (which is the correct answer)
Method 2:
Original New
let h=16 h=32
let w=10 w=10
let l = 2 l=6
Original volume=160
New volume = 32*10*6 = 1920cm^3
Why doesn't the 2nd method work?
Cheers
Hi,
To express: "For every eight x, there at least ten y" as an inequality,
would it be:
8x >(or equal to) 10y ?
i showed my teacher this, and she seems to think that it is 8x < (or equal to) 10y.
Thanks
how do you do Q4 of core for VCAA 2008 EXAM1
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2008furmath1-w.pdf
i got D. because the IQR = 90-20= 70 and the median = 35. thus median is half of the IQR.
Yeah I got D as well; never quite understood why it couldn't have been a right answer..I'll demonstrate why that is wrong through an example. Take the numbers 1, 3, 4, 5, 7, 8, 10. Median is 5, Q1 is 3 and Q3 is 8. IQR=5 => IQR/2=2.5
I'll demonstrate why that is wrong through an example. Take the numbers 1, 3, 4, 5, 7, 8, 10. Median is 5, Q1 is 3 and Q3 is 8. IQR=5 => IQR/2=2.5
2.5=/=5
Median=/=IQR/2
Furthermore, the median isn't the average of Q1 and Q3 e.g. in this case that would be 5.5 which clearly isn't the median. The median is the 50%ile value, but that does not necessarily mean that it's half the IQR or the average of Q1 and Q3. You can also look at skewed boxplots if you want to visualise this.
Yeah I got D as well; never quite understood why it couldn't have been a right answer..The mean is affected by extreme values and therefore will be much higher than the median in this situation. There are 7 outliers which will all push the mean up, while the median would stay lower.
The mean is affected by extreme values and therefore will be much higher than the median in this situation. There are 7 outliers which will all push the mean up, while the median would stay lower.
I guess D is feasible, but they want something conclusive. I don't think from a box plot we can conclude that it is exactly half of the interquartile range, it could be every so slightly off (35.5 seconds) and therefore D would be false. The scale makes it hard to see the specific times and also, time is a continous variable: the questions use "closest to" as it's impossible for us to determine an exact value, therefore we can find what's looks close to the IQR but it may not actually be.
It appears that the question required the application of BOTH the sin rule and cos rule..Yeah. True. I didn't explain it properly, I mean the second part of the question to get the angle.
question 5 in business maths : http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2010furmath1-w.pdf
how do you tell if its reducing balance depreciation or flat rate deprecation?Spoilerthe way i interpreted the question was that the server depreciated by 20% of its original value each year.
Hi does anyone know how to do the final network question n the 2012 vcaa exam 1 cause its doing my head in. Please help me, cause i feel like my heads gonna explode?
To achieve minimum number of days Lisa starts activity D after activity A is completed by John, then she does activity E. By the time activity E is completed, total number of days taken is 3+7+6=16
Then 16+5=21. Therefore D is correct. :)
I dont understand question 2007 exam 1 linesr graphs if maximum vlue of z occurs at thrle pploint (100,0)if you sub that point into the objective function Z=200. Now you need to test for possible values of k where (100,0) gives the maximum Z value. If k=1, Z=2x + y. Subbing all the co ordinates in you get that Z is still the maximum at (100,0). When k=2, Z=2x + 2y. If you sub in (100,0) and (50,50) you get 200. You only want one maximum at (100,0) so k must be 1.
Hey cuties,
Let's say I'm given quarterly seasonal indices for rainfall in mm of Summer, Autumn, Spring & Winter.
In terms of describing a seasonal index of ... for Summer, what would you guys use?
The rainfall in Summer is typically:
VCAA 2005 Ex1 q11: '% above the yearly average'
VCAA 2009 q4c: '% above the average for the four seasons of the year'
Most of the commercial papers I've done: '% above the seasonal average'
Essentials Textbook: '% higher than the quarterly average'
I'm a tad confused. Are they all the same/different? Anyone know/have evidence as to what VCAA expects?
Hope you understand the question.
Thanks A LOT!!! :)
For questions Jan-Feb, I talk about the yearly average.Monthly average?
Monthly average?
Hi, Have a question about seasonal indices.
'Given that the seasonal indices for winter and autumn are 1.41 and 0.92 respectively, then it is reasonable to conclude that'
D) Autumn sales are 8% less than yearly average
E) Winter sales are approximately 35% of the yearly sales
I thought that D would have been the answer, although the solutions say that E is correct,
with explanation:
Winter sales =
(1.41/4)×100=35.25%
I thought it would've been D, as I have an explanation in my book that says if the seasonal index is 0.92, it indicates a performance of 8% below the average.
Thanks
Thanks Yacoubb and Zealous! :) But then how come VCAA used 'yearly average' in 2005... Is that correct aswell?
And I've that question aswell, then I saw the VCAA papers so I was like, what? :(
And there was one question with seasonal index 0.8, to correct for seasonality1/0.8 = 1.25 Therefore 25% increase.
(D) increase by 20%
(E) increase by 25%
Answer is E. How?!
Trouble smoothing median question 4 please explain?Question 4 is about a time series plot.
thanks, but why do you use 2 behind and one above? since it is say median why do you.use mean smoothing?I did it from 1 below and 2 below.
In networks, when there are loops, it equals 1 from say A to A (point A has the loop), not 2? There was confusion with this at school. Thanks! 8)A loop in an adjacency matrix is recorded as 1!
In networks, when there are loops, it equals 1 from say A to A (point A has the loop), not 2? There was confusion with this at school. Thanks! 8)
A loop in an adjacency matrix is recorded as 1!
Also for 2012 Vcaa ex 1)
And module 5)
Q9) Why can't you just do B E H? After B is done, then so can E be done, then H > finish? Because after B is done, that allows D to be completed then simply H can be done too?
Does anyone know how to solve the median here? I know it's a tad embarrassing, but isn't it supposed to be 500 (6th point) + 450 (7th point)/2 =475? The answer says it's 440 with 430+450.
To achieve minimum number of days Lisa starts activity D after activity A is completed by John, then she does activity E. By the time activity E is completed, total number of days taken is 3+7+6=
Then 16+5=21. Therefore D is correct.
Cort, you have to write out all the numbers in order from lowest to highest and then find the middle of the 6th and 7th values.
Also for 2012 Vcaa ex 1)
Module 4)
Q9) How would you know to pick between A or C?
Hi guys just wondering, if I ace both further maths exams do I get a 50?
Thanks
Q9) How would you know to pick between A or C?
If there's a box plot with an outlier; and the question asks for the 5 point summary, do i include it as the max/min value or the end of the whisker?
;)
Thankyou ;D
My exam coordinator said yesterday further starts at 9am. This is a mistake right? It starts at 3pm yeah?
Range divided by 6. You see, this method could only be applied if your data distribution was approximately symmetric with no extreme values (or outliers).
For business maths.. struggling with reducing balance q's. :( From VCAA 2008.
Question 8
A loan of $300 000 is taken out to finance a new business venture.
The loan is to be repaid fully over twenty years with quarterly payments of $6727.80.
Interest is calculated quarterly on the reducing balance.
The annual interest rate for this loan is closest to:
A. 4.1%
B. 6.5%
C. 7.3%
D. 19.5%
E. 26.7%
Got a quick question =)
VCAA FM2011 Exam 1
Geometry and Trigonometry Q9
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2011furmath1-w.pdf Page 18
How can we be sure that triangles ABC and ABD are the similar triangles? or a better question: is there some way we can completely disprove the triangles ABC and BCD are similar (given we are given one angle and one side length)?
It does make sense that ABC and ABD would be similar, but when you look at BCD, with a bit of flipping etc. you can get a triangle that looks very similar to ABD, which sort of led me on the wrong track.
Angle ABD = angle ACB = thetaAwesome! thanks plato.
The angle at A is common to triangles ABC and ABD
ie angle ABD = angle ABC
Now that the two triangles ABC and ABD have two angles in common, it must mean that the third angle is also the same for each triangle.
ie angle ADB = angle ABC
With three angles in common, these triangles must then be similar.
Can someone please help me with this question? Crashing questions are my weakness :(
There are five paths.
BGIJ - 17
BDFJ - 18
BDCEHJ - 19
AFJ - 14
ACEHJ - 15
You could assume you cannot reduce J to zero but, if you could, it means every one of these paths is reduced by one and the critical path would be 18 long.
You need to reduce an activity on the critical path, BDCEHJ.
You can only reduce one of C, E or H by one hour, otherwise you make BDFJ become a critical path of 18 which means only a one hour reduction.
D cannot be reduced below zero and so you must reduce B which will also reduce paths BGIJ, BDFJ and BDCEHJ. But you cannot reduce these paths to be less than 15 which, if you did, is where ACEHJ would become the single, new critical path (and also activity B would disappear with zero time).
So – reducing B (and the project) by four hours will make two critical paths, ACEHJ and BDCEHJ, both 15 hours long. This is a four hour reduction and the answer is D.
Hey everybody, could i please get help with this exam
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2011furmath2-w.pdf
Q2) Graphs and relations about Mike's Hike, i dont understand the whole question
Thank you.
Hey everybody, could i please get help with this exam
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2011furmath2-w.pdf
Q2) Graphs and relations about Mike's Hike, i dont understand the whole question
Thank you.
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2010furmath1-w.pdf
Networks, Q6
How is the cut 23? I thought 5 was going in the opposite direction.
need help for core
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2010furmath1-w.pdf
Q7 and 8 please :)
need help for core
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2010furmath1-w.pdf
Q7 and 8 please :)
Question 7:
We can see that the relationship between the variables is positive-immediately cancelling out options D and E.
The dots are close to one another and in a completely straight line, so it cannot be A as a 0.98 shows a strong relationship.
0.23 is no relationship, but there is some sort of relationship between the variables, the dots aren't totally random in their placement! So that leaves us with B :)
Question 8:
Cancel E straight away as foot length is the x variable, not the y.
Pick 2 clear points that are on the line. For eg. (30,180) and (34,185) and get the gradient of the line using rise/run method ie y2-y1/x2-x1.
Get the c value (cause the line will be in the form y=mx+c) by subbing in another point say (28,177)
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2010furmath1-w.pdf
Number patterns, question 8.
How is it A? I thought if r>1 the graph should be positive?
Thanks :)
If the first term is a negative and it is multiplied by a positive number greater than 1, the result is a greater negative. Therefor the graph must decrease as n increases.
Maybe you are you confusing r (common ratio) with r (correlation coefficient).
There are five paths.Such a great explanation. Thank you.
BGIJ - 17
BDFJ - 18
BDCEHJ - 19
AFJ - 14
ACEHJ - 15
You could assume you cannot reduce J to zero but, if you could, it means every one of these paths is reduced by one and the critical path would be 18 long.
You need to reduce an activity on the critical path, BDCEHJ.
You can only reduce one of C, E or H by one hour, otherwise you make BDFJ become a critical path of 18 which means only a one hour reduction.
D cannot be reduced below zero and so you must reduce B which will also reduce paths BGIJ, BDFJ and BDCEHJ. But you cannot reduce these paths to be less than 15 which, if you did, is where ACEHJ would become the single, new critical path (and also activity B would disappear with zero time).
So – reducing B (and the project) by four hours will make two critical paths, ACEHJ and BDCEHJ, both 15 hours long. This is a four hour reduction and the answer is D.
Argh , still confused on Q9 of 2012 Ex 1 Networks.Time Activity Person
is this statement correct? If a graph can be rearranged to be planar, it is planar?
Thanks for the help
i dont understand how this question is 4 hours, i got it wrong when i did it in timed conditions, then i went and did it after i finished and got 5, i took the maximum time which is 19, minus by the minimum which is 14 = 5''
(http://i41.tinypic.com/2njvzug.jpg)
heres pic, apparently its D-4 hours
There is obviously room for ambiguity here. In a sequence that does not refer to t(n+1) or t(n-1), then assume n will start at one rather than zero.
Your first term would be t(1) = a = 41
If we are told to find the proportion of x after n days, and we end up with a matrix such as:
_ _
| 590.18... |
| 410.43... |
|_ 499.39..._|
Say we started off with 1500 in total at the beginning, rounding to the nearest whole number would only give 590+410+499=1499.
In this case, should we round up the value with the highest decimal so that 410 becomes 411, and we once again have a total of 1500?
And If anyone has MAV 2012 exam 2, how do you get Q3)a) of core? I just did a statistics table and used the given linear regression to get my y-values then i just applied reciprocal on those y-values and then sketched the new regression. Or am I meant to simply look at the given graph and its data and just insert in calc with plain eye?The data was given in Question 2. So take all the BMI values and find the reciprocal of each one, then fit a linear regression line to the sleep time and 1/BMI.
when asked to draw a regression line, do you need to only draw at where the points start and end of the original data ? Or are you meant to extend it so it hits the Y-axis and goes further than the most furthest x-value on the plot?Plot it like you're drawing a linear line. So you can extend (extrapolate) the line past the data given.
Hi tcstudent!
The graph is showing the distance Mike travels. During the hours where the graph is in a slope he's travelling at a constant speed, and where the graph is just a horizontal line he is stationary (as his distance is not changing.
a) Average speed is given by the total distance he travels/total time taken.
He travels 16km in 7 hours so, 16/7=2.3 km/h
b) The equation with the variables they want you to find is the equation of the second slope (between 3 to 7 hours).
You can use simultaneous equations to solve this.
The variables from the graph are t (for the x axis) and d for the y axis, (as the equation is in the form y=mx+c). So pick two points on the line, say (5,13) and (3,10) and sub them in to the equation. (Pick clear points so you don't have to estimate).
The two equations I got from these points are:
13=a5+b and 10=a3+b. Plug them in to your CAS and you get a=3/2 and b=11/2 which in decimals are 1.5 and 5.5.
c) I made a mistake with this one first time I did it.
Sketching the line for the distance traveled by Katie first is a good thing to do. This also helps with the next question!
The line intersects Michael's line at t=2. Therefore they meet at 2 hours.
However just to be super careful incase it's not like 2.1 or something, double check in the exam if you have time!
Use the equation for the first slope in Michael travels (d=5t, get the five from the rise/run of the line) and make it equal the the equation for Katies distance travelled.
Plug in 5t=-3t+16 into the cas to get t=2 hrs.
d) As you can see from the lines on the graph, the distance between Michael and Katie becomes 3km somewhere between 1-2 hours until they finally meet at 2.
So since the distance is the y value here, makes Katies distance-Michael's=3 to find t when their distance apart is 3
-3t+16-5t=3
solve on CAS, t=1.625
After two when they're moving away from each other, you can see just from the graph that at t=3, Katie is at 7km and Michael is at 10km from his destination, difference of 3km.
So they are only 3km near each other from t=1.625 and t=3
3-1.625=1.38 km
Hope that helps! :)
The data was given in Question 2. So take all the BMI values and find the reciprocal of each one, then fit a linear regression line to the sleep time and 1/BMI.
Plot it like you're drawing a linear line. So you can extend (extrapolate) the line past the data given.
Hey guys 2012 Exam 2 , Question 2B about some stupid weather LOl here is the question
(http://i43.tinypic.com/242bv39.jpg)
Question B
Hope it wasn't too confusing. I didn't even understand the question at all the first time I did it.
Hey guys 2012 Exam 2 , Question 2B about some stupid weather LOl here is the question
(http://i43.tinypic.com/242bv39.jpg)
Question B
I am currently doing business related maths. I own both textbooks of MAths quest and essentials but i find maths quest to be way to long. Just want to know which one you think addresses business related mathematics better?Isn't Business Maths in Maths Quest like ... 2 chapters? I don't think it is extremely long, just plan out how much you want to do when, and you should get it done.
Hi guys, when a question asks to plot the values, do you just put the points on the graph or do you drew a line through them?
For a scatter plot, you only put the values on the graph. You fit a regression line on the graph when they ask you to "fit a regression line on the graph".
Is there a way to find out when a matrix becomes a steady state??
as S1=TSo and S3=t^3 So and thus Sn=T^n So
is there a way to find out at what value of n the steady state appears?
why is the answer C? i square rooted the answer and it doesn't work because then you need imaginary numbers, so i took the square root and i got E
All the questions recently have been about modules I didn't do.. sigh o.o
can someone help me on this one, i have entered them in list 1 and 2 respectively and done lin reg, but my equation is different to that of the back of book. Can someone outline the steps
thats exactly what i did, exept putting x on x-axis and y on the y. I'm not sure how to do that, is it already set that way? I have casioclasspad 330I don't know how to use the classpad, but I found these instructions in the textbook on how to calculate the regression line using the casio classpad. I added in that question because the instruction relate to it, use this as somewhat of a template for answering your question :)
Hey, I've attached a question below and was wondering why the answer is E (1588)The seasonal index for Quarter 3 is actually 1.6
Thanks. :)
The seasonal index for Quarter 3 is actually 1.6
4-(0.65+1.1+0.65) = 1.6
Now you just divide the sales value by the SI ---> 2540/1.6 = 1587.5 = 1588 :)
arrggg those silly mistakes right! >:(
Haha yeah, frustrating! Thanks for that.
I've got another question.
Average no. of children per family in Denmark = 1.4
Standard deviation per family in Denmark is 0.3
Assuming the data is normally distributed, what percentage have less than two children?
I've got my answer as 97.5%, however the answer says its 98.5%. Is that a typo or am i looking at it wrong?
What's the difference between a seasonal trend and a cyclic trend? :|
Can someone help me out with this question I'm a little confused....
Thanks in advance!
I keep getting $3, is that what's happening to you?I have no clue how to do it to be honest haha! How do you go about it?
I have no clue how to do it to be honest haha! How do you go about it?
The answer is D ($2.75) though if that helps? That is the closest to $3 I guess?
Ok so first I used the points (100,170) and (0,20) to get the gradient which was 1.5, and I'm pretty sure the y-intercept is 20, so my equation was C=1.5n+20.
So I subbed in 80 for n to get the cost of making of 80 apple pies, which was $140.
Then since they made a profit of $100, they would have to have sold those pies for $100 more than what it cost to make them, so they sold them for $240.
Then I divided $240 by 80 to get $3 per pie, and it looks nothing like any of the answers D:
i know the 1/y reciprocal transformation is in the form 1/y=a+bx
i was doing doing part C and my equation was 1/y= 0.006+1x (1/y=0.006+x) and the answer has it as 1/y=x, i know the 0.006 is negligible but isn't the answer incorrect?
just a quick question in regards to residual plots. Say i did a x^2 transformation, i have x values in list one , y list 2, x^2 list 3 and residual values list 4 (casio class pad). When i do my residual plot, do i use my original x values or the new x^2 values and my residual values? i think you use original x? not sure, my residual plot always looks different to that of back of book when i try both variations
The only other way I can see you calculating the residuals without reading from the graph is if the question also gives you a set of actual values. Which you would then use to create a regression line. From there its simply the case ofCheers MagicGeko, it was a multiple choice question for my practice test and it was really hard to accurately pinpoint the co-ordinates of all the points :/ but looking through practice exam questions they all supplied a table of values :). When you are asked to use 3 median method and given a table of values, do you have to reorder the points so they're lowest to highest? Also, how/what do you analyse for percentaged segmented bar charts in order to get full marks?
residual value = actual value - predicted value
Though I am quite sure you won't be asked to determine the residual from the graph alone, especially if its hard to make out the points (I haven't crossed any questions that do this...well at least none come to mind).
And no they are not the same.
A log10(y) is called a log transformation whereas a 1/y is called a reciprocal transformation.
Basically they serve the same purpose, its just that the reciprocal transformation compresses the data to an even greater extent than the log transformation.
hope that cleared some things up somewhat :)
When you are asked to use 3 median method and given a table of values, do you have to reorder the points so they're lowest to highest?
When you're making a box plot from a frequency table that has classes (100- ,200-, 300-) instead of specific numbers, do you use the middle number like 100- would be 150 ?You have to estimate the 5 point summaries. This is a good video showing you what to do
how do we find the linear regression formula from a graph/scatterplot?
You have to estimate the 5 point summaries.
Okay, so if I'm using this table and it asks me to find the min-q1-median-q3-max of the high dosage group, would I just use the median ( ( Median = x) of the interval or the actual interval (Median = x - x)i reckon you use the midpoint of the intervals. I don't know if i'm doing it right but.. i think the median is (226+1)th number, 113.5th number, so its the 800- gram interval? And for Q1, its (113.5+1)th number, 57.25th number, so its 700- gram interval? And for Q3, its (113.5+1)th number, so 57.25th number but ABOVE the median, so its still in the 800- gram interval? Min=600- and max=1000-. i dont even know. What is the answer though?
Is the height of something considered to be numerical or categorical data?
Most likely numerical. It could be categorical if it was short, normal and tall or something but most of the time it's in cm
Nah, continuous. Cm doesn't have to be a whole number it could be 178.8586589754798548
I'm pretty sure if it's cm it will still be continuous even if they only have whole numbers
Yeah, a lot of teachers say different answers for shoe size, but it can be either, large medium small or in numbers. If they don't state which one it is in the question then they are wrong.
And I thought further would be my easiest subject....boy was I wrongDiscrete:
And I thought further would be my easiest subject....boy was I wrong
Don't worry! I think every Further student starts off thinking they're going to score 40+ with little difficulty. Most learn that this is not the case. Further is about perfection - if you don't perfect your work for Further, and minimise your errors, scoring high is not really possible. Good luck to you all though - just remember not to underestimate this subject.
That's exactly why I'm trying to get my head around it while it's still relatively early days
Don't worry! I think every Further student starts off thinking they're going to score 40+ with little difficulty. Most learn that this is not the case. Further is about perfection - if you don't perfect your work for Further, and minimise your errors, scoring high is not really possible. Good luck to you all though - just remember not to underestimate this subject.
Hi guys. This is my first ever post here so, I'm kinda new.
I've recently been given a practice sac from my teacher and I'm stuck on a question that requires us to comment on the shape, centre and spread of a boxplot. If someone could detail what needs to be said in each of those three it'd be much appreciated. Thank you.
Hey guys, I was wondering if someone could help me with the question attached.
Use this formula:
For y=a+bx, b=rS(y)/S(x), a=mean(Y)-mean(x)b
Where r is correlation coeff and S is standard deviation. So all you need to do is to sub the given values in.
So u should get b=-0.67, a=9.16. Therefore, the ans is A
just a quick question - i calculated my lower fence at it was 26%. the lowest score in a maths test out of a class was 26, is this considered an outlier, or does it have to be below 26?Lower fence? Um.. i never heard of that lol. To see if 26 is an outlier, you must use the forumula Q1-(1.5xIQR)< x<Q3+(1.5xIQR). Just because the lowest value is 26 doesn't mean it's an outlier. To find out outlier, you must have all the other information (Q1, IQR,Q3). You should get two numbers that x must be between, if 26 isn't between the two numbers then it is an outlier.
also what are some good resources to do when you have 3 more weeks until your sac and you've finished everything you have? I've done about 12 practice sacs , a+ , checkpoints all textbook questions don't know what to do to occupy myself for the next few weeks.
thanks
just a quick question - i calculated my lower fence at it was 26%. the lowest score in a maths test out of a class was 26, is this considered an outlier, or does it have to be below 26?
also what are some good resources to do when you have 3 more weeks until your sac and you've finished everything you have? I've done about 12 practice sacs , a+ , checkpoints all textbook questions don't know what to do to occupy myself for the next few weeks.
thanks
Lower fence? Um.. i never heard of that lol. To see if 26 is an outlier, you must use the forumula Q1-(1.5xIQR)< x<Q3+(1.5xIQR). Just because the lowest value is 26 doesn't mean it's an outlier. To find out outlier, you must have all the other information (Q1, IQR,Q3). You should get two numbers that x must be between, if 26 isn't between the two numbers then it is an outlier.
also what are some good resources to do when you have 3 more weeks until your sac and you've finished everything you have? I've done about 12 practice sacs , a+ , checkpoints all textbook questions don't know what to do to occupy myself for the next few weeks.
thanks
for the data, –1, 0, 3, 5, 7 the range is 8 either way you work it out, but in the further if the lowest data was -8, can the highest-(-)lowest change it to a positive sign?
Yea, i knew that, but it was just the way of thinking about it since you can't have a negative range. All good, thanks ;D
I seem to be a little confused.If I was asked for a 5 number summary, I'd be looking for the min, Q1, median, Q3 and max. Then the questions following may ask you to calculate other values.
Are the 5 summary statistics different to the 5 number summary?
5 summary statistics: median, IQR, Range, Mode, Mean
5 number summary: Sample min, Q1, median, Q3, sample max
Is this correct?
Thanks
calculate the GDP of a country that would be considered to have a GDP in the top 2.5%Top 2.5% means 2 standard deviations away from the mean, z score of 2. The z score corresponds to the standard deviation, so if you have a z score of 1.5, it is +1.5s. Tbh, im not sure if i answered your question when i dont really know what you're asking.
compare z scores of two countries
can anyone help me with these questions? we were just given random data and those question.
(for the 1st one) some people told me to use the bell curve. like, mean+2s others told me to rearrange the z score?
how to use the z score to compare data?
for example the question says to compare of australia (-1.04) to the distribution of GDP
disclaimer, i haven't started geo and trig yet (going off year 11 knowledge here), so could be wrong
basically to find how far O is from the chord, you want to find the measurements of that triangle within the circle.
if the radius is 14cm, we know that the distance from A to O is 14cm. and chord AB is 4cm, but we only want half of that (from A to the middle). so we know the measurements of the triangle are 14cm and 4cm. using pythag, you calculate 142-42, which gives you 180. the square root of 180 is 13.416407865, so the chord should be 13.42cm away from O.
i'm about to eat but i'll do the other ones and edit this post after i get back lol
oh whoops, i really need to proofread my posts. yeah, that should have been 22, thank you for that :P
as for question 13 a:
i'm going to use a lot of decimal values for each number here just for the sake of being more accurate, hopefully it doesn't make it more confusing
your calculator tell you that 8 square root 2 is equivalent to 11.3137. you can find that out just by typing it into your calculator and pressing CTRL+Enter. that lets you split the square into two triangles with the diagonal of 11.3137 acting as the hypotenuse. we know that a2+b2=c2, and because it's taken from a square we know that both a and b will be the same. so basically a2+b2 will equal 11.31372, which is 127.99980769.
127.99980769 divided by 2 is 63.999903845, which is both our a2 and b2 cos they're the same. remember that we need to square root these to find the length of the sides, so we end up with 7.99999399031.
now we can put the triangles back together, and we're left with a square that has sides of 7.9999939901cm. we want to find the area of the square, which has the formula of length2. so you take the value we found for the length of the side, and square it, which will give you 63.999903845. if you round up, that means the square will have an area of 64cm2.
hopefully that helped! tbh i think i might have used more steps than necessary, but i looked over it and i'm pretty sure that should get you the right answer. i'm not sure which textbook you're using but if you check the answers section i think it should hopefully be right haha. using that you should be able to solve 13b as well, cos it's basically the same question. if this explanation is too confusing i can try rephrase some of it :)
When doing transition matrices, how do you find initial state if it isn't given to you but the transition matrix is???I assume you mean question 7.
Here's the question attached:
Further Question Thread!
When a question asks to 'plot' points, do you draw a line through the points or not?No, you literally only 'plot' points on the graph. When they ask eg.'add a line of best fit' or 'sketch linear regression line' then you draw a line through the points with the given equation or line of best fit by eye. Read the questions carefully and if they want to fit a line in, they'll tell you.
hows this done
Can someone please explain question 1. d)
I can't figure out how to get those answers?
I got the mean to be 4.4 and the standard deviation to be 3.9??
Thanks in advance!
(Picture attached)
Upper Bound = greater value of the range
Lower Bound = lower value of the range
4km is 4,000m, which is 400,000cm. So on the map the length is (400,000cm)/50,000=8cm.Thanks, but I'm still a little puzzled, I believe I have been taught calculating contour map distance wrong because I was led to believe you just simply times the distance by the number to the right in the scale. So what I was doing was
how is Q9 drawn? i know the math, but when i drew it and tried to figure it out it didnt get the answer.The diagram for 9 even though it's a bit dodgy.
with Q13, how do i do it?
thanks
The diagram for 9 even though it's a bit dodgy.
Also, i think for question 15, from the top of my head it's using either the sine or cosine rule. I think you have 3 angles and a side (30cm) 105, 37.5, 37.5 (??). Im not up to the trigonometry module just yet and this is all the things i remember last year, so i might be wrong.
how do you draw this? if you want to figure it out as well its 110m.
Ive tried different drawings best ive got is 116m...
stuck on this for ages :(
someone help please
I'll have a try. What's a chord? And do I need to worry about it in this q?
Thanks
how do i do these 2? i dont think i got the diagram right.
thanks
Thanks for that Thorium :)
i also had these, how do i do 17a, i figured out 17b (after looking at answers for value of a).
And also 2d and 2e.
Thanks
I had a go with question 17a, i have attached the solution.
Can someone help me with part b.
Thanks.
Questions:
It might seem weird at first, but they've used that method in the first question. The determinant of the matrix they've given is 2*5 - 3*3 = 1, which gives us:
(forgive the bad notation, AN doesn't seem to handle [ and ] that well)
So, you don't really have two different methods, it's actually the one mentioned in the second picture. So, always use the method in the second picture if it's a 2x2. If you have a higher order matrix, find the inverse using your CAS.
For this, I'm going to introduce a notation you're probably not aware of, which comes from the methods curriculum - is the probability of A if you already know that B has happened. We can then put this into a matrix equation like so:Legend! Thanks so much I will look at this great explanation soon thank you so much :)
Remembering this whole set up can be a little annoying, so here's some tips - first, for the two column matrices, the one on the far right will always be the state before the one on the initial left, and the matrix in the middle is the transition matrix. To remember how we laid out the transition matrix, for , X will be whatever is in the left most matrix in the same row, and Y will be whatever you'd get if you multiplied the matrices out. If you can find another way which works for you, use that - the best way to remember this is whatever way works for you! :)
Now, to interpret this question. It says that 10% of the wagons that were at point A ended at point B - this means that . It also says that 8% of the wagons that started at point B ended at point A, this means that . So, this gives us the following matrix equation:
Now, here's something cool - the columns of any transition matrix MUST add up to one. Using this information, we can now complete the transition matrix, giving us:
Now, for part b, we're told that initially 125 wagons were at each starting point. So, we can now plug this into the far-right matrix (also called the initial state matrix, for this reason):
(note: if you know anything about probabilities, you'll know that they must be between 0 and 1. Don't worry, though - what I'm doing here is perfectly fine if you change those "Pr"s to "n"s like I did above - and it still works! ;) )
However, using this transition matrix only counts for one week, so in truth we actually have to apply it twice to get two weeks like the question wants us to. Using a CAS, this gives us:
So, 130 carts are at point A and 120 carts are at point B.
Part c is the same principle, but we don't have whole numbers to work with. So, we know that 40% start at point A, and that columns must add up to 100%, so we get:
But once again - the use of one transition matrix only counts for one week, and this questions wants to know about 6 weeks, so we have to use it 6 times, giving us:
Plugging this into the CAS, we get:
So, 51% of the carriages will be at point A, and 49% of the carriages will be at point B.
looking for some help on this one, answer is d
Hey how do you answer questions that end in decimal places but don't specify how many decimal places to answer it to, for example if the predicted number of passengers on a plane is 199.483 (answer from least sq reg line). Would you say 199 passengers, or round to 2dp?
Well... when it comes to stuff like that, just look to common sense. Are you really going to have a 0.483 of a person?Thank you! would that be the same for calculating the mean of the data?
If it HAS to be whole, round to the nearest whole.
If it ISN'T always whole, round to 2dp or as specified.
Re: Further Question Thread!oh cheers !
This question has already been answered in the link above. :)
Business Maths Question - help appreciated.
James and Jamie have just finished repaying a 5 year, $8000 reducing balance loan.
During the first year interest was debited monthly at 8.5% p.a.; during the next 2 years the rate fell to 8% p.a. but rose to 8.3% p.a. for the remaining period of the loan.
Before signing their contract James and Jamie were also given the option of fixing the interest rate at 8.25% p.a. (debited monthly) for the term of the loan.
By considering the total amount of interest that they paid, determine whether James and Jamie made the right decision in choosing the variable interest rate for the loan rather than the fixed rate.AnswersFixed: Interest = $1790.20
Variable: Interest = $1784.51 so correct decision is the variable, by $5.69
?
I'm not sure if I'm allowed to post here for questions that aren't math ones in a sense, but just wondering, when our sac marks are rounded, do they take the total of all our sac marks, proportionate it to a mark out of 100, then round, or do they round the mark of each sac to out of 20 or out of 40 for each sac separately? hope it makes sense :)
I'm not sure if I'm allowed to post here for questions that aren't math ones in a sense, but just wondering, when our sac marks are rounded, do they take the total of all our sac marks, proportionate it to a mark out of 100, then round, or do they round the mark of each sac to out of 20 or out of 40 for each sac separately? hope it makes sense :)
Hi,
Can a line of regression tell us if there is a relationship between two variables?
The scatter plot shows no relationship, and the regression line gradient is about 2, and r = 2.0
Thanks :)
Question relating to trigonometry and geometry.
The following diagram shows a cross-sectional view of a beehive with its regular hexagonal compartments.
Only shows one triangle within a hexagonal compartment and the base at 10mm
Determine the value of an interior angle of each hexagonal compartment, as shown in the diagram.
I put down 360/6 = 60 degrees, but this was marked wrong. How do you calculate this the right way?
Can someone help with this problem please? Ones in black pen thanks!These should both be done with a TVM app on your calculator.
Hi guys,First up, don't worry about using x. Just let RT = 1 unit long.
I worked out the right answer by using the sin rule, where the unknown (hypotenuse) is root 2 x over sin 60, the 'opposite' is x giving you E (if you let x initially be RT). However, considering that this could be 2 right-angled triangles, why can't you let x denote RT. Then from this you get RQ being root 2 x. As SR would also be x, then couldn't you use pythag to get SQ. However, this doesn't give you the same answer as the above (the correct one). Why not?
Hope this made sense!
Hey guys,I asked my teacher about this one, we did it a couple of times and in the end she told me it was an error from the book... but i did get 360m over and over again.
Not sure how to answer this, e.g. for 12 a)i I get 360 m, answer is 362m.
Isn't it just 2/2.4 = 300/x, or is this an oversimplification of the problem?
Hey guys,The view 300m from the window is 302m from where the girl is standing. If you use this distance, the answer is 362.
Not sure how to answer this, e.g. for 12 a)i I get 360 m, answer is 362m.
Isn't it just 2/2.4 = 300/x, or is this an oversimplification of the problem?
Hi guys,
If this is all the information that is given, would you be able to work out ST or not? Or do they have to give you angle SQT? Could you for example make a triangle PST and work it out from there?
I think since angles SQP and TQP are 90 degrees, SQT has to be 90 degrees?
So a pythagoras calculator should work.
Nope - we're working three dimensions here, and so the angle SQT could be anything.
I'd have to see the diagram to be absolutely sure, because if you have a regular hexagon, that's right.
Where did you get this question?
Question:
Joel invests $55,000 into an annuity at 7.8% interest compounding annually. After the interest has been added each year he plans to withdraw $6000 from this account to travel.
a) Using this formula A=PR^n - (Q(R^n-1))/R-1 (Reducing balance - annuities formula)
State the Q and R values.
b) How many trips would Joel be able to take before the balance in the account falls below $39,000?
c) How many trips can Joel make from this investment?
Hey guys. A question in my textbook about business mathematics has been bugging me and causing me quite a bit of stress. I've tried solving it the way the textbook says, but I keep on getting the wrong answer according to the book, so I figure it's either the example it used being wrong (I followed it exactly), or the answer itself. Two teachers have given me two different solutions too. Any insight would be great, because the SAC is getting closer and I am beginning to worry.It may happen in real life but I don't think there has been a further question like this. From what I can see, exam questions have all calculated and paid interest at the same time.
(http://i61.tinypic.com/2ljoxdu.png)
i know what you did but i dont get how that makes sense?
why do you multiply it by 5?
5w >= b would mean that at least 5 white loafs would be made for each brown?
ok that clears it up but with w >= 5b if we sub 1 we get w>= 5 however it says atleast so wouldnt it need to be w <= 5 or am i thinking of it wrong?
alright i get everything, i just dont get why you times the other letter by what your supposed (in my mind) to times the first letter by. if i have at least 5 loafs white bread for 1 brown wouldnt it be 5w >= b i just dont get why its 5b cause thats 5 brown?
How do you sketch a objective functions? for example C = 10x + 5y, with other inequalities such as x >= 0,, y >= 0,, x + y >= 8 ....
do we treat it as an equation to graph? or is it an inequality some how? (objective function)
thanks
Hi guys, need help.
How can you tell when the two coincide for the first time using numbers?
The answer is at the 24th bar.
I used my CAS to calculate each sequence up to their 24th bar, and when looking at the two numbers from either sequence I didn't see any relevance.
Thanks in advance.
Number patterns question. Solutions provided.Is there more information prior to this question? There seems to something missing, aside from the possible cause of Elmo's sex change during the question.
Can someone explain to me how they got they answer b = 5?
Also, their solutions figure out a = 0.90 by doing another method.
Is it acceptable to use the information that 'a' is found by "reducing usage deficit by 10% compared with the prev month", therefore a = 1 - (10/100) = 0.90?
Thanks in advance.
in a similar triangles question, if two lines are parallel what does this tell us and how can this tell us when solving the question?
Like with this question, i know how to do it, but being parallel does it help me in any way? does it mean i can/can't do a certain method ?
Thanks
thanks for that!! is their anything else you could add please?
thanks
Is it possible to calculate outliers using this formula (where o is potential outliers)
o < mean - 2*standard deviations and o > mean + 2 standard deviations?
I saw this in an Insight paper and just wanted to confirm it :)
Hi guys, apparently the answer is E… I don't get why?
Also does correspond mean the same thing as correlate in the context of explaining the relationship between x and y?
Well, they've given you a residual plot graph. For a linear correlation between to variables, 'x' and 'y', the residuals should be evenly spaced above and below the x-axis. That is, the linear regression line y=mx+c overestimates some 'y' values and also underestimates some 'y' values, leaving residuals.
In the graph they've given, the residuals aren't evenly spaced and there appears to be a pattern in the graph - almost like a quadratic. Because of this pattern, we can't confirm that there is a linear relationship between the variables.
so the equation of the graph given is y = x^2/5Yep, that approach is fine. So convert the graph into an equation, then see which of the options fits the equation. Though, it's highly unlikely you'll get a question like this on a further exam.
then do i go trial and error with the given graphs A-E? so the answer is D this is because when i sub the values in they give me the right y value. e.g. the equation is y = x^2/5 so if i look at D its, y= (5)^2/5 = 5 and the point is 5,5 which has been satisfied. is this the best approach?
Can someone please tell me how to do this question??? (VCCA 2013 Exam 1, Module 2)
Question 8
There are four telecommunications towers in a city. The towers are called Grey Tower, Black Tower, Silver
Tower and White Tower.
Grey Tower is 10 km due west of Black Tower.
Silver Tower is 10 km from Grey Tower on a bearing of 300°.
White Tower is 10 km due north of Silver Tower.
Correct to the nearest degree, the bearing of Black Tower from White Tower is
A. 051°
B. 129°
C. 141°
D. 309°
E. 321°
Hi guys
When a question asks you to comment on the shape, centre and spread of a distribution (3 marks), where would outliers fall under? Would you mention it under 'shape' or 'spread'?
Thanks :)
Hi guys,
This is a question from 2008 Insight paper (Matrices). My question is: is this right? Isn't the total profit calculated per store rather than per fruit pack? (Also there is an error for the profit for bulk, it is meant to say 52.80-33.00)
does anyone know how to fill in the table and how they got those values??You fill in the table by getting it to equal 5000 pairs of shoes. It says they need to make 5000 shoes per week, but they only make in the first 3, week(production) 1000 pairs,then they lack 4000 (deficit) as they don't reach the target of 5000. The second week, they only make 3000, they lack 2000 to get to target of 5000. For week 3, they make 3667, they lack 1333 to get to target of 5000. not really clear explanation but i hope you get it.
heres all necessary info attached. where b = 6,000
k = 30,000 and m=20
oh yeah that makes sense, thats really easy then haha. i completely didnt even notice that!! thanks haha, that mark was the only one i lost and i was like wtf is this, haha all good now, cheers :)Yeah just read the question carefully as it says "until capacity of 5000 shoes per week is reached".I have no idea how they got k and m as well.
Hi guys,For the first question, I think that putting aside the volume rise that ur confused with , that the gradients of the first line segments are incorrect for option d. This because the line segment doesn't become less steep(there is only a slight difference, which isn't really emphasised ) when the lady opens it 'partially' it still seems to be going at the same rate as the hot water which was 'fully' open . Thus ,putting aside that volume rise option d , cannot be the right answer, so that only leaves you with b as that option has a distinctive change in the slope , from when the tap is open 'fully' and 'partially'.
A bit confused with this question - Kilbaha 2014, Graphs & Relations.
I thought the answer is D because as the y-axis is in litres (not bath level) wouldn't the volume remain unchanged even after the child is placed in the bath? Kilbaha states that the answer is B as it will shoot up when the child is placed in, but we haven't actually added any extra water? :S
For the second attached qn, I interpreted "from 2005 and including 2005" as t=0 and hence 2020, as t=15. The answer requires t=16. Does anyone have tips on interpreting things like this, I seem to muck up dates and things like that :(
Thanks :)
Hi guys,For question 2, cliche but the only way to minimize that mistake is to read carefully. it says "including 2005" so you count 2005 as t=1. Just make sure when they say including, you count from there.
A bit confused with this question - Kilbaha 2014, Graphs & Relations.
I thought the answer is D because as the y-axis is in litres (not bath level) wouldn't the volume remain unchanged even after the child is placed in the bath? Kilbaha states that the answer is B as it will shoot up when the child is placed in, but we haven't actually added any extra water? :S
For the second attached qn, I interpreted "from 2005 and including 2005" as t=0 and hence 2020, as t=15. The answer requires t=16. Does anyone have tips on interpreting things like this, I seem to muck up dates and things like that :(
Thanks :)
Matrices multiple-choice question. Half an hour later... still can't work it out.The way I would go about the question is by using the simultaneous equation's techniques in matrices. Since u haven't actually said which is the answer I'm not sure if the way I did it is correct.
If A = | 1 4 1 | and X = | p | and AX = | b | then,
| 2 -3 0 | | q | | 2a |
| 1 0 0 | | r | | a |
A. r = b - a
B. r = a - b
C. r = -1
D. r = 1
E. r = a + b
with q6, idk what they did, i got C personallyWow , q6 is baffling , I got the same answer , I don't understand .
with q4 i got B, i dont know where the 4 x 6 came from? the question didnt make much sense to me there was something missing i think?
- i didnt do 1/2 lol
Wow , q6 is baffling , I got the same answer , I don't understand .
Which trial is it from ?
Also ,it reminds me of a VCAA question which was similar, however, the answer in the multiple choice were intervals so instead of having the exact value it said 'between 10 and 15' so I don't think they'll ask such a question, now.
But I am going to ask my teacher, u should too, its better safe than sorry.
with q6, idk what they did, i got C personally
with q4 i got B, i dont know where the 4 x 6 came from? the question didnt make much sense to me there was something missing i think?
- i didnt do 1/2 lol
The way I would go about the question is by using the simultaneous equation's techniques in matrices. Since u haven't actually said which is the answer I'm not sure if the way I did it is correct.
Firstly , my answer was option a, so if that's not the answer disregard my explanation.
So what I did is I acted as if my unknown were in matrix x (which it is ) , so the question itself does A*X=AX , to find X I did the inverse of A multiplied by the product matrix AX, so A -1*AX , this would give u the value of X .
Input in calculator and answer is the third value in the 3*1 matrix , which for me was b-1a which is equivalent to b-a ,meaning that the answer is a
I hope that helps.
As I said , if my answer was incorrect plz disregard it , and tell me so we can figure out how to actually do the question.
Thanks for the reply. Your answer was indeed correct as I found out today, so your explanation would be on the money.There is no need to substitute numbers , in fact you simply place the matrix calculations into ur CAS and it will give you the expression , which is option a .There is no need to over complicate the question (I should take my own advice some times, as I too have a tendency to do such )
Just one more problem I had.
When reading your explanation, you mentioned multiplying the inverse of A by the product matrix of AX. I went ahead and multiplied the two, substituting "b" with a random 1, "a" with 2 and "2a" with 4. I got 2, 0 and -1 for X. How did you figure out the answer was A instead of A or D? For A, b-a / 2-1 = 1 and then for D, a+b / -1+2 = 1, so I got the same answer.
why is this a straight line? (the cross section)
why is this a straight line? (the cross section)Technically, the line shouldn't be a 'straight' line, as the gaps in between the 2m intervals are not the same in length.
why have they said it has reached 60m? it in within the 50m contour lineI presume that the information before the question would have stated Z to be 60m high.
How do you differentiate between options A and C?
The answer is A, but I chose C as the balance of the loan reaches near 0 assuming that it has been paid off?
Thanks
Edit; also question 3 from the VCAA 2010 exam 1 (MC)
I've never seen a question stated like that before, how exactly do we calculate the standard deviation?
it doesnt mention anything along those lines?I don't.
so how do you know it reaches 59.99?
How do you differentiate between options A and C?
The answer is A, but I chose C as the balance of the loan reaches near 0 assuming that it has been paid off?
Thanks
If Peter hadn't missed the fourth payment than you would have been correct to assume that the balance of the loan reaches 0 at the end of 8-month period. However, as he misses the fourth payment, the amount of interest he pays over the duration of the loan increases. Therefore he does not fully pay off the loan at the end of the 8-month period as he initially predicted.Got it, makes sense.
Imagine 7% interest on $500 and 7% interest on $400. The interest on the sum of $500 is greater. This is what happens in this scenario. As he doesn't reduce the principal of the loan for a month, the interest accrued is greater than what it normally should be and therefore he doesn't fully repay the loan within the period he had initially planned. Thus the answer is A and not C.
If you need any further clarification please let me know.
What is the question asking us to do?
I'm finding the shortest distance (the pole will be perpendicular to the wall) at which it will hit when it falls.
By doing this I obtain answer E, however the answer is C.
So I think I may be misinterpreting the question.
Thanks in advance.
;also question 3 from the VCAA 2010 exam 1 (MC)
I've never seen a question stated like that before, how exactly do we calculate the standard deviation?
What is the question asking us to do?
I'm finding the shortest distance (the pole will be perpendicular to the wall) at which it will hit when it falls.
By doing this I obtain answer E, however the answer is C.
So I think I may be misinterpreting the question.
struggling with this question
struggling with this question
I believe this question was asked by someone else, but they never received an answer.The y-axis just seems to be mislabeled (perhaps due to the fickle nature of computers). Count the boxes (1 box = 1 delivery) and use that to find the median. Tedious, but that's about all I can suggest.
Thanks.
@ The person who asked the question which Billion has posted:The y-axis just seems to be mislabeled (perhaps due to the fickle nature of computers). Count the boxes (1 box = 1 delivery) and use that to find the median. Tedious, but that's about all I can suggest.Hey, thanks for taking the time to answer the question.
If you're still unsure...SpoilerThe total adds up to 49 deliveries.
Median should be th term. (Please excuse that type of notation.) Therefore, 25th value.
The 25th value is in the 3rd category or the 10-15 one. This eliminates option E.
Note that this is a histogram, where the categories are continuous...
which means that we use the mid-point of this category. i.e. midpoint of 10 and 15 = 12.5
I believe the answer you are looking for is C.
Please correct me if I am wrong, as I can't recall everything at the moment and have left my reference book elsewhere.
how do you know AM = AN do the 45 degree angles always mean this?
Hi, I got the correct answer, however the assessor's report says there was a "relatively routine computation"
I calculated the correct answer by extending the triangle. Is there another, more efficient method?
Thanks.
with the corner principle for graphs and relations, if they are all integers - say for a given context - is their ANY possible way to maximise the objective function from points within. eg. if corners are 1,8 6,2 and 1,2 , is there any way it can be 4,3 for example?
Hey man, this is how i do it, i dont think there is another simple wayYeah, that's the same way I did.
you like the colours haha? :)
Is it just me or did anyone find 2011 exam 2 quite hard? Geo and trig, matrices and graphs
I've been getting around 98/100 then got 91/100 and lost all marks on exam 2
Where did you lose your marks on it for? Perhaps you can separate it out and analyze your faults - make sure they never happen again. Looking over it I remember the lighthouse similar triangle question really was a bit tough.
Looking at the grade distributions. The A+ cutoff for 2011 exam 2 was ~84.2%, compared to an A+ cutoff of 85% last year. And then compared to 88% in 2012. So I guess you can conclude it was marginally harder than 2012 however compared to last years it was relatively the same. Maybe you did it in the wrong mindset haha, some exams I do I find I need to break and just get in the right head space.
where do you get the info about A+ cutoffs etc
i dont want to make another thread for this - but how many exams has everyone done ??
yeah i think that may have been it, ive just been doing heaps of exams lately, and 4th exam 2 of the day as well so i was fried haha.
would you be able to explain to me last question of graphs and relations http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2011furmath2-w.pdf
why they subtracted the equations and made it equal 3
cheers man
94 exams so far, yourself?
- ill be stopping exams tomorrow night so i can read over my notes and relax before the exam
as of this post 101, should be 106 when all done (the joys of being a year 11)
i don't really think it was worth it tbh
if anyone is interested i can post a full list of the exams i have done as well as the ones which i thought were actually worth doing?
seeing that you've done 94 is making feel better about my self now that i know im not the only one.
yeah would you be able to put a list together?theres no attachment, try again? or pop me an email with the attachment
i honestly reckon i should've capped it to around 50 or so, but then again year 11 advantages hahah :)
btw just a quick question, if you look at the attached. Say this question asked, what is the total revenue of the 203 hot chocolates, would i sub 203 into the second revenue one, or sub 200 in the first and 3 in the second
also questions like, mark has a fixed cost of 1000 and $10 for the first days, and $20 for every day after, find the equation that shows cost a after 10 days, how do we do this?
cheers
theres no attachment, try again? or pop me an email with the attachment
https://docs.google.com/document/d/1pYDO-7qCchz4XUaQetMT0ga2X7kdhRJ8Tee2BaeGNeE/edit?usp=sharing
this is also the order i did them in
a little bit of information about how i went about it:
our school did networks, graphs and relations and matrices
i did number patterns in gma and quickly ditched networks after the sac
i dropped marks on 3/5 sacs (2 on bivariate, 4 on networks, 1 on matrices), but other people dropped more (networks lol), meaning i finished as number 1
i finished the course over easter, then finished it again in the winter holidays. i did 1 paper a day starting day 1 of term 3.
would i recommend doing the same? definitely not. id only do vcaa, mav and select papers from neap if i was to do it again.
Damnnnn. That's impressive. Both of you. If my school had offered further in year 11 I would've definitely done it. Feel so emasculated only having done like 25. I do maybe one every two or three days - I find them so damn repetitive ugh. Plus I've done all the commercial ones offered by my school - maybe excluding 1 or 2. But yeah I've done like 35 methods in total, 35 physics in total - coupled with like 15 singular essays. Oh the joys of year 12.
Also Liquid you didn't attach anything =/
Both these questions are from the VCAA 2013 E1 (Module 3)
Q8) Don't understand it at all...
(http://puu.sh/cokKR/eb95b3b0e5.png)
attached it sorry - forgot about it.
and anyone want to explain the last graphs and relations question, http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2011furmath2-w.pdf
i dont know why they minused the two equations and made it equal 3?
Okay so this question. They're asking you to find WHEN they're 3km apart. To do this we can create an equation to find the distance between them. We can do this by subtracting the equation of Michael's Journey from Katie's journey. It's kinda hard to really articulate without printing this out and doing it via hand but I chucked them into CAS and found I have to use Michael's first journey equation.
We can conclude that if we subtract the distance of Michael's first journey from Katie's journey we will have an equation for the distance apart.
So dissecting this you can see we are subtracting the distance of Michael's first journey from Katie's journey and then equating it to 3 (Trying to find when the distance between is equal to 3)
BUT All we have found is when they are first 3km apart - now we need to find when they are last 3km apart. Now if you were to draw Katie's journey onto the graph given you'd see it is approximately 3km away at t=3. So we know it is approximately at t=3. To confirm we are going to have to subtract Katie's journey from the journey of Michael (This time it is rather easy as he's not moving so d=10 is the equation).
Dissecting this you can see we subtracted Katie's journey from the journey of Michael at t=3. Solving this:
So we can conclude they were first 3km away at 1.625km, They continued to get closer and closer and finally were 3km seperated again at 3km. So for 3-1.625 their radio transmitters would work.
Not gonna lie - this was a wierd question, first time I've seen something like this in a further exam. I guess it shows that only 3% of people got full marks for question 2.
When using random samples in exam 2, do we write CAS speak to show the working out? As in first I'd allocate each sample a number, then could I say
Menu, Prob …..?
why is abd and dcb not similar?Only one angle is the same - you have no proof they both have another angle the same, so you cannot say that they are similar.
ok that makes sense.
just a few more questions in the course
1) if its not a transition matrix what makes it different to a transition matrix, other then columns adding to 1? can it be raised to a power for steady state? etc..
2) what essentially does Sx mean other then the spread around mean, is there anything too add? how can it be affected?
3) a quick question, if you look at the attached. Say this question asked, what is the total revenue of the 203 hot chocolates, would i sub 203 into the second revenue one, or sub 200 in the first and 3 in the second
4) also questions like, mark has a fixed cost of 1000 and $10 for the first days, and $20 for every day after, find the equation that shows cost a after 10 days, how do we do this?
and how does this work??
how can you square it?
and also this. why dont we use m = y2-y1/x2-x1 this seem to work all the time?
heres the triangles, do you mind shoing me how they can be flipped etc so they are in same positions
with the spped/ d/t
i use the m = y2 ....
0,0 and 15,6 gets me a gradient of 6/15 = 0.4, not 24?
edit: dw figured out the 24km/hr part didnt see axis had min
First line is from the fact that they're similar triangles (I'd need to see the triangles to explain why), the second line is just a cross multiplication of the first line.
thanks euler!
just a question, could you please clarify this again
thanks
can someone provide me with the reasons we smooth data? reduce all variation? seasonal only? etcc
can someone give me a constraint for this and tell me why its that.
i originally got 3g is less then or equal to p, this is wrong
yeap sorry!!
Help please!
Could someone help with Q3? I got E, from tan^-1(226/210)
Got a Multiple Choice question I couldn't figure out.
A regular pentagon, ABCDE, has all sides equal to 8cm. The length of EC is closest to: (The triangle is at the top half of the pentagon, thus forming a triangle with 8cm on the left and right upper sides)
A: 13cm
B: 16cm
C: 17cm
D: 22cm
E: 26cm
I got the right answer but later figured out I mistakenly used Pythagoras, so now idk. Thanks heaps :)
Help please!
Could someone help with Q3? I got E, from tan^-1(226/210)
Got a Multiple Choice question I couldn't figure out.
A regular pentagon, ABCDE, has all sides equal to 8cm. The length of EC is closest to: (The triangle is at the top half of the pentagon, thus forming a triangle with 8cm on the left and right upper sides)
I got the right answer but later figured out I mistakenly used Pythagoras, so now idk. Thanks heaps :)
Thanks guys! I got one more if you guys wanted to help, its from the engage free exam, I tried to use the gradient to find b and c, which gave me answer D in the end, but that doesn't work because c-b=5.
Dam looks like everyone beat me to them all. Whatever I got good practice out of it.This is exactly the attitude to have! ;)
IMMEDIATELY dump c and d, since the subtraction won't give 5.
So, we're stuck with a or b. Well, distance is the same at times b and c, so equate and solve:
So, the answer is a.
Thank you!! copy and pasted right in my ref book!
Wait...you still have room in your reference book?
Wait...you still have room in your reference book?
I had over 100 blank pages in mine when I walked into both my methods and specialist exams - and by that, I do mean 100 pages each. :P
my bound books about 600 pages, about 3-4 books together stuck by gaffa / electrical tape lol
Another question - 2012 MAV Exam 1
I thought that the way to work out these question was similar to 2011 VCAA - so you do (for Labour for example) 0.2 + 0.2 = 0.4 * 300 (initial) to work out how many people change and then do the same thing for the 2 others, giving you D not C…
i think i have asked this before. But if it is not a transition matrix what makes it different to a transition matrix other then columns adding to 1. is their still a steady state solution with a non transition matrix? what else is not a feature..I don't entirely understand your question but a transition matrix must be :
thanks
Another question - 2012 MAV Exam 1
I thought that the way to work out these question was similar to 2011 VCAA - so you do (for Labour for example) 0.2 + 0.2 = 0.4 * 300 (initial) to work out how many people change and then do the same thing for the 2 others, giving you D not C…
well if you look in the matrices section of this exam http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2010furmath2-w.pdf
they give a matrix G, not a transition matrix, but it seems to have a steady state (in response to part D), hows this possible?
well if you look in the matrices section of this exam http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2010furmath2-w.pdfWhoops never realised that , so now I'm confused ??????
they give a matrix G, not a transition matrix, but it seems to have a steady state (in response to part D), hows this possible?
hey guys,
so I've heard if you square the one step dominance you get either the two step or the final dominance? is this true?
just a quick year 7 question. If a question says this is in $'000s, does this mean something that is 17.3, is in fact 173 000 ? or 173 00 ? just a bit unsure. And how are we meant to enter it and express is, in the 173000 form or 17.3 form ? this was on one of the vcaa exams in the past so just clearing up on it.Well, the question would be saying that the numbers given are in thousands, so 17.3 would correspond to 17,300.
I just wanted to know, do I have to do the same modules on both further exams??
or must i complete the same set of modules on both exams.
I used my calculator to work out the number of votes for each party on election day.
Next: 300-210 = 90
250-200 = 50
140-100 = 40
Next: 90+50+40 = 180
Therefore 180 votes were changed by election day, so the answer is C.
Does any know if you can use your calculator during reading time?You cannot. This should also be highlighted before the exam begins.
Goes with out saying - someone remember to come home and scan a copy of their answer book (your highlighted answers don't matter)... That way a few of us can confirm the answers for all of the modules and get an answer set up :).
are we allowed to look at our summary book during reading time?
Sorry, stupid question but I just want to be sure
are we allowed to take in 2 calculators?
alright thanks. quick question, i know how to solve this by finding all the equations, vertex points etc, but ive been seeing you can just use the gradient, can someone tell me how this is done?I only solve them through finding vertices then seeing which fits. I don't think you can use gradient?? Well if you can, stick to what you know! good luck mate!
thanks
Sorry, stupid question but I just want to be sure
are we allowed to take in 2 calculators?
Pretty sure you can take in a graphics (CAS) and a scientific calculator.
This is true, but reminder that this will take up more space on your table.
I have taken this excerpt from VCAA's website (http://www.vcaa.vic.edu.au/Pages/vce/exams/authorisedmaterials.aspx):
"Further Mathematics Examination 1:
-one approved graphics or CAS calculator or CAS software and one scientific calculator
-one bound reference that may be annotated
Further Mathematics Examination 2:
-one approved graphics or CAS calculator or CAS software and one scientific calculator
-one bound reference that may be annotated"
So does that mean one or the other?
In the exam can u choose any three modules plus core, or are they set school by school on which modules you must complete?
Is it possible for anyone to upload the exam with suggested answers?
Although I should give it time, I know we're all eagerly worried about the exam... :)
for core, the categorical data question q4, is the answer 3 or 4?
for core, the categorical data question q4, is the answer 3 or 4?3. Sex, type of car and postcode.
3. Sex, type of car and postcode.
Shit, i said two, didn't know Postcode was categorical.
One of many. I also did this :(
what wll i be looking at with rank 3, exam 1 37/40 - 2 really stupid mis read questions - and 60/60 exam 2? study score..Mid to low 40's, depending on the cohort strength and cutoffs for exam 1
Can someone help me with matrices question 6 from the multie choice exam?(i) referred to the number of the row, (j) referred to the number of the column and when the 2 numbers were added they would equal to the number it was representing, for example row 1 coloumn 1 should be representing the number 2 as 1 plus 1 clearly equals 2, as well row 3 column 2 would be 5 as 2 plus 3 equal 5. I hope that helps :)
Ok, for exam 2, when we are dealing with questions that have a) b) c) d), in Geometry and Trig, if we find the answer to say question a) which gives an answer of root 2, but wants it to one decimal place, so we write 1.4 cm, then if in the next part b) they ask us to calculate something that requires that length, do we use 1.4 (the answer to part a but rounded to 1 dp) or do we keep using root 2? For example in the TSSM 2014 exam paper it seems they have used the rounded answer for further calculations instead of the actual answer.If it says "using your answer from part a, find..." Then you would use the rounded answer, exactly as it is written above. Otherwise always use the exact answer, such as root 2.
Thanks, and What about in a show that question? because people who don't get it will have to use the rounded answer?If it's a show that question then I would say use that, because technically you have been given the exact length by the exam writers, so you should use that in any calculations you do.
Thank you! I have one more question if it isn't too much of a bother! If they ask us for the mode of a set of data values, but there is a maximum frequency for two data values, do we say both of those values are the mode, and/or state the data is bimodal? What if there are 3 data values with the same maximum frequency? Or would we say there is no mode?List all of the values that are equal most frequent, if there is more than one then list more than one. Not necessary to say that it is bimodal, but you wouldn't lose marks by doing so.
When we're required to give rounded answers, do we first have to indicate something like x = 35.235... ≈ 35.24No need to show the approximation symbol. They won't be picking on you for that sort of stuff. Just make your final answer very clear with an underline or box.
or can we just say x = 35.24 and do we actually need to use '≈' ?
For 'show that' questions, do we need to write formulas out?"Show that" questions: show a crazy amount of working out to be safe. Don't risk showing too little, you won't be penalised for showing too much working out. So if it's geometry using the cos rule to find a longer length, show each step of the working out (use less calculator). See http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2009furmath2-w.pdf Geometry and Trig Q3a,b for some "show that" questions (not sure if they're in other modules); then see the assessment report to see what steps were necessary.
'Approximately symmetric' and 'normal distribution' mean the same thing right?Yep. They both refer to bell curves in further.
just a question say i found the answer to length AD to be 37.44 and answer says to nearest metre so i write 37m. In the next question it ask me to find BX, and to find BX i need to use AD, do i use the 37.44 or 37?
On the 2012 Vcaa further maths exam 2,
On the core section, question 4a.
I got (ws3.00pm)^2 = 3.3 + 0.5 x ws9.00am.
However, it's wrong. The answer is: (ws3.00pm)^2 = 3.4 + 6.6 x ws9.00am.
I triple checked the variable that i placed in my CAS, however i still got it wrong....
someone please explain!
Thanks :)
I know what you have done wrong, quite a silly mistake, but it happens. When selecting "Calc" and "Linear Reg" make sure the correct list for the transformed variable is selected, the answer you got is from the normal variable not the transformed variable.
I dropped 3.5 marks in my sacs out of 80, I'm equal second in my cohort the top 4 are two marks apart most people will be aiming for 30-35 and there are 8ish out of 70 kids aiming for 40 most should get it, is that a strong cohort? I aced multiple choice if I ace short answer what could I expect to get? Any chance of a 50?Dropping 3.5/80 is a low-mid range A+, so chances of a 50 would be slim, but high 40's is still very achievable.
How do you know when to round up or down? because in a matrices module, it was 331.25 but they rounded down, this was about trouts so you can't have .25 of a trout. Another question in the graphs and relations module, was referring to students, 42.22, i rounded it to 43 but the answer was 42... help!General rule is when the decimal is below .5, you round down, if it's 0.5 or greater you round up.
Does anybody remember if for 3c where they ask max amount of tomatoes to ensure no loss, did they ask you to round to nearest whole kilograms? I don't recall reading that part so i left the answer as 15.2
Will someone be uploading exam 2? + Solutions?They're up, in the exam discussion forum.
What SS can I get for:Please note there is a separate thread dedicated to this in the exam discussion forum.
SAC: 99.7/100 (Rank 1) (Average cohort about 80people)
Exam 1: 38/40
Exam 2: 57/60
Can anyone confirm wether or not the values of 58 and 60 are outliers or not. The textbook says they are but i dont think they as the upper fence is 61, thus there inside it and not considered outliers.
Is there any other information for this question?
Can someone please explain how to do part viii of this question!?
A nice logic question. If you aren't familiar with the 68-95-99.7% rule, refer to this picture. You'll see that 95% of values fall between two standard deviations of the mean, and so 5% are outside those two standard deviations. By symmetry, we know that either "tail-end" should have 2.5% each. Now, we want to know the score such that 97.5% will score higher than it - so we need to start counting from those tail ends. So, we start with the 2.5% after 3 standard deviations. Then, we add the 95% from the above diagram, and we'll get 97.5% (alternatively, you could've added each segment - ie, gone to +1 sd, then 0, -1sd, -2sd).Left the question for a while and came back to it....omg I can't believe how simple the question was yet I didn't get it haha! Thanks heaps for the explanation as well EulerFan!
So, 97.5% of people will score ABOVE 2 sd below the mean, which is 100-2(15)=100-30=70.
omfg eulerfan, you're HERE aswell........ everywhere i go! :P
Hey can someone please show me where they get the seasonal index of 1.30 from in part 2 of example 12. Background info to the question is in the other attachment. Thanks!
This may seem like a stupid question but, for the bound reference, can i use a book with a spiral spine if it does not have perforated pages??
Just want to make sure I'm doing it right from the start
Thanks :o
This may seem like a stupid question but, for the bound reference, can i use a book with a spiral spine if it does not have perforated pages??
Just want to make sure I'm doing it right from the start
Thanks :o
A table of values for against is as shown.
Given that , find values of and .
Thanks!
When y=4.2, x=1, so:
y=kx^n ===> 4.2=k(1^n) ===> k=4.2
Welp, that was easy. Now, when x=2, y=33.6:
33.6=4.2(2^n) ===> 2^n=8 ===> 2^n=2^3 ===> n=3
So, n=3 and k=4.2
Note that the last step might prove tricky for the average Further student - solving 33.6=4.2(2^n) with a CAS is absolutely fine. You could also solve it using a simultaneous equation solver on your CAS, but mine didn't like that for whatever reason, so you might get a similar issue.
Make sure you don't tab the pages. I was told that as long as they can't be removed that I could have them. Unfortunately, they wouldn't have any of that and I was forced to cut mine off, minutes before go time. >:(
Keep getting C answers says D can someone explainSpotted:
Spotted:i was using the sum equation thats why i was a bit confused. Cheers for clearing that up for me
Striped:
So the question is asking for the year when the number of striped is twice the number of spotted. Thus, equate them as so:
Solve for n;
Can somebody answer this in a SAC style answer so i know whats required.When the data isn't numerical.
When is it not appropriate to set up an Ordered Stem and Leaf Plot for a data set?
When the data isn't numerical.
How reliable are these z scores for interpretive purposes?
I believe the first box plot is positively skewed because most of the data is found at the beginning of the plot. The second box plot should be approximately symmetrical as the data is evenly distributed throughout the plot. The outlier is included in the range calculations
Would the first (blue) one be negatively skewed, how so would it be positively skewed?Because the median drifts to the positive side of the IQR.
Because the median drifts to the positive side of the IQR.
Question:a) implies continuous data
The number of goals scored by the gal attack each week for a netball team would be best represented in a:
a) histogram
b) frequency diagram
c) frequency polygon
d) pie chart
3) cumulative frequency graph
What is the difference between options a), b) and c)?
(a) is correct
Currently in class we are doing the Geometry and Trigonometry module.
I didnt quite understand how to do this textbook (Maths Quest) question (based on the sine rule)
The answers :
a.)129.1 degrees
b.) 68km
Thanks! :)
Thanks EulerFan101!to quote MathIsFun (very useful btw):
:)
Also, can anyone please explain the difference between a vertex and an apex? Thanks!
Apex=The point (vertex) furthest from the base of an object.
Thanks EulerFan101!
:)
Also, can anyone please explain the difference between a vertex and an apex? Thanks!
I have a transition matrix diagram question:
In a transition matrix diagram do you have to label a loop around a point, with 100%, if there is no transition away from that point? E.g A proportion of 1 of the people at A will be at A after the next transition...
If you do not label the 100% loop on the diagram is it still technically correct or not? Because to me it seems redundant however I can also see why it should be there.
how many decimal points do we round answers to if it is not specified?
how's to prepare for further math first SACs ? ;)
In a further core sac are we suppose to draw residuals/ scatterplots and all those other charts accurately? It just seems too time consuming tbh
I'm just not getting this 'without solving for the pronumeral, solve this equation' stuff..
This probably looks like child's play to you guys but could someone please show me how to do this (with full workings)
If 6a=2a+10, find the value of 13-2a without solving for a.
:'( Thanks
in my textbook it says
in a negatively skewed boxplot, the median occurs further towards the right end of the box & left tail is longer
and in a positively skewed boxplot, the median occurs further towards the left end of the box & right tail is longer
but
i saw a facebook post
https://www.facebook.com/photo.php?fbid=969678223063087&set=gm.431048803739825&type=1&theater
if you can't see it, the image is here: https://fbcdn-sphotos-b-a.akamaihd.net/hphotos-ak-xtf1/v/t1.0-9/11068300_969678223063087_3082187454809633619_n.jpg?oh=6683a0ed2ec77dced1089faf04e17683&oe=556FDC74&__gda__=1434052399_0a8b94eb1f21a4a3a4559be9324620dc
the comments are all saying it is positively skewed
but, the median is towards the right of the box, which is not a characteristic of positive skew (according to textbook)
so
is my textbook wrong
or is the boxplot not positively skewed & are all the comments wrong
lol
I've just received the results for my first Further Maths SAC. It was on Graphs and Relations (it was out of 40) and I just have a question on how my marks will be conveyed to VCAA. Hypothetically speaking, let's just say I got 97.5% and the SAC accounts for 20 VCAA marks. Of that how many VCAA marks would I get? 20? 19.5? Is it in the same ratio. For example is a 36/40 equivalent to 18/20 VCAA marks?It entirely depends on how your school has structured your SACs.
Hi ALL!
What would i comment on this box plot. it is from chocolate sales in one month. I get confused with what to say. Other than the skewness my teacher has said to relate it back to the scenario in this case it is cholcate production but how do i relate it ???
What's the range of sales? How about the median? What does the median suggest? Any points in there that we can't really consider? Why/why not? How spread out is the data? What does this suggest in the variation of chocolate sales each month?
The data is a positive skew. The range of sales varied from 355 to 601 with one massive sale in chocolates with 906 in sales.
What does the median mean in a sales in a situation like this ? Would it mean most of the sales was at around the 461.5
Can anyone explain how you get the answer in Question 5 of vcaa Exam 1-2005? Thankyou!
Can anyone explain how you get the answer in Question 5 of vcaa Exam 1-2005? Thankyou!
Hey guys.
Reality is: you just have to take in the actual table properly.
One variable you need to omit. Try and have a guess as to which on it is!Then figure out the direction the no. of mobile phones are going:SpoilerText messaging use is kind of useless in this one.Then multiply the x value (no. of phones in a household) with the y value (the amount of households with that no. of phones.)SpoilerSince they're the columns, check out the totals at the bottom of the table.
e.g. if there were 10 households with 1 phone, go 10 x 1 and so forthThen add them together:Spoilerso:
0 x 34
1 x 78
2 x 30
3 x 12Note that this is the amount of phones all together...Spoiler0 + 78 + 60 + 36 = 174 phones
so we have one last step: find the mean.
How do we usually do that?So therefore we take our total and divide by the amount of households there are.Spoilermean = (sum of values)/ (no. of values there are)... and that's exactly how the answer arises. Thus the answer is A.Spoiler174 phones / 154 households = approx. 1.12987...
I hope that all made sense. Please tell me if that's not.
Makes sense from a methods kids point of view, but never got taught it nor did i ever see it in the textbook (essentials)?
Hi,
Could someone please help me with this trig question. I keep getting the wrong answer to the text book.
Thanks !! :)
How do you find IQR from a dot plot? In VCAA 2013 Exam 2 question 2b, I not sure how they got their IQR and Q1.
Why can't you solve this question by typing the values into the CAS (e.g "70" in column 1 and then "1" in column 2), finding the mean and standard deviation that way and going from there?
Also how do you find median in a dot plot? I'm stuck on VCAA 2012 exam 2 question 1a (LOL)
And I'm stuck on 1b as well
Why can't you solve this question by typing the values into the CAS (e.g "70" in column 1 and then "1" in column 2), finding the mean and standard deviation that way and going from there?
Also, the mean and standard deviation must take very value in the column(s) into account to be calculated, so just entering 70 and the count (1) wouldn't give you the correct values for them. I think. I have a very flimsy knowledge of cool CAS tricks so there still might be a way to do it like that.
In this case, if you just entered 70 as your only bit of data, then the CAS should say you have a mean of 70 and standard deviation of 0 (which is pretty bogus. :P). One data point is never enough to find a mean or sd.Thought so, time to edit my post with that exact information so I look smart.
Whereas the median lies at the midpoint of a distribution, the mean is the balance point of the distribution. For approximately symmetric distributions, both the median and mean will be approximately equal in value.
Hi all,
Regarding the following image, I'm inclined to classify the following box plot as slightly positively skewed on a SAC. Would it more closely resemble an approximately symmetric distribution? Is it appropriate to classify a box plot as slightly positively skewed?
(http://i57.tinypic.com/dgoxo2.png)
Similarly so with this one, although I'm more confident that this is positively skewed.
(http://i62.tinypic.com/346b814.png)
Thanks!
Ok so when I do practise exams for further,I do them with my CAS in radian mode (I always forget to change it to degrees bc I also do methods) and I get the right answers. Today I realised that I did my sac with my CAS in radian mode.
Would my IQR, regression equation, Pearson coefficient be different, should I go back next lesson and redo the calculations with my CAS in degree mode?
Can someone explain the whole process of finding seasonal indices, deseasonalising the data and adjusting it?
a:=0.7233, b:=1.2294, etc.
To deseasonalise data, you use the following formula:Solve(y=5.6970+(0.1364*14),y
and you should get:Would the terms 'bar graph' and 'column graph' be interchangeable, or if the question asked for bar graph would you specifically have to draw bars that are going horizontally, and if it asked for column graphs would you have to draw vertical bars?I'm not actually 100% on this one, but I'm pretty sure that they're used synonymously. I checked MathIsFun, and that seems to say they are the same; but sources based around MS Excel seem to be saying that bars are horizontal and columns are vertical (which is how Excel organises them so it's user friendly, I believe). If you're doing a question designed for an Excel based SAC, I'd differentiate between 'bar' and 'column'. Otherwise you should be safe just drawing it vertically (and I don't think I've seen a test question ask for anything other than that before - maybe a textbook though).
if this came up in the applications SAC (excel), how would I answer it?Not sure on what 'general terms' means. It could mean not quoting the statistics in your comment, or rounding to integers or something like that. As a general rule, more information is better than less (as long as it's concise).
using mean, range, iqr etc,describe your data in general terms
does this mean just stating the mean, range etc lol
what does 'in general terms' mean?
Can deseasonalised values be larger than the actual value??Yes. They can be either bigger or smaller. Think about if you divide your actual value by the seasonal index (to get the deseasonalised figure obviously) and what happens when the seasonal index is <1.00 or great than >1.00. So the opposite applies for getting the actual value.
For example, r in this case is 0.3515 (to 4 decimal places). From this, I've derived that a weak positive relationship exists between the two variables. Should I state this relationship is a weak linear positive relationship?
After further analysis using a residual plot, I've concluded that there is a clear pattern which confirms that the use of a linear equation to describe the relationship between the variables in non-suitable. Is this correct?
Can I jump from saying that a linear relationship exists between the variables when discussing r and then build a contradicting conclusion based on a residual analysis?
Thanks again. 8)
I'd say yes, call it linear if you're using r. When you use Pearson's, you're making the assumptions that: (Quoth Essentials, explanations are great. Love 'em)You can always transform the data later on and state that it (Or, its r2 value) is the more appropriate because... or that it implies/shows that the natural data is not linear because... (so yes, you should be allowed to change your mind)
- Variables are numeric
- The relationship is linear
- and that there are no outliers. The correlation coefficient can give a misleading indication of the strength of a linear relationship if there are outliers present*
Seems pretty clear to me that your data is non-linear, but it probably still has quite a low Correlation/Determination.
*Although I haven't actually seen this one in practice. Maybe I just haven't run into a problem with outliers. I don't think it applies to your data anyway, so you should be fine.
Sorry to be annoying, but why is 0.8 x actual figure a 20% reduction? What am I missing?
Hello :)
For part (d) of this textbook question I having some trouble... What is a residual plot?
The book doesn't explain it very well :'(
The table below shows the scores obtained by nine students on two tests. We want to be able to predict Test B scores from Test A scores.
Test A score (x) 18 15 9 12 11 19 11 14 16
Test B score (y) 15 17 11 10 13 17 11 15 19
Use your calculator to perform each of the following steps of a regression analysis.
a Construct a scatterplot. Name the variables test a and test b.
b Determine the equation of the least squares line along with the values of r and r 2.
c Display the regression line on the scatterplot.
d Obtain a residual plot.
Thankyou :) :) :)
This can easily be done on your calculator :)You can also get the residual plot by changing the variable on the y axis to 'stat.resid' (I think it's called that..) if you're using a ti-nspire
Once you have set up your scatterplot: click menu > analyse (4) > residuals (7) > residual plot (2)
Your residual plot will then appear!!
The question asked what is a residual plot, but thanks for showing how to do it on a calculator :)
What is a residual plot?
Hi, I'm back!
Can someone have a look at the 2010 Exam 1? I'm wondering about the following questions:
1. Question 3. Can someone explain how to do that please?
2. Question 8. The correct answer is B, but I was pretty darn sure it was C. Isn't the y-intercept at 167? Am I reading it wrong?
3. Question 9. I got the answer right, but just generally, when doing a question like that, am I just supposed to sort of see a similar pattern between the actual data and the residual plots? Is that how it works? Coz that's what I've been doing....but is there a better way?
Thanks!
How do you confirm the skew of something, is it something to do with the proportion of mean to median?
Thanks
When asked to list what types of transformations would be suitable for a table of data values, should I only base my answer on the 'circle of transformations' suggestion, or compare r-values for more accuracy? One of the transformations in the 'circle of transformations' gives a pretty low r value compared to the other transformations.
When asked to list what types of transformations would be suitable for a table of data values.I think the keyword here is list; definitely base it off the circle of transformations. As long as you're taking it from the right quadrant, it will be suitable. I'm 90% sure that they'll ask for 'most' suitable or appropriate if they want an r2. If it's a question written by a teacher you might want to double check though.
(I know I'm explaining this horribly, I'm sorry. I hope I explained it well enough. It's sort of difficult to word it.)^^^
When sketching inequalities do you shade the wanted or unwanted region. Does it matter as long as you have a key (stating what the shaded region represents) next to the graph?
When sketching inequalities do you shade the wanted or unwanted region. Does it matter as long as you have a key (stating what the shaded region represents) next to the graph?
Can someone explain to me what a triangular matrix is?It's when all the 0s of a matrix form a triangle on or just before the leading diagonal. They can be in the upper or lower corner, here's some examples:
Thanks.
It's when all the 0s of a matrix form a triangle on or just before the leading diagonal. They can be in the upper or lower corner, here's some examples:
Note that it doesn't matter what happens on the leading diagonal. The 0s in the last one could have a mixture of non-zeroes as well, I have just illustrated this way so that you can clearly see the "triangle".
How many modes does there have to be before the data is considered to have "no modes"?It wouldn't matter. It wouldn't just randomly switch to "no modes", there is no set point for such a thing to happen haha!
Example: 1, 1, 1, 2, 3, 3, 3, 4, 5, 5, 5, 6, 7, 7, 7, 8, 9, 9, 9
The modes for this data are 1, 3, 5, 7, 9
Is having 5 modes too many?
In a further core sac are we suppose to draw residuals/ scatterplots and all those other charts accurately? It just seems too time consuming tbh
in the image attachedI don't see an image :(
Hey everyone,
I have just dropped biology and am starting general maths 1/2. Do you think that it will impact my knowledge on the subject by starting a semester later?
Thanks :)
I don't see an image :(
idk it wont let me attach it for some reason. dammit. TT.TT
Hi :)
Does anyone know why we use 'centering' when smoothing time series plots?
Like what does centering actually do to the data?
Thanks :)
Centering is used when using even numbers (ie. 2 mean or 4 mean).
If we have an even number of data values, the value we find will fall between them, hence is not a time point from the original series; we don't want this to happen.
For example, 1 and 2 will become 1.5. However, if we centre the data we are finding the value that will form exactly on that point.
I'm not sure if this has clarified the concept enough for you? Let me know :)
If you still haven't gotten it, you could upload it externally and insert it into your post like that. (Try Imgur, maybe?)
Why might it be incorrect to assume that braking distance on cars is not normally distributed?
Of course it would be. Remember that a normal distribution takes negative values - can a braking car break a negative distance?
do you think it's too late to get a statement for the further exams? I think i was deprived of a 50 since i was rank 1 all year and got A+ on all areas of study including BOTH exams, and the rank 3 got a 49.... I know 48 is a decent score, but I don't think i was fairly marked? Cheers :)
How would I do part h in the attachment without making guesses??
Hi :)
Just a quick question about units, do we need to give units for things like standard deviation?
For example, if we were given data on the 'number of children per school' and then asked to calculate the standard deviation, do we write the standard deviation is X children (or just X)
Thanks! :)
Hi!
Q: Given a table with average rainfall for 4 seasons, and the seasonal index for two of the seasons, how would i find the seasonal index for one of the missing seasons??
E.g. question 11 from core section of 2012 exam 1 (/attached pic) where we're asked to find the SI for spring
Answer was approx 1.13
Thank you :)
I'm not sure if this is right.... but this is how I worked it out.
4 - 1.01 - 0.96 = 2.03
2.03 is the sum of the winter and spring seasonal index
I then assumed that winter had a SI of 0.9 as its average rainfall was lower than that of summer, thus the seasonal index would be lower than 0.96.
Then, I did 2.03 - 0.9 which = 1.13
T= _ _ S= _ _
| 0.66 0.04 0.04 0.08 | | 25 |
| 0.09 0.84 0.15 0.09 | | 25 |
| 0.13 0.08 0.77 0.07 | | 25 |
| 0.12 0.04 0.04 0.76 | | 25 |
- - - -
Determine where the one hundred new cars will be in the long-term, how many weeks does it take to reach this steady state?
Is there a faster method to finding this?
I found the long-term= _ _
| 12.4031 | Adelaide
| 42.5356 | Canberra
| 27.2318 | Melbourne
| 17.8295 | Sydney
- -
[[Just wondering when you say the number of cars out of the matrix, even if it's above 0.5 do you round down seeing you can't have a fraction of a car? Or is it normal to round up? ]]
Thankyou!!!
Your method makes sense... but i feel so insecure having to 'assume' the value of something :/You could also find the seasonal index by doing the following:
It depends on the question. If it seems realistic to round down even if it's 0.5, do it. Further maths is primarily based around real world maths and if I were selling cars (or whatever the question is about, it's hard to tell) I wouldn't count profit on cars I couldn't technically sell. Might wanna ask your maths teacher if you're still not sure; they're the one marking your SAC, not me. :)Just wondering when you say the number of cars out of the matrix, even if it's above 0.5 do you round down seeing you can't have a fraction of a car? Or is it normal to round up?Bump please I have a sac on this tomorrow.
Hi!similar triangles yeah
Could someone please help me with this question :)
Marcia is 1.5 m tall and casts a shadow 4 m long. Her shadow and the shadow cast by a tree
nearby are parallel on the ground. The end of Marcia’s shadow on the ground lines up with
the end of a shadow cast by the tree h m high. If the distance between the tree and Marcia
is 20 m, find h, the height of the tree.
:-\
similar triangles yeah
Marcia is 1.5 m tall and casts a shadow 4 m long. Her shadow and the shadow cast by a tree
nearby are parallel on the ground. The end of Marcia’s shadow on the ground lines up with
the end of a shadow cast by the tree h m high. If the distance between the tree and Marcia
is 20 m, find h, the height of the tree.
My textbook says: "Bivariate or (x,y,) data is data where both x and y could vary independently."Edit: Totally misread that. If both variables are independent, there's no relation between x and y. By extension, that means that Pearson's Correlation Coefficient and the Coefficient of Determination are either really low, or 0. I'm very close to 100% sure that you'll never get a question where both variables are dependent or independent as there's not much you can do with those in the way of SAC/exam questions. It's probably mentioned as a bit of background, so you're not totally blindsided if the VCAA or whoever brings it up in the future.
I thought in bivariate data there was always one independent and dependent variable?
:)
When would you say there is random variation in a time-series data?
Would it be whenever the trend is none of: cyclical or seasonal?
:)
would i not be awarded the mark? would a question this simple even be worth 2 marks?I'd give you full marks for that; one mark for applying the formula and one mark for the correct answer. Well, as long as you wrote down your working out.
Thanks!
I have another question:
if a question asks you to find an answer and round to 1 decimal place (part a.), then asks you to do something else for part b that uses the answer to part a, should we uses the rounded number or the actual number?
eg
a) find radius to 1 d.p
b) calculate the perimeter of the circle
do you use the rounded radius or the actual value when calculating the perimeter?
I think that in methods you are supposed to use the actual number (unless specifically instructed not to), but in further questions & worked solutions, i noticed that they have always used the rounded number
Can someone please explain how to do parts d.) and e.) ?Ew, time series are annoying (imo).
Use the least squares regression line and seasonal indices to estimate the sales for the business in the third quarter of 2004. Compare this with the actual figure for the third quarter of 2004 and find the percentage difference.First off, there's two things the question is asking us for - a prediction of the cash made in the third quarter of 2004 and a calculation to show how accurate this is. I'm going to put these into two different spoilers because damn, I love spoilers. ;)
Use the equation of the least squares regression line and the seasonal indices to forecast the sales for the business in the third quarter of 2005Same stuff as before, but it's really important to note that's it's asking you for a totally unique value. So we first need to work out the value of the third quarter of 2005.
I've also attached a photo with the answers :)Legend. Saved me some time <3
I can't figure out how to do part b (see attachment). I've tried using the sine rule and made a mistake somewhere I think...any help would be awesome :)
i got 67.7m for part b. Is that correct? (if it is, i'll post the working out)Yeah that's it. That would be sooo good if you could, TIA!!!
The total sum of all indices must be 12. we are missing one of the twelve values. To find it use 12 minus the sum of the given values
How do i find r when i am given the equation of the least squares regression line and not a table of values?A least squares regression equation can be found for any bivariate plot, regardless of the value of r. Conversely, a known least squares regression line can fit an unlimited variation in the spread in a scatterplot.
Hey i got a different answer to BoB regarding a networks question :/All of your six trees are valid.
The answer is apparently 5 but i found 6 trees
1- A-B-D-G
2- A-B-E-G
3- A-C-E-G
4- A-C-E-B-D-G
5- A-C-F-H-E-G
6- A-C-F-H-E-B-D-G
are one of these solutions wrong?
Another question from BoB... is the answer provided there wrong?The graph does not show a connection from C to A. Hence the matrix should not.
Question - Draw a matrix of the graph.
The answer matrix says that A-C doesnt exist, however C-A does... is it wrong? Or am i missing something?
Can't seem to get 83.6cm.
I got something like 85+ cm
cheers
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2011furmath2-w.pdf
Module 3 question 2 c and d
Looking at the solutions, i kinda get it but not 100%. Could some please show me in detail how they get the answer. Seeing this question made me consider re-evaluating my aim for a 45+ study score.
Hey guys, i hope everyone is doing well in further.
This is not really a further maths question but i was wondering where everyone is up to in their further maths course? have you finished all SACS and finished the course? Or are you still completing the Further maths content and SACS? :P
I finished all the content in holidays before term 1.. (nerd lol).. I am now going back and doing 5-6 questions in every exercise.. there's a few things i forgot :(
Thats cool, dw i did something similar :P
Anyway have you finished all your SACS for the year?
No i have 2 more to go.. Can't slack off during those.. need 100% for both. I had an allergic reaction during my matrices sac and got 74% :( fml and its my forte lol
Damn, thats really unfortunate :-\ But im sure you can easily score a 100% in your final two! What SACS are they anyway?
I only have Graphs and Relations and Trig & Geo left
Graphs and Relations and Networks..
Is your textbook Maths Quest 12 Further Mathematics?
Yup, How about you?
Same.. how good is 11D haha.. its a nice break from number punching on cas and further logic questions :D
Same.. how good is 11D haha.. its a nice break from number punching on cas and further logic questions :D
Hey, have you finished the coursework for networks yet? I've got a few questions to ask if you have.
I am currently as we speak starting a quote of questions from 15D.. any questions from 14A-15C i can help.
He might not be using maths quest :P, but you should be able to help him nevertheless :)
You know what u made me think off... 'you should be able to help him'.. if only in further people get extra marks in the exam for doing other modules.. if they have extra time .. would be fun
I am currently as we speak starting a quote of questions from 15D.. any questions from 14A-15C i can help.
So, I see you are aiming for a high study score for further maths similar to what I want to achieve. Therefore, I'm assuming you know that every question is extremely important in the exam because losing ~6 marks can drop down your ss below 45. Hence, where i'm trying to go with this is whether or not it is 'dangerous' to do networks for the exam because of its ambiguity and the fact that it is based more on logical reasoning than maths; you generally do not know if your answer is absolutely correct. Therefore, are you planning to do another model for the exam to replace networks? That is what i'm most likely planning to do after I finished my networks sac. I want to see what you have to say, or anybody else, regarding this.
Are step graphs simply just a hybrid function which is defined by constant functions?? Thankyou!
Hey Frank, did you do geometry and trigonometry module? How did you find the SAC?Nope, did matrices sorry.
Hey Frank, did you do geometry and trigonometry module? How did you find the SAC?I did Geometry and Trigonometry.
What strategy do you guys use for those linear programming questions where the corner is continuous (eg. 10.2) but only integer solutions are accepted?
integer numbers inside the area allowed- any numbers inside there. Time consuming but not many questions like these appears
Yeah, going through past VCAA questions I couldn't find any.
But my teacher said I need to learn how to do this so I think it will be on the SAC coming up.
How do you know when to use a point IN the feasible region and when to use a feasible region vertex?
Or should you never assume it is a corner?
The answer to this is 1:9, however I had 1:27. The solutions said the scale factor had to be squared rather then cube because the length wasn't changing as the cross-sectional area did or something like that..I can't really follow what they mean...any help would be appreciated thanks!Let's simplify the question by considering a cube with side length L. The volume is LxLxL =L3
Hey guys quick question, thanks in advance :)
The bearing of a ship,S from lighthouse,A, is 055 Degrees. A second lighthouse, B is due east of A. The bearing of S from B is 302 degrees. Find the magnitude of angle ASB.
Key word here is vertical. Some of those answers are just straight line graphs. One is a hyperbola and one is a horizontal line.Ahhh thank you
If a critical path goes through a dummy activity, do we include the dummy activity as part of the critical path?
For example, is the critical path B-G-J-M-N
or
B-dummy-G-J-M-N
Quick question
The rectangular prism shown above has a square end with an area of 36 cm^2 (Just a regular rectangular prism...)
The length of the prism is twice the width of the prism. Point M is the midpoint of AB.
Angle CMD is closest to
A. 25.3°
B. 35.2°
C. 35.3°
D. 45.2°
E. 45.3°
I got C is this correct??
Thanks in advance
If a critical path goes through a dummy activity, do we include the dummy activity as part of the critical path?
For example, is the critical path B-G-J-M-N
or
B-dummy-G-J-M-N
Is there a picture that comes with the question? Because I don't know where point C, M and D are.
Here's the question, coincidentally i have it lying around lol.I got C as well. Should be correct :)
Could someone please explain how to do the question attached below?As printed, there is no correct answer to the question.
(The answer is E)
Thankyou!
As printed, there is no correct answer to the question.
I suggest the difference equation is not meant to be
tn+1 = 2tn - 1
but
tn+1 = 2tn - 1 which would give E as the answer
Are we only expected to input integer values into objectives functions in vce?I don't think you should restrict yourself to only thinking in integer terms.For example, non-integer values in objective functions could be examined if an answer is wanted correct to the nearest cent.
Also with the 'sliding line' technique, why do we swap the coefficients of x and y at the start? thanksss
I don't think you should restrict yourself to only thinking in integer terms.For example, non-integer values in objective functions could be examined if an answer is wanted correct to the nearest cent.Well I looked online and the sliding method I learnt was that you get the coefficients of x and y in the objective function, so in this case 12 for the x and -3 for the y and you plot an x coordinate (-3,0) and y coordinate (0,12) and use a ruler to get a line between these two points, which gives the gradient of 4 that you got.
I am guessing at what you might mean by swapping the x and y coefficients "at the start"?
If the objective function is, say, P=12x-3y, then the sliding line method is easier if you could rewrite this function in the form y=mx+c
So P=12x-3y would become y=4x-P/3
Then slide a line, with a gradient of 4, up as far as you can go, and still touch the feasible region, to maximise P or down as far as you can go to minimise P.
Can you call a histogram a descriptive statistic? This question was actually on a psych exam and the solutions said it could be but it doesn't sound right..pls confirm
I did further last year and a friend asked me for help today. Unfortunately I completely forgot how to work things out. I would appreciate it if someone could help me out with this so I can forward it to my friend. Thanks in advance!My dodgy attempt...
Help please
Therefore, the answer is A. (I hope that was right, haven't did matrices for ages)
If we are asked to use a percentage value in a question (e.g. The organisation had 62% of the market share) and the question was asking us for the initial state matrix, would the matrix need to be in the decimal or integer form (e.g. 0.62 or 62)?
decimal formThank you
decimal form
Could someone tell me how to do q9 in 2010 VCAA exam 1?Assuming that you mean the Core, here's how I did it:
Your help would be very appreciated :)
Need help with Q8 Linear Relations FM 2013 exam 1. And also Q9 Linear Relations FM 2010 VCAA exam 1.
Your help would be very appreciated!
For a residual plot, does the x-axis scale remain the same and the y scale changes? thanks
for the exams, are we expected to know how to plot residuals on our CAS?I've seen some residual plots in the multiple choice, most can be done through elimination but if you have some extra time at the end it might be useful to plot the residual on your CAS, as for smoothing large numbers of results, you won't have to.
also, would we ever need to smooth a large number of results?
I've seen some residual plots in the multiple choice, most can be done through elimination but if you have some extra time at the end it might be useful to plot the residual on your CAS, as for smoothing large numbers of results, you won't have to.
But it's definitely good to know how to do 4-moving median smoothing with centring and maybe even practice with 6-moving median/mean just to get a good feel for it.
-Someone please correct me if i'm wrong for the smoothing thing, i've not done too many exams.
for the exams, are we expected to know how to plot residuals on our CAS?
thanks guys ;D
also
do we need to label points with coordinates when we plot them?
Are we expected to know blending for graphs and relations?
Thanks!!
Also, for core, if a value is on the upper/lower fence is it considered an outlier? Or are outliers only points beyond the fences?
fences? If they are a dot on the scale of a boxplot its an outlier. If you need to draw a boxplot and want to know which one is an outlier u can work it out with Q1-1.5xIQR and Q3+1.5xIQR. I dont get what u mean by fences.
At my school we call fences the exact point of (Q1 - 1.5IQR) and (Q3 + 1.5IQR).
So what I mean... those points mentioned above [(Q1 - 1.5IQR) and (Q3 + 1.5IQR)], if something was equal to that value would it be an outlier or not?
Example: If Q1 - 1.5IQR = 4 and I have a data value that was 4 - is this value an outlier? or not?
At my school we call fences the exact point of (Q1 - 1.5IQR) and (Q3 + 1.5IQR).
So what I mean... those points mentioned above [(Q1 - 1.5IQR) and (Q3 + 1.5IQR)], if something was equal to that value would it be an outlier or not?
Example: If Q1 - 1.5IQR = 4 and I have a data value that was 4 - is this value an outlier? or not?
My book says it is an outlier - the equation is Q1-1.5xIQR (<=)x(>=)Q3+1.5xIQR, the (<=) means that it could be equal to, so it would be an outlier.
But other people are saying it isnt, so before i sue my book for trying to ruin my chance of a 50, i will wait for others to say stuff
Well, according to maths quest, what i said above is correct because an outlier lies outside the interval of the attached picture.
What book are you using?
I use Essentials, and my book just says less than/greater than but not equal to? Ahhh!!
I have attached a photo.
Yes, that's correct. What maths quest and essentials are saying is the same thing.
An outlier is a data point that is outside this interval
Q1 - 1.5 x IQR <= x <= Q3 + 1.5 x IQR
which is the same thing as an outlier that is within these intervals:
x < Q1 - 1.5 x IQR and x > Q3 + 1.5 x IQR
Isn't Maths Quest saying that an outlier can be, for instance, the value of Q1 - 1.5IQR, whereas Essentials is saying that would not be an outlier as it has to be less than (and not equal) to that value?
Sorry I'm really confused now :/
No, maths quest is not saying that. It is saying that an outlier must be less than (and not equal to) Q1 - 1.5IQR, which is what essentials is saying.
Basically, just understand this:
An outlier must be less than (but not equal to) Q1 - 1.5IQR or greater than (but not equal to) Q3 + 1.5IQR
(http://i.imgur.com/XQVVfKN.png)
the answer is B
does that mean when considering average rate of change, we just look at the number (as if it had | | around it) and ignore the sign (positive/negative)
in this case it asked for maximum rate & the answer was when it was decreasing fastest
I thought we were meant to use the formula 'standard deviation=range/4' but it turns out that was wrong...
I thought we were meant to use the formula 'standard deviation=range/4' but it turns out that was wrong...
Thank you! :)
I thought the same when I did that question! My teacher told me to just do it graphically and mark the graph with the standard deviations given to you.
I thought the same when I did that question! My teacher told me to just do it graphically and mark the graph with the standard deviations given to you. Here:Spoiler(http://i.imgur.com/nrEG3xc.png)
I've only marked out a standard deviation of 2°C to save some time, but here you can see it fits the normal distribution's bell curve almost perfectly, whereas the others would be significantly over or under fitting (from memory).
It's possible to do this mathematically by inputting the data here into your CAS calculator's spreadsheet pages and getting the statistics (menu + 4 + 1 +1 on the colour CAS), but, it will take longer than the graphical version that MightyBeh has used. There are a number of other ways in which you could do this via calculator, some of which are not discussed in Further. With a sensible guess, you can eliminate many of the options, such as E (too big).
Could someone please explain how to do this question?My teacher told me when dealing with large data sets standard deviation= range/6.
(Graph is attached)
Using the 68–95–99.7% rule, the standard deviation for temperature is closest to
A. 1 °C
B. 2 °C
C. 3 °C
D. 4 °C
E. 6 °CSpoilerAnswer is B
I thought we were meant to use the formula 'standard deviation=range/4' but it turns out that was wrong...
Thank you! :)
NUMBER PATTERNSI got b) -2
the sum of the first four terms of a geometric sequence has the value -30
the sum of the first and third terms is 30
the value of the common ratio for this sequence is:
a) -3
b) -2
c) -1
d) 0
e) 1
thanks in advance
I got b) -2
Equation 1 a(r^(4)-1)/(r-1)=-30
Equation 2 a+a(r)^(3-1)=30
Solve for a and r
a=6 and r=-2
Sorry i hope thats clear dunno how to use latex yet :/
Youre welcome :)
yeah that does make sense!
thank you so much :D
if a (1/y) transformation is done, and y=mx+c becomes 1/y=mx+c, is "1/y" now called the dependant variable? (instead of y)
something very similar to this came up heffernan 2015 prac exam 2 & the dependant variable was called 1/y
I recently completed this exam however my school is marking it for us so I haven't got the solutions yet.yep, thanks
I wrote 1/y as my answer.
This was my reasoning: a dependent variable is defined as the variable that is measured. Since in this instant you were measuring 1/y not just y, it is considered the dependent variable. Does that make sense? :)
yep, thanks
another question
if something is 'one and a half times bigger than' something else, is it 1.5x the size or 2.5x the size
i think it is 2.5x but heffernan thinks 1.5x
Why is option D wrong?It doesn't work both ways, it's a bit like working out the gradient with 'run' over 'rise' instead the standard 'rise'/'run'.
in the solution, it says that you can only say 49% of the variation of the dependant variable is explained by variation in the independant variable but doesn't this work the other way around as well?
also,Looks like a pretty standard circle of transformations question to me? Does your textbook have all of these?
how are we supposed to know these transformations? my textbook has a list of transformations & when to apply them but some of these are not in there...
is this likely to come up in an exam 1? (this is from MAV)
also,
how are we supposed to know these transformations? my textbook has a list of transformations & when to apply them but some of these are not in there...
is this likely to come up in an exam 1? (this is from MAV)
Thankyou for your help MightyBeh! :)
Could someone please help me on how to do the following attached question? Thanks!
Thankyou for your help MightyBeh! :)
Could someone please help me on how to do the following attached question? Thanks!
I'm a bit unsure of how to do this question (Attached below) I don't really know which length you need to first find by using Pythagoras' theorm to figure out length BG?
Would it be from Point B to the middle of line DC?
Any help would be great!
The answer is 415cm :)
Hi, do you guys reckon it's worth doing ITUTE exams?Haven't tried them myself, but skimming through their 2014 batch makes me think that they might stray a bit from the course. Probably good to do if you have nothing else left, but otherwise I'd steer clear.
Cheers.
For the following contour map (image attached below) to find the horizontal distance between points A and B would I measure either the red line or the pink line with my ruler? (Before using the scale to convert this value to the distance in reality)
Any help would be great! :)
Hi guys.
With Q 3 f(i) (VCAA 2012 Exam 2) in the examiners report, they say -"Alternatively, the ‘sliding line’ method could be used".
I got the question correct; but what is the 'sliding line' method?
Cheers.
Can someone please explain how to do this question? (attached below)
The correct answer is D :)
Hi guys.
With Q 3 f(i) (VCAA 2012 Exam 2) in the examiners report, they say -"Alternatively, the ‘sliding line’ method could be used".
I got the question correct; but what is the 'sliding line' method?
Cheers.
Pretty much you rearrange the objective function until you have an equation in terms of y. Then using your ruler (this is why this technique is rarely use as it can be inaccurate), you slide your ruler across the feasible region (with it angled according to the equation you found), where the last point your ruler touches is the max/min value. For maximising, you begin sliding ruler from bottom left corner to top right, for minimising you start sliding ruler from top right to bottom left... does that make sense??
Wow lol, that method spells human error all over it,
Do you ever recommend using this method? Ever?
Yes. For (usually multiple choice) questions that don't give any values.
This type of question came up on one of the company papers I have done, and my teacher said the only way to solve it was to use the sliding line technique.
Strange, i've never encountered a question where i was required to use this technique.
PLEASE HELP!!
-A data set of 8 values has the following characteristics
Mode=41
Mean=32
Median=37.5
Range=32
One of the data set values is 36
Complete the data values in ascending order
17(already gven in the question),___,_____,_____,_____,_____,_____,_____
PLEASE HELP!!I don't think the question works..maybe I'm missing something. I got to (17,a,b,36,39,41,41,49). Must be two 41's for it to be the mode, must have 39 to get a median of 37.5. Got the 49 from the range instruction. So that left me with a and b, which cannot give a sum and be numbers less than 17 and fit the instruction that the mean=32
-A data set of 8 values has the following characteristics
Mode=41
Mean=32
Median=37.5
Range=32
One of the data set values is 36
Complete the data values in ascending order
17(already gven in the question),___,_____,_____,_____,_____,_____,_____
I don't think the question works..maybe I'm missing something. I got to (17,a,b,36,39,41,41,49). Must be two 41's for it to be the mode, must have 39 to get a median of 37.5. Got the 49 from the range instruction. So that left me with a and b, which cannot give a sum and be numbers less than 17 and fit the instruction that the mean=32
edit: not the only one with this problem which is a relief, the question is wrong I'd say.
It was mentioned in a VCAA examiners report....The sliding line method is best done by calculation rather than sliding a ruler. If you compare the calculated gradient of the objective function with the caculated gradients of the constraints, you can see which lines are steeper in comparison with others. It can then be easy to imagine sliding the objective function to its limit.
So I would highly recommend learning how to do it. It is only unreliable when the data points are close together, otherwise it's a great way to proof-read your linear programming questions.
Must be two 41's for it to be the modePerhaps this is where everyone is going wrong? What if the were, say, three 41s?
Hey guys,Yes, but the whole question pretty much revolves around the "clearly doesn't seem to occur" bit, so that's not areally a valid reason? ???
Thanks so much for all helping out :)!
In the end, after so many possibilities, i have come to a final conclusion...THIS QUESTION IS WRONG
REASON: Because since the mean is 32 and there are 8 numbers(32*8=256) we should be getting a total of 256 when the numbers are added up, which clearly doesn't seem to occur.
Yes, but the whole question pretty much revolves around the "clearly doesn't seem to occur" bit, so that's not areally a valid reason? ???
Need help with Q9 MODULE 2 EXAM 1 2009.This one took a few steps, and there's probably a few ways to go about it. Here's how I did it though:
Cheers.
I managed to get the right answer for the attached question below. However, my working out was overly complicated and, although i got the right answer, i believe there is a much simpler way of working it out.
Can someone please attempt the question and post their working out?
What's the answer? I think I got it but my method feels too simple ::)
Post your answer and i'll say if it's right or wrong. This has been the most challenging question i've seen in further maths so far, so it's good practice.1/sqrt(2pi)?
1/sqrt(2pi)?
Nope. But remember the question asked for three decimal places, so your answer would be 0.399, but it's still not right.
Wouldn't it just be finding the area of the triangle: using herons formula. Which comes to 0.43301
Then since area ratio is 1:2. Divide area of the triangle by two: 0.21650
To find area of circle
Then since pi*r^2 = area of the circle
Divide 0.21650 by pi = 0.06891 and then sqrt of 0.06891 = 0.263
Isn't that it?
I got 0.214m, yay or nay?
Yay :)
Is this how you worked it out?
A(shaded region) = [0.5 x sin(60)] - [pi x r^2]
A(reflective material) = [0.25 x sin(60)] - [0.5 x pi x r^2]
pi x r^2 = [0.25 x sin(60)] - [0.5 x pi x r^2]
r = 0.214 m
This question was in fact a VCAA question. Only 4% got full marks.
Yay :)
Is this how you worked it out?
A(shaded region) = 0.5 x sin(60) - pi x r^2
A(reflective material) = 0.25 x sin(60) - 0.5 x pi x r^2
pi x r^2 = 0.25 x sin(60) - 0.5 x pi x r^2
r = 0.214 m
This question was in fact a VCAA question. Only 4% for full marks.
Oh right I see, I'm on my phone so I didn't really read the question properly lol. Anyways good question to post. What year is this from?
Nope! Working's attached :)
Edit: Although the method was very similar
2004 exam 2
Oh, i see. So you just found the area of the triangle differently.
2004 exam 2
Oh, i see. So you just found the area of the triangle differently.
Yep! I actually really liked this question, I should give those older exams a shot ;)
My teacher all year has been teaching us business maths, networks & decision maths and matrices. I got my sac back for business and I did terrible so my cousin has decided to last minute teach me trig/geometry for the exam IN ONE WEEK! Does anyone think this a reasonable/horrible idea, considering business was my weakest subject in further? I find trig and geometry a lot simpler and less complicated than business (because business has sooo many formulas to remember) but i'm just worried I'm going to crash and burn when the exam comes around!!
Matrices module, 2011, Exam 1, Question 8
The assessors report does not cover this module because it was completed 'reasonably well' which leaves illiterates like me, helpless
Can someone show a worked solution, my cas does not want to solve for x with these types of questions
Matrices module, 2011, Exam 1, Question 8
The assessors report does not cover this module because it was completed 'reasonably well' which leaves illiterates like me, helpless
Can someone show a worked solution, my cas does not want to solve for x with these types of questions
Hey Further Maths students,
Im having trouble with understanding this question and why they used the volume scale factor, since the radius for both shapes is the same, wouldn't the sides be out of proportions and therefore the use of k, k^2 or even k^3 become impossible?
-i have attached the question, but its the first time doing this so i may have done it wrong, so ill link the VCAA exam it is off. ()
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2009furmath2-w.pdf Page 15, Q4B TRIG
-VCAA used the solution of: (20/50)^3=0.064, 1-0.064=93.6% I just dont understand the first bit, and if anyone has a different way of solving this or explaining this, that would be great! I prefer longer methods, like actually finding the volume of both, although this did not work when i tried that....
Thanks in advance, good luck everyone.
Hey Further Maths students,Alternative way (basically the same but with more working and a bit more intuitive)-Choose an arbitrary radius, say for example 2cm (initial radius when h=50). Then find the little radius at h=20 by scaling down using your arbitrary value. So 2/50=r/20 --->r=4/5. So Big volume=(pi*2^2*50)/3 and small volume=(pi*(4/5)^2*20)/3. Now just do 1-(small volume/big volume)
Im having trouble with understanding this question and why they used the volume scale factor, since the radius for both shapes is the same, wouldn't the sides be out of proportions and therefore the use of k, k^2 or even k^3 become impossible?
-i have attached the question, but its the first time doing this so i may have done it wrong, so ill link the VCAA exam it is off. ()
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2009furmath2-w.pdf Page 15, Q4B TRIG
-VCAA used the solution of: (20/50)^3=0.064, 1-0.064=93.6% I just dont understand the first bit, and if anyone has a different way of solving this or explaining this, that would be great! I prefer longer methods, like actually finding the volume of both, although this did not work when i tried that....
Thanks in advance, good luck everyone.
Hi everyone
I was going over all the past exam papers I have done and I am stuck on question 13 from Core 2006 exam 1.
I'm just confused about how they got 0.86 in the formula on VCAA report
Hi guys,
Can someone help me with VCAA 2007 Exam 1 Question 9 from Graphs and Relations?
Thanks! :)
Hi guys,
Can someone help me with VCAA 2007 Exam 1 Question 9 from Graphs and Relations?
Thanks! :)
Define Z(k,x,y)=2x+(k*y)
z(k,x1,y1) ≥ z(k,x2,y2)
z(1,50,50) ≥ z(1,100,0)
comes up with false, so we know that the point (100,0) is larger than (50,50) when k = 1.Hi,
Can anyone please help me with question 9 from 2008 exam 1 (Graphs and Relations) Why isn't the answer E?
and also questions 8 2009 exam 1 (Graphs and Relations)
Thank you
Hi,
Can anyone please help me with question 9 from 2008 exam 1 (Graphs and Relations) Why isn't the answer E?
But I'm sure the amazing AN people will be on it soon! :)
Hi,
I'm really stuck on question 2c and onwards in matrices on last years exam 2, could anyone explain to me how I'm supposed to keep the state matrix constant?
Thanks :D
PS, I got 36/40 on exam 1 and 47/60 on exam 2 (lower than usual) anyone know what kind of SS I'm in for??
Are you referring to where it states that "the number of voters in the city is expected to remain constant until the election is held in June?"
Hi,
I'm really stuck on question 2c and onwards in matrices on last years exam 2, could anyone explain to me how I'm supposed to keep the state matrix constant?
Thanks :D
PS, I got 36/40 on exam 1 and 47/60 on exam 2 (lower than usual) anyone know what kind of SS I'm in for??
What's your SAC average?
Workings for 2c - 2d are attached, did you need help with question 3 as well? :)
Edit: Do you mean in the part before 2b where it says 'the number of voters in the city is expected to remain constant'? 90% sure that just means the sum of all the values in any state matrix will add up to 12000.
EDIT: holi moli, ignore me. I thought you were asking for question 9 of 2009haha its okay paper-back. Thank you anyway for helping :)
E is correct if you forget (like I did the first time I did the question ::) ) that only the corner points of the feasible region are to be included in your calculation (I'm looking at you, (0,100) >:().I still don't understand MightyBeh :( Because I got the two equations and the intersection (20,50) then I sub 20 and 50 into Z=x+4y and I got 220. Why isn't that right?
To (accurately) find the coordinates of point M we first need to know the equation of the lines and solve for the intersection. I'm too lazy to type it out so I'm going to assume you had no issues with this part and know that the coordinates of M are (20,50). (Let me know if you did have issues though and I'll show you <3 )
So our corner points are: (0,60), (20,50), (40,0) and (0,0). Obviously we don't need to include 0,0 though because none of the equations are going to be maximised there.
Then I just subbed in the three reasonable points to each equation (thankfully the answer is A.)
(0,60)
(M)
(40,0)
So the function Z = x + y is maximised at the point M. :)
(http://i.imgur.com/lo5ILSl.jpg)
Thanks heaps! Yeah that's what I meant with the state matrix. My sac average is A+With your 2014 exam scores, around ~39+ raw I think.
I still don't understand MightyBeh :( Because I got the two equations and the intersection (20,50) then I sub 20 and 50 into Z=x+4y and I got 220. Why isn't that right?
Thank you so much!!! :) MightyBehyou're welcome! <3
How many marks can you lose in exam 2 for a 50 study score? Assuming full marks in SACs and exam 1Probably around 3 max
Hey guys, i got both these questions correct, however im not really sure i know the reasoning behind them so if anyone is able to clarify why that would be great.
So with Question 1 B here, they convert the sides lengths into the same unit of measurement (cm or m, both work) which i understand, and then they use k^2 which again i understand.
With Question 5 here,a block of land has an area of 4000m^2, and the map is 10cm^2. Following the last question, wouldnt we have to convert these into the same measurement? Can anyone explain clearly to me why they dont do this?
Cheers!
Okay, so now I have a question about scales. When a question talks about the measurements of a map as being in mm, do we always convert it to cm? That is, do we always assume that scales are in cm:cm; like where it says 1:5000, would it always be assumed that it is referring to cm, seeing as they hardly ever specify the units?
Yeah, my wording's a bit off.
Everyone excited/nervous/bleh about the exam coming up?
I would assume 1 unit : x units? I reckon that if it seemed ambiguous at all in a VCAA question they'd specify units.
Pretty bleh about exam 1 personally, but think exam 2 will turn out okay ;)
Thanks, and you'll do great; you seem really smart! :)
I have another question:
For the Question attached and highlighted, I did it and got 200%, but the answer is 100%. Why is that?
You may have calculated that 2011 is twice the original (hence 200%), but this is an INCREASE by only 100%, since the original of 2005 is already 100% of the 2005.
You may have calculated that 2011 is twice the original (hence 200%), but this is an INCREASE by only 100%, since the original of 2005 is already 100% of the 2005.
Hey guys. 2013 VCAA Exam 1: Can you please help me with question 8 Trig and question 7 and 8 in graphs and relations. Thanks so much!
For Question 8, Geo and Trig, basically you'd have to draw a diagram to get the answer, *was sort of lazy drawing it out right now, so here's the solution from itute. Basically you find the angle of the larger triangle as 51 degrees, and then since it lies on a 180 degree line you take away 51 from 180 to get the bearing of Black tower from white tower.
For Question 7 Graphs and Relations, all you really have to do is find the gradient of the straight line, as it represent the value for k in the rule. so the rule is H = k/d^2, to find k just find the gradient of the straight line which you could use any two points for. You should get the gradient as 58.4. Hence the rule is H=58.4/d^2.
Why can't I substitute in numbers for x and y to get k? 25.7 = k/(0.44^2). The answer I got was C; H = 4.98/d^2. I substituted in the x coordinate H = 4.98/(0.44^2) and the answer is 25.7, the y value in the question. What am I doing wrong? And can you help me with question 8? Thanks you so much!!
Hey everyone, I'm aware that the SS you get is quite dependent upon both your sacs and your exam, but considering you have an A average in your sacs (most likely going to scale up from the level of difficulty??), what kind of percentage should you be aiming for in the exam to have a chance of obtaining a SS of over 40?
Thanks!
I've explained this one before! I think Latex is being weird though so if the worded explanation isn't enough I'll re-do the working out. :)
Although I'd also like to add since doing that the first time I've run into this rule which I think was mentioned in the itute and VCAA solutions:
(x/a) + (y/b) = 1,
where a and b are the x and y intercepts, respectively. (pretty sure it's relevant ::) )
That link won't work. Can you copy the worked solution or tell me how to find it? And how would I use that formula? Both the x and y ints are 0, so 0/a + 0/b != 1.
What should I do over the next two days to prepare for the exam.
I've ran out of exam 1's..
Why can't I substitute in numbers for x and y to get k? 25.7 = k/(0.44^2). The answer I got was C; H = 4.98/d^2. I substituted in the x coordinate H = 4.98/(0.44^2) and the answer is 25.7, the y value in the question. What am I doing wrong? And can you help me with question 8? Thanks you so much!!
Hi
Could someone please explain Q.3a (matrices module) from last years exam 2?
I've read the examiners report but still don't understand it!
I thought element 0.4 (row 2, column 3) in matrix T would have some role in the answer??
I'll try explain this as best as i can, in the first transition matrix, you see that 10% of B changes to C before C withdraws, That's clear right? You can see from the matrix.
Next, in the second matrix, which depicts what would happen after Mr Choi withdraws, 10% would split equally, 5% will go to A (10% to 15%) and 5% to B (80% to 85%), you can see how the 10% would split equally between A and B, right? since 5% of a total 10% goes to B, 5/10 * 100 = 50%
Oh I get it! Thank you so much! I was struggling with this question for so long :)
You can't substitute the coordinates to find k here, because it's plotted as H against 1/d^2, if you had the original graph, which would be H against D, you would be able to use it to find the coefficient. Since you have the transformed graph, you'll need to find the K using the gradient of the straight line.
Question 3 from VCAA 2010 Exam 1, please! :)
Oh I get it! Thank you so much! I was struggling with this question for so long :)
I've explained this one before! I think Latex is being weird though so if the worded explanation isn't enough I'll re-do the working out. :)
Although I'd also like to add since doing that the first time I've run into this rule which I think was mentioned in the itute and VCAA solutions:
(x/a) + (y/b) = 1,
where a and b are the x and y intercepts, respectively. (pretty sure it's relevant ::) )
Definitely above 90%. No more than a couple of marks each exam, it gets pretty competitive above 40
EDIT; Fixed the link ::)
The images aren't loading for me :(
Here's copied but without the latex, hopefully that makes it readable :)SpoilerThis one was actually kind of tough - I checked out the examiner's report and the itute solutions and neither of them really gave a clear, step by step explanation on how to do the question - although itute was a bit better than the VCAA.
Because Z is maximised at the points M and N, we can say that Z(m) and Z(n) are equal. For that to make much sense though, we need to know the coordinates of M and N. They're pretty clear on the graph as long as you work out the the interval is 5 (and maybe have a ruler to double check your points line up) but if you really wanted to you could set up some simultaneous equations to find them, too.
In any case, the coordinates of M and N are (20,50) and (45,25) respectively. We can set up two equations/functions for Z with this information:
Z = 20a + 50b (M)
Z = 45a + 25b (N)
Because we know Z has to be equal for both M and N to find a and b, we can quickly throw out some of the options that would give us something ridiculous - this means we don't have to worry about either of the options with negative values (A, E) and can probably get away without checking that D fits our rules because the numbers are pretty different to A, B and C. (Note: With multiple choice questions, you can usually eliminate two options after reading the question or minimal working out: in this case it was D and E)
So that leaves us with option B and option C to check, like so:
B. Z = 45*15 + 25*15 =1050
B. Z = 20*15 + 50*15=1050
We can already see that these are equal (and therefore, B is the answer), but let's check C to be sure we haven't messed up somewhere:
C. Z = 45*15 + 25*25 =1300
C. Z = 20*15 + 50*25 =1550
So B is our answer - of course some of the constraints I set were maybe a little too general (option A could've probably been a reasonable choice) but in the end, there's only five equations to check so realistically you probably wouldn't need to set any at all.
Can you guys help me with question 7 Matrices from Further Exam 1 2013?First you need to consider how you would get the mean in a set of data. (Think back to Core Module.)
Hi, could someone please explain VCAA 2013 Exam 2 Graphs and Relations question 4? specifically, 4ei and 4eii? I've read the examiner's report but I don't really understand it still.
Thanks!
Hi, could someone please explain VCAA 2013 Exam 2 Graphs and Relations question 4? specifically, 4ei and 4eii? I've read the examiner's report but I don't really understand it still.
Thanks!
For 4ei, you take your answers from the last part (4d/4c) and apply the rules they give you in the question. ($60 per powered, $30 per unpowered)
The cost function that comes out of that is:
cost = 60x + 30y
Then we just sub in our two minimums from 4d to find the lower cost;
(2,9) cost = 60(2) + 30(9) = $390
(3,8) cost = 60(3) + 30(8) = $420
So clearly (2,9) is the real minimum of the function, with the lowest cost being $390
For 4eii,
I'm not 100% sure on the logic, but here's itute's solutions which are a bit clearer than the VCAA's.
For this question, you'd obviously have to refer to the solution region in the graph, you can see that there are some integer points that could be solutions in your graph right?
Since in this context we're talking about an integer number of things (power and unpowered camps) we really can't have the maximum at the corner vertex, since we're more than likely to get a decimal amount of camp sites, which is impossible.
By looking at the solution region, you can see the smallest integer number of powered and unpowered camp sites will occur at either 2,9 or 3,8. Anything beyond below that is a decimal or not in the solution region so it has to be one of those two points. using the objective function 60x+30y you find that the point 2,9 gives the minimum cost which is $390.
For question 4 eii you have to understand that since all girls have to use one campsite and all boys have to use one campsites, it means that there are 24 boys at powered campsite and 24 girls and unpowered camp sites. powered campsites carry 6 people, 24/6 = 4, so X must equal to 4 powered campsites required is = 4. Unpowered campsites carry 4 people, 24/4 = 6. unpowered campsites required would be 6.
So look at the solution region, you see that 4,6 isn't in that region and it has to match constraints y => 2x, to match this constraint y= 2* 4 and so y must = 8. so the points we have now are 4,8
Now just find the cost using the objective function 60x+30y, and you get 480$.
It's a bit long but i hope you understand..
EDIT: So MightyBeh beat me to it :P
How do you tell the difference between cyclic and random variations in time series? I understand seasonal variation has to have regular intervals between the peaks and troughs, but is it possible for it to get confusing with cyclic sometimes as well?
Hello again guys,
Heres a matrices question aswell as a core one..
For the core one i have no idea why the answer gave would best suit the stem and leaf plot, as i believe distance travelled would be a better answer...
For the matrices one, i have only seen this question once, and im confused on how to do it. If anyone has any idea on the theory behind it, or atleast the method of solving any question like that, i will be grateful.
Hello again guys,
Heres a matrices question aswell as a core one..
For the core one i have no idea why the answer gave would best suit the stem and leaf plot, as i believe distance travelled would be a better answer...
For the matrices one, i have only seen this question once, and im confused on how to do it. If anyone has any idea on the theory behind it, or atleast the method of solving any question like that, i will be grateful.
For the Matrices one, you want to know how many eggs, baby trout and adult trout, that could be added or removed at the pond of each year will allow the population to remain constant.
For this question you firstly have to find S1 and once you do that you takeaway S1 from S0. Basically S0-S1 Once you found that difference, you know that if you add that amount every year, the population will remain constant.
Not great at explaining that one, but if you need further explanation let me know.
EDIT: Law already answered :P
Okay i understand the core one, thanks to both of you,
But for the matrices one, what does it mean for the population to remain constant? i assume it means like a steady state so the values wont change at all from one year to the next, but when i subsitute these new added values into the S0, the values change yet again? Im pretty sure i can just always use S0-S1 if the question comes up, but id like to understand what it means as ill understand it easier,
Thanks :)
You can't substitute the coordinates to find k here, because it's plotted as H against 1/d^2, if you had the original graph, which would be H against D, you would be able to use it to find the coefficient. Since you have the transformed graph, you'll need to find the K using the gradient of the straight line.
How do you guys do those weird matrices questions? The ones with m and n and whatnot. I always find myself guessing them in the end. (Usually MCQs).
Thanks!
How do you guys do those weird matrices questions? The ones with m and n and whatnot. I always find myself guessing them in the end. (Usually MCQs).
Thanks!
Hey. I found a worked solution for an insight exam 1 for a transformed data (as you can see in the attached image) they just substituted in points instead of finding the gradient. So confused about this! Please help anyone.
How do you guys do those weird matrices questions? The ones with m and n and whatnot. I always find myself guessing them in the end. (Usually MCQs).
Thanks!
Always think about these type of questions as y=(any variable) multiplied by x. For the sake of this question. Lets make this variable (k)
In this question y is plotted against x^3.
The rule connecting y and x would thus be y=kx^3.
We got coordinates in the graph= (8,2)
We sub these points in= 2=k8.
Now when we sub x in= It is not 8^3 its simply 8 because its already cubed. And the rule is y=kx^3
So solve(y=k x 8,k) and k equals= 1/4.
Thus y=1/4 times x^3. We can simplify this to x^3/4.
Thus y=x^3/4.
That is C.
You can't substitute the coordinates to find k here, because it's plotted as H against 1/d^2, if you had the original graph, which would be H against D, you would be able to use it to find the coefficient. Since you have the transformed graph, you'll need to find the K using the gradient of the straight line.
This is what TheMereCat said:
Is the moving average smoothing technique affected by outliers ? For this reason would it be more advantageous to use median smoothing if outliers are present ? Thanks :)
Here is variable matrices question from the past 3 years. Do you want me to post more?
hi all,
here's a question from NEAP 2006 graphs + relations (Q10):
shouldn't b, c and e all be suitable options, according to the circle of transformations? i'm a little confused at NEAP's explanation, i don't remember learning anything like it in class.
thanks!
For Question 9, is the question incorrect?
Since residual = y-ypredicted.
Shouldn't you have to use the equation, then square root the value to find y, then do 2-2.5
to get something close to ~0.5?
apparently the answer is B, and they squared the y value- minus y2 predicted value....
need help with this question from paper 1 VCE 2013 : Module 1 Number Patterns, Question 8.Put this sequence into the calculator and check when it starts to become constant.
Question 8
The initial rate of pay for a job is $10 per hour.
A worker’s skill increases the longer she works on this job. As a result, the hourly rate of pay increases each
month.
The hourly rate of pay in the nth month of working on this job is given by the difference equation
Sn+1= 0.2×Sn + 15 S1= 10
The maximum hourly rate of pay that the worker can earn in this job is closest to
A.
$3.00
B.
$12.00
C.
$12.50
D.
$18.75
E.
$75.00
Would you ever need to find outliers of bivariate data? If so, how would you do it?Yeah, but it's more likely to be an Exam 1 type question and unlikely to appear; chances are they'll ask for the residual from a given point with a given equation (see above two posts for an example).
Thanks, AngelWings! Super nervous about tomorrow! :/
Another question:
VCAA 2012 Q6 from Geo&Trig:
I got it wrong and understand that it has to do with linear and volume scale factors. But the reason I got it wrong was because I did the following:
V=((pi) x (r^2)) x h
V2=((pi) x (3r^2)) x 3h (3r)^2 not 3(r^2) I think just having a quick look
This gave me 9( (pi) x (h) x (r^2) ).
Then I just subbed in (pi) x (h) x (r^2)=V, and got 9V.
What did I do wrong?
Thanks, AngelWings! Super nervous about tomorrow! :/
Another question:
VCAA 2012 Q6 from Geo&Trig:
I got it wrong and understand that it has to do with linear and volume scale factors. But the reason I got it wrong was because I did the following:
V=((pi) x (r^2)) x h
V2=((pi) x (3r^2)) x 3h
This gave me 9( (pi) x (h) x (r^2) ).
Then I just subbed in (pi) x (h) x (r^2)=V, and got 9V.
What did I do wrong?
Thanks, AngelWings! Super nervous about tomorrow! :/
HiFor question 13:
Can anyone please help me with question 13 (core) question 9 (number patterns) and question 9 (matrices) from 2014 exam 1
Thank you :)
Can someone explain Q12 (CORE) from VCAA 2014?I've actually done this one in detail before and asked anybody who didn't know how to do it to PM me, but I guess I'll put it on the forum for you all, 'cause I'm feeling nice.
Cheers!
You guys have worked hard (I assume), so you guys have nothing to worry about. Try your best, breathe, be prepared and smash it out of the park.
While you're on that paper, n.a, have a look at Q9 of the Geometry section.
For VCAA 2008 Further Exam 1. Core question 10. What's the difference between multiple choice's D and E?
Hey guys, i get a bit confused with questions that give data and ask how it's best displayed? Can anyone help with what each method of displaying data (box plots/bar charts/histogram etc) are used for ??My understanding:
In the five number summary, when stating the maximum, can it also be an outlier?Yep! (so can the minimum)
I've actually done this one in detail before and asked anybody who didn't know how to do it to PM me, but I guess I'll put it on the forum for you all, 'cause I'm feeling nice.
Quick Question- When applying a log transformation to linearise the data, do we you natural log or log base 10?base 10, it should be the default on the TI if you leave the field blank. :)
base 10, it should be the default on the TI if you leave the field blank. :)
What's the consensus on mean vs. median? Doing a check on my bound reference and it's not there.
Is it just outliers/skew = median, symmetric/no outliers = mean?
Yeah no extreme values/outliers and skew means you should use meanAwesome, thanks <3
And for extreme values/outliers and skew you should use median.
I'm taking a protractor and ruler into the exam as a final resort (bearings questions). I struggled to do VCAA 2013 Geo & Trig Q8, and I got the right answer by double checking with a calculated sketch.We can bring in a protractor? I swear bearings will be the last thing I see ::)
We can bring in a protractor? I swear bearings will be the last thing I see ::)
Crap. I don't have a protractor. I'll have to do with what I've got.
From the VCE exams navigator booklet:
"Basic stationery items do not include...or geometrical drawing instruments such as compasses, set squares, and protractors."
What's the difference between a cyclic variation graph and a seasonal variation graph? I swear they look the same
What's the difference between a cyclic variation graph and a seasonal variation graph? I swear they look the same
this video explains it pretty well (I saw a link to it on another further maths thread):
https://www.youtube.com/watch?v=ca0rDWo7IpI
Can someone tell me the answer for q9 of graphs and relations pwease.
this should probably be an exam discussion thread I'm guessing but oh well
I got C (point R)
Hi, can anyone tell me how to solve question 3b. in the matrices module of the vcaa 2010 exam 2 paper?
Anyone still got that 3-Median formula?
Anyways...Thanks everyone for all your help! I wish you all good luck, and I wish you all the best. I hope to meet you all one day, you're a great bunch of people!
-Orson
I've just started the core for statistics. In regards to histograms, I'm unsure of what data I need to put into the set interval on the CAS. How do I know what my HStart and HStep should be?yo fam you dont need to worry about that, all you need to do is cntrl + menu --> graph fit --> fit to data (i think, its been a long time so i might of mixed it up) and you're set) unless the question is very specific, but i doubt it would be
Help would be muchly appreciated!
Could someone please help me with the following problem on seasonal indices:
To correct for seasonality, the actual number of bathing suits sold in Autumn should be:
The seasonal index of Autumn is 0.4
The answer is an increase of 250% but if we must take 250% of the actual figure to get the deseasonalised values isn't this an increase of 150%?
Thanks in advance
I always do 100/seasonal index to show how much to increase or decrease.
So 100/0.4 = 250, which means we must increase by 250%
But what happens to the original 100% which is already accounted for?
But what happens to the original 100% which is already accounted for?
Where is this question from? :)
I think the answer should be an increase of 150% or 250% of the original seasonal index.
It is from chapter 6 review of Cambridge. I understand how it is an increase of 250% but if the 100% is already accounted for I can't see why it isn't an increase of 150%.
The answer is wrong.
As you suggested, the answer should be an increase of 150% :)
For this question attached.
how do you find q1 and q3.
Because the median is the average between the dots i have circled in red ?
so which dot do i use as the median then?( in order to allow me to find q1 and q3) ?
When two values are the median, you take the value that is halfway between both of them. Therefore, your median would be 2.
So instead of circling both the medians, put a line between them. Then, just count the dots and find your Q1 and Q3 as usual :)
For the distribution attached .
the answer says The outliers are at 5, 8, 36 and 40.
However when you check for the lower fence you get 6.
therefore 8 shouldn't be a outlier right?
so the outliers should be 5,36 and 40 right?
Yes, the outliers should be at 5, 36 and 40.
The box plot is incorrect. You might also notice that the upper fence should be at 30, however the whisker seems to extend further than this. This question is completely wrong :)
Thanks for clarifying Peanut Butter :)
the further book literally has so many errors !!
also when we mention these outliers can we say their values directly?
or do we have to say that they are possible outliers and then state their values ?
You have used the formula to prove that the values are outliers.
You can just say something like: the data contains outliers at 5, 36 and 40
Does that answer your question? :)
How would you go about answering these types of questions as attached?
the answer says b) On average, brand A batteries have longer and less variable lifetimes.
Like how do they determine the above answer ?
Brand A has a higher median than Brand B. Which means on average they have longer lifetimes. ( I should be quoting medians here..this is why i didnt get a 50 in further lol)
Brand B has more variability than A. Roughly Brand B has variations from 18-52 hours compared to A's 22-50 hours. Thus on average Brand A batteries have longer and less variable lifetimes.
Always express the answer with numerical proof.. vcaa made a point about that sometime ago.
What is the question asking you to do if it says 'compare'? E.g. Compare the mean and standard deviation to the median and IQR for the sample. Btw, I haven't done further maths 1/2.Probably just a short comment on the differences - the mean/median are measures of centre and in a symmetrical distribution they should be about the same. A mean significantly different from the median usually implies a skew and/or outliers. Standard deviation with the IQR seems a bit odd though, since the numbers don't really line up (1sx is 34%, IQR is 50%). A comment on whether the mean or median is more appropriate for the data is mostly optional but a good idea most of the time.
What is the question asking you to do if it says 'compare'? E.g. Compare the mean and standard deviation to the median and IQR for the sample. Btw, I haven't done further maths 1/2.
Does anyone have any practice sacs they could send over on the first couple of chapters of core?? Or know where I can get any? thanks
I'm the same! I would really appreciate some recent SACs if possible! Especially any tips about Excel in regards to the statistics SAC.I find it extremely impossible that the whole state can't help a sister out :o
I find it extremely impossible that the whole state can't help a sister out :o
We would if we could. Check up the Legal section of the rules for AN forums and you'll actually find out that practise SACs are actually school property and copyrighted. To avoid copyright issues and what not, we cannot supply practise SACs.
I can suggest that you check up old VCAA exams, such as 2002-2005's Exam 2 for Excel-based SACs.
For Core, I would advise any Core modules in practise exams from other places besides VCAA, such as TSFX, TSSM, Heffernan and so forth. I would also recommend Checkpoints, StudyOn and (AN's own) ExamPro books as good resources to test your knowledge, as well as other Further textbooks. An alternative would be to make your own.
Hopefully those resources will keep you going for a while.
Thanks for the clarification, I was unaware of this until now. :)
What modules is everyone doing?
I'm doing:
1) Number Patterns
2) Graphs and Relations
3) Matrices
Hey guys,
I don't understand how I got this question wrong. Aren't 0, 1, 2, 3 and '4 or more' categories for the number of DVD players? How are they numerical variables if there are only 5 things (categories!) that we can choose from? What's the difference between these requirements and a list of ordinal categorical requirements?
Cheers :)
P.S: link to image, in case you can't see the attachment: http://i.imgur.com/BJg4Oqv.png
Hey guys
I was just hoping someone would explain to me what the difference between seasonal and cyclic time series data is.
I was just hoping someone would explain to me what the difference between seasonal and cyclic time series data is.
The difference between seasonal and cyclic time series data is that with cyclic time series there is no regular periods between peaks.Actually, seasonal variation has roughly regular intervals that repeat within a year or less, whereas cyclic is a repeating pattern beyond a year (though the trend can be much more vague, as Senor said).
Hi guys,As for recursion and financial modelling, I can suggest that you try more related Checkpoints questions to keep up to speed. Check up some more questions online - I'm sure you could find a few with a quick search. Unfortunately, it's been a long time since I studied this, so I'm afraid I'm not the most helpful person on AN.
Any general tips and revision strategies for recursion and financial modelling?
I have a SAC for this core topic coming up in mid-may.
I haven't started this topic at school as of yet.
Thanks
Hi, could someone please explain "Correcting for seasonlity"? I don't understand how or why it's used.
Here's a question I'm stuck on:
The seasonal index of January is 1.2 and the actual sales figure is 9.6.
To correct the actual monthly sales figure for seasonality we need to:
A) decrease the actual sales figures by around 20%
B) increase the actual sales figures by around 20%
C) decrease the actual sales figures by around 17%
D) increase the actual sales figures by around 17%
E) increase the actual sales figures by around 80%
Thanks in advance :)
"To correct for seasonality" means to basically get a seasonal index of one. So you want to go from 1.2 to 1. Since the SI is getting lower, it must be decreasing (therefore the answer has to be either a or c).
To figure out the percentage:
(1.2-1)/1.2 * 100 = 17 %
That formula ^ is pretty much the difference in seasonal indices over the original seasonal index. Does that make sense? :)
Hey could someone please tell me if by smoothing the time series, do we try to remove seasonality and random fluctuations in the time series, or just the random fluctuations????
Any help would be great
How does the lack of a clear pattern in a residual plot support the assumption that the relationship between the RV AND EV is linear?
Hey,
I can't give you a very technical answer, but if there was a clear pattern (such as a U-shaped curve) it would suggest that the points would be better suited to a non-linear model.
Check out this website, it explains it better than I can :D : http://stattrek.com/statistics/dictionary.aspx?definition=Residual%20plot
How does the lack of a clear pattern in a residual plot support the assumption that the relationship between the RV AND EV is linear?
I can't give you a very technical answer, but if there was a clear pattern (such as a U-shaped curve) it would suggest that the points would be better suited to a non-linear model.Just an addition to Clarke54321's post quoted above, 'randomness' is generally needed to cancel out positive and negative residuals, as such, a +5 residual would be cancelled out by a -5 residual and so forth.
Check out this website, it explains it better than I can :D : http://stattrek.com/statistics/dictionary.aspx?definition=Residual%20plot
Just an addition to Clarke54321's post quoted above, 'randomness' is generally needed to cancel out positive and negative residuals, as such, a +5 residual would be cancelled out by a -5 residual and so forth.
Hey guys, it would raeally be appreciated if you guys could tell me an estimated study score for these results:
Sacs: B+
Exam 1 A+
Exam 2: A+
So far, I am doing terribly for sacs but am doing really good for practice exams, but I have a weak cohort that will probably struggle in the exams but do alright on the sacs, meaning my ranking will be around 5-10 and my sacs will probably scale down. I would really just like to get an estimate on my study score. Hoping to get above 40. Btw, I am in year 10 so if I screw up further, do use think it would be worth me repeating it in year 11 along side methods 3/4?
Hi, can someone please explain how to do this recursion question? I don't get how you can go from u(n+1) to u(n-1). Thank you :)
Hi, can someone please help me with "How does an outlier affect the r value (correlation coefficient)?"Remember that r is for classifying the strength of a linear relationship, and it's calculated using every point of data that you have. On top of that, the mean and the standard deviation are both pretty heavily affected by outliers (mean will be much higher/lower, standard deviation will be really high when it shouldn't) so the correlation coefficient is pretty useless if you include outliers.
How would you describe a time series trend using "general terms"?
How would you describe a time series trend using "general terms"?
Hey guys, how do you know if a scatterplot has an outlier? Are you meant to be able to tell simply by looking at the scatterplot or can the correlation coefficient indicate the presence of an outlier/s?
Hey guys, how do you know if a scatterplot has an outlier? Are you meant to be able to tell simply by looking at the scatterplot or can the correlation coefficient indicate the presence of an outlier/s?Hey Minerva,
Hey Minerva,
Just to add on to Clarke, I believe it is a bit of both. What I usually do is doing 2 calculations to find the correlation coefficient; one with outlier and one without. If your coefficient shows an extreme change than you are 100% confident that it is an outlier. This method just gives you that extra oomph in knowing you're right :')
Hi all,
I have my recursion and finance SAC coming up this week and just have a question.
When finding the rate for compound interest loans and investments the model is 1+ r/100, whilst the model for reducing balance depreciation is 1-r/100. Could someone please explain the significance of the 1.
Thanks
My interpretation of '1' is simply the 'original' amount (1 = 100% = the original or principal amount).
Take into consideration the brackets (1 + r)
If the interest rate is 5%, then its 1 + (5/100) which is 1.05, MEANING the original amount (100%) plus an additional 5% = 105% = 1.05. Then of course, 1.05 is multiplied by itself however many periods/years.
Ali invested $26,000 into an account earning compound interest at the rate of 4.5% per annum. After 5 compounding periods, the value of Ali's investment will be $26,614.86 correct to the nearest cent.
The annual interest rate is compounding
A) weekly
B) fortnightly
C) monthly
D) quarterly
E) annually
Guys, how do I go about doing this one?
Definitely missing something simple here. The answer is A but I keep getting something completely different.
For this question attached i have a query.
i got the equation as Vn=(0.918)^n x Vo
now we know V10=13770 therefore Vo=32397.17399
the book says the initial cost is $32397.17
however i rounded up and said the initial cost is $32397.18
reason is because when you sub my initial cost value into the equation you have a value of at least $13770.
where as when you sub in the books initial cost value into the equation you have a value of less than $13770.
Who would be right in this case and whats the best thing to do in these situations ?
This rule for the effective interest rate(attached) is for when n is the number of times the interest compounds each year.
What if in a question something is depreciating instead of compounding , whats the rule then?
Would it just be
Guys, how do I go about doing this one?As a.t has said, there is an error here if we say there are 52 weeks in a year (which is what I expect VCAA would want you to assume; although 52 weeks is only 364 days.)
Definitely missing something simple here. The answer is A but I keep getting something completely different.
For this question attached i have a query.The book value after 10 years is likely to have been rounded to the nearest ten dollars. Therefore, it would make more sense for the question to ask for the initial cost of the machine rounded at least to the nearest dollar, if not the nearest ten dollars. You would expect greater clarity in a text book and I would think an exam question would avoid the issue. Given all this, I would round the answer here to the nearest cent.
i got the equation as Vn=(0.918)^n x Vo
now we know V10=13770 therefore Vo=32397.17399
the book says the initial cost is $32397.17
however i rounded up and said the initial cost is $32397.18
reason is because when you sub my initial cost value into the equation you have a value of at least $13770.
where as when you sub in the books initial cost value into the equation you have a value of less than $13770.
Who would be right in this case and whats the best thing to do in these situations ?
This rule for the effective interest rate(attached) is for when n is the number of times the interest compounds each year.The study design only links the topic of effective interest rates to investments or loans. Therefore, I don't think application to depreciation is an issue to worry about.
What if in a question something is depreciating instead of compounding , whats the rule then?
Would it just be
The book value after 10 years is likely to have been rounded to the nearest ten dollars. Therefore, it would make more sense for the question to ask for the initial cost of the machine rounded at least to the nearest dollar, if not the nearest ten dollars. You would expect greater clarity in a text book and I would think an exam question would avoid the issue. Given all this, I would round the answer here to the nearest cent.
The study design only links the topic of effective interest rates to investments or loans. Therefore, I don't think application to depreciation is an issue to worry about.
The format of the formula for effective interet rate is slighly different to what VCAA has published on the new formula sheet in their sample exam papers for 2016. Find this on the VCAA website on the same page as you would look to find past further maths exam papers.
How would I answer the attached financial maths question?
Thanks for your help :)
Can someone help me with the attached question? The answer is 144652 L but I got 142237.Your figure is after 6 days, the answer is 144652L.
Hi can someone please help me with this question
How to work out the annual depreciation if they give the initial purchase price?
Hi, can someone show me how to do this Geo & Trig question? ThanksFirst find the radius of the "parallel" (the line of latitude) that passes through both cities.
Calculate the shortest distance from Newcastle, Australia (latitude 33°S, longitude 153°E) to Mendoza, Argentina (latitude 33°S, longitude 72°W), correct to the nearest kilometre.
The answer is 15 080km.
Hi all,
Is there a correct number of cuts you can apportion to a network? What I mean is, can VCAA take marks off if you have done, say 6 cuts, when there were supposed to be 5 made?
Sorry, I hope this makes some sense. :)
Hi everyone,
Does anyone have advice on how to work out these types of questions with efficiency? Or networks in general?
Thank-you in advance :)
I stuffed up my recursion and financial SAC. I got 79% on it and also got 92% on my data SAC. I was wondering whether it was still possible to achieve a 40 ss in further?Yes
Hi guys, how do I find the area of this triangle using one of the 3 methods from Geo&Trig?
Thanks! :)
Cheers, just a question: how do you know that 5mm is perpendicular to b // it's a 90degree angle?Oh I assumed that. If that wasn't the case then we actually don't have enough information to find the area.
Can anyone please help me with this question?Unique solution means when you only get one answer. So for simultaneous equations that means when you only get one set of coordinates for when the lines intersect. Easiest way to do it is to put it in the CAS to solve the equations simultaneously.
Hi Guys,
How is this graph planar? Even when rearranging the edges so that they don't intersect wouldn't they still cross due to their positioning?
Thanks :)
Hey guys,
Just wondering in Bearings if it says find A from B do we start at B?
Hey everyone,Let's consider two separate samples taken:
Can someone please explain to me why the mean is greater than the median for positively skewed data and vice versa for negatively skewed data.
Thanks very much! :)
The mean is pulled in the direction of the extreme scores or tail (same as the direction of the skew)
This is a question from the Sample exam.
Consider the following four statements. A permutation matrix is always:
I a square matrix
II a binary matrix
III a diagonal matrix
IV equal to the transpose of itself.
How many of the statements above are true?
A. 0
B. 1
C. 2
D. 3
E. 4
The answers say C, which is 2. But I've done some calculations and found that Statement IV (A permutation matrix is always equal to the transpose of itself) is true.
I'm confused about this..
Anyone that can help, it would be appreciated.
Thanks :)
Hey, can someone show me how to put this question in matrix form? thanks :)
Hey guys
If I need to make a boxplot and a I have outliers on either ends of the boxplot, what will my min and max value be? Do my tails go up to the value in the lower fence which is the minimum and the same for the upper fence?
Hey,That helped!
If you have outliers, these will count as your min or max value. If you don't have outliers, the ends of the tails will be your max and min.
I hope that answered your question! :)
That helped!
What if I have outliers, where will my tails extend to?
If you have outliers, your outliers will be beyond your tails.Thanks!
However, in some circumstances, you may be given a diagram of a box plot where you have single points beyond your tails. In this case, you cannot just assume that they are outliers. Here, you must apply the upper and lower fence formula (Upper Fence: Q3+1.5*IQR and Lower Fence Q1-1.5*IQR) to work out if they are outliers.
Thanks!
Also, how can the standard deviation be used when comparing data distributions in terms of centre and spread?
If one data distribution has a higher standard deviation than the other, you could conclude that this distribution is more variable than the other. This is because it will be moving further and further away from the mean.Thank you!!
In terms of centre, mean would be a more appropriate measure as opposed to standard deviation.
The solutions from Itute:Does anyone know if this question involves an inverse relationship? Itute solutions gave a negative answer in their solutions...... This is from the sample exam for the new Further Maths study design.Q5a
Question 5 (4 marks)
There is an association between the variables population density, in people per square kilometre,
and area, in square kilometres, of 38 inner suburbs of the same city.
For this association, r2 = 0.141
a. Write down the value of the correlation coefficient for this association between the variables
population density and area.
Round your answer to three decimal places.
Thanks! :)
population density = population / area,
inverse relationship between population density and area, .: r = − sqrt(0.141), approximately − 0.375
Q5a
population density = population / area,
inverse relationship between population density and area, .: r = − sqrt(0.141), approximately − 0.375
Im assuming r2 refers to the correlation coefficient of determination. In this case the correlation coefficient will be the square root of the r2 value. It is only negative if the scatter plot has a negative skew. A negative skew would look like a linear function with a negative gradient. :)
A bit of a stupid question I guess but in relation to the attached question, my understanding is that the 6 wouldn't be counted because its heading from the sink to the source and hence would be: 8+4+11=23
But its multiple choice and the options are: 4, 11, 14, 21, and 29.
So, in all cases should I definitely be counting the 6 thereby getting 29?
Hi Coffee,Thanks, Clarke. I was a bit confused since in the textbook it said not to if it was moving upwards like in the above example. ???
Yes, you should be counting the 6 to obtain 29.
Thanks, Clarke. I was a bit confused since in the textbook it said not to if it was moving upwards like in the above example. ???
Hope you guys don't mind me asking another question (this one is a bit lengthy). I'm mostly confused by the wording of the question and what its actually asking me to do.
1. The Houndsworth Town Sports Association is planning a sports carnival. Traffic through the town will be diverted around the sporting venues during the carnival. The network (attached below) shows the road that can be used during the carnival represented by the edges and intersection of those roads shown as vertices.
The number on the edges are the maximum number of cars that can travel on the road each hour. The roads will be restricted to allow one-way traffic only, as shown by the arrows.
a. How many cars per hour can enter the diversion roads?
I'm guessing this is just asking from A - B, thus 180? But correct me if I'm wrong.
One cut (Cut 1) is shown on the diagram above.
b. i. If the capacity of Cut 1 is 150, what is the value of m?
ii. Show that the smallest value of m that will ensure there will be no build-up of cars at intersection B is 50.
The capacity of the road between intersection B and intersection E is 50 (m = 50). The maximum flow through the network is currently 150 cars per hour.
c. Mark in the cut that determines the maximum flow on the network above.
I don't quite understand how m = 50? I thought it would just be 150-130=20.
The Sport Association have noticed that there could be a build-up of traffic at intersection E and F.
d. If the road between intersections F and H was improved, what is the maximum capacity is should take to the solve the potential traffic build-up at F?
In order to solve the potential build-up of traffic at intersection E, the Sports Association open another road from intersection E to intersection D.
e. i. What is the minimum capacity of this road that will avoid traffic build-up at intersection E?
ii. Explain why a road between intersection E and D cannot solve potential traffic build-up in the network.
Super sorry for the incredibly lengthy question, I'm just really confused about what the hell its asking me to do and how to go about getting there.
1. a. I think you're right but not 100% sure.
b. i. You're right, the answer is 30
ii. The inflow to node B is 180 which comes from the source, which means to prevent congestion the outflow cannot exceed 180. We already have 90+40=130 so m has to be maximum of 50 so that the cut doesn't exceed 180.
c. The cut goes through 30, 40 and 80.
d. The inflow is 100 and the outflow is only 80 which is 20 less. So we should increase it to 100.
e. i. The inflow is 50 and the outflow is only 30 which is 20 less. So the new road from E to D should be at least 20.
ii. I think it's because there's still some congestion at other intersections in the network, for example the outflow of C is 100 which exceeds its inflow of 90. Not 100% sure.
Hope I helped.
Hi everyone,I think postcodes are ordinal as you can put them in order e.g. 3000, 3001, 3002 etc
I understand that postcode is a categorical variable, however, is it nominal or ordinal? Can you please explain why?
Thanks!
Hi guys,Wouldn't that just be 5800
How would I go about working out the following question?
1. The ovens and other equipment in Phillip's kitchen have been depreciated using a flat-rate depreciation method. A recurrence relation that models the value of the kitchen equipment after n years, Vn, is shown below.
Vo = 5800, Vn+1=Vn-350
a. What was the original purchase price of the kitchen equipment?
Thanks :)
Wouldn't that just be 5800
Haha, is that legit what its asking me? ;D :P I'm so sorry, I overthink these things man.
How many marks can you afford to lose in both further math exams in order to score an A or an A plus :p?
Hey guys,Not sure if this was unintentionally unanswered but for a major segment, you're better off doing this.
can anyone pls help me out in finding an area of a major segment?
Hi guys,
I was just wondering, when comparing parallel box plots, what would it imply if there was a statement saying "the test scores in Box plot A, on average were higher, than the Box plot B"
"the median of Box plot A is higher than the median of Box plot B"
Alright, but is the median the only factor you could discuss. I understand it is the main one though.
Thanks :)
"the median of Box plot A is higher than the median of Box plot B"A box plot gives you information on the min, lower quartile, median, upper quartile and max. You can infer range and IQR by extension.
Alright, but is the median the only factor you could discuss. I understand it is the main one though.
Thanks :)
Hi everyone,
I understand that postcode is a categorical variable, however, is it nominal or ordinal? Can you please explain why?
Thanks!
According to the 2016 VCAA Sample Exam it's nominal although according to the ABS website it's ordinal (which makes sense IMO).
According to the 2016 VCAA Sample Exam it's nominal although according to the ABS website it's ordinal (which makes sense IMO).My bad! I can see the arguments for both :P
My bad! I can see the arguments for both :P
How about age? Is it discrete or continuous cos ive seen questions with differing answersIf you're going to round to, say, the nearest year, then it is discrete.
What's your argument for it being categorically nominal?I'm leaning to ordinal, someone who thinks it is nominal would probably argue better than me.
I'm leaning to ordinal, someone who thinks it is nominal would probably argue better than me.
I guess you could argue that you can't really put locations in order, as that is what postcodes represent.
:) This a question from the sample exam issued:
"There is an association between the variables population density, in people per square kilometre, and area, in square kilometres, of 38 inner suburbs of the same city.
For this association, r^2 = 0.141"
This is the solution:
population density = population/area , inverse relationship
between population density and area, .: r = − sqrt(0.141) ≈ − 0.375
So basically, what does it mean by inverse relationship. Our textbook never really explained that. Also how can you tell if the r value is negative or not since there is no scatter plot to determine it.
Hey,
I questioned this too!! It's so odd, I've never seen a question like this without the actual scatterplot or some further information.
Can someone pls explain this question to me? Correct answer is BThis looks like some kind of question I'd get in microeconomics regarding production possibility curves...
thanks!
I have a few questions regarding NEAP Exam One 2016. The question are attached below.
CORE
Question 18: The answer I got is C ($2440). I entered the following into my CAS.
N: 120
I: 5
PV: 23000
Pmt: BLANK
FV: 0
Ppy: 12
Cpy: 12
The solutions say that A is the correct response. Is this a mistake?
Question 24: The answer I got is A ($16.12). However the solutions gave B. I am not entirely certain about the correct way to work this one out, but I entered the following into my calculator.
N: 60 and then 1825
I: 5
PV: 25000
Pmt: 0
FV: BLANK
Ppy: 12 and then 365
Cpy: 12 and then 365
Have I made a mistake?
Geometry and Mensuration
Question 4: I'm not entirely certain how to go about answering/visualising this question. I got the correct answer (D), but I don't really understand the scenario where there are different longitudes and latitudes for each coordinate. How should I visualise this?
[img]https://s13.postimg.org/iy1e4m2ab/Question_18.jpg[/img]
[img]https://s13.postimg.org/tm553gc9f/Question_24.jpg[/img]
[img]https://s13.postimg.org/xfylcltlf/Question_4.jpg[/img]
How would you do this question attached ?
Answer is E
A is true because the humidity was increasing for 7 of the days out of the total 10.
C is true as the humidity was above 50% for 5.5 days out of the total 10.
D is true as in both days 2 and 3, the humidity increases by 20% (day 2 is represented by the second column, day 3 is represented by the third column)
E is not true because on day 7 it decreases by 15% and on day 9 it increases by about 15%.
I didn't even bother checking B but E is obviously not true therefore it's the answer.
For everyone doing graphs and relations:
Theres a question about a chick selling coffee. Now, it asks for the break even point, which i calculated to be 71.2.
However I was just wondering since you cant sell 0.2 of a coffee, would you round the breakeven point. In the answer it says 72,
I wanted to know in which cases you have to round the break even point. And also how would you know whether to round it up or down?
Round up for pretty much everything. 71.2 coffees is pretty inarguably more than 71.0 coffees, but like you said you can only sell whole coffees so you need to round up. It's pretty much a context check; you should generally be able to tell how you should round by thinking about the question. :)
As for whether to round up or down, it depends on what's the better outcome. In this case selling more coffee is the better outcome in terms of profit so you round up. It's a bit like those normal distribution questions about running or golf or whatever, where it's better to have lower numbers. Alternatively looking at it on a graph is a pretty easy way to tell what you should do.
If you don't get a 50 in further you have to be pretty dense
I got 45 last year and nearly killed myself
If you don't get a 50 in further you have to be pretty dense
So True andy i was really upset with my score too :'( :'(Given that two of you registered like an hour ago and the three of you have been making stupid posts on this thread and in this thread, I can only assume you thought it'd be a hilarious time to troll ATAR Notes etc etc. Fair enough, each to their own, right? But I'll tell you one time: stop being stupid or I'll just call your school and ask them to tell you the same.
does anyone know how to do this?
http://i.imgur.com/ADjS053.jpg
Hi everyone,
If a question in the Financial and Recursion module asks how many months will it take to fully repay the loan and the answer is 18.25, for example, do I round this up to 19 months (even if it says round to the nearest whole number)?
It makes sense for this to be the case as a loan can't be fully paid in those 18 months.
Thanks! :)
Hi Everyone,
How do you know if three mean smoothing is more appropriate than four mean smoothing from a table of data?
Also, is study score a continuous or discrete data value?
Hey guys,
Can someone help me with this question? the answer is B
Hi Moaning Myrtle,Yeah, I had a feeling it might've been. Thanks for the help.
Anyone please correct me if I'm wrong, but I believe this question relates to the old study design. Effective interest is still examinable in the current one, but it's applied differently from the previous Business Maths module.
Yeah, I had a feeling it might've been. Thanks for the help.
Also, are annuities and perpetuities a 'type' of interest-only loan?
How would you go about this question?
Hi,
I have written out some solutions. I'm not sure if it makes sense. But in any case the answer is 2 which is C.
If you apply a transformation to a variable, let's say 1/y=3.73+3.1456x, and the question asks 'what is the dependent/response variable', would you say y, or 1/y
I havent read anything that confirms it directly, but I was doing a trial in which I was given an equation with a transformed variable.
The question was asking for the r^2 sentence, and the answer had the variable written in the transformed state eg. Log(death rate).
Can someone kindly help me with this? :)
Hey,
Would it just be 1.53/9= 170g?
OMG, im such an idiot. I read it as 'mean weight instead of total weight'.
Regardless, I love you clarke legit. Always answering my questions <3
?
Moderator warning: Please contribute more to your posts in the future.
Hey,Hey anything with deposits involved is from the old study design yeah?
I'm 95% sure that this is from the old study design. Someone correct me if I am wrong, however.
?Others say this is on the old study design but I'll take a crack anyway. $3000 deposit means we have already paid $3000. Therefore we must pay $12000 off the loan.
Moderator warning: Please contribute more to your posts in the future.
Out of curiosity, where did the question come from?
Hi,
Does anyone know the real difference between saying that a time series plot is irregular or has no trend at all? Also, what is a secular trend?
Another question I have is the attached finance one. Could someone please help.
Thanks! :)
If you lose 3-4 marks in total over both exams, can you get a 45?
If you lose 3-4 marks in total over both exams, can you get a 45?Yeah, but go in with the mindset you won't lose any! ;)
Also, Clarke54321, what's the answer for the finance question you attached?
(http://uploads.tapatalk-cdn.com/20161024/9ec3e03145d2f9719993693568904170.jpg)
Hey guys, can someone pls explain part B. I did it but my answer is differing quite a bit from the solutions itute provided.Spoiler(http://uploads.tapatalk-cdn.com/20161024/845a8f9b135bb621f1dbc5584bcc549a.jpg)
Hey,
Itute are wrong!!! I had this same problem, but their solutions to this question are wrong except the first part.
Omg, thank god!!! I was so worried bc my answers were completely off.
Was your answer for the part b i $802.48?
I think my answer was $802.47 instead of .48. I might have just rounded wrongly! :)My teacher was telling us that bc it says minimum u would have to round up to .48?? Does that make sense?
My teacher was telling us that bc it says minimum u would have to round up to .48?? Does that make sense?
Also, what was your answer for part c? I got 802.53
For Exam 2 (V3), Q4 in Section A I got y=7.72664+7.70152x but according to iTutes it's 7700+7700. Does anyone know where I might have gone wrong?Is this from the sample exam? Can you attach your question so we can see what you're talking about?
For Exam 2 (V3), Q4 in Section A I got y=7.72664+7.70152x but according to iTutes it's 7700+7700. Does anyone know where I might have gone wrong?
Is this from the sample exam? Can you attach your question so we can see what you're talking about?Attached below :)
Also apparently itute's solutions are wrong.
Yes the equation should be y=7.7+7.7x, itute's answers are wrong.Ok, I just asked my teacher and apparently I need to multiply it by 100?
Attached below :)Your answer is right, I don't think you need to multiply it by 100. Itute's soloutions are wrong!!! I think this question was previously in the 2012 or 2014 paper, so if u go there u can see that 7.7 is the right answer
Ok, I just asked my teacher and apparently I need to multiply it by 100?
Also, for the following question I get 7700+7700log(90)=22747.7 but according to iTutes it's 23000. Am I wrong?
Your answer is right, I don't think you need to multiply it by 100. Itute's soloutions are wrong!!! I think this question was previously in the 2012 or 2014 paper, so if u go there u can see that 7.7 is the right answer
Would the variable 'roadworthiness' (i.e. either roadworthy or unroadworthy) be classed as nominal or ordinal data?Nominal, don't think it can be ordered
Thanks :)
Hi!
With the financial solver do you always round? So if you get a future value that you have to put in the present value box do you use the whole number or the rounded number?
Thanks
The seasonal index for heaters in winter is 1.25 to correct for seasonality, the actual heater sales in winter should be? A) reduced by 20% B)increased by 20% C) reduced by 25% D) increased by 25% E) reduced by 75%Do 1/1.25= 0.8
Use exact values, only round for the final answer - and to however many decimal places that it says.
Is it true we have to use pen on the exam 2?
Is it true we have to use pen on the exam 2?
In regards to rounding again, im so confused on what to do?!?
Our teacher sent us this from VCAA: "In general, only unrounded answers should be used for subsequent calculations. However, rounded answers should be used in financial modelling if this answer represents a physically payable amount. Dollar values can only be ‘paid’ if they are at most 2 decimal places. If a financial solver returns, for example, a repayment amount of $156.7643256 then this must be rounded to $156.76 for any future calculations using the solver. This is different to calculations in other areas, for example, geometry where it is appropriate to use multiple decimal places for calculated quantities that are used in future calculations."
So do we round or not in financial calculator when taking fv to pv for another calculation?
The seasonal index for heaters in winter is 1.25 to correct for seasonality, the actual heater sales in winter should be? A) reduced by 20% B)increased by 20% C) reduced by 25% D) increased by 25% E) reduced by 75%The way I do it is, you need to reduce 1.25 to 1... So you need to decrease it by 0.25. 0.25/1.25 = 20%, therefore A, reduce by 20%. :)
In regards to rounding again, im so confused on what to do?!?Hey I kind of get what vcaa is saying. For eg if u had a payment of -43.26738 then ur fv would be 0. But to find the extra payment that u need to pay, u need to make ur Payment -43.27 to find the amt of money left. Bc it'll be a tiny number the decimal places make a huge difference.
Our teacher sent us this from VCAA: "In general, only unrounded answers should be used for subsequent calculations. However, rounded answers should be used in financial modelling if this answer represents a physically payable amount. Dollar values can only be ‘paid’ if they are at most 2 decimal places. If a financial solver returns, for example, a repayment amount of $156.7643256 then this must be rounded to $156.76 for any future calculations using the solver. This is different to calculations in other areas, for example, geometry where it is appropriate to use multiple decimal places for calculated quantities that are used in future calculations."
So do we round or not in financial calculator when taking fv to pv for another calculation?
Can anybody please detail their explanation to this question!Working's attached. Really you just need to repeat pythagoras' theorem a few times, but there might be a faster way that I neglected.
Thanks.
Working's attached. Really you just need to repeat pythagoras' theorem a few times, but there might be a faster way that I neglected.
Hiya! If anyone could give me guidance on this question regarding one and two step dominance matrices, I'll repay you with a giant watermelon :']
⇉Click here for the question⇇
Hiya! If anyone could give me guidance on this question regarding one and two step dominance matrices, I'll repay you with a giant watermelon :'](http://uploads.tapatalk-cdn.com/20161027/e5c18527c9bb730faae95524fdbd8bac.jpg)
⇉Click here for the question⇇
For this question attached i got the answer C, but answers say B who is correct ?Hmm for this don't you have to add your payment value to the 'extra value' and that will be ur final payment?
For this question attached i got the answer E, but answers say D who is correct ?For this one, I think you are right. The Answers must be wrong
Could someone please help me out with the attached questions? I'm not sure what formulas I'm supposed to be using :-\The answer for 7d is to be done separately. So it says after 2years. First find out what the flat rate depreciation would be (you already did this in part a). Your answer is $6000. So, it's saying that the value MUST be the same, meaning that the value has to be 6000. So just plop this in ur cas solve(6000=8400-0.25n,n) n will equal 9600. Meaning when the bike has travelled 9600 km, it's value will be the same as flat rate depreciation after 2 years.
Thanks, guys!
How would you guys approach 2010 MC question 3If you look at the histogram it looks like a bell curve meaning the normal distribution rule can be used. Your mean is 180, and 180 keeps increasing or decreasing by 2. Hence 2 is ur standard deviation.
It basically asks for the standard deviation when it gives iqr and a boxplot
Hmm for this don't you have to add your payment value to the 'extra value' and that will be ur final payment?
But if the question is asking for the 'extra payment' then I think C is correct
For this one, I think you are right. The Answers must be wrong
For this question the answer should be C) 40km right ? not what the answers have (D)
For this question the answer should be C) 40km right ? not what the answers have (D)Yup the answer should be c. It must be a typo from the solutions
For this question attached i got the answer C, but answers say B who is correct ?
Yeah it should be 40km, D! :)
Yup the answer should be c. It must be a typo from the solutions
Thanks for confirming :) cant believe these exams have these many errors !!!( thank god for you guys ;) :))AHahahh, most company exams have many mistakes
I got B.Really? Can you pls post your explanation for B?
AHahahh, most company exams have many mistakes
Really? Can you pls post your explanation for B?
Using finance solver:Omg I feel so stupid now. I think my fingers became a bit too excited bc I swear I remember putting the same values in :/
N: 35
I%: 3.85
PV: 42000
Pmt: -1260
FV: -760.18
PPY/CPY: 12/12
The person still needs to pay the bank $760.18
Omg I feel so stupid now. I think my fingers became a bit too excited bc I swear I remember putting the same values in :/
Hey Again,Because the order is 3 * 2, C is out. The i and j are 'coordinates' of the matrix, so we can eliminate another two be checking the first element of the matrix, where (i,j) -> (1,1). Adding the i and j components like given in the rule gives us '2', which means A and D are not the correct answer. Comparing the remaining B and E, the first element that differs is at (2,1), which means the value should be 3, Eliminating B. The only option left to choose is E. :)
This question... how do you do it? Apparently the answer is E according to VCAA. :(
For this question attached and solution.You added in an extra 3 at the end
shouldnt sum of frequencies = 2+4+6+3+11+5+3+3=37
=> (31/37) x 100=83.78 %
How did solutions get sum of frequency as 34?
hahahahahahaI think the exam will be easy bc it's the first year of a new SD, but I'm not sure. I'm just going to go with my gut feeling in the exam
do you reckon the vcaa exam will be relatively easy. im kinda scared now, i cant afford to drop any marks
How do u do this whole question...it's on 2016 vcaa sample exam?Click this link, most of the answers are there
If i lose 1 mark on this exam, and 3-4 on the next one, what study score would i be expecting
Hihi
Financial question here, would like the steps involved ^^
NEAP 2016 Exam 1
Q24
A loan is taken where there are no repayments until the end of the 5-year period.
How much extra interest is charged when the compounding period is changed from monthly to daily on a loan of $25,000 at 5%pa?
(A is 96.88)
The answer is supposed to be $16.12 (according to my teacher).Yeah got it! Thank you c:
Hopefully that is what you are getting. Otherwise I can write up the solution for you :).
Yeah got it! Thank you c:An example of confounding V
'Nother question though:
What's the difference between confounding and coincidence correlation? An example would be nice too (http://i.imgur.com/V3d9HPx.gif)
An example of confounding V
(http://uploads.tapatalk-cdn.com/20161027/6d9d16cddfe0ab3ccf4021c3b3dccbd3.jpg)
And coincidence is just coincidence. I remember there was an example in the book about people that like cheese usually gettin divorced. But does liking cheese cause getting divorced? Nope, it's purely coincidental!
Wait is that a part of the course? Haven't seen it in past VCAA exams. :S
i got D it seems like an equal amount of people got either D or B..Yeh I got D as well initially then looked in my cambridge essentials textbook and saw this :o
Yeh I got D as well initially then looked in my cambridge essentials textbook and saw this :oPost this in the further exam discussion thread. It'll prove useful to a lot of people as this question stumped many
what do you peeps think?
Where can I find the further exam discussion thread?Click on this link
I'm really disappointed .. I just found that I've made 4 wrong answers. I have an A average in SACs and assuming that I got an A on Exam 1, is it still possible for me to get a 40?Yes
:o whar study score should I expect to receive with the number 1 ranking for sacs (99/100) with exam 1 37-38/40? Maybe a 59/60 for Exam 2
(http://uploads.tapatalk-cdn.com/20161028/5d76f23d0e4397effc2a229195eaec87.jpg)Seems fine to me. :)
Guys is the inequation for part b x> (or equal to) 2y ??
How do you guys think we should study for exam 2? Just do more practice exams? Not really sure what else to do, I feel like I've done enough already ::)
I don't see why the Further kids have to miss out on their own question thread! Post anything you're stuck with here and we'll try our best to help you out.
It might be a good idea to sticky this thread, just like the Methods and Specialist ones.
I was wondering for the first question I attached, my teacher says you round to 19 but others say round to 18 payments as it is the 'nearest whole number', unlike 19. Please help!!!
I need help with crashing in NETWORKS, my teacher doesnt know it and i dont either.
I was wondering for the first question I attached, my teacher says you round to 19 but others say round to 18 payments as it is the 'nearest whole number', unlike 19. Please help!!!
quick question. On the VCE 2015 further written exam 2.
Can someone explain the question 3e on the networks module to me and how the answer is 33 minutes, 7 minutes increase?
I don't understand why you just won't just go to F and H again. and rather divert? It is because of the mention of least effect?
Cheers
Write down the ESTs for each activity on your new network (with the dummy activity) and you'll find out that the completion time increases from 26 to 33. I was actually confused about that question too until I did that.
hey, can someone please help me with this question? I've attached a picture underneathNot 100% sure I'm correct, so let me know if it's wrong. ::)
question: Find the shortest distance along the surface of the bowl between C and D where CD is the diameter of the water surface, to the nearest whole centimetre.
Where would you place the dummy activity? my critical path remains to be 35
Hey, can someone please help me with this question from VCAA 2014 Exam 2 (Q3b from the business module): The cricket club had invested $45 550 in an account for four years. After four years of compounding interest, the value of the investment was $60 000.
Interest on the account had been calculated and paid quarterly.
b. What was the annual rate of interest for this investment?
Oops I thought you were talking about a different question. So basically you want to finish B and D first because it takes a total of 12 minutes as opposed to A and C which takes a total of 13 minutes. Right after that you can do D (because we know C and D can't occur at the same time), then F and H and I as in the normal critical path. So you end up adding 3+9+8+6+3+4 which = 33. It's a difficult question and kind of hard to explain, sorry if I confuse you.
Enter N=16, PV=45550, Pmt=0, FV=-60000, Ppy=Cpy=4 and you'll get annual interest rate to be 6.948, round to 6.9%.
Oops I thought you were talking about a different question. So basically you want to finish B and D first because it takes a total of 12 minutes as opposed to A and C which takes a total of 13 minutes. Right after that you can do D (because we know C and D can't occur at the same time), then F and H and I as in the normal critical path. So you end up adding 3+9+8+6+3+4 which = 33. It's a difficult question and kind of hard to explain, sorry if I confuse you.
Enter N=16, PV=45550, Pmt=0, FV=-60000, Ppy=Cpy=4 and you'll get annual interest rate to be 6.948, round to 6.9%.
Ah, can't believe it was that easy. Thank you!
I understand it all but isn't it when finding the critical path you are looking for the longest path? then wouldn't you go A - C rather than B-D? when going B-D you would still have to do C. As it dose not specify with C or D must be done first
No worries.
A critical path is usually the longest path because you can't complete the project without completing the longer duration activities first. But this isn't a typical critical path problem.
"when going B-D you would still have to do C" - that's why you do C right after completing B and D? If you do that you'll realise that all activities are able to be completed in 33 minutes hence it's the critical path (in this circumstance where C and D can't be completed at the same time).
It doesn't specify if you go with C or D first because you have to figure out which one will have the least impact on the minimum completion time. If you go with C first as you suggest, then the path would be A-C-D-F-H-I which is 5+8+9+6+3+4=35. Which is obviously more than 33.
Can someone help me with this pls?
Alright I was at Tudor and my Tudor was talking about how someone forgot to shade in what module they were doing and they got zero that section . I JUST REALISED I TICKED THE BOX INSTEAD OF SHADING ( the area where it has 4 boxes and u choose your module) but I did write down what module it was in the box and it was ticked. Will I be penalised or am I just overreacting ??? :-X
Multiple Choice is all computerised so if it does not pickup that you shaded in the box it will give it an error and not sure what happens next - maybe goes into a pile with others that manually need to be checked with the written module and marked that way, I'm not too sure ???.
Fkk shitting bricks now :-\Speak to your VCE co-ordinator or equivalent at your school, the earlier the better. I'm sure you'll be fine.
Can someone help me with this pls?
Alright I was at Tudor and my Tudor was talking about how someone forgot to shade in what module they were doing and they got zero that section . I JUST REALISED I TICKED THE BOX INSTEAD OF SHADING ( the area where it has 4 boxes and u choose your module) but I did write down what module it was in the box and it was ticked. Will I be penalised or am I just overreacting ??? :-X
I got the same answer as EdwinJS (Bank B charges less interest) but I got a different amount for Bank B.
Got the same amount of interest of $360409.60 for Bank A.
For Bank B enter:
N:120 (10 years)
I: 5%
PV: -$500,000
PmT: $3585.04
FV: $266,811.57
PpY: 12
CpY: 12
I think EdwinJS is wrong in thinking that the loan payment changes or that it has to continue for another 10 years because it doesn't say that anywhere (in the brackets it says which loan will incur the least interest and time) Enter:
N: 78.47
I: 7%
PV: -$266,811.57
PmT: $3585.04
FV: 0
PpY: 52
CpY: 52
Add 78.47+120 to get total loan amount of 198.47 months. 198.47*3585.04 = $711537 total repayments for Bank B loan. 711537-500000 = $211537 interest incurred on Bank B loan.
So Bank A's loan incurs $360409.06 interest in 240 months. And Bank B's loan incurs $211537 interest in about 199 months.
I agree that you can't assume that the loan goes for another 10 years once the rate changes to 7% but I don't think you can assume that the payment will be 3585.04 per week. Is this guy loaded with money?...That's about $14000 payment per month. I'm not sure if this is realistic???
Can someone help me with this pls?Thanks for the help guys!
Thanks for the help guys!
The solutions provided -->(http://uploads.tapatalk-cdn.com/20161029/ce1ea6a256bddf5ab53d8ff75f008991.jpg)
Ive had a question in a MAV exam where its asking if the variable "age of graduates" (in years) is discrete or continuous. I thought it would be discrete as age in years can be counted, but the suggested answers say continuous. Whos right?Age is continuous. Technically you are only say 18 years old for 1 second, after that you would be 18 and 1 second, 18 and 2 seconds etc, so your age is not "18" but 18.xyz etc
Not 100% sure I'm correct, so let me know if it's wrong. ::)
Ive had a question in a MAV exam where its asking if the variable "age of graduates" (in years) is discrete or continuous. I thought it would be discrete as age in years can be counted, but the suggested answers say continuous. Whos right?
Hey, do we need to know average rate of inflation, GST and capital gain for tomorrow's exam or is it part of the old SD for financial? I have come across a few of these questions from past exams. Thanks :)
I've just had a look at this question on the exam and I believe it to be continuous. It does not explicitly state "age in years". You cannot automatically make these assumptions unless it is explicitly stated in the question. Age could be any sort of value, such as 18 years old or 18 years and 6 months (which would be 18.5). Even though in most cases we as people really just round age down to the nearest whole number, we cannot ignore the fact these values actually exist.
I would say no, given these aren't mentioned in the revised study design for 2016. Here's the study design if you want to have a look further. Cover the points listed: http://www.vcaa.vic.edu.au/Documents/vce/mathematics/MathematicsSD-2016.pdf
I guess if you REALLY wanted to protect yourself, you could always include just the different formulas at the back of your bound notes.
Heyyy, was just wondering how to do the last question on this about final payment??? (forget about my working out i think its wrong)Forgive me/correct me if I'm wrong! My brain's a little fried from today.
Forgive me/correct me if I'm wrong! My brain's a little fried from today.Working out9.a) I think is 71 repayments as on finance solver:
N =? (70.81)
I = 5.4
PV = 230,000
Pmt = -3800
FV = 0
Ppy =12
b) After two years so n = 24, then FV becomes 160089.82
Interest = annual rate/ months/100 x this
Interest = 5.4/1200 x 160089.82 = 720.40
Therefore amount that reduces principal = payment - interest
= 3800 -720.40
= 3079.60
c) After two years (24 payments) we saw he still owed 160089.82
So use finance solver to find new repayments over 10 months
N = 10
I = 5.4
PV = 160089.82
Pmt = ? -> 16,407.87 damn he rich
FV = 0
Ppy = 12
d) Find the balance on the second last repayment (9th month, to determine the payment on the tenth) so
N= 9
I = 5.4
PV = 160089.82
Pmt = 16407.87
FV = ? -> $16334.39 owing
Ppy = 12
Tenth payment
Interest + 16334.39
Interest = 5.4/1200 x 16334.39 = 73.50
Tenth payment = $16407.89
THOUGH, I have no idea if I'm right LOL. Someone help x]
It feels like I looked into it too hard to only be marked 1 point per question..
For some reason I can't do this question, save me!
Invested $45,550 for four years. After four years of compounding interest, the investment was $60,000.
Interest had been calculated and paid quarterly.
What was the annual rate of interest for this investment?
-snip-Thanks!
Hey can anyone come up with 5 generic terms on how to describe the general pattern of some statistics/ describing the shape of the distributionNot sure if this is what you're looking for?
Thanks :)
Not sure if this is what you're looking for?
Negatively skewed, positively skewed, symmetric with outliers
Example for comparing two data sets:
Male and female results are, on average, approximately the same. Both have a mean of around 14.5 However, the males' results are more widely spread. The standard deviation of the males is 2.8 compared to 1.6 for the females. Female results are symmetrically skewed, as shown by the stem plots.
Or for regression?
Positive/negative
Linear/non-linear
Strong/moderate/weak association
With outliers
Time series?
Seasonal, cyclic, structural change, random fluctuations, increasing/decreasing trend...
Example for time series:
The time series plot shows an increasing trend between the quarters March 2013 to June 2014. There is a structural change between June 2014 and September 2014 when the number of commuters jumps dramatically.
There is an increasing trend between September 2014 and December 2015.
Hey, does anyone know where I can find 2016 Further exam 2?Right here :)
hey guys, i just picked up unit 3 further without a foundation in 1/2 and in the first chapter they asked: Comment on the shape of the histogram. What does this tell you about the distribution of this data set? We had to draw a histogram on CAS which seemed like it was all levelled. Anyway, I have no idea what kind of shapes histograms can be and what a distribution of a data set is (as well as potential answers), can someone please explain :) Do histograms make up a big part of core? thanks so much!
Thanks Aaron!
Can anyone solve this question too: The pH scale measures acidity using a log (base 10) scale. For each decrease in pH of 1, the acidity of a substance increases by a factor of 10. If a liquid’s pH value decreases by 0.7, by how much has the acidity of the liquid increased? I somewhat understand using log base 10 but not when it comes to pH, is this also a big part of core? Thanks again :)
What is the trickiest part of further
Hi, I got 93% on my first further maths SAC. Has that ruined my chance of getting a study score of 50?
Hi, what types of percentages in ur sacs do u need for further to get 40+ :D
Is there a quick and easy way to do seasonal adjustment on CAS (ti-nspire). I find it takes a lot of time solving by hand.
Standard Deviation : 10
Mean: 40
What is the range of the top 97.5%?
[Note] I understand you must go 2 standard deviations down so the bottom of the range is 20 however I don't understand how many you go up. As 3 up there is still another 0.15% on the top, so do you go 4?
Moderator edit [Aaron]: Thread merged with VCE Further Question Thread.
For this question: Sketch a negatively skewed distribution with mean 50 and standard deviation 10, how do I know that it is 2 standard deviations from the mean and 95% of the data is within the range of 30 and 70?
Need help with 4 b)
(http://i64.tinypic.com/dfdiip.jpg)
Help with question 2 please if possible
How do you find moving mean smoothing, median smoothing and seasonal indices on the cas?1.
Also can someone explain how to graphically median smooth a time series?
Thanks
According to my 2014 Further cheat sheets for calculating seasonal indices:Like smoothing, it will either be fill the blank or use sections of the data. If the question supplies very little information (typically a number or two), then it's likely a deseasonalising question, where the formula is deseasonalised value = actual value/ seasonal index .
"Step 1: Calculate monthly/ quarterly/ yearly/ etc. average of data [by using the 'mean' function or by fraction symbol.]
Step 2: Express each as a decimal for each figure e.g. Data/ average = decimal [press menu + 2 + 1* for decimal if fraction.]
Step 3: Average ratios from step 2, to get each season's index...
The seasonal indices in the table above should add to how many seasons/ cycles it has, due to its intervals."
Not exactly quick, but should be slightly faster than by hand. Hopefully that helps.
* According to the TI NSpire black and white screen (black calculator) that I had. Should still be similar on other models.
Any tips and tricks on a bound reference for sacs and end of year exam?
Should i include all the important formulas at the front or go from chapter by chapter?
Thanks
Depends on you. My preference is that I left cheat sheets at the beginning with a contents page, then individual notes in the back, chapter by chapter. Remember that you won't have much time to flip through looking for specific things, so it's smarter to leave important formulas together somewhere.Tips and Tricks - Bound ReferenceI would recommend:
1. getting started on this ASAP, because you won't want a massive looming task at the end of the year.
2. making it fit the requirements listed by VCAA. (You must anyway if you plan on bringing one.)
3. using different books for theory and textbook questions to save time.
4. buying yourself some sticker tabs or a pack of highlighters to mark out chapters.
5. organising it how you can understand and easily read it. It's worse if you can't read your own notes when you're stressed.Those should be more than enough to help you for now. :) If you need a sample page, Engage Education has some great free samples or PM me and if I have the time, I'll send one over.Tips and Tricks - SAC cheat sheetsI would recommend:
1. make it short and sweet.
2. keep it colour coded and consistent.
3. write calculator tips and leave an example where you see fit, especially if you're iffy with a concept.
Any tips and tricks on a bound reference for sacs and end of year exam?
Should i include all the important formulas at the front or go from chapter by chapter?
Thanks
Where can we find the free samples from engage? I cant seem to find themLooks like it's currently under renovation. So sorry about that. I didn't know. I think it'll be up and running again soon.
Hey! Does anyone have any old practice SACs (or just any practice questions in general) for data analysis that they could post?We can't post old practise SACs as these are the legal property of the school or person. I can, however, direct you to Checkpoints and ExamPro, which will provide great practise questions.
We can't post old practise SACs as these are the legal property of the school or person. I can, however, direct you to Checkpoints and ExamPro, which will provide great practise questions.
What kind of things do we have to write about when describing a time series plot and a smoothed time series plot? What kind of things about the graph should we focus on? Also do we have to write our descriptions in any specific way?
So I have a SAC coming up next term for Data Analysis, and whilst preparing for it, I've noticed that I am repeatedly getting answers ever so slightly wrong due to rounding. I think it is because I generally round during working out, and not only my for final answer. Does it really matter if you round during the working out? or are you meant to use the un-rounded values until you give your final answer?Or does it simply not matter?
Is 64 pages for my bound refrence to small?
You should create a bound reference that is right for you. There is no guideline to the amount of pages your bound reference should be.Yeah but it dont know what is right for me and how many pages is right for me
Ideally your bound reference acts as a support in your exams, so it should not be too detailed. A good starting point is completing a few VCAA exams using only your bound reference (the sections you have been taught at least) - this will indicate whether it needs some finetuning.
Keep in mind that each exam is only 90 minutes duration, so you won't have time to sit there and go through your bound reference in detail. It goes very fast.
Yeah but it dont know what is right for me and how many pages is right for meIf you are a detailed person who loves having notes with you/ started it with detailed notes and are carrying through with it, I'd say 64 pages is not enough. If you are less worried about detail/ haven't got many notes in it right now, then 64 pages will suffice. It will depend on you.
Im really concerned i will run out of pages and have to dopy evreything to another textbook whch is extremely tedious
If you are a detailed person who loves having notes with you/ started it with detailed notes and are carrying through with it, I'd say 64 pages is not enough. If you are less worried about detail/ haven't got many notes in it right now, then 64 pages will suffice. It will depend on you.So how do i attach more pages to them
I would attach extra pages in case. My bound reference from Further actually has about 15 blank pages at the end in case I was ever going to add more details. Although there is no precise number, it is better to have more than less for now. (Just make sure you know how much is blank.) There is no loss in binding more pages, because you can tear them out later (and recycle them). If you really want a numerical answer: whatever you end up with by the time you finish your content + another 5-10 pages for exam questions you did wrong during practise.
Hi, im doing some transformations stuff and am having trouble with getting an answer back out of the equation.Hey, whatwas the original question?
To put it simply, the transformation i did was 1/y vs x and it turned out to (-1.441e-5) + x(2.34e-5)
how do i get an answer out of this? it needs to be somewhere around 6 thousand to make sense in the data.
the original least squares regression line was 1151.58 - 411.8x.
any help is appreciated.
Ok so when u fill in that data of the age of corola which should be on the x axis as it is the explanatory response and the prive should be the y as it is the response variable you should see. Non linear line that goes straight that curves to the right, therefore according to the forumlas you need you change your x axis by 1over x or your y axis by 1/yaxis or your x axis by kig x ir tour yaxis by log y.
Im going to change my x acis to 1/x and you will see that it is now linear. Remember to do this you go back to list and spread shits and add a new collum and call it xsq as it cant be x which would be the same name as the x column. and underneath it press = 1/xand select variable refrence and you should see a list of values
Then go back to your graph and change the x axis by clicking on it to 1/x and then press menu-analyze-regression-show linear and thats your equation, plug in 10 to the x in that equation and u have your answer for 5c.
(Yep so my equation was y=15399.3x + 2683.59
So how do i attach more pages to themTaping pages in is fine, iirc. I would double check the guidelines on VCAA and with your teacher in case. Pretty sure I did this with my Methods one.
Taping pages in is fine, iirc. I would double check the guidelines on VCAA and with your teacher in case. Pretty sure I did this with my Methods one.How about cutting at the red line?
In my opinion though, I would recommend that you just add a small stack of blank printer paper to the end, tear off the cover of your bound reference notebook and get it properly bound at your local Officeworks or favoured binding place for a few dollars. (It's almost always under $10, even with the fancier backings and spines.) If it is one of those books where the pages are hard to tear because they were originally A3 pages (usually your average < $1 exercise book), such as this or these, then cut at the crease where the spine is so you actually have separate A4 pages before binding.
hey
i am stuck on the attached questions, any help will be appreciated.....
thanks!
How about cutting at the red line?Should be just as fine. Might make it a little harder to read some of the notes beside the red line when bound, but whatever floats your boat. :)
heyLooks like Hungry4Apples has you covered for this!
i am stuck on the attached questions, any help will be appreciated.....
thanks!
Hey there,Could you give an example? It sounds like it's fine though. If it's something along the lines of 'the coefficient of determination of 0.9284 (92.84%) indicates that ...', I can't imagine you'd lose marks. :)
if I write out the coefficient of determination (r^2) as both a decimal and a percentage, is that okay?
I did so in my SAC today, and I'm feeling very anxious as to whether I lost a mark for that or not.
Thanks!
Could you give an example? It sounds like it's fine though. If it's something along the lines of 'the coefficient of determination of 0.9284 (92.84%) indicates that ...', I can't imagine you'd lose marks. :)
If I can remember clearly, the question asked to specify the coefficient of determination, and then interpret it. What I did was write out 'coefficient of determination = 0.642 or 64.2% and then in the next line, I interpreted it using 'the coefficient of determination of 64.2% indicates that...'That's perfectly fine! You should get full marks for that. :)
Hello again,
so today in my SAC - I used both the correlation coefficient and the residual plot to suggest the superior predictive model.
I recognise that using the coefficient of determination is the right way, but yet again - the pressure under SAC conditions eats away at me.
Is using the correlation coefficient alright, or was I meant to use the coefficient of determination? Thanks.
Hey everyone!!!Its ultimately your exam scores that determind your study scores. I've heard alot of people getting good or bad study scored only to get completley different study scores to what they got in their ss
I did my first SAC and got a 70/80 (88%) . I was rank 4 ans was quite surprised with my score (and rank!) as I had not done the last chapter in time for my SAC
However I was curious, can someone tell me their SAC marks and exam marks- ans what overall study score did you get?
What do I say for 'Which prediction from part d and c is more reliable ?No, its rekated to the r value which is the correlatin coeffection. A higher r value means its more accurate. The correlation coefficient is a measurement of the strength of a linear relationship which is the x and y axis.
is it related to intra/extrapolation.
Can someone help me with this ASAPresidual value is the original value - predicted value
Really dont get it
"In 1990 18.4% of the population in Belarus were obese whereas in 2010 17.1% of the population were obese. Calculate and interpret the residual value when the least square regression line is used to predict the 2010 from 1990. Round to 1 decimal place.
- Have the 1990 and 2010 data sets on my calc
Can someone help me with this ASAP
Really dont get it
"In 1990 18.4% of the population in Belarus were obese whereas in 2010 17.1% of the population were obese. Calculate and interpret the residual value when the least square regression line is used to predict the 2010 from 1990. Round to 1 decimal place.
- Have the 1990 and 2010 data sets on my calc
HOW WOULD I GO ABOUT ANSWERSING THIS I DONT GET WHAT IT MEANS???
'interpret the vertical intercept of least square regression line in terms of variables 1990 and 2010"
i have the data for 2010 on 1990 on my calc
Mod Edit [Aaron]: Posts merged. Double posting unjustified.
I had this exact same question on my sac.Thank you so much legit lifesaver! dont know of this is too much of a ask but im so lost, what would you say for the interpt part of the question
so you do
17.1%-(8.1+0.93*18.4%)
=-8.112x-8.1
Can someone help me with this ASAPThe vertical intercept estimates the average vlaue of the response variable when the explanatory variable equals 0
Really dont get it
"In 1990 18.4% of the population in Belarus were obese whereas in 2010 17.1% of the population were obese. Calculate and interpret the residual value when the least square regression line is used to predict the 2010 from 1990. Round to 1 decimal place.
- Have the 1990 and 2010 data sets on my calc
HOW WOULD I GO ABOUT ANSWERSING THIS I DONT GET WHAT IT MEANS???
'interpret the vertical intercept of least square regression line in terms of variables 1990 and 2010"
i have the data for 2010 on 1990 on my calc
Mod Edit [Aaron]: Posts merged. Double posting unjustified.
I had this exact same question on my sac.Also where did you get the 8.1+0.93 bit?
so you do
17.1%-(8.1+0.93*18.4%)
=-8.112x-8.1
I had this exact same question on my sac.
so you do
17.1%-(8.1+0.93*18.4%)
=-8.112x-8.1
I had this exact same question on my sac.I dont know what the regression line is since i dont have the data but whatever it is you put the 1990 obesity rate in the x.
so you do
17.1%-(8.1+0.93*18.4%)
=-8.112x-8.1
Also where did you get the 8.1+0.93 bit?
my least sq regression line equation was y=6.24+0.993x
with y being twentyten and x being 1990
Thank you so much legit lifesaver! dont know of this is too much of a ask but im so lost, what would you say for the interpt part of the question
? thanks again all good if you can't answer xxxx
The way my teacher interepreted it was 2010 is expected to be 8.1% for a 0% in 1990
for working out the vertical intercept i did 17.1%(6.24+0.993x18.4%)Whats the original question
=-7.4
would this be correct?
Also for the residual question i did
original=17.1%
predicted=6.24+0.993(18.4)
=24.5
residual=actual-predicted
=17.1-24.5=-7.4
Got the same answer for both? feel like I've made a mistake somewhere?
---
"Comment on the improvement or otherwise of each of the transformed equations compared to the original equation (y=6.24+0.993x) . Use mathmatical reasoning to support your comments"
Ok so i found that the orginial equation y=6.24+0.993x had a higher r2 value than the others it was 0.800 and th other transformed questions y2=0.57
logx=0.53
and 1/x=0.26
so based on this the orginal is an imporvment but im not sure on the wording or how to explain this? Anyone know how i would go about it?
Mod Edit [Aaron]: Merged double post again.
Hey guys,
I was wondering whether or not we need to include units when giving residual values?
AND
when we write linear equations do we have to write it in terms of the variables?
as in deseasonalised sales=39 + 23xtime period
or can we just do y=mx+c (if so would we have to first define the variables?)
thanks
Hi,
Could someone help me out with question 11, b (recurrence relations):
Really just need someone to explain how its done... The question is attached below
Thanks a heap xD
So it asks for the first seven terms u0 being the first. You simply sub in the previous u value to find the next. I think where you are getting confused is to do with the n-1 part.
All you need to think about is finding the terms, so for u1, you need to sub in u0, since n=1 so n-1=1-1=0
so the first seven terms are, 6, -5 (-6+1), 6 (--5+1), -5, 6, -5, 6
The pattern repeats because it is -u(n+1), so the negative makes a negative a positive
Same technique applies to part 2
This is probably a very dumb question!! But finishing my further sac today and later discussing with my friends left me very worried about this lolThis is always the tricky part because the 'rules' of significant figures actually vary a little bit between people, let alone in VCE - and this is one that changes between people. I'd say that would normally be 2 significant figures, but some claim 3 for this. If you don't get the mark for it, it's something that can be argued with your teacher and possibly won. They usually do give a little leniency when it comes down to small things like that, with around 1.0 error either side where rounding errors would've occurred. It'll be best if you ask your teacher whether 150 is 3 significant figures or not. (If I were in the same position, I probably would have written 1.50 x 102 to avoid the issue altogether.)
Say I obtain a value of 150.3 and need to round it to 3 significant figures. How would I go about that? I ended up rounding it to 151 but many of my friends rounded it to 150 (which is 2 SF's?), and I took my textbook in too which is what I based it off but some of them told me the textbook itself is wrong. Some rounded it to 150.0 but isn't that 4 SF's?... I ended up asking my physics teacher and he said it seemed odd to round it up to 151.
I'm probably overthinking it but would love a clear answer to this!!
Hi,Have you tried substituting n=2 and using your value for u1 into the equation? If not, give it a go. The rest may come after you go forwards and backwards with values you know or find out along the way.
Would you be able to help me with Question 11.B, I understand 11.A completely.
However, no matter what i do it doesn't seem to work out.
Thanks
Where can we find the free samples from engage? I cant seem to find themIt's back up and running again, but this time they only have practise exams*. Sorry for that. You can check it out here. Good luck!
This is probably a very dumb question!! But finishing my further sac today and later discussing with my friends left me very worried about this lol150.3 is rounded to three significant figures by writing 150. The zero in this example is the third significant figure.
Say I obtain a value of 150.3 and need to round it to 3 significant figures. How would I go about that? I ended up rounding it to 151 but many of my friends rounded it to 150 (which is 2 SF's?), and I took my textbook in too which is what I based it off but some of them told me the textbook itself is wrong. Some rounded it to 150.0 but isn't that 4 SF's?... I ended up asking my physics teacher and he said it seemed odd to round it up to 151.
I'm probably overthinking it but would love a clear answer to this!!
Hi,The recurrence relation in Question 11 B. has got at least two problems as far as the study design is concerned.
Would you be able to help me with Question 11.B, I understand 11.A completely.
However, no matter what i do it doesn't seem to work out.
Thanks
in b), would i include the H0 in the number of iterations?Hey Mardi, no you would not
Hey,Best to use the unrouded to increase accuracy
I am confused about using rounded and unrounded answers in Further. In the exam, what are we expected to use?
For example, if part a asked for an answer to 2 dp
and then for part b you need to use part a's answer, do we use the rounded or unrounded answer??
thanks
Hey,
I am confused about using rounded and unrounded answers in Further. In the exam, what are we expected to use?
For example, if part a asked for an answer to 2 dp
and then for part b you need to use part a's answer, do we use the rounded or unrounded answer??
thanks
Hey guys what do i pit in my finace solver for all of question 8 and 9 as i got it wrong
For 9G, do you mean question 7?Thank you Siruis black!
Question 7:
a) N: 60
I : 6.15
PV: -25000
Pmt: -120
FV: need to be determined = 42378.588
Ppy and cpy both are 12
b) All same except of Pmt which is now 120 not -120
Question 8: a) N: 120
I : 6
PV : 0
Pmt: -500
FV: 81939.67
Ppy and cpy 12
b) after ten years
N: 120
I: 6
PV : -81939.67 from previous question
Pmt 500
FV : 67141.10
Ppy and cpy 12
Hope that helps ;D
And for the second picture where its chapter 8 review how do i do question 7c
Thank you
Hey guys what do i pit in my finace solver for all of question 8 and 9 as i got it wrong
And for the second picture where its chapter 8 review how do i do question 7c
Thank you
(Ps wtf i cant upload thoose 2 pictures cause they are to large apparently)
http://imgur.com/a/a4UsE
Hey could u answer theese questions
For the first picture, how do i do 9 and 10
Yeah i got it. Thank you
Okay Hun,
Financial modelling can be daunting, but it's simple:
So for question 7c this is how you would do it:
You can either keep putting the recurrence relation into your calculator 12 times until you get the answer, however this would be time-consuming and opens the doors for error. An easier way to do this would be: using the nth term rule : Vn+1= (1+R/100)^n * Vo ( if you can't understand this formula, it is on page 286 on your textbook under COMPOUND INTEREST LOANS AND INVESTMENT)
Then, it's simple, you substitute the values : Vn + (1+ 6.8/12/100)^12* 30000
And you will end up with :$ 32104.80. For this question I think you're a bit confused you don't use the finance solver, just use the nth term
If you are referring to the 7d, then you would use the finance solver for that one and this is how you would do it:
N: 18 (compounded for 18 months)
I(%): 6.8
PV: 30000 (initial amount that we loaned, remember it's positive because we borrowed it)
Pmt:0
FV: ? (this is what we want to find out)
Yeah i got it
Thanks 'hun'!!
Its the hardest further topic so far
Ppy/Cpy: 12
And when you press enter, voila!! you get your answer :$ 33211.94
Hey could u answer theese questions (my teacher isnt responding and i have my sac tomorow :(Question 10
http://imgur.com/a/NKJcG
For the first picture, how do i do 9 and 10
For the second pic, how do i do 2b
Question 10Why do u do 1+(r/4)/100=1.00864
Solve (19282.65 = R8 * 18000)
You get R = 1.00864 and R = 1 + (r/4)/100
And solve this and you get r = 3.456
I hope you understand :)Thank you sirius black
Why do u do 1+(r/4)/100=1.00864
Hey,At a meeting with assessors this year, we were told that the correct answer will be the same either way. But they suggest the previous answer, rounded as required in that question, is the better option to use.
I am confused about using rounded and unrounded answers in Further. In the exam, what are we expected to use?
For example, if part a asked for an answer to 2 dp
and then for part b you need to use part a's answer, do we use the rounded or unrounded answer??
thanks
Hey, for the Core Data Analysis section, I was wondering whether or not a distribution has to be perfectly symmetrical to describe it as symmetrical in the exam?I think I remember that it doesn't necessarily have to be perfectly symmetrical to say that it is, although it is best to err on the side of caution and say that it is slightly positively/ negatively skewed as the case may be. Generally past papers have been reasonably clear as to whether they're looking for slightly skewed or symmetrical.
And if something is reasonably symmetrical, but not perfectly, could you say it was slightly positively/negatively skewed?
Thanks.
Hey all,It looks like you're right in this case and that's just a typo. (Then again, I just glimpsed this for a second.)
Can someone help me with this question?
The seasonal indices for the number of bathing suits sold at a surf shop are given in the
table.
Quarter: Summer Autumn Winter Spring
Seasonal index: 1.8 0.4 0.3 1.5
12. To correct for seasonality, the actual number of bathing suits sold in Autumn
should be:
A) reduced by 60%
B) reduced by 40%
C) increased by 40%
D) increased by 60%
E) increased by 250%
I'm not too sure if the textbook has a typo, but I seem to get 'increased by 150%'
Hey guys, how do i do the lastt question
I dont know the concept
This requires you to know how the mean and standard deviation are calculated.I dont get why standard deviation doesnt change, i just accept that it just doesnt.
Do you remember how to......calculate a mean?You can do so by taking the sum of all the data and then dividing by the number of data pieces (samples)....calculate a standard deviation?To calculate a standard deviation, you must take the variance of the data (so the data variation, or how far one single data point is away from the mean) and then take its square root. You can search the true formula, involving the sum of squares if you'd like the whole statistics story there or the entire formula if you want, but all you need to really know is that standard deviation is the spread of data and that's where the normal distribution comes from (it assumes your data is normal or close to it).Working out + AnswerFrom this, you can tell that by changing the points directly, you'll definitely be influencing the mean - and, if you read the question correctly, say that the stakes are reduced by 5 cm - so you know that the mean will likely also go down 5 cm. This cuts out options B and E automatically.
Then we need to know if the standard deviation will change. The spread will not move if the points are directly changed. That's because it is according to the position of the mean, rather than the points themselves; all the points will change, so the mean changes, but how far each point from the mean is, will not. (PM me if this isn't an adequate explanation for you... I'll be back regularly in about a week - after my exams are over.)
Summary: mean - will change, standard deviation - will not change.
The correct option should be option C.
Math sac tomorrow and im kind of freaking out. I have done the chapters (8,9) and the practice sac and have made my notes for chap 9 but not 8 yet. Has anyone done the financial math sac yet and if so how was it? and tips
I dont get why standard deviation doesnt change, i just accept that it just doesnt.It takes a lot more explaining than the time I have now, but I'd be happy to come back at the end of next week to discuss this if you wish. I currently am on exams (2 down, 3 more to go) and right now on a study break, so I'll come back to this soon. Pop me a PM to remind me if I forget, please. Sorry about the delay!
The spread will not move if the points are directly changed. That's because it is according to the position of the mean,
Not to sure about that, is that because the ratio of the other points to the mean stay the same?
Not to sure what sd is :/
Thank you so much! :)
Math sac tomorrow and im kind of freaking out. I have done the chapters (8,9) and the practice sac and have made my notes for chap 9 but not 8 yet. Has anyone done the financial math sac yet and if so how was it? and tipsSorry I didn't see this earlier; had a killer exam this morning! Sirius has a great answer, but I thought I'd add my two cents, despite not doing financial maths since Year 9 maths (it wasn't part of Core until last year).
-Know your equations/formulas: In financial maths there are a heaps of different equations for different loans and investments and whatnot (depreciation, annuities, perpetuity etc.), therefore it is highly important to know which one of these the question is asking you to apply. Whether the question is asking for a reducing balance loan or a interest only loan know these equations and when to use them. It is really not that difficult, you will have these in your notes anyways. Just try not to confuse them as much as I do! ;)I cannot agree that there are heaps of equations and formulas in the current Further financial curriculum. There is only the compound interest formula along with basic percentage calculations to solve simple loan, investment and depreciation problems. You do not need any other financial formula.
I dont get why standard deviation doesnt change, i just accept that it just doesnt.
The spread will not move if the points are directly changed. That's because it is according to the position of the mean,
Not to sure about that, is that because the ratio of the other points to the mean stay the same?
Not to sure what sd is :/
Thank you so much! :)
It takes a lot more explaining than the time I have now, but I'd be happy to come back at the end of next week to discuss this if you wish. I currently am on exams (2 down, 3 more to go) and right now on a study break, so I'll come back to this soon.I'm back after a wild 36 hours the day before yesterday (had to deal with some Semester 2 stuff yesterday). I've attached a PDF document below for you guys to read. You'll need Adobe Reader to view it. If anyone has any troubles understanding it, feel free to PM me.
However, you can kind of say that the ratio remains the same. I guess that's one way you can think of it.
(http://uploads.tapatalk-cdn.com/20170703/057066504183d73932b6dba4f2e6dbb2.jpg)
Please can you help me work out part C
Mod edit: Merged with Further Maths Q&A
Hey guys my bound reference is two books sticky taped together do you thinks thats alright my teacher said he didnt know.
http://imgur.com/a/P0CCe
Hi, for question 321 B wht do i draw 2x on tthe graph
And how do i do ei and ii
My question is what are the recommended modules to complete for the end of year exam this year?Complete the ones you have done as a cohort at your school. In my opinion it is not worth it to try and be adventurous and try a module you have not had extensive experience with.
Any tips for summary books/bound references?Don't make it too lengthy, don't bring in a textbook. You have 90 minutes per exam.... and when you consider the amount of questions, it isn't much time per. You have to know *exactly* where to find certain points if you have to use your reference at any point.
Hey... just a question that kinda need help on...So we know the volume of a rectangular prism is L*W*H
The rectangular prism shown has a volume of 12.8cm3. A second rectangular prism is made with half length, 4 times height and 2 times width. the volume of the second prism is???
Anyone able to help???
So we know the volume of a rectangular prism is L*W*H
Let Vi = volume of the initial prism, Li be the length of the initial prism etc. V2 is the volume of the second prism
Vi=Li*Wi*Hi
V2 = 1/2 *Li*2*Wi *4*Hi* = 4*Li*Wi*Hi = 4Vi
So it's just 4*12.8
If you want to do it quicker just divide by 2, multiply by 4 and multiply by 4.
So we know the volume of a rectangular prism is L*W*H
Let Vi = volume of the initial prism, Li be the length of the initial prism etc. V2 is the volume of the second prism
Vi=Li*Wi*Hi
V2 = 1/2 *Li*2*Wi *4*Hi* = 4*Li*Wi*Hi = 4Vi
So it's just 4*12.8
If you want to do it quicker just divide by 2, multiply by 4 and multiply by 4.
The critical path is AEIJ and is 15 days long.
The path CGJM is 14 days and so each of these activities has a float time of one.
The path CHM is 13 days which means H must have a float of two because C and M are known to have a float of one from above.
Pls help, my sac is in 2 days
https://imgur.com/a/ysHVu
Not sure how to do q15
hey guys,
I was just doing a question that required me to find 22.3% of 5170000. However when a get my answer it says 1.15291E6. What does the E mean????
Think of the E as 10 to the power of X, where X is the number after it - so E6 would be 10^6.
1.15291E6 means to multiply 1.15291 and 10^6 (in other words, move the decimal point 6 times to the right), which gives you 1152910!
https://imgur.com/a/oeEBU250, 000 x 1.005 = 251250 - Value before withdrawl
Hey guys just some questions in that link, i wrote it on the paper except on c annd d, how do i do that
https://imgur.com/a/oeEBUI'll answer a couple more questions for you :)
Hey guys just some questions in that link, i wrote it on the paper except on c annd d, how do i do that
250, 000 x 1.005 = 251250 - Value before withdrawlThank you! that make sense
THUS
Interest = 250k - 250.1250K = 1250 =)
I'll answer a couple more questions for you :)Thank you so much! Super helpful!!
4. It looks like you need to go over sequences. a) If tn+1=3tn-4, then you know the value of a term is the 3*(previous term) -4. So t1=3*t0-4 = 3*2 -4=6-4 = 2 which is the same as t0. So every term in the sequence is the same, which is unusual because they often change (for 1 mark I imagine you'd only need to say it's unusual because every term is 2).
b) it's actually the Fibonacci sequence with some different starting terms (but you don't need to know that). You should be able to see from the rule that a term is equal to the previous term + the term before that, ie the sum of the past 2 terms. So the sequence goes 3, 4, 3+4=7, 7+4=11, 11+7=18 etc ie 3,4,7,11,18.
For 6d (depreciation)
Method 1: It starts off at 150000 and decreases by 15% of the original price per year. So decreases by 0.15*150000= 22500 per year
So the value is 150000-22500*n
Method 2: The value reduces by 20% per year. So initial value is 150000, value after a year is 0.8*150000, value after two years is 0.8*0.8*150000. You were on the right track.
Value is initial value * 0.8n = 0.8n * 150000
Pls help, my sac is in 2 days
https://imgur.com/a/ysHVu
Not sure how to do q15
Think of the E as 10 to the power of X, where X is the number after it - so E6 would be 10^6.
1.15291E6 means to multiply 1.15291 and 10^6 (in other words, move the decimal point 6 times to the right), which gives you 1152910!
On the CAS, is 'finance solver' ONLY for compound interest (i.e. not simple interest)?
How to I know if I should use the formula for simple interest or the finance solver?The finance solver for the simple interest page is the same as the formula instead on the finanical solver your inputting what it is asking you.
because I was doing a past exam and I got the answer completely wrong cause I used the formula and not he finance solver
The finance solver for the simple interest page is the same as the formula instead on the finanical solver your inputting what it is asking you.
That being said, if you find the formula easier to use then do that as opposed to the financial solver.
This was a common thread of discussion when this study design came out was whether to use Financial solver for simple interest questions or just use the formula. It all came down to what you personally feel comfortable with.
Also you shouldn't get the question right If you used the financial solver as opposed to the formula. They should both give you the correct answer.
It would be the same thing as I mentioned for simple interest, do what is comfortable .
Damn, I made a typo, I meant to ask in relation to compound interest not simple interest. [so how do I know if I use the finance solver or the equation for COMPOUND INTEREST?]
Hey people,
Where the hell can I find the solutions to the FM 2017 exams for the northern hemisphere, I cant seem to find them ANYWHERE and I'm starting to get a BIT JUST A BIT annoyed.
hey guys,If it really is everything that you get stuck on, I'd suggest you go back through that section of your textbook thoroughly. Khan Academy is also a good resource for learning the content, I'm pretty sure most of the stuff from graphs and relations fits into algebra 1 and algebra 2. You're probably better off using it in companion to your textbook and just searching for the relevant bits and pieces as you need it though, because there's a lot of irrelevant stuff in there.
i need help on graphs and relations , i cant seem to understand it whatsoever
is there any tips you guys could give me??
Hey people,You can find the exams and reports at:
Where the hell can I find the solutions to the FM 2017 exams for the northern hemisphere, I cant seem to find them ANYWHERE and I'm starting to get a BIT JUST A BIT annoyed.
In the exam, do I have to show working out for one mark questions?Not that I know of, however, it is probably in your best interest to write down one line of quick calculation to show where it came from in case people get picky or you accidentally get it wrong somehow.
Thanks in adavance
In the exam, do I have to show working out for one mark questions?
Thanks in adavance
Do you think you have to know population statistics and correlation and causality as it's in the study design and I haven't seen it on past vcaa exams before?Population statistics? Maybe not, but definitely correlation and causality. Both of those have been indirectly or directly in exams before, so keep it in your mind! :) (Ideally, I'd put all of this in your bound reference as a "just in case" situation.)
Hey guys, I can't seem to understand why that's the answer. Why is my answer unacceptable?I've never done further but i'll try to help :)
I've never done further but i'll try to help :)
the first 60 tanks sell for 500
then tank 61,62,63...,150 sell for 700
The end point (60,30000) you have from the 60 tanks should be the start point for the second line (the line where each tank costs 700) You have incorrectly included it on the part (a) line
The answers have this part correct
Then from there the equation will not be 700n since it doesn't start at the origin it starts at the endpoint for the first 60 tanks which is the point (60, 30000) Thus you will have a different equation for the line.
Also I think your position for 60 tanks on the graph is a little off your points there seem to be directly between 50 and 75 (i.e. 62.5) so try to make it clear that it isn't directly between 50 and 75 placing it a little to the left.
Why must the new graph begin where the previous one left off? Can't this just be a type of step graph? Or can step graphs only ever be horizontal and angled graphs must always connect?Think of it logically if the cost goes to X and then you continue selling the cost can't magically jump an extra 1000$ right? This is just one situation here were they sell 60 tanks for some cost and then continue selling tanks at a different cost.
When doing the VCCA practice exams from their past study design, is it recommended to do number patterns as well?Yes. Most of the questions should be relevant to the current study design as well.
What's the most reliable way of distinguishing between a random fluctuation and seasonality when analysing a time series?
Think of it logically if the cost goes to X and then you continue selling the cost can't magically jump an extra 1000$ right? This is just one situation here were they sell 60 tanks for some cost and then continue selling tanks at a different cost.
Can anyone figure these financial ones out? I get a different answer on financial solver compared to when I use equations (not sure why).
Thanks
Can anyone figure these financial ones out? I get a different answer on financial solver compared to when I use equations (not sure why).
Thanks
This are the answers I got:
a) 19 months
b) $802.47
c)$802.50
tell me if there correct so I can explain, if not then we'll try and figure them out together.
Those are the answers I got too. But the answers from itute give different answers (They could be wrong, what's your opinion on how they worked it out?)
For Part b ii) Did you use the PMT of -802.47 that gives FV = -0.025... then add it on to the payment to get $802.50 as the final answer? That's how I got it.. Thanks for the help so far!
Please help!! I have a question about financial maths
"The price of the equipment, $8360, included 10% GST (Goods and Services Tax). Calculate the price of the equipment before the GST was added."
I know that the answer is 8360/1.1 = 7600, but I am struggling to understand why the answer isn't 8360*0.9 = 7524.
Thanks in advance!!
Are questions relating to GST and hire purchase plan still relevant to the study design?
Are questions relating to GST and hire purchase plan still relevant to the study design?
Still relevant to General Year 11, but not for further.
Hi everyone,
For the further exam, is it acceptable to bring in a workbook (my notes throughout the year) and duct tape it to a further maths company notes book? I will make sure that I tape it together very firmly to ensure that the two books won't separate.
Thanks very much
8360 is 7600 plus 10% of 7600 added on.
7600 + (10/100)*7600 = 7600 + 760 = 8360
Doing 0.9*8360 is like subtracting 10% of 8360 which is not the same as adding 10% of 7600.
8360 - (10/100)*8360 = 8360 - 836 = 7524
10% of 8360 is greater than 10% of 7600. (836>760).
Think of dividing by 1.1 as a shortcut of going backwards algebraically.
Let's say 7360 = x.
100% + 10% of x = 8360
1.1x = 8360
Now, we divide by 1.1 on both sides to find x
1.1x/1.1 = 8360/1.1
x = 8360/1.1
x = 7600
Hi everyone,
If a question comes up in the finance section of the exam and asks for us to round to the nearest whole number (for payments) must we always round up? For example let's say you get 12.3 payments on the finance solver, do you have to go up to 13 if the question asks to the nearest whole number?
Thanks :D
Hi everyone,Always round up
If a question comes up in the finance section of the exam and asks for us to round to the nearest whole number (for payments) must we always round up? For example let's say you get 12.3 payments on the finance solver, do you have to go up to 13 if the question asks to the nearest whole number?
Thanks :D
Need help for Graphs and the types of data which are used for each!Repost need help..
Using mainly the Australian Bureau of Statistics and the Cambridge textbook I have made this list of notes; however, when faced with multiple options in exam 1, I sometimes make a mistake as the data can possibly fall within more than one graph and its quite frustrating! So I am looking for someone with the perfect notes who can help me with this issue.
Two-Way Frequency table: categorical data
Bar Chart: Categorical data
Stacked or Segmented Bar Chart: Comparing two or more categorical variables
Frequency Table: Categorical or discrete numerical data
Dot Plots: Categorical and discrete numerical data
Stem and Leaf Plot: Discrete and continuous numerical data
Back to Back Stem and Leaf Plot: Categorical (i.e. Sex) Discrete and continuous numerical data
Histograms: Ungrouped Discrete and continuous numerical data
Box Plot: Categorical and discrete numerical data
Parallel Box Plot: Numerical data sets
Scatter Plot: Numerical data
Repost need help..
I relied on the Cambridge Textbook's notes on this topic for these types of questions and sometimes it just doesn't work out as more than one graph is appropriate according to their notes. I think when it comes to this, you just have to use common sense and actually picture whether a type of graph would suit the data.
hey boys can anyone help me with some questionsQ5: Clearly the inequalities compose of: x <= 7, 2 <= y <= 6.
Q5 and Q8 for graphs and relations
Q4 for matrices
Q24 from finance
http://www.vcaa.vic.edu.au/Documents/exams/mathematics/2017/nht/2017FM1-nht-w.pdf
I need some help with this question. It is from the 2011 exam.
Do you suggest i put my practice sacs / exmas i have done for maths in my bound reference book?I would put only the questions you struggle with in your bound reference and not all the practice sacs/exams in it.
Hey guys!
I've attached a question below which has me absolutely stumped. It's a question from 2016 Insight and I've never come across a trend line where deseasonalised sales are predicted from sales; it doesn't make sense to me.
I've also attached the answer if needed.
Deseasonalised data is aiming to find an underlying trend in seasonal data,
When we're predicting data outside of the samples taken (forecasting for instance), we must use the deseasonilised regression line to find the deseasonalised value and the times it by that months sI, which will get it back to an actual prediction.
Summary, in forecasting, use deseasonalised regression line and then multiply that deseasonalised prediction by its si to convert it back to actual sales.
Any help would be greatly appreciated!
Hey guys!
I've attached a question below which has me absolutely stumped. It's a question from 2016 Insight and I've never come across a trend line where deseasonalised sales are predicted from sales; it doesn't make sense to me.
I've also attached the answer if needed.
Any help would be greatly appreciated!
can someone explain to me about inequalities
i.e " Xavier must work at least twice as many hours as Younnis" and let x be Xavier and y be Younnis. I dont understand why its y<=x/2?
thanks!
Can someone please help me with this financial math multiple choice question, it has got me. The answers B but even following their suggested method to work it out (attached also) I still can seem to get even close to their answer.
Hey guys, can someone explain how the answer is C?I think you might be right. At least, B is what I get from my rusty knowledge.
I'm pretty sure it's B but maybe I could be wrong
Hi guys if someone could help with this question that would be great!Alright, so I have never done this before, so please take this with caution. I - probably, maybe, likely - will get this wrong.
i have no idea what to do with it
thanks heaps!!!
Hi guys if someone could help with this question that would be great!
i have no idea what to do with it
thanks heaps!!!
Alright, so I have never done this before, so please take this with caution. I - probably, maybe, likely - will get this wrong.SpoilerFrom this site, I took their formulas and input the following numbers in:
I = (12 months x 2 years) x $25 = $600
P = $500 - $50 = $450
t = 2 yearsSpoilerThus you substitute the numbers into the rf formula to get:
rf = (100 x 600) / (450 x 2) = 66.7% approximately. (Please excuse lack of LaTeX.)
My assumption then is that E is right.
I initially thought E as well, but when I checked I saw it was B.
That being said, I’m 99% sure that hire-purchase isn’t in the course anymore (this was from 2009 VCAA)
hey need help with Q7 of matrices in 2017 NHTWhile I don't entirely understand this and don't think I've ever encountered this either, I do have a resource for you right here from Engage Education.
how do you interpret two-step dominances??
Oh the question didn't attachSorry, I don't do further maths so take what I say with a grain of salt.
I circled the one that I think is the answer and pointed to the one which MAV thinks is correct. Who's right?first Q: MAV is correct since the two variables are not completely random
CAN SOMEONE PLZ EXPLAIN THE SLIDING LINE TO ME?!!?!?!?!?!
Oh the question didn't attach
first Q: MAV is correct since the two variables are not completely random
2nd Q: r=.68 is moderate, not weak
and the word 'tends' indicates that it is not an exact causal relationship, so you shud try to find answers with the word 'tends'
I circled the one that I think is the answer and pointed to the one which MAV thinks is correct. Who's right?Question 11 shows that there is a trend there that appears to have a moderate correlation. There is likely some sort of explanation, making C more correct.
Hi, would really appreciate if someone could help with this question. I don't understand why it's C and not B. Thanks!
Hi, would really appreciate if someone could help with this question. I don't understand why it's C and not B. Thanks!
CAN SOMEONE PLEASE EXPLAIN THIS QUESTION!!!Use the fact that triangle ABD and triangle ABC are similar (they are equiangular).
Can someone explain 2008 exam 1 question 9??? (core!!)I assumed VCAA E1 2008 Core Q9.
HOW do i do correction for seasonality?This type of question always comes up once in a while. It came up in 2014. I remember sitting this exam with this one in my reference book. I've previously done a 2011 one which was awfully similar too. (If that gap is accurate, it's due for a come back but before that it hadn't been around for years, so... who knows?) Here's how to do it:
QUESTION was - the seasonal index for sales in winter is 0.75
To correct seasonality, the actual sales in winter should be
a)increased by 25%
b) reduced by 25%
c)reduced by 33%
d)increased by 33%
I have no idea how to do it and thought it was c, but the answer is D
RECURSION/FINANCIAL - Can someone please explain why the answer is C.Not too sure, but upon my 5 seconds of research, I found the difference to be the definition of each, so maybe that's something to check with your notes or textbook. C just seemed to suit the situation more. Also, maybe the use of V0 over V1? But I wouldn't have any idea about that. Haven't looked into financial recursions much.
I knew it was either C or D but had no idea how i can tell between unit cost and flat rate with such little information!
THANKS
Not too sure, but upon my 5 seconds of research, I found the difference to be the definition of each, so maybe that's something to check with your notes or textbook. C just seemed to suit the situation more. Also, maybe the use of V0 over V1? But I wouldn't have any idea about that. Haven't looked into financial recursions much.
RECURSION / FINANCE -Can someone please explain to me how to get the answer?
The solutions said that the monthly interest rate would be 7.2% / 1200....why 1200??
Recursion - Also how o i solve for this, it said to use finance solver which i did but received the incorrect value :-(
Q. Loan is taken out where there are no repayments until end of year 5
How much extra interest is charged when the compounding period is changed from monthly to daily on a loan of $25000 at 5% per annum?
a) $16.21
b)$96.88
c)$112.75
HEY, can someone explain how to get question 8! I got 7 which was E but have no idea how to get question 8hey you just need to rewrite all the possible paths with e and f and change it up according to the new change. so i think you add 6 hours the F's EST or something. check, im not 100% sure
NETWORKS
If you look on page 129 people were talking about how they might've got the answer wrong. So if you got A I'm pretty sure you're correct! :)Thank You! Yeah i am not getting A either = :-( , my answer is like in the thousands...
HEY, can someone explain how to get question 8! I got 7 which was E but have no idea how to get question 8
NETWORKS
Recursion - Also how o i solve for this, it said to use finance solver which i did but received the incorrect value :-(
Q. Loan is taken out where there are no repayments until end of year 5
How much extra interest is charged when the compounding period is changed from monthly to daily on a loan of $25000 at 5% per annum?
a) $16.21
b)$96.88
c)$112.75
Can someone please help with this question from the 2017 Insight paper: (geometry and measurement)I forgot they updated the Geometry and Measurement module. This is one of the newer things. I think you might be right though. -2 degrees in longitude should yield 8 minutes earlier. I may be wrong though because, like I said, this isn’t something I have done.
A teacher, located at Torquay (38 S, 144E) releases the results of her exam to all students at the same time.
What time will student Georgia who is in Terang (38 S, 142 E) receive her results if the teacher releases them at 9:30 a.m in Torquay?
a). 9.22 am
b). 9.30 am
c) 9:38 am
d) 10.00 am
e) 10:38 am
To me the answer should be A as Torquay is further east than Terang and would therefore be ahead in time, but the answer is C?
Am i reading this wrong?
Thankyou!
So....where they both ordinal? Someone please say yes. You can order them by sweetness from lowest sweetness to most sweet (light->scented->sugar).. i changed my answer from ordinal&nominal to ordinal&ordinal in literally the last 7 seconds before handing in the paper. I decided to bite the bullet just incase VCAA decide to be annoying with this question.
Pretty sure it was ordinal & nominal!
But you can order them and isn't that the same justification that vcaa had for last year with under and over 50?
But you can order them and isn't that the same justification that vcaa had for last year with under and over 50?
It’s nominal most likely (in my opinion) as saying that light, scented and sugar is ordered is almost the same as saying red, orange and yellow are ordered.
There is no interval between the values: ‘light, scented and sugar’ like all ordinal data do (e.g. level of satisfaction, shoe size) to confirm this. I think if instead the level of sweetness was worded differently e.g. high sweetness, medium sweetness etc. it would have been more clear as ordinal.
But....red orange and yellow can be ordered by wavelength ;D
I found question 8 of geometry tricky. Did anyone understand itUsing the copy of the exam, I can tell you that Geometry Question 8 can be calculated by forming an equilateral triangle using the radii of the three circles and subtracting out the area of the three sectors you've formed inside the triangle. If that doesn't make sense, PM me and I'll draw it out for you after I've completed my own uni exams (I have one left).
Hey guys,
For Exam Two, it say that for financial math all answers should be rounded to the nearest cent unless otherwise instructed.
Does that mean for a value of say $1865.292, do i round to $1865.29 or $1865.30?
Thanks and good luck to all on Monday
Can someone please help with this question from the 2017 Insight paper: (geometry and measurement)I've never done this module so I could be completely wrong. But if the teacher releases them at 9:30, then there is no way that someone could get the answers earlier than that
A teacher, located at Torquay (38 S, 144E) releases the results of her exam to all students at the same time.
What time will student Georgia who is in Terang (38 S, 142 E) receive her results if the teacher releases them at 9:30 a.m in Torquay?
a). 9.22 am
b). 9.30 am
c) 9:38 am
d) 10.00 am
e) 10:38 am
To me the answer should be A as Torquay is further east than Terang and would therefore be ahead in time, but the answer is C?
Am i reading this wrong?
Thankyou!
Can anyone help me to work out this question and show how they worked it out please.
' Kuong invests $8500 at 6% interest per annum, compounding quaterly. The amount of interest he earns during the fourth year of investment is?
P.S the answer is $623.63 but not sure how it is worked out.
Thanks
Can anyone help me to work out this question and show how they worked it out please.
' Kuong invests $8500 at 6% interest per annum, compounding quaterly. The amount of interest he earns during the fourth year of investment is?
P.S the answer is $623.63 but not sure how it is worked out.
Thanks
This is how i'd work it out.. obviously there may be an easier way. You want to find out how much interest is earned over the 4th year of the investment.
4 years, compounding quarterly: 8500(1+(0.06/4))^16 = $10786.377 (future value after the 4th year, rounded)
3 years, compounding quarterly: 8500(1+(0.06/4))^12 = $10162.754 (future value after the 3rd year, rounded)
difference: 10786.377 - 10162.754 = approx 623.623
Edit: same as BlinkieBill's... i'll keep mine since it shows the formula if you were to do by hand
Hey i plugged all this into my financial solver.
For N=12 (after 3 years) I got FV= 10162.75
N=16 (after four years) I got FV= 10786.38
Then i subtracted and got 623.23 - you can subtract since there are no additions or payments
Mod edit: Post restored.
Hey
how important are units in further?
do we get marks taken off for not writing them??
Can any help with this questions, pleaseI would usually say "after x amount of years the value of the car is y"
The value of of the car could also be depreciated using reducing balance depreciation.
Using the this method, the value Vn, in dollars, of the car after n years would be modelled by the recurrence relation
Vo = 28000 Vn+1= 0.29Vn
After how many years would the car first have a value less than $10,000?
I can do it on the casio classpad in sequence but what working out would you do?
Thanks
Can someone please explain Permutation/transpose matrices to me?I don't remember much of this, but I definitely remember it was also covered in Methods. Would recommend you look for some Methods resources or check out this Khan Academy link for transpose matrices and this Wolfram Alpha link for permutation matrices. Sorry that I'm not super helpful here.
if we are to write down a matrix and the elements represent prices, do we have to write it to 2dp??If it represents prices, just enough zeroes to give 2dp. It's easier to see a price in 2dp because we work with cents and they'll probably ask you to round to it anyway. Same goes with integer dollars, unless otherwise stated.
i got a 2x1 column matrix where one element is an integer and the other is an exact decimal
How do you answer - interpret the standard score?
from further 2016 sample exam Q5bii
Interpret the z-score of this suburb’s population density with reference to the mean populationI would write a sentence like "This suburb's population density was relatively [higher/ lower] than the mean population density, with a [positive/negative] z score of [insert z score here]. This indicates that [more/ less] people live in this suburb per square kilometre."
density.
I can do it on the casio classpad in sequence but what working out would you do?
I would usually say "after x amount of years the value of the car is y"What I used to do was write up a line of the equation I used and the numbers I originally substituted with.
could be different
Hey, I was just wondering if someone could help me on how I would go about this question (geometry and measurement)!
'Two similar cones of radius 4 cm and r cm (smaller than the first) are shown below.
The volume of the larger cone is three times the volume of the smaller cone.
The value of r is closest to...'
Options are 0.8 (A), 1.9 (B), 2.1 (C), 2.5 (D), and 2.8 (E).
Thankyou in advance!!
when drawing a regression line, what do vcca look for.?They will intend for you to use some reference points that are not too close to each other and draw the line over the entire graph provided.
Is it enough to get 2 points on the graph accurate from the equation present or does the line need to go through specific points?
Hope that helps.SpoilerKnowing that the cones are similar, the volumes of the cones will be = 43 : r3.
We also know that the volume of the larger cone will be 3x the volume of the smaller one, so 3b: b, where b is the volume of the smaller cone, which is r3. Thus we actually have:This can help you find r, which would be:Spoilerr3 = b
3b = 3r3 = 43 = 64Spoiler3r3 = 64
r3 = 64/3
r = cube root of 64/3 = 2.77 cm approx.
which rounds to 2.8.
This gives Option E.
Thankyou! May I ask, where did you get the 3b = 3r^3
Thankyou! May I ask, where did you get the 3b = 3r^3Oh, sorry! Should've said that b is just an arbitrary number that I used to make the volume of the smaller cone, so it wasn't going to be the same pronumeral (and less confusing).
Oh, sorry! Should've said that b is just an arbitrary number that I used to make the volume of the smaller cone, so it wasn't going to be the same pronumeral (and less confusing).
The question states that the larger cone's volume is 3 times that of the smaller cone's.
If I call the smaller cone's volume 'b', then 3b is the larger cone's volume.
We found that smaller cone's volume (b) is also r3 when scaled from length.
Substitute b = r3 into 3b and you get: 3b = 3r3.
That should make a bit more sense now.
HiYeah, VCAA confirmed this in Examiners Reports for previous years :)
For financial questions - does writing down the financial solver inputs actually count as working out??
I want to put some working down for them multi-steps to at least get 1/2 marks ya know
Is 'year' numerical or categorical?
I just had a quick question about financial stuff.I can't help so much here, but I have a couple of links that might help (try the given Further formula sheet and this amortisation table site). Hope that helps.
If they don't give you much information in the question for amortisation tables, what are various ways to find out the different columns in the table? Like the interest, payment, principal reduction ,etc,etc
So, I was wondering for Geometry whether VCAA can use angles in degrees, minutes and seconds and if so how would you convert on the CAS...This video should help. Hopefully you have the same calculator. If you have the ClassPad, try this site instead.
Because it was on a TSSM practice exam I did and I had never come across it before
Mod edit: Posts merged. Please edit your existing post rather than double posting.
When we are using an objective function and are trying to find the maximum or minimum, is it a given that the maximum or minimum point will always be a corner point of the feasible region?Not sure what you mean here.
VCE Further Mathematics 2 (NHT) 2017Not sure what your question was, but my understanding of the question is that they want you to graph it when under the 1/x transformation, so you're essentially going 60 / (1/x) = 60x. Thus the answer.
I have a question about drawing the graph in module 4
Question 1c ii.
I also attached the answer for the value of value of k from the previous question
Pen or pencil for the exam?Either is fine as long as you don't write lightly in pencil and don't use anything lighter than HB. Pen is generally preferred due to its legibility.
Hey, so when a questions asks " use RECURIONS to show value after x years" - do i use the recurance realtion or the rule for the nth term formula?
Where can i get the answers for exam 1
I don't see why the Further kids have to miss out on their own question thread! Post anything you're stuck with here and we'll try our best to help you out.
It might be a good idea to sticky this thread, just like the Methods and Specialist ones.
They are reasonably similar. You’ll find pre-2016 finance questions don’t quite extensively test the current study design, but there are still plenty of finance related questions in the business-related mathematics and recursion modules of the pre-2016 exams. I found that everything else was still super relevant to the current study design.Thanks 8)
For the core data analysis part of further, are the core data analysis section of past exams a good way to revise for sacs after attempting all the past sacs from my school?Yes to both your questions. You'll need to find some newer stuff or check out the number patterns and business maths modules for help in the financial recursion modules though, as that's a newer addition in recent years.
Is the core data analysis section from further exam before 2016 similar to the current study design?
Thanks
Yes to both your questions. You'll need to find some newer stuff or check out the number patterns and business maths modules for help in the financial recursion modules though, as that's a newer addition in recent years.Thanks AngelWings
The ages of people surveyed was normally distributed with a mean of 19.5 years and a standard deviation of 2.9 yearsI didn't do Further, but I suspect this is an application of the 68-95-99.7% rule for normal distributions. That is, 68% of values will lie 1 SD from the mean, 95% will lie 2 SD from the mean, and 99.7% will lie 3 SD from the mean. The best way to answer this type of question (from my knowledge) is to draw a normal distribution curve, shade the area which you want, and work it out from there :)
Estimate the percentage of people between 19.5 and 25.3
Estimate the percentage of people below 16.6
Does anybody know what formula is needed and how these questions are worked out?
The ages of people surveyed was normally distributed with a mean of 19.5 years and a standard deviation of 2.9 years
Estimate the percentage of people between 19.5 and 25.3
Estimate the percentage of people below 16.6
Does anybody know what formula is needed and how these questions are worked out?
I didn't do Further, but I suspect this is an application of the 68-95-99.7% rule for normal distributions. That is, 68% of values will lie 1 SD from the mean, 95% will lie 2 SD from the mean, and 99.7% will lie 3 SD from the mean. The best way to answer this type of question (from my knowledge) is to draw a normal distribution curve, shade the area which you want, and work it out from there :)VanillaRice has already answered your question, but I'd like to recommend that you copy the image of the normal distribution with the standard deviations and associated percentages straight into your bound reference. This type of question is one that reappears frequently in exams.
Could someone explain standard deviation?Standard deviation is essentially how spread out a set of data is. By spread out, I mean that on average, how far away are the values from the mean? I guess you could see it as how 'different' each of the values in your data set is different from the mean.
Somehow I made it through general without knowing how to work it out. 😂 I’ve seen a formula but there’s a symbol I don’t know, (it sort of looks like £ but less money-like I think?) I asked but they looked at me funny and said I should know it because we had already done our SAC on it.
Like, what even is standard deviation? Is it something about how different the data is?
Can someone please explain why im wrong? - Ive attched the answersHi there,
Thanks guys for the help :)There is, but the way you’d do it would be similar to how you do it on Excel. In all honesty, there won’t be a time you’d be have to do the entire thing in an exam (perhaps one value in the entire table is possible), but there is a chance it’ll be an application SAC (usually this is broken down to parts, so there is some guidance). If anything, it might be faster to do it as a table on paper and use the CAS for its basic calculator functions.
Does anyone know if it's possible to work out deseasonalized figures for a group of data on the CAS?
What's the best way to determine the type of association depicted in a scatter plot through inspection/without calculating the correlation coefficient? These questions are usually multiple choice, and I always get them wrong because I keep overthinking it... is there any mathematical method or do you have to just know on your own?Here's a diagram for all the scatterplot associations (linear), strong, moderate, weak and positive and negative. And obviously non-linear would be curved somewhere in the scatterplot.
Here's a diagram for all the scatterplot associations (linear), strong, moderate, weak and positive and negative. And obviously non-linear would be curved somewhere in the scatterplot.If r is a positive association, then would r^2 also be a positive association?
Whilst this is a useful visual aid, please don't fall into VCAA's trap of merely looking at any scatterplot without calculating the 'r' value and jumping to conclusions about its associations. Because you never know, for e.g. 'strong' and 'moderate' relationships can look very very similar!
Instead, judge by the correlation coefficient value! (And it's really easily found on the CAS, so no need to stress about that, if you've got all your x and y values sorted out!)
To judge from the 'r' value, I'm sure you have some sort of table or diagram that has the range of values of 'r' and then what relationship that would mean (e.g. strong positive relationship, weak negative relationship)
Hope this helps! :)
If r is a positive association, then would r^2 also be a positive association?
Here's a diagram for all the scatterplot associations (linear), strong, moderate, weak and positive and negative. And obviously non-linear would be curved somewhere in the scatterplot.
Whilst this is a useful visual aid, please don't fall into VCAA's trap of merely looking at any scatterplot without calculating the 'r' value and jumping to conclusions about its associations. Because you never know, for e.g. 'strong' and 'moderate' relationships can look very very similar!
Instead, judge by the correlation coefficient value! (And it's really easily found on the CAS, so no need to stress about that, if you've got all your x and y values sorted out!)
To judge from the 'r' value, I'm sure you have some sort of table or diagram that has the range of values of 'r' and then what relationship that would mean (e.g. strong positive relationship, weak negative relationship)
Hope this helps! :)
My answer was 12 but my textbook says its 13.
Hiya. I'd be inclined to assume it's an error in the textbook's answers; there a often small mistakes like this in the answer section and from what I can I tell your answer of 12 should indeed be correct.
Hi againAside from the small leeway given to some questions (e.g. to compensate for preemptive rounding), it could also be the scenario it is in. If the question is a worded question about the minimum number of trees that will line the side of a freeway (just a random example) and the answer becomes 12.47, then it'll have to be rounded up to 13, not 12. This is due to the feasibility of the scenario, as 12 wouldn't quite reach the minimum. (If that makes sense. If it doesn't, I'll find an example to explain what I mean.)
why does 12.47 round to 13 (if you want it to be to two significant figures?)
wouldn't you just look at the next number after 2 which in the case of this example is 4 and according to the rule numbers 0-4 you dont round up? My answer was 12 but my textbook says its 13.
I understand why 12.57 would round to 13 (for two sig fig) but why would 12.47?
Can someone please explain correcting for seasonality to me?Correcting for seasonality is a bit of a long one to explain. In the shortest explanation of this, the main equation you'll need is: actual value = deseasonalised value x seasonal index. Basically what you want to do is to correct it to 1 or 100 (whatever the case may be) to get it back to 'normal', so that 1 or 100 is the actual value and apply the above equation.
I've been trying to work it out for a solid hour!
Does anyone have a cas guide on doing seasonal adjustments quickly on the spreadsheet?See “how to calculate seasonal indices” link in previous post.
Does anyone know how to make a good further maths summary book, and what should be in it, and would the same thing apply to math methods?
how does one study for further like for that specific chapter, for example i finished a chapter and like did all the review questions and questions in the book but i want to test myself and my knowledge on the topicGenerally the best way to do so is Checkpoints, books like ExamPro and practise exams. The chapters will be based loosely around the various modules in Further.
Would it be too early to start exams in ~April?
A few questions
1.How would you determine the location of the upper fence and the lower fence when you're shown a boxplot with outliers.
2.If you're shown a boxplot with outliers and you're asked to estimate the percentage of values that are less than a certain number, do you include the outliers when determining the percentage?
3. the distribution of heights of 19-year old woman is approximately normal, with a mean of 170cm and a standard deviation of 5cm
What percentage of these women have heights: between 160 and 175 cm
like 160 is 2 standard deviations below the mean, and 175 is 1 standard deviation above the mean, so how would you work it out in this case since there are different standard deviations (2 and 1)
4. if you're given two variables, number in theatre and time (minutes), and given values for both variables and asked to draw a scatterplot, how do you determine the response and explanatory variables if they aren't given to you?
Thanks :)
I just wanted to get some opinions on how early practice exams should be started. I have almost finished the chapter questions for core and my modules but plan to finish chapter reviews and then A+ questions before starting exams.I did the questions our teacher gave us from old exams to prepare for Sacs however I didn't actually start doing practice exams until we finished all the content (mid term 3). I still managed to get through all the practice exams I could get my hands on (37 to be exact) and if I had've started earlier I would have had less to focus on prior to the exam and I would have forgotten what I learnt from doing the exam.
Would it be too early to start exams in ~April?
Could you attach a picture of what you mean. I can't quote visualise itMy book closes but not fully, as in the pages don't really touch each other when closing
My book closes but not fully, as in the pages don't really touch each other when closingPretty sure that's fine, as long as the book is A4 or smaller in total.
Hey all,Logs are found on the second line after clicking the keyboard button, according to the first 5 seconds of this video. Ln is log with base e. Log by default is log to the base 10, but can be altered to have any base as necessary. Logs are used to (a) counteract exponential (kind of the same way division is the opposite of multiply) (b) used to find unknowns when they're the power e.g. 10x=100 can be undone by doing log10(100)=x. Further information can be found on here.
I'm sort of confused about how to use logs and their functions in the CAS Classpad II. Can anyone help me with this, maybe give me an example question/tutorial to work through?
Also are they related to least squares regression? My class is going too fast for me and everything has been blurring together...
Thank you! x3
Hi angelwings,Someone could correct me if i'm wrong but your pages, including your fold out pieces, have to be A4 size max.
Do you know if it's a breach of vcaa rules if my bound reference for further maths is bigger than A4 size?
Also, do you think it's good if my bound reference for further is just notes from my textbook and also worked examples from my textbook?
Thanks ;D
Someone could correct me if i'm wrong but your pages, including your fold out pieces, have to be A4 size max.Thanks ;D
Also i don't think anyone can really tell you what is and what is not a good idea for you bound ref because it is personal :) Just make sure that you are comfortable using it and it covers everything that you need for the exam. In my case, I'm using a notebook which will include hard questions and things that i tend to forget.
Thanks ;DPersonally i think the textbook is a bit too easy in terms of it's questions, or they are worded incorrectly and so i tend to steer away from it. For me, it's much more reassuring making notes from scratch because:
Wouldn't it be a better idea to just take in the textbook for the exam, and the bound reference for sacs?
Highly recommend not taking in the textbook. You don't get much time in each of your exams and having to flick through pages and pages to find the specific content point that you're after takes time. Doing notes yourself will ensure that you know where things are for ready access, and not to mention the fact that you will understand what you've put in because ideally you've written it yourself. :)Is it true that writing things generally makes us remember them better as opposed to typing them?
Do you know if it's a breach of vcaa rules if my bound reference for further maths is bigger than A4 size?Is it a breach if it's larger than A4? Yes it is. That include any tabs that sticks out of it.
Also, do you think it's good if my bound reference for further is just notes from my textbook and also worked examples from my textbook?
Someone could correct me if i'm wrong but your pages, including your fold out pieces, have to be A4 size max.Pretty much. See here for the rules.
Wouldn't it be a better idea to just take in the textbook for the exam, and the bound reference for sacs?I would recommend that if you intend to take the textbook that it fits the VCAA rules and that you're familiar with where everything is. If you're intending to mark it with permanent tabs, don't forget that the entire book + tabs must be within A4 size. I actually think it's better to make your bound reference reference for exams, because you'll be way more familiar with that and you can reorganise everything to your standards (most students like to put in formulas, cheat sheets, questions they got wrong and concepts for each module they learnt). This is harder with a textbook.
Is it true that writing things generally makes us remember them better as opposed to typing them?Yes, but I can't recall the stats properly, however I think it was marginally better.
Does anyone know how a residual plot is drawn?I'm pretty sure the residual plot is the regression line turned so it's a straight horizontal line
How can we conclude if a residual plot suggests that the use of a linear model to fit data would not work?If there is no pattern in the residual plot it suggests the data is linear. If there is a clear pattern (eg parabolic) then a linear model most likely would not fit - however after a transformation it may.
How can we conclude if a residual plot suggests that the use of a linear model to fit data would not work?
Y = -0.01+4.1x^20. That is really the only way to round it.
But the question said to write the slope and intercept correct to one decimal
The answer said y = 4x^2
Does anyone know how to round -0.01 correct to one decimal place
Thanks ;D
HELP HELP HELP!!!!If my stats skills don't serve me wrong, in order to get these statistics, mostly z score and often st. dev.., this is an assumption we make of the data set.
If we have the z score (-1.4) , the mean (0.471) and the standard deviation (0.128), how does this justify that the data is a normal distribution?? PLS HELP :)
When we are drawing a graph (e.g a bar chart) Do we need to draw horizontal lines across? Like if our Y axis counts in 2’s do we need to do a dotted line for the numbers that aren’t listed or is that just something they do in textbooks to help us read it?In any VCE maths exam, you only need to draw on a graph whatever the question instructs you to draw, so, no, these lines are not necessary
Just need help with b i) and ii)
need help with Q4, Q7 in 2013 further exam 1 -- business.
How do you work out the quarterly interest rate from an amortization table? (#financial maths sucks)
Hi!This is basically just the whole 'correlation does not equal causation' thing. It's saying that just because something appears to be related does not mean that one thing causes the other. Experimentation allows other variables to be controlled whereas if only observation is used to determine the relationship there could be many, many other factors influencing it. (15 weird things that appear to be related)
Can someone please explain what they are saying in the study design when they say
"cause and effect; the difference between observation and experimentation when collecting data and the need for experimentation to definitively determine cause and effect" and "non-causal explanations for an observed association including common response, confounding, and coincidence;discussion and communication of these explanations in a particular situation in a systematic and concise manner." ?
I am not sure whether our teachers have explained this differently or whether we have missed learning it. Please explain? :-\
This is basically just the whole 'correlation does not equal causation' thing. It's saying that just because something appears to be related does not mean that one thing causes the other. Experimentation allows other variables to be controlled whereas if only observation is used to determine the relationship there could be many, many other factors influencing it. (15 weird things that appear to be related)
The non-casual explanations are basically just explanations other than them being related.
Common response: Both of the variables measured are due to a 3rd unmeasured variable
Confounding: There are other uncontrolled variables affecting the results
Coincidence: They just happen to appear related.
The communication thing is just being able to say whether they are related and what other possible explanations for the apparent relationship could be (i.e. the things listed above).
Hey guys can you give me tips to help tackle these question pls
Chris borrows $100000 at 8% compounding monthly, to be paid over 10 years with repayments of $1213.28 each month. After 5 years, the interest rate is reduced to 7.5%pa. (i dont know what to do for the After 5 years interest rate change)
a)Find the new repayment required for Chris to pay off loan in the same amount of time.
b)How much money does Chris save due to the interest rate cut?
the answers
a) $1199
b)$856.80
How relevant are some of the extremely old exams from 2006-2015 to the new 16-18 study design? Should these earlier practice exams be done in timed conditions despite having a slightly different lay out of topics? Or would it be better to simply focus on the last two year's exams and other company trial exams that have been released following the study design change.Hi Lear. First of all, the extremely old exams can still be used because all the main topics are still there - the core will be data analysis, and the other two modules will still be relevant, regarding financial, it is still tested as 'Business Related Mathematics' in these paper, and therefore you can still use them under timed conditions. However, do note that there will be slightly fewer questions if you are practicing using the older papers, therefore you should finish with lots of time to spare. I do recommend going through the older practice exams if you need practice, preferably the much later ones e.g. 2013-2015, but do remember that practicing the 2016 and 2017 exam papers are priority because you do need to get used to the questions asked in terms of Financial and Recursion Modelling [there will be more working out for this compared to Business Related Mathematics]. Company Trial Exams that have been released following the study design change is also a good way to practice. In summary, you can still use the older exam papers to practice and practicing is important so try to do as many papers and get as much practice in as possible. Good luck :)
Is it worth doing checkpoints at this stage of the year as they spoil vcaa exams?
Is it worth doing checkpoints at this stage of the year as they spoil vcaa exams?
Hi.It is included in the study design so I'll learn it just to be safe, it doesn't take much time.
Just wondering...does anybody know whether it is critical to know the process of Dijkstra's algorithm? Is there likely to be a question on the exams that ask for us to go through the process of finding an answer using the algorithm and we will lose marks if we dont?
If not, I won't waste time trying to get a thorough understanding of it, but if it is...well...I'm probably gonna have to try ::)
How many marks can one afford to drop across both Exam 1 and 2 combined for a 50?
Assuming 100% SACs of course.
Would like to know this too! Would someone who is rank 2-3 be able to get a 50? given that rank 1,2,3 only differ by a a few marks.It's possible. For example if rank 1 score 100% in exams, then rank 2 lost 1-2 mark on Exam 2.
How many marks can one afford to drop across both Exam 1 and 2 combined for a 50?A safe bet is
Assuming 100% SACs of course.
How many marks can one afford to drop across both Exam 1 and 2 combined for a 50?
Assuming 100% SACs of course.
can anyone help me with cuts in networks? It's really confusing me as I'm not sure how to find the maximum amount of cuts when calulcating flow and stuff (basically how do I know I'm not missing important cuts???)
Hey, I'd look into the exhaustion method for working it out (there's a few vids on youtube that explain it well). I would even do it for the ones where it said 'draw the cut' just to ensure I had the right one.
Hey, I'd look into the exhaustion method for working it out (there's a few vids on youtube that explain it well). I would even do it for the ones where it said 'draw the cut' just to ensure I had the right one.
Anyone got some good tips and tricks for graphs and relations module?
Particularly Linear Programming.
Anyone got some good tips and tricks for graphs and relations module?
Particularly Linear Programming.
Hey can anyone help me with the 2016 Exam 1 question 16? How do you find the seasonal index for something when theres two missing seasonal indices? I'm so confused lol
What I would do for this (and there may be another, easier way), is to find the 'quarterly average' by adding all of the 'long term average' values together, and dividing it by the number of days of the week (7) (89+93+110+132+145+190+160/7=131.285714286). After this, divide the value for Saturday by the quarterly average (190/131.285714286=1.44722524483, which can be rounded to 1.45). Therefore, the answer is D.
Sorry, hope that wasn't too confusing!!! ;)
Has anyone got the answers to Neap VCE Further Mathematics Units 3&4 Trial Examination 2016?Sorry, but it's against forum rules to provide this as it's copyrighted material.
Can someone explain question 9 and 10 on data analysis 2017 further exam 1?I'm assuming this is for VCAA 2017 Exam 1? I won't provide the answers, but the thinking process very briefly.
Thanks.
Is this still on the study design? (Q3 2006 exam 2)
If it is how would I go about doing it? This is also on exam 1 I think (or maybe it was 2007 exam 1). I know how to do 3 median smoothing but I've never had to get an equation from it. The provided solutions say to use 3 points but I don't know how I'm supposed to figure out which points to use?
The only way VCAA can ask a question about that is if they explain what it is in the question and it can be solved using basic further maths techniques.awesome, thanks!
How would you compare percentages for this data (that relates to dolphin activity)?
Just need some help with this question.Answer is E
I was hoping someone could help me out with 2016 VCAA Exam 2 Graphs and Relations module Question 3D.If you rearrange \(Q=mx+ny\) in terms of \(y\) you get, \(y=\frac{-m}{n}x+\frac{Q}{n}\). \(\frac{-m}{n}\) corresponds to the gradient of the profit equation so \(\frac{-m}{n}=-1\) therefore \(m=n\)
Even by looking at the examiners report below I do not understand.
(https://i.imgur.com/c6OG1BL.png)
How can they assume that since the gradient = -1 , m=n
There is a link there that I am not understanding.
Any tips for calculating interest questions?
Having trouble with Q5. c) ii)
Any tips for calculating interest questions?So to do that you'd first work out how much they payed over the first 3 years.
Having trouble with Q5. c) ii)
Interest is equal to:
total amount paid - the amount paid off the loan
which is equal to
number of payments*monthly payment amount - initial value of the loan - amount that needs to be paid off (FV)
which for a reducing balance loan that has this relation : V0=x , Vn+1= (1+r/n*100)*Vn -- D
it would be
(D*n) - (V0-Vn)
and for a loan that has been fully paid off it would be
D*n - V0
In your case, the terms of the loan change, which must be accounted for while calculating interest.
it would equal to:
11000*total number of payments - 480,000
lol I would give you the answer, but idk where my CAS is at the moment
I'm just confused with why interest equals total amount of payments - Pv.The interest is the difference between the amount you borrowed (Pv) and the amount you payed back (total payments). So to work out the difference you subtract the amount you borrowed from the amount you payed back and you're left with the interest that you payed.
I'm just confused with why interest equals total amount of payments - Pv.
Hey I have a question regarding the study design.
I just completed the 2012 Further Exam 1, and came across this question. I've attached it below.
It involves infinite geometric sequences and is quite strange. Is this type of question still a part of the study design? Would I need to learn how to do them?
Thank you for any input.
Hey I have a question regarding the study design.
I just completed the 2012 Further Exam 1, and came across this question. I've attached it below.
It involves infinite geometric sequences and is quite strange. Is this type of question still a part of the study design? Would I need to learn how to do them?
Thank you for any input.
A loan of $15,000 is taken out compounding monthly with an interest rate of 4.5% Per annum. Payments are also made monthly and the loan will be paid off in 7 years.
a) What is the monthly payment
b) How much interest is paid in the first two years.
For part b I seem to be getting different answers depending on if I make a reducing balance table and sum up the interest for each payment compared to using Financial solver.
Which method is correct?
I got $1187.94 using the TVM, I think its correct... I feel like the other method is more time consuming because you have to fill in the table up to 24 payments.You're right. But a counter argument is that it is 'more correct' as TVM incurs rounding errors whereas the table doesn't. I get 1187.9986 using table.
Hey I have a question about the study design again.Hey,
For this question in 2013, it asks for the effective rate of interest. I know the difference between nominal and effective annual interest when its referring to compound interest but i don't understand what they're doing here at all.
What formula are the using? Is this something that isn't in the study design.
Thank you for any input.
I have a question about significant figures, this question required the value of 109.894 to be rounded to 3 significant figures, so how is 110 correct? I thought trailing zeros in non-decimal numbers are not significant? If this is the case... how would we round this number to 3 sigfig?The guidelines for significant figures is as follows:
Is it worth doing the NSW (HSC) bostes exam?
You're right. But a counter argument is that it is 'more correct' as TVM incurs rounding errors whereas the table doesn't. I get 1187.9986 using table.
I got the same value (1187.99865079, on float12) using TVM solver.
First, I found the monthly payment to be 208.5024... This value is stored as –tvm.pmt.
Second, I found the balance of the loan after 24 payments to be 11183.9405... (I used the exact value of the monthly payment for this). This value is stored as -tvm.fv
Then I calculated the interest paid in the first two years by calculating 24*-tvm.pmt – (15000 – -tvm.fv). (ie. total paid in two years minus the principal reduction).
I believe there will be no rounding errors using this method.
<snip>
The answers claim it to be $1187.94 which then should be incorrect by roughly $0.06 when rounding to 2 d.p....right?
Insight 2018 Exam I believe
<snip>
Is there any "hence" instruction, or any indication that the rounded answer from part a. is to be considered the actual monthly payment? (This is touching on issues in the other thread).
Otherwise, I'm inclined to think that Insight's answer is wrong, until I see evidence from VCAA that this kind of rounding is acceptable.
Any advice for this question.Here’s a hint :
Any advice for this question?
Got A, but answer is D.
In my opinion answer should be C.
4200-600=3600
Interest for the year = 0.06*3600=216
Total to paid that year = 3600+216= 3816
3816/12=318
NOTE: Hire Purchase is No longer on the study design for 3/4 I think
Is hire purchase not just another term for simple interest? we got told that at school, so it will still be in the study design.
How do we answer question 3 vcaa exam 1 2010 (attached).It's been done recently.
are the vcaa 2010 answers wrong for question 4 a) ii). See attached.I'm assuming this is from the financial maths module. Back in my day (which makes me sound old), financial recursions wasn't a part of the core modules, so I haven't done financial maths in ages. I'll leave this to someone else. Sorry!
are the vcaa 2010 answers wrong for question 4 a) ii). See attached.Yes, looks like they have included a decimal in the wrong spot... the working out included beneath gives what would be the correct answer, you just need to round it to the nearest whole number.
Hi.That’ll give you the monthly interest rate. You then have to times it by 12 as the question asks for the annual interest rate.
Is somebody able to explain how to work out this answer? Its from the 2015 Exam 1 VCAA exam.
I would have thought that you work out the amount of interest that is earned (5885.72-5870.5=15.22) and then divide this by the lowest monthly balance (15.22/4870.5=0.00312493), and then multiply it by 100, but this does not give any of the answers.
The correct answer is D.
That’ll give you the monthly interest rate. You then have to times it by 12 as the question asks for the annual interest rate.Haha yep that would make sense! I knew I was on the right track! ::)
How to answer question 2 b) from 2009 further exam 2?2b from which section of the exam?
2b from which section of the exam?
How to answer question 2 b) from 2009 further exam 2?$250, $6 interest
Hey so for this question I was asked explain association.
As you can see, although the box plots have scales of 5 i wasn't accurate in my estimation of the medians of the three years. I estimated 51, 62 and 69. Would this still be considered right or would I need 52, 63 and 69 to be right.
Thanks!
need help with
2013 Further exam 1, business related maths, question 4 and 7
2018 NHT further exam, matrices, question 8
Thanks
and an attempt/your current understandingYou'd hate to see the methods question thread :')
You'd hate to see the methods question thread :')
mate, I am well aware :P It was and continues to be one of my key frustrations both as a former natmod on AN and a teacher.
Spoonfeeding them the answer may help with getting the answer to that particular question, but if they just repeat the same flaw over and over in future questions have they really learnt? Could argue they will learn based on your worked solution which may be true, but in most cases it'll just get repeated later on.
need help with
2013 Further exam 1, business related maths, question 4 and 7
2018 NHT further exam, matrices, question 8
Thanks
Hey guys,Nope. It isn’t actually an activity. It would whatever the dummy is linking from that are the predecessors
Can a dummy be counted as a predecessor? (Networks)
Extremely odd question but does anyone know if we are allowed to write ON our bound references during the exam?
Thanks!If you're worried about it just ask when you walk in, they'll tell you.
Don’t plan to use it for working out but rather have a premade checklist with common mistakes at the back to tick off when I’ve finished my exam.
Would one lose marks for adding a unit where a statistic is calculated?No. So long as it’s the correct unit of measurement you won’t lose marks
For example in the 2017 Exam 2, would 72 eggs rather than simply 72 for Question 1ai be marked as wrong?
NHT EXAM 2, Q2FMatrix B allocates the new members seats - they don’t choose their seats, so it’s still added. You multiply the T matrix by the state matrix, ending up with the people’s choice of seats, then you add B into their allocated seats.
Can someone please explain to me why the answer is 84. The answer I got was 82.
To my understanding, it would be the transition matrix multiplied by K2, and then you get the answer from the matrix. You wouldn't add the B matrix because those people don't get the option of choosing their seats as stated by the question. So why does VCAA add the B matrix :( ???
Do we need to know about hire purchase agreements for exam?No
Hi,
I need help with question 9 from the networks section (attached below).
Hi,
just wondering, will we loose marks if we write an answer without units? for example, if a question asks for the range of the temperature in a graph, can you just write, say, 20, or do we have to write 20 degrees celcius?
Thanks!
Which exam is this from?
I believe this sort of a grey area. Some believe that since things such as range/median/IQR are *calculations* it is inappropriate to include units. For example, if we were to calculate the median amount of humans in 10 groups and we got a decimal value it would not make sense to put units as we cannot effectively have for example 6.5 humans. I’m not sure about further but I have lost marks in methods for providing a unit when calculating the expected value of a probability distribution table that involved some sort of tangible object/thing.
So is it best to include the units just to be safe?Include units when asked. However you can include units even when not asked but make sure it is the correct unit as adopting an inaccurate unit will lead to a wrong answer. This is the same principle when people answer the question in a worded format (but if the worded format mislead from the question/answer, the answer will be wrong) when simply the numerical answer is what vcaa is looking for.
nht further exam 2, question 6 recurrence relations (attached below).This is a little bit different than your usual financial core. There isn't an exact interest per annum but rather it charges its customers by 1.5% of interest if bills are not paid after the due date (in months). Therefore there will be no interest charged if they paid their bills on time. So the correct answer should be $203 (since Marcus paid his bills one month after due month, 1.015x200=203)
So if it said 1.5% per annum, then would $200.25 be the correct answer?
So does that mean the interest rate per annum is actually 18% (1.5x12)?
Thanks
This is a little bit different than your usual financial core. There isn't an exact interest per annum but rather it charges its customers by 1.5% of interest if bills are not paid after the due date (in months). Therefore there will be no interest charged if they paid their bills on time. So the correct answer should be $203 (since Marcus paid his bills one month after due month, 1.015x200=203)
But it says interest on this amount will compound monthly?Interest will compound for x amount of months that the customer doesn't pay its bill after due month, don't be confused with the your usual compound interest question. This one has a slightly different rule.
What does "decay arithmetically" mean? Have looked online for an answer but nothing really seems to explain this well.I would assume it’s just referring to an arithmetic sequence with a negative difference. E.g 10, 8, 6, 4, etc
What does "decay arithmetically" mean? Have looked online for an answer but nothing really seems to explain this well.
Nht 2017 further maths exam 2, data analysis, question 2 b) iii).
Isn't the answer -19.0 and not -18.9?
Also, do we need units for residual values?
Wait...are residuals a percentage?No, just the units in this one is. The question itself had percentages, so... I think I added the units in unnecessarily in all honesty.
Do you include lump sum payments in total interest paid during lets say, a reducing balance loan?Are you talking about the lump sum of like an initial deposit that is payed, then reducing balance for the remaining value?
Do you include lump sum payments in total interest paid during lets say, a reducing balance loan?
Are you talking about the lump sum of like an initial deposit that is payed, then reducing balance for the remaining value?
Yep. I now realise you wouldn't include interest on it, but would u include it in total amount paid for lets say a car.Yeah you would, it's still a payment.
Yep. I now realise you wouldn't include interest on it, but would u include it in total amount paid for lets say a car.
Hi! Could someone please explain why 30% is the answer?I'm not sure if this is the right way of doing the question but you could say there are 120 rooms (as winter has 100% occupancy) and in Summer only 85 rooms are used. To have 100% occupancy in summer, you would need to close 35 of the 120 rooms which is equivalent to 29.2%.
I don't the question or how to work it out at all... and it's the only one in the practice exam I couldn't get.. :P
Ah yup, that really just comes down to knowing the definition of what that line is. It’s not really something you can ‘work out’ during the exam. It’s just a fact you are supposed to know.
Questions like these scare me the most as I don’t plan to take my textbook in and this sort of random things I dismissed when making my personal bound reference. Plz don’t do this VCAA :(
Are you serious... it’s like they make us focus on application questions so much that we ignore the “content” and then surprise us with a... definition??? This shit better not pop up on FridayIts not really about definition, its about understanding. We should all know by now that adding all residual equals to 0 and that residual is vertical distance between the line and the actual dot, so by using the previous example. Its pretty obvious...
hey everyone, sorry if this question has already been answered but just in regards to time series plots, are irregular fluctuatiosn ALWAYS a feature? according to question 11 on the NH 2018 exam 1 examiner's report, they are but im not quite sure if this is right. thanks!!Yes
Its not really about definition, its about understanding. We should all know by now that adding all residual equals to 0 and that residual is vertical distance between the line and the actual dot, so by using the previous example. Its pretty obvious...
I think it’s reasonable for a person to not make the connection between ‘least squares’ and residual values. Often even the term 'least squares' is not taught and rather students are simply told to press certain buttons on their calculator to get ‘the line’ of the graph.Completely true. I made the exact same mistake, and a few other people I know (including one student who is probably rank 1 in our cohort) made the exact same mistake. It's a very easy thing to not connect these two ideas.
What may be obvious to you is not obvious to all students :)
Its not really about definition, its about understanding. We should all know by now that adding all residual equals to 0 and that residual is vertical distance between the line and the actual dot, so by using the previous example. Its pretty obvious...Well I honestly didn’t know that... but thanks for the enlightenment lol
I think it’s reasonable for a person to not make the connection between ‘least squares’ and residual values. Often even the term 'least squares' is not taught and rather students are simply told to press certain buttons on their calculator to get ‘the line’ of the graph.This is spot on. I didn’t even know what the least square line did until I literally just google searched “least squares meaning”, which pretty much gives the answer to question 7. We weren’t really taught what it is or what it does, just how to find it and use it. (Gotta love atarnotes tho, thanks guys!)
What may be obvious to you is not obvious to all students :)
Have never had a great understanding of inverses so can't wrap my head around this question...
Anyone able to explain why the answer is A?
Have never had a great understanding of inverses so can't wrap my head around this question...
Anyone able to explain why the answer is A?
By definition of inverses, Q^–1 * Q gives the identity matrix.
Since Q = wP, we require that Q^–1 * wP is the identity matrix. Hence Q^–1 = (1/w) * P^–1, since P * P^–1 is the identity matrix, and w * (1/w) = 1.
Hey Guys,I would always just do it to the ends of the graph that it gives you. That way you can show the x intercept. Also, generally the line wont have a boundary or anything, so just go to the edges, even if it is extrapolation.
When drawing a least square regression line in exam 2 are you supposed to extend the line past the max and min x values of the data points given? I was thinking you don't extend the line because that would show extrapolation but the 2017 answers had a question that extended the line to reach the y axis etc.
Hey Guys,
When drawing a least square regression line in exam 2 are you supposed to extend the line past the max and min x values of the data points given? I was thinking you don't extend the line because that would show extrapolation but the 2017 answers had a question that extended the line to reach the y axis etc.
Related to this, are we supposed to label the end points? I don’t recall any of the normal VCAA exams requiring labelling for the least square regression line but did 2018 NHT EXAM 2 last night and they had the end points labelled?Not sure whether it is required, but I always label a couple of points just in case my line is slightly off. Definitely label the y intercept, because this is generally easy enough to find from the line, and may be something in the middle and at the end.
The issue is if we haven’t been given an instruction to label we don’t know exactly how many decimal places we should label to. And VCAA often mentions how kids lose marks for putting extra yet incorrect information (haven’t said anything specifically on lines though)That's overkill, there is no need to label, just make sure your end points are accurate. Label or not, Vcaa still needs to check whether the line is correct.
That's overkill, there is no need to label, just make sure your end points are accurate. Label or not, Vcaa still needs to check whether the line is correct.
That's what I thought too until I saw the VCAA 2018 NHT Exam 2 report having them labelled. Now I am not too sure.I checked others and they weren't labelled. So I wouldn't worry about this, VCAA would of mentioned to include coords for end points if they were needed
Interesting...
(https://i.imgur.com/29kzm50.png)
Can anyone help me with this question? I don't know how to find the residual without the actual value. Its from NHT Exam 1
Thank you!!
Hey Guys,
When drawing a least square regression line in exam 2 are you supposed to extend the line past the max and min x values of the data points given? I was thinking you don't extend the line because that would show extrapolation but the 2017 answers had a question that extended the line to reach the y axis etc.
In regards to Matrices, does VCAA by default put the win on the comlumns or the rows on dominance matrices.
Like this
loses to
[ x x x ]
[ x x x ] wins
[ x x x ]
or
wins
[ x x x ]
[ x x x ] loses to
[ x x x ]
What would be the inverse of the 2x2 matrix:
[2k 3k]
[4k 7k]
Thats one matrix btw^
Hey Guys,
I need help with this tricky NHT 2017 exam 1 question. the answers say something about 600/400 X 15
but i dont get it can someone pls explain
the answer is A by the way
Thanks :)
Hey Guys,I think you've attached the wrong screenshot as the correct answer to the question in the screenshot is B
I need help with this tricky NHT 2017 exam 1 question. the answers say something about 600/400 X 15
but i dont get it can someone pls explain
the answer is A by the way
Thanks :)
Hi guys!You are rank 1 so your cohort won't impact you too much if you get the highest score (or close to the highest score) in your cohort. If you continue doing this well in exam 2 you are looking at a study score in the high 40's.
I'm in yr 10 and just had my first 3&4 exam yesterday, further maths.
So far I've got A+ for all SACS and a sitting at rank 1
I was just wondering about what study score I can expect, I dropped a mark in exam 1 :'(
I've heard that SS depends also on how the state does and your school cohort.
Hi guys!It really depends on how you go on the exam on Monday - I know a kid who got a 50 as rank one who dropped 1 mark on exam 1 then full marked exam 2 ... then I know others who got low 40's because they bombed the 2nd exam with a similar 1st exam mark. It really really depends on how you do in exam 2 - either way you should be comfortably above 40!
I'm in yr 10 and just had my first 3&4 exam yesterday, further maths.
So far I've got A+ for all SACS and a sitting at rank 1
I was just wondering about what study score I can expect, I dropped a mark in exam 1 :'(
I've heard that SS depends also on how the state does and your school cohort.
It really depends on how you go on the exam on Monday - I know a kid who got a 50 as rank one who dropped 1 mark on exam 1 then full marked exam 2 ... then I know others who got low 40's because they bombed the 2nd exam with a similar 1st exam mark. It really really depends on how you do in exam 2 - either way you should be comfortably above 40!
Just want to clarify - one exam that I did (I think it was a VCAA?) said that irregular variation is a feature of every time series graph. Is this right?
I am correcting the 2018 Heffernan exam (2) and it does not mention this in the solution when it asks for the pattern in a time series plot that is shown above.
Hi Everyone, i was wondering if someone could explain how to do graphs and relations questions regarding when the objective function has the same gradient as a line on the graph. I know how to do that (yay it was on exam 1!), but i was just wondering how i would be to go about finding actual integers on the line, as in like a max or min?
Thanks :)
NOTE: For this, you cannot use inequalities. Instead you’ll have to solve the given inequality for y and then graph it as a >function<
Could someone help me with question 13.You just had to use b=r X Sy/Sx and then just put that into the solve function on your CAS
As far as I was concerned if you don't have all the individual data you need this formula r=(Σ(x-¯x)(y-¯y))/((n-1) s_x s_y )
so you generate (x,y) values with the least squares regression line but the question does not provide a n value?
Can anyone tell me if we are meant to use pen in exam 2? I saw something about it in the 2017 examiner's report but I'd definitely prefer to use my mechanical pencil if we're allowed to!
you have to use pens. the papers are scanned .
Hey Guys, can someone please help me with financial, i have no idea what type of formula to use of any question, Can someone help me understand it a bit more? Thanks
Are you sure?
I know quite a few people who did further in pencil last year and got study scores. Perhaps one must use a dark pencil?
Scanned images are used for assessing and students should ensure their answers can be clearly read. Students were asked to write in blue or black pen. Students are urged to take greater care with the presentation of their responses
Does anyone know the solution to Question 4b on the 2017 exam as i am not sure how to get the answer. Is there also any goof practice papers that can be similar to the exam on Monday
Thanks
Does anyone know the solution to Question 4b on the 2017 exam as i am not sure how to get the answer. Is there also any goof practice papers that can be similar to the exam on Monday
Thanks
Mustafa i'd be looking at the Exam Assessor Report for last year's Exam 2 and noting down the questions that alot of students got incorrect. They would be the first questions i'd predict would be on this year's one.
Here's the link for you: https://www.vcaa.vic.edu.au/Documents/exams/mathematics/2017/fm2_examrep17.pdf
Hi,Look at the top of this page. Already been answered.
For exam 2, in the exam guidelines it asks us to use pen. Are they adamant about that, or can we use pencil instead? I know that the exams are photocopied, so just wanted to be sure.
Please post the question here so we do not have to go looking for it. No one can even tell what module you are referring to.
Practice paper recommendations
- VCAA 2016 Exam 2
- VCAA 2017 NHT Exam 2
- VCAA 2017 Exam 2
- VCAA 2018 NHT Exam 2
- MAV 2018 Exam 2
- Heffernan 2018 Exam 2
I would advised not doing NHT (only if you want a confiedence booster).While the 2018 NHT was probably a lower standard, I felt like the 2017 one was still quite decent (although it was a while ago that I did it). It is still VCAA questions and so it is likely going to be better preparation than company exams. Thats just my opinion though.
I would advised not doing NHT (only if you want a confiedence booster).
It will. However, lead you in blind as well as giving someone false hopes. I would do the VCAA 2017 exam as this are the only real exams.VCAA 2016 as well as this is still the current study design.
It will. However, lead you in blind as well as giving someone false hopes. I would do the VCAA 2017 exam as this are the only real exams.
it is possible to have a non linear relationship between two variables but still have the relationship be strong?It would be possible, but I assume we wouldn't need to know this for further, as we are studying linear relationships. The only time that non-linear associations are involved in the course is when r is less than 25 (or greater than -25), when we are working with residual plots to determine whether the relationship is linear or non-linear based on residual placement, and for transformations.
It would be possible, but I assume we wouldn't need to know this for further, as we are studying linear relationships. The only time that non-linear associations are involved in the course is when r is less than 25 (or greater than -25), when we are working with residual plots to determine whether the relationship is linear or non-linear based on residual placement, and for transformations.
I believe you are expected know how to judge the strength of the linearised form of a non-linear relationship – eg. determine the correlation coefficient of bivariate data after a log / reciprocal / squared transformation has been applied.
Yes, but that is after the data has been linearised with the transformation, so I wouldn't say it is judging the strength of non-linear data, as it is not the original data that is being judged.
Yes, I agree. Just trying to clarify the issue.lol sorry!
Maybe a silly question but are you allowed to write outside the lines on exam 2?
Maybe a silly question but are you allowed to write outside the lines on exam 2?Do you mean outside the border of the page? Like the yellow area on the image attached?
Do you mean outside the border of the page? Like the yellow area on the image attached?pretty sure you don't, cause if its only the black border...you really can't even write it therefore making the text meaningless.
what would you do for this
Hey guys I need help with this VCAA question form 2015 exam 2.You would say 70-75, because if this interval was 70-74 and the next was 75-80, then all of the values between 74 and 75 (e.g. 74.5) would be excluded. It would really be 74.9999999999999999999 going on forever but you would just say 75.
The answer says the modal inerval is 70-75, but shouldnt it be 70-74 becaues its a histogram, and like 75+ are part of the following intervals?
Thanks
what would you do for this
what would you do for this
Why is the mean affected by outliers and skewness?The mean takes into account all data points, including outliers and ones that would influence the skew of the data. Think back to how you calculate the mean and you'll notice that outliers will pull them in the direction they're in e.g. an outlier higher than the rest of the data will make the mean much higher than if the outlier's data was excluded.
Hi,
I was confused with one of the questions on NHT 2018 exam 2 (probably something simple that I am overseeing).
With Q7d) - how did they get an annual interest rate of 9.5%?
With the starting amount being ($5000) compounding monthly (assuming), how is the annual interest rate 9.5%?
I keep on getting 9.2% using both the eqn – (6000=(1+x/12/100)^24x5000) and finance solver (N=24, PV = -5000, PMT = 0, FV = 6000, CYPY = 12, giving I% as 9.2).
Thank you!
Question 4 from VCAA sample exam attachedconsidering the response variable isn't listed as population (in thousands) but rather population, then 7700 should be the correct answer
Requires you to create an equation for some log(x) transformed data. However the y is population (000's)
Looked at itute solutions and they come up with the equations population=7700+7700(log area) ...2sf.
This is done if you x1000 the population data before graphing.
However if you don't do this you get the equation population=7.7+7.7(log area). Which also works but in the following question you just have to multiply your prediction by 1000 to get the answer.
Thoughts? Do you think they'd give marks for either equation?
Its not compounding monthly though. Your thinking is correct, but get rid of the 12 (cause not compounding monthly and change 24 months to 2 years).
So it should be:
(1+x/100)^2 x 5000 = 6000, x
Hope that helps and good luck tomorrow!
Question 4 from VCAA sample exam attachedI highly doubt that they would accept both answers. Even if something is written like population (thousands) you need to leave the data in it's original form to find the linear regression line, otherwise inputing data into the line would result in extremely incorrect results.
Requires you to create an equation for some log(x) transformed data. However the y is population (000's)
Looked at itute solutions and they come up with the equations population=7700+7700(log area) ...2sf.
This is done if you x1000 the population data before graphing.
However if you don't do this you get the equation population=7.7+7.7(log area). Which also works but in the following question you just have to multiply your prediction by 1000 to get the answer.
Thoughts? Do you think they'd give marks for either equation?
I don't know if anybody has noticed this yet, but the VCAA sample exam is basically just questions from a couple of past exams mixed together.So which one do you mean original? 7700 or 7.7?
Most of the Data section is from the 2014 VCAA exam 2, the finance and matrices sections makes reference to a question that came up in the 2013 exam 2, and I am not sure about the others. Just thought I'd mention it as some of the questions overlap and if there aren't answers for the sample exam questions (there might be - I have no clue), you could probably use these for some answers.
I highly doubt that they would accept both answers. Even if something is written like population (thousands) you need to leave the data in it's original form to find the linear regression line, otherwise inputing data into the line would result in extremely incorrect results.
So which one do you mean original? 7700 or 7.7?oh sorry the 2014 examiners report has 7.7 so this would be what they would accept. I'll edit to make clearer.
considering the response variable isn't listed as population (in thousands) but rather population, then 7700 should be the correct answerThe original data in the table along the side has it listed as population (thousands), so the thousands is the unit. If it were to say length (mm), the equation generally would not use the variable as length (mm), but just state length. It is the same for this, as thousands is simply the unit.
oh sorry the 2014 examiners report has 7.7 so this would be what they would accept. I'll edit to make clearer.that cleared some misunderstandings, neap (or some other companies, can't remember) did the full "7700" for regression, got me confused
The original data in the table along the side has it listed as population (thousands), so the thousands is the unit. If it were to say length (mm), the equation generally would not use the variable as length (mm), but just state length. It is the same for this, as thousands is simply the unit.
that cleared some misunderstandings, neap (or some other companies, can't remember) did the full "7700" for regression, got me confusedAh I hate it when the companies give you answers that VCAA would consider wrong! Super confusing :-\
always listen to vcaa :)100%. Examiner reports are the greatest thing they could have given us (apart from the answers to this years exam, of course ;))
Can anyone explain the answer to part c of this question? VCAA said the answer is 8 trucks. It's from VCAA 2017 NHT Further Exam Networks Module Q3. Thank you (:Basically for this, you just need to find the path from the entrance to the exit that will allow for the maximum number of trucks to pass through. They all have to follow each other, so if must be one path. Its similar to a max flow question, just with one path only.
Basically for this, you just need to find the path from the entrance to the exit that will allow for the maximum number of trucks to pass through. They all have to follow each other, so if must be one path. Its similar to a max flow question, just with one path only.
Looking at the graph, the path that would allow for the largest number of trucks to pass through would be the path highlighted yellow in the attached document. Although some streets allow more than 8 trucks (e.g. two allow 9), there is one that allows only 8, and therefore this is the maximum number that will be able to pass through each day.
if the question says-After looking through past exam 2's up to 2013, I haven't been able to find any questions asking this. However, in the 2017 NHT Exam 2, question 3 a of the data analysis section. According to the answers, all you need to say is increasing trend, as you suggested.
Describe the trend, if any, over time
do we have to include irregular fluctuations and all that other stuff or do we only just say if it's increasing or decreasing?
When asked for shape of distribution do you include if there is outliers or not?Yes you do and I think you even have to mention the number of outliers for things like boxplots e.g "with two outliers"
Hey can anyone help me with this 2007 exam 2 question. I cant seem to get 7.3...7000-500 = 6500
b. Another store offers the same $7000 office furniture for $500 deposit and 36 monthly instalments of
$220.
ii. Calculate the annual flat rate of interest charged by this store.
Write your answer as a percentage correct to one decimal place
using reading time for solving questions or actually reading :'( not sure what to do considering last time, i ran out of time to check all modules for exam 1 :-\I use it to make note of all the details that normally trip me up - so noting whether an interest rate is monthly or annual or whatever. Just making note of easily avoidable errors so that I don't actually make them.
I use it to make note of all the details that normally trip me up - so noting whether an interest rate is monthly or annual or whatever. Just making note of easily avoidable errors so that I don't actually make them.yeah thats what i tried to do for exam 1 but i think my paranoia that i was making a silly mistake made me lose so much time....
using reading time for solving questions or actually reading :'( not sure what to do considering last time, i ran out of time to check all modules for exam 1 :-\Yeah like PhoenixxFire said, definitely use reading time to try and comprehend questions and pinpoint anything you think you are going to have trouble with. Get an idea of what you have to come so you can plan out your time basically (e.g. if you notice that the financial area has quite a few questions that you took a long time with in practice exams, try to allocate a little longer to this and move through faster with other sections that you could do easily.)
Also:OMG yes the most incredible advice. I will never do this wrong again after it lost me a mark in one SAC - that I would otherwise have gotten 100% on :'( .
Everyone please make sure your CAS is set to just FLOAT (it's caused people to lose marks because their cas setting aren't right)
Could someone predict my study score?
Sacs: 87% (defs not rank one)
Exam one: 40/40
Exam two:58/60
could you just sub in 3 and 4 as \(n\) and then minus the \(V_3\) from the \(V_4\)?Thanks, but why is V3 involved?
the difference should be the interest?
Thanks, but why is V3 involved?The question only wants the interest in the fourth year not the total interest so you have to subtract the total interest earned in the first 3 years (v3) from the total interest earned in the first four years (v4) to get just the interest in the fourth year.
Q: The Central Australia tour visits Kakadu National Park where the students are shown a flock of the endangered lesser yellow-breasted scrub thrushes. The Park Ranger leading the tour explains that there are only 2 500 birds remaining. The Ranger tells the students that out of each 100 adult birds, only 5 chicks are raised each year. However, on average, 500 birds die each year.Yep it's necessary to add it in. 5 chicks per 100 birds is 5% so the recurrence relation would be Vn+1 = 1.05Vn - 500
I wrote that the recurrence relation is V0 = 2500 , Vn+1 = Vn - 500 , however I don't know how to add in the 100 adult birds and 5 chicks raised (or if it is even necessary to add it in)
Yep it's necessary to add it in. 5 chicks per 100 birds is 5% so the recurrence relation would be Vn+1 = 1.05Vn - 500
It could potentially be a bit different depending on if the 5 chicks are added before or after the 500 die but I'm pretty sure it would be this way around.
oh so it's like compound interest right ? :PYeah sort of, you can't change this equation into Vn=R^n * V0 format because of the -500. You just have to leave it as Vn+1 = 1.05Vn - 500.
I can see what you've done, but I can't connected the dots. Can u please clarify what the 'compound factor' means for 'R' (in Vn=R^n * V0) ?
Hi Guys,
Can someone please explain how to do part (c). Question is in the attachment.
Thanks
Hi Guys,As the interest is compounding monthly, you need to divide 6(the monthly interest rate)/12(the number of months in 1 year)=0.5 %. Then you need to divide the 0.5 by 100 to have it as a decimal form of the percentage, and add this to 1, resulting in 1.005.
Need help to do this question. It is about compound interest. Specifically, Modelling compound interest with recurrence relations. Thanks
I don't know how they got an R value of 1.005. The R value I obtained was 1.00375. Has it got to do with a rounding error. When are we meant to round our answers? In the final answer, when we convert the yearly rate to a monthly rate or when we find the R value.
The question and the answer in the book are in the attachments
All help will be appreciated. Thanks
Thanks Galaxy. For some reason, when I did the question, I was looking at the example as well and accidently took the values given from the example instead of the question in the attachment LOL ;D. Anyway, thanks for the help. Without you, I wouldn't have realised the silly mistake I made.Haha I do that all of the time...looks like you were on the right track anyway, so thats amazing!
Yeah that answer is wrong - the balance definitely shouldn’t be going up in a reducing balance loan.
So is my answer correct?Yep
Yep
Hi Guys,What specifically are you stuck on? How are you trying to approach the question at the moment? You’ll learn more from it if you do as much of it as you can and then post your workings and thought process behind it up here rather than us explaining the whole thing.
Need help with the questions in the attachment. Would really appreciate it if someone can help me to solve it. The quesiton is inregards to reducing balance loans with changing conditions.
Thanks
What specifically are you stuck on? How are you trying to approach the question at the moment? You’ll learn more from it if you do as much of it as you can and then post your workings and thought process behind it up here rather than us explaining the whole thing.
For instance, how to do part (b). When you do it, what is the answer you get for it?to work out the interest payed over the term of the loan, you need to calculate the amount that is payed in total (payments x years x compounding periods per year + downpayment --> 1384 x 30 x 12=498240) and then subtract the initial value ($179994.242...) of the loan from this (498240-179994.24=318245.75). So $318,245.75 in interest was payed.
What specifically are you stuck on? How are you trying to approach the question at the moment? You’ll learn more from it if you do as much of it as you can and then post your workings and thought process behind it up here rather than us explaining the whole thing.
I have already stated this to this particular user.
dream chaser, I am not trying to be rude here but this seems (from my perspective) like you're just wanting us to do your work for you. It is very important that you have a go at it yourself and show us what you have done so we can genuinely help you. If we just give you answers, you may be able to answer that question, but what about a different question on the same topic?
It will be much more beneficial to you if you take the time to attempt it first, as Further is a subject where mistakes are very common and hence what spreads students out on the distribution.
I am posting this as you have been posting quite a bit on here (and this is OK, we are more than willing to help you).. it's just that you need to show some effort too.
This is a PSA directed at all users who post questions in the Further board.. please actually try the question yourself or demonstrate you have at least had a think about it so we can target the misconceptions as well as provide you with the answer to move forward.
Aaron, I have tried to attempt the question my self as well before I posted for help on Atar Notes. The answer I got was the same as Galaxies. However, in the book, they give a different answer so I am completely confused what is right and what is wrong.
That's all cool, so show us your working out and how you got your answer so we can address it and tell you whether the book is right/wrong. :)
If you really want me to show you how I did it, I'll show you.
First, you find the selling price of the house. I did this by using the financial solver on the CAS and substituting all the values I knew to find the unknown, which in this case on my CAS was PV(the present value). I got an answer of $229994.24. Then to find interest, you multiply 12 x 30 x 1384 - the selling price of the house - 50000. I wasn't sure if 50000 should be reduced or not. However, now i know. Thank you Galaxy for the help
Hi,Think from the bank prespective.
Would someone be able to explain to me how annuity works. I know that there is a formula used for it: Vn+1=RVn - D and that it is used to describe how much money is left in an investment. But I don't get the context of it or how it is used. For instance, I don't understand why the D value(payment received) minuses the value of the annuity. If someone is receiving money from the bank or insurance company, wouldn't there be more money in the investment?
Would appreciate all help given
Thanks :)
Think from the bank prespective.
You have x amount of money with you which someone gave to you(investment)
Now every n days/weeks/years you are giving D payment to the investor. Thus -D, if the investor adds payment to the investment it would be +D.
Hi,Take this scenario,
Would someone be able to explain to me how annuity works. I know that there is a formula used for it: Vn+1=RVn - D and that it is used to describe how much money is left in an investment. But I don't get the context of it or how it is used. For instance, I don't understand why the D value(payment received) minuses the value of the annuity. If someone is receiving money from the bank or insurance company, wouldn't there be more money in the investment?
Would appreciate all help given
Thanks :)
Oh okay, so for annuities, think of it in terms of a bank perspective, not the person investing perspective?
Take this scenario,
you invested $1000 in a bank. Lets ignore interest rate just for now.
if bank said every months they will give you payment of $10.
you will gradually lose money from the $1000, on a realistic interest rate xD.
So, in this scenario Vn<V0. as some money is always given to you per n period.
and the difference between the money you gained and the initial amount = interest earned.
Scenario 2,
this time you will be putting D payment in the bank instead of recieving payment. so D is added onto V0.
...
on the cas, think from your perspective. The way i have done and taught others for sign is;
+ if the money is coming into your pocket
- if the money is going out of your pocket.
Always make sure FV and PV have different signs.
And think realistically, think what does negative sign what really means. like there is no such thing as negative money, but what it means is either you are loosing money/ owe money. Right! just look for the meaning and you will be fine
Okay. However, I still don't understand why it is -D. If the money is giving the investor money, wouldn't the value of the investment go up in value?no.
no.
well its sign conventions. i will keep them consistent.
so you invested $1000 in bank. Thus out of your pocket and it will have - sign. -1000
Now you recieved payment of D, -1000 +D, lets say D = 10 from previous example.
So v0 = -1000
V1 = -1000+10 = -990.
The fomula is based on from the bank prespective
Okay. However, I still don't understand why it is -D. If the bank is giving the investor money, wouldn't the value of the investment go up in value and hence, be +D?Remember bank is giving the money back to you which in this should be greater than interest earned.
Okay. Would the perpetuity formula be based from the bank perspective as well? Also, thanks for the help. Much appreciated :D
Also try to graphically represent a annuity and perpetuity over n period. See the pattern yourself how the money changes over time!
Hi Guys,
I need help with this question. This is the question:
Jarrod saves $500 per month in an account that pays interest at a rate of 6% per annum, compounding monthly.
(a) If he makes monthly deposits of $500 to the account, how much will he have in the account at the end of 10 years?
My understanding of question: I know for this question, I can use the financial solver to complete it. I know that it involves Annuity, however it also involves increasing the value of the investment as well. Therefore, an annuity investment. As a result of that, on the financial solver(CAS-the TI-nspire notation):
N=120
I(%)=6
PV=?
Pmt=-500
FV=?
PpY=12
CpY=12
PmtAt=END
Btw, PV=Present value of Annuity. In this case, how much is invested. FV=Future value of Annuity.
I know for the question, I need to find FV. That means, PV should be given but I don't think it is. Hence, why I can't complete the question. Could someone please help me :D
All help will be appreciated
Thanks :)
I haven't done this in a looooong time but reading the question, you're right- they don't give you the PV value. It might be right to assume that the PV value just starts with 0. What's the answer? This might be wrong so someone please check!!!
Thank you very much dream chaser for helping us to assist you, by providing working out and your explanations. :) It is much appreciated that you've taken the time to read my post and acknowledge it.
I don't think that PV will be zero as the investment will not simply increase by not giving anything to the bank/insurace company in the first place. The answer is $81939.67.The PV will be zero because they're asking how much he will have in total after 10 years of saving. Unless otherwise stated, this means you can assume that he starts with 0 savings. Putting 0 as the PV will give you an answer of $81939.67
Hi Guys,I would just put this into the finance solver on your CAS
Need help with this question
Question: Roslyn earns an annual salary of $54200,which is paid monthly. She did not join the superannuation fund until her 37th birthday and she now pays 7% of her gross salary to the superannuation fund. Her employer contributes a further 14%.
(a) What amount of money is placed each month into her superannuation fund?
This question I am able to do. I did:
21/100 x $54200 = $11382. Then $11382/12 = $948.50 per month.
Now this is where I got stuck...
(b) The superannuation fund pays 4.2% per annum compound interest, compounded monthly. Assuming that Roslyn's annual salary remains constant, what is the amount of superannuation she will have available at her 60th birthday?
This is the way I did it, bare in mind this method is completely wrong as I got the wrong answer in the end.
Vn=R^n x V0, where R=1+r/100
Vn=R^n x 948.50
R=1+r/100
r=4.2/1=0.35% monthly rate
R=1+0.35/100 1.0035
Vn =(1.0035)^n x 948.50
V276=(1.0035)^276 x 948.50
V276 = $2487.90
Therefore my answer is $2487.90. However the actual answer to this question is $439829.26. Can someone please show me how to get this answer.
(c) Suppose that when Roslyn retires at 60 years of age, she places her superannuation in a perpetuity that will provide a monthly income without using any of the principal. If the perpetuity pays 4.25% per annum compounding monthly, what monthly payment will Roslyn receive?Your solution for this is fine, you just used the wrong value. Replace $2487.90 with $439829.26 and it'll give you the correct answer.
My answer is completely wrong as I used the answer I obtained in part (b) for this.
D=r/100 x V0
r=4.25%/12
r=0.354167% monthly rate.
D=0.354167/100 x $2487.90
D=$8.81.
Therefore my answer is $8.81. The answer obtained in the book is $1557.73. How do I get that answer?
So basically I need help with part (b) and (c) with this question. Also, if anyone reads this, could you please read a couple of my previous posts on the Further Maths Questions Thread to see whether I am able to complete a previous question of mine. It was in regards to PV and FV and the topic was on annuity investments(I posted it yesterday).
All the help will be much appreciated. Thanks. By the way, Merry Christmas to Everyone for yesterday. :) :D
(b) The superannuation fund pays 4.2% per annum compound interest, compounded monthly. Assuming that Roslyn's annual salary remains constant, what is the amount of superannuation she will have available at her 60th birthday?
This is the way I did it, bare in mind this method is completely wrong as I got the wrong answer in the end.
Vn=R^n x V0, where R=1+r/100
Vn=R^n x 948.50
R=1+r/100
r=4.2/1=0.35% monthly rate
R=1+0.35/100 1.0035
Vn =(1.0035)^n x 948.50
V276=(1.0035)^276 x 948.50
V276 = $2487.90
Therefore my answer is $2487.90. However the actual answer to this question is $439829.26. Can someone please show me how to get this answer.
(c) Suppose that when Roslyn retires at 60 years of age, she places her superannuation in a perpetuity that will provide a monthly income without using any of the principal. If the perpetuity pays 4.25% per annum compounding monthly, what monthly payment will Roslyn receive?
My answer is completely wrong as I used the answer I obtained in part (b) for this.
D=r/100 x V0
r=4.25%/12
r=0.354167% monthly rate.
D=0.354167/100 x $2487.90
D=$8.81.
Therefore my answer is $8.81. The answer obtained in the book is $1557.73. How do I get that answer?
948.5 is not how much the initial investment is. It’s how much is being added by the employer every month.
Your super annual Annuation is there to support you once you retire. Think of it as a retirement piggy bank. You start earning it when you start working. Your employer contributes to the piggy bank every month and it slowly piles up over time. Initially, of course, there was nothing in this piggy bank. However it starts adding up every time your employer adds another 948.50 to it. Once you retire you’re going to break open that piggy bank and it’ll support you :)
Okay. How come in my question it says that Roslyn pays 7% of her gross salary to the superannuation. Does this mean she alongside her employer is adding money into her superannuation fund or still only the employer each month.Yes, in this example both Roslyn and the employer contribute to Roslyn's super.
Is this how it works? So at the start, Roslyn starts with $0.00. Then after one month, she has $948.50. As 4.2%p.a /12 =0.35% monthly rate and 0.35/100 x $948.50 = $3.32. Then this gets added on to the $948.50 which makes $951.83. Therefore, she will have $951.83 in her superannuation account after one month. And this process continues every month right?Almost, after one month she will have $948.50. After two months she will have 948.50*2=$1897 plus the interest on the first month amount (=$3.32) which is equal to $1900.32. This process continues each month.
Yes, in this example both Roslyn and the employer contribute to Roslyn's super.Almost, after one month she will have $948.50. After two months she will have 948.50*2=$1897 plus the interest on the first month amount (=$3.32) which is equal to $1900.32. This process continues each month.
Why wouldn't the first month be $951.82?I think you answered your own question. The first month isn't $951.82 as there wasn't any money in the super to gain interest over that time (as V0=0). You're correct in saying if V0 didn't equal zero, then there would be interest in the first month.
If V0 didn't equal zero, then there would be interest in the first month right?
Hey can anyone please tell me if I've done these two questions correctly?The first part looks right but why did you change your answer to 84 months in the second part?
https://imgur.com/a/vmHFYo8
(took me way too long to try and attach this picture lol)
Sorry, for the second question, I change my answer to 84 months
The first part looks right but why did you change your answer to 84 months in the second part?Thank you :)
Need help with question c please!
https://imgur.com/a/VJvY0V2
I'm not sure whether the answer is 1407 or 1408 players. Here is my thinking: if you plug in the numbers into the equation, you get 1407.37488.
As soon as 1 year elapsed, there will be 1407.37488 players. So if you round it down to 1407 players, this means that 1 year has not passed yet. However if you round it up to 1408 players, 1 year has already elapsed.
My working out is a bit messy to comprehend, but hopefully you understand :P
just came up with a helpful idea for my summary book, but was wondering what kind of excerise books we're alowed to bring into the year 12 exam... :(It can be basically anything as long as it is A4 and securely bound. You also can't have notebooks with perforated edges.
The bound reference must be in book format of A4 size or smaller when closed.(From https://www.vcaa.vic.edu.au/Pages/vce/exams/authorisedmaterials.aspx#bound)
The number of pages is not specified.
Pages must be permanently bound and securely attached to the spine.
There must be a single horizontal or vertical spine.
The bound reference may be:
a textbook
a securely bound lecture pad
a permanently bound student-constructed set of notes without fold-outs
an exercise book.
The form of binding is not specified but it must be secure, and pages must not be readily detachable or designed to be removed. Binding can include cloth, glue, staple, spiral or comb binding.
Would it be helpful to do every past exam on the VCAA website like all the way to 2002, for exam/sac revision even though most of them are not part of the study design?Probably better to do the parts that remain relevant. I know since 2014 (when I did Further), there have been a lot of changes. Typically I'd advise doing VCAA exams closer to exams, as these are the closest you're going to get to the real deal.
Probably better to do the parts that remain relevant. I know since 2014 (when I did Further), there have been a lot of changes. Typically I'd advise doing VCAA exams closer to exams, as these are the closest you're going to get to the real deal.
So how would you go about studying for sacs? Just using the relevant VCAA past exams? Are there other resources that will help like study guides or topic tests (from atar notes, checkpoints etc)?There are so many extra questions out there to help study for SAC's. Your school might give you SAC's from previous years which are definitely good to use. I used NEAP questions before most of my exams, as well as A+ questions. I only got a copy of the ATAR Notes topic tests later in the year, but these also seemed like they would have been really good prep for SAC's. There are so many resources for SAC prep questions out there, and it's up to you whether or not you use VCAA past questions. If you are going to use the past exam questions, though, it could be a good idea to get a checkpoints book as it easily splits up the relevant questions from the past few years, but remember you will still need questions for when you are preparing for the actual exams.
My question is shouldn't the price of selling of the painting be more because ultimately, the person would have to give back that 30000 + interest or is it because it is an interest only loan that the answer I got is correct which gives the selling price of the painting.Sometimes questions are framed in a way to make sense of the situation which can lead to confusion about what they're really asking for. In this case, you are just finding the amount that needs to be paid back on the loan. Although, I'm not sure if you're answer is right because it looks like you've calculated it assuming its simple interest rather than compound interest.
Also, could someone please explain to me how annuities work.Is there any particular part of annuities you are having trouble with or just annuities in general?
Hi Guys,Compounding is about how often the interest is calculated. e.g. if the interest is calculated monthly you'll get interest on previous months interest - so you'll end up with more money, whereas if it's calculated annually you'll only get interest on the base amount.
Can someone please explain to me why the answer to this question is A. I understand that the answer would be A,B or C because it is compound interest due to the graph being geometric. What is the difference between compounding and credited and are they always the same time period(for eg. If it is compounding monthly, this means that it is credited monthly as well).
Also, not related to this question but can we get questions related to savings accounts and its amortisation table. Is it part of the study design? Because in the Further Maths Cambridge book, they only have ammortisation tables for reducing balance loans and annuities individually. Not both together.The study design says that you need to know about amortisation of a reducing balance loan or annuity and that you need to be able to interpret amortisation tables, so I'm pretty sure that question would still be in the study design (it would come under being able to interpret it).
The question is in one of the attachments of this post. An example of a savings account is also given in the other attachment if you are unclear what it is.
All help will be much appreciated.
Thanks
Compounding is about how often the interest is calculated. e.g. if the interest is calculated monthly you'll get interest on previous months interest - so you'll end up with more money, whereas if it's calculated annually you'll only get interest on the base amount.
Credited refers to how often it gets paid into the account - this is normally the same as the compounding period but doesn't have to be.
The graph shows that money is only added to the account once a year. This means that it must be credited annually - the only option where this occurs is A.
The study design says that you need to know about amortisation of a reducing balance loan or annuity and that you need to be able to interpret amortisation tables, so I'm pretty sure that question would still be in the study design (it would come under being able to interpret it).
https://imgur.com/a/MU3vB2WMallacoota is east of Portland so the sun will rise in Mallacoota earlier than in Portland
My question is why do I have to add 32 minutes to 6:03am to get the answer E rather than subtracting 32 minutes?
Anyone know if I'm doing this right? ThanksYou've got the recurrence part right but for part b, you've set n=3/2 when it should be 18 as the interest is being compounded monthly, so each month interest is being received.
https://imgur.com/a/rlr8Aer
Hi! I've just started further maths this year, and I was wondering what does 'count' mean? For example, when I plot a histogram, I am asked to say what the 'count' is. Does it mean the values along the x axis that are part of a given interval?I think you're right, it's just the number of items belonging to a given x
Thanks so much!
Hi,I haven't done stem plots in ages, however:
I was having trouble with this question, was wondering if anyone can explain.
Question is:
A single back-to-back stem plot would be an appropriate graphical tool to investigate the association between a car's speed, in kilometres per hour, and the:
A) Driver's age, in years.
B) Car's colour (white, red, grey, other).
C) Car's fuel consumption, in kilometres per litre.
D) Average distance travelled, in kilometres.
E) Driver's sex (female, male)
Answer is E not sure how.
Thanks :)
Hi!We can't supply a school's or company's that you'd usually pay for due to copyright reasons. You can try writing your own questions, hope someone who wrote their own questions is willing to share or try questions from Checkpoints, ATAR Notes and previous VCAA questions though!
Does anyone know where I can find practise SACs?
Thanks in advance!
Hi Guys,Bumping for you. Been a long time since I did financial maths (and it wasn't part of Core when I did Further). I'll let someone else help you to avoid inaccuracies. :)
Need help with part (c) with this question. Not sure how to tackle it. Would really appreciate the help thanks. Also, for part (a), I got $272.06 and part (b) $24735.17. I think they are correct. Could someone notify me on that as well.
Thanks
how should i comment on the distribution of a boxplot in terms of its shape, centre and spread?According to my bound reference, sentences.
should i just list them out or would i have to write a few sentences???
- thank you in advanced! :)
When a questions asks for the spread of data, do we give the range or the IQR??The three valid stats you could provide as measures of spread are IQR, range and standard deviation. From memory, IQR is most reliable of the three, because the other two can be swayed quite easily by outliers. Not entirely sure here, but in the instance it's not specified, I'd be leaning towards putting all three if asked for numbers (depends on marks though) and, if commenting, probably just discuss the IQR.
Hey everyone, was looking at my textbook trying to catch up because I have missed a lot of school but when an activity "crashes" does that mean that the time for that activity is now shorte.Crashing is just speeding up (or reducing) the completion time of a particular activity so your understanding is correct
So if activity G is 15 days long and crashes by 2 days. Does that mean the time now for activity G is 13.
I know its a simple question was just a bit confused as my teacher never explained crashing and just dove into the questions.
Thanks everyone!!
Is it a good idea to buy the ExamPro Further Maths book? Seems like it's for the old study design :-[I can't remember how much the study design changed but I'd be a bit wary of getting it. It may be useful for just doing practice questions but I wouldn't count on it as being a substitute for past VCAA exams (as I'm not sure if the format is different in the exampro book). I'd probably only get it second hand, I don't think it's worth buying new as there are probably better options out there.
(ISBN 978-0-9875376-0-7)
Are we still required to do a 3/5 median line? This includes marking points and drawing a 3/5 median line.
A key example of this is VCAA 2011 Exam 2 Question 3b. ;)
Hi everyone,
I just had a question on Data analysis. I was just wondering what the advantage of converting a two-way table into percentages would be, and if there is specific terminology I would have to use in answering the question.
Thank you!
Hey all, I'm not sure how to do these questions and was wondering if anyone would be able to help me out
1. Geoff has a compound interest investment that earns interest compounding monthly. The balance of Geoff's compound interest investment was $4418.80 after 6 months. The balance of Geoff's compound interest investment was $4862.80 after 2 years. The amount of money that Geoff initially invested is closest to:
A. $4000
B. $4015
C. $4280
D. $4370
E. $4715
2. A printer was purchased for $680. After 4 years, the printer has a value of $125. On average, 1920 pages were printed every year during those 4 years. The value of the printer was depreciated using a unit cost method of depreciation. The depreciation in the value of the printer, per page printed, is closest to:
A. 3 cents
B. 4 cents
C. 5 cents
D. 6 cents
E. 7 cents
Thank you!
Hey, I don't have my calculator on me, but to solve question one you would use your financial calculator on the CAS.Thanks so much!! I should've done it like this haha I initially did trial and error bleugh
Q1. Assuming that Geoff isn't adding money to this account, first you would want to calculate the annual interest rate. To do this enter the following in the financial solver.
N - 18 (24 months - 6 months)
I - (leave blank/0)
PV - -4418.80
Pmt - 0
FV - 4862.80
ppy - 12
cpy - 12
pmt at End.
Once you've found the annual interest rate, you can enter the following in your CAS,
N - 6 (Time taken to reach the first value mentioned)
PV - (0/leave blank)
I - (Enter value previously found)
Pmt - 0
FV - 4418.80
ppy - 12
cpy - 12
pmt at End.
This should give you your answer, (my guess is that it would be somewhere around $4280)
Q2. The Unit cost depreciation rule (from what I remember) is as follows
Vn = V0 - nD
V0 being the initial price of the asset
Vn being the value of the asset after n units of use
n being amount of 'uses'
D being cost of one 'use'
In this case, you are trying to find D. V0 = $680, 1920 x 4 = n (amount of uses) and Vn = $125.
In your cas you can simply type in Menu -> algebra -> solve (125 = 680 - (1920 x 4)x,x
This should give you your answer. Hope this helps :)
Also, congrats on your accounting & further scores! am definitely aiming for a score like that in further! :D
Hey,
I was wondering about the N value for finance solver
If an investment/whatever is compounding monthly (or other units), you times the yearly value by 12 right? This is what we were taught at school & what some of the examples in the cambridge further 3/4 textbook show
however, I've encountered a few questions where the answers in the textbook were the 'year' value, not the actual 'month' value (they did not times the 'year' value by 12). I've shown them below:
(9G q7&8 )
7) Bree has $25 000 in an account that pays interest at a rate of 6.15% per annum compounding monthly.
a) If she makes monthly deposits of $120 to the account, how much will she have in the account at the end of 5 years?
b) If she makes monthly withdrawals of $120 from the account, how much will she have in the account at the end of 5 years?
8 ) Jarrod saves $500 per month in an account that pays interest at a rate of 6% per annum, compounding monthly.
a) If he makes monthly deposits of $500 to the account, how much will he have in the account at the end of 10 years?
b) Suppose that, after 10 years of making deposits, Jarrod starts withdrawing $500 each month from the account. How much will he have in the account at the end of another 10 years?
Would the answers be the textbook's wrong and be a fluke or have I been learning incorrect content? :s
Thanks!
Hey guys!
I've been trying to figure out how to do this question for 20 mins now lol.
Calculate the number of interest-bearing periods, n, required, and hence the time in more meaningful
terms when:
Vn = $2100, Vo = $1200, r = 3% per half-year
Using the formula Vn = Vo x Rn then i get
2100 = 1200 x (1 + (3/2)/100)n
Apparently, this is wrong and i'd appreciate if anyone can tell me why.
Also, can this problem be done using the Finance Solver?
It's not wrong. What is your reason for thinking it is wrong?
Yes:
N = ?
I = 3
PV = 1200
Pmt = 0
FV = –2100
PPY/CPY = 2
(or you can do PV = –1200, FV = 2100).
N is the total number of payments from the first exchange of money (ie. borrowing or investment of a principal) to the final exchange of money (ie. the transfer of the outstanding balance to whomever it is owed). Assuming that the number of compounding periods per year = number of payments per year, then N also gives the total number of compounding periods.Yeah I entered those values into my finance solver as well, but got 42378.59 for the first question :L (the right answer came up when i changed the N value to 5 just to see what would happen)
Yes, to find the balance of an asset after y years, with monthly payments, then N will be y * 12.
For 7(a) I get the same answer as the textbook. Here are my tvm solver entries:
N = 5*12
I = 6.15
PV = –25000
Pmt = –120
FV = ?
PPY/CPY = 12
For (b), make Pmt = 120 and everything else the same, and I get the same answer as the textbook.
Again, I got the same answers as the textbook. For (a), my tvm solver entries were:
N = 10*12
I = 6
PV = 0
Pmt = –500
FV = ?
PPY/CPY = 12
For (b), my tvm solver entries were:
PV = answer from (a)
Pmt = 500
Everything else the same as (a).
I don't think you have misunderstood the content. Perhaps you have misunderstood these particular questions, or you have used incorrect tvm entries.
If i do it as above, i get n = 34.31 --> 34.31 half-year interest bearing periods = 17.16 years
However, according to the solutions, it says that there are 19 periods = 9.5 years
In order to see if the the textbook gave incorrect answers by mistake, i attempted several other questions that were exactly similar to this one. But i just ended up completely different answers to the textbook solutions just like how i did above.
(MathQuest Further Maths 6th Edition: Chapter 6.5 Q13a)
Yeah I entered those values into my finance solver as well, but got 42378.59 for the first question :L (the right answer came up when i changed the N value to 5 just to see what would happen)
I'm not sure whats up with my finance solver then awks
(And for 7b, I did the exact same values with +120 as the PMT and got 25569.07 for the FV :/)
Yes, I got 42378.59 for 7(a) and 25569.07 for 7(b), and those are the answers given in my textbook. Are you using the revised edition of the textbook? The first edition of the book for the new study design was notorious for errors...Ah I'm using the pdf copy of the textbook, which must be the older edition. That sucks :(
If i do it as above, i get n = 34.31 --> 34.31 half-year interest bearing periods = 17.16 years
However, according to the solutions, it says that there are 19 periods = 9.5 years
In order to see if the the textbook gave incorrect answers by mistake, i attempted several other questions that were exactly similar to this one. But i just ended up completely different answers to the textbook solutions just like how i did above.
(MathQuest Further Maths 6th Edition: Chapter 6.5 Q13a)
hey with these?The answer is 1680. The height of the pyramid isn't the same as the height of each triangle, you can use Pythagoras' theorem to find the height of the triangles.
ive done question 11a btw.
with 11b, is the ans wrong? it says 1680
Hi guys
Just got a 68% on my first further sac data and analysis
pretty bummed as i had high expectations
Does that mean that i would need a 90%+ for all other sacs and exam to even consider a 40ss or is that completely out of reach now
Also what are some study techniques and methods to maximize marks on sacs? Lost quite a few marks on the open ended questions, how are ways to minimize mistakes?
Also anyone got practice sacs for recursion analysis?
Thanks guys
hey! i'm not entirely sure if these questions are in the further maths course – i've checked the study design but it's a bit vague on latitudes/longitudes so i was wondering if someone would be able to help me double check :DIf you're interested, the distance between any 2 lat,long locations is given by the Haversine formula: https://en.wikipedia.org/wiki/Haversine_formula
if they are, would someone be able to help me out please as i'm not sure on how to do them :L (the fact that both the latitudes and longitudes are different is messing with my head :()
thanks very much!
Find the distance around the parallel of latitude for the following locations:
a) X: latitude: 32ºS, longitude 50ºE ; Y: latitude 32ºN, longitude 80ºE
b) X: latitude: 12ºS, longitude 30ºE ; Y: latitude 12ºN, longitude 80ºE
note* my textbook is possibly the one with many typos because i've found some errors previously, so if someone has an updated textbook and would be able to check (19B q19b and c), that'd be awesome! tysmm
Hey guys!
So this is the answer to a question from an Insight exam from Matrices:
23% of members choosing C will change to W = 0.23 * 51=11.73 =12 people
9% of members choosing A will change to W = 0.09 *73 =6.57 = 7 people
65% of members choosing W will continue with W = 0.65 *101 = 65.65 =66 people
66+7+12 = 85
In total, 85 members will choose the weights class in the second week.
So I did this all in one step rather than than rounding after every step (basically 0.23 * 51 + 0.09 *73 +0.65 *101) and got 83.95, which i rounded to 84.
My question is, is this wrong? Has anyone seen this type of question on a VCAA exam and seen which method to use?
Hey Rani, when I was studying methods last year the general consensus was to use unrounded answers for all your working out and then round at the end. With most vcaa questions, the final rounded answer will be the same regardless whether you rounded while working or not. However, if you need to round an answer in a previous question and use the same value for a new one, use the rounded value. Basically, use unrounded unless it says so.
Hey ANTry substituting values into into the new transformed equation and see where it leads you. Also consider what an inverse transformation on the x axis does to your original graph.
If someone helps me with a question from the NHT exam 2017, I'd greatly appreciate it. I have attached the photos below. I am having trouble with question 1C)ii. The original question is also attached.
Thanks
Try substituting values into into the new transformed equation and see where it leads you. Also consider what an inverse transformation on the x axis does to your original graph.
Let me know if that didn’t quite help and you need some clues. :)
Sorry but I don't quite understandOk, I’ll try to break this down.
Ok, I’ll try to break this down.
1. Remember the original equation. Then have a look at the original graph. How does the question Q1c)ii. differ to the original graph? (What transformation is used?)
2. We now want the transformed equation. It’ll make it easier to visualise and graph, as, if you work it out correctly, you’ll be able to substitute values and work out what type of graph you’ll be drawing. How can we do this given we know which transformation we are applying? Can we substitute something somewhere in the original equation to achieve this? If so, substitute as you see fit.
3. What sort of equation do you now have? Graph it. (Remember to substitute the value of k you would’ve worked out for the previous part of the question when you do this!)
4. Make sure you hit at least two points with their correct coordinates to gain the mark. (Assessors usually look for that in questions like this.)
Does what I’ve done and why I’m doing it make sense now?NoteNote: You may have realised I did a few unnecessary steps e.g. find the transformed equation. This is because this is the way that I understand the most and thus can explain the best. (Plus, getting an equation means you can double check that you’ve got the right graph almost instantly.) There’s more than one way to reason this question out and still get the same correct graph.
Hey AN
If someone helps me with a question from the NHT exam 2017, I'd greatly appreciate it. I have attached the photos below. I am having trouble with question 1C)ii. The original question is also attached.
Thanks
Now I don't know how the VCE curriculum works, but if your up to this kind of topic, you would've done something like graphing earlier. If you have then I'm sure you would've looked at Hyperbolas and what not. That's exactly what this equation is, it's of the form y = 1/x, except the '1' is a k which only changes steepness and not the shape.
I agree, but the answer is a linear graph...
I agree, but the answer is a linear graph...It should be linear because your graphing y vs 1/x. Think of it this way. A linear graph at it's most basic form has an equation y = m(x). Graphing y vs x means as x increases, y increases in a constant proportion to it. Now consider the equation y = k/x. If we graph y vs x, as x increases y decreases giving a hyperbola. Now if we graph y vs 1/x, isn't this equation the same as graphing y vs x for y = mx. Think about it, y = k/x is of the form y = k(1/x), meaning that 'm' the gradient is k and the 'x' is replaced by 1/x. You could have anything in the brackets for example y = k(e^x). In that case graphing y vs e^x will be a linear graph, as y changes by a constant proportion when comparing it to e^x.
It should be linear because your graphing y vs 1/x. Think of it this way. A linear graph at it's most basic form has an equation y = m(x). Graphing y vs x means as x increases, y increases in a constant proportion to it. Now consider the equation y = k/x. If we graph y vs x, as x increases y decreases giving a hyperbola. Now if we graph y vs 1/x, isn't this equation the same as graphing y vs x for y = mx. Think about it, y = k/x is of the form y = k(1/x), meaning that 'm' the gradient is k and the 'x' is replaced by 1/x. You could have anything in the brackets for example y = k(e^x). In that case graphing y vs e^x will be a linear graph, as y changes by a constant proportion when comparing it to e^x.
So in the end basically in the equation y = mx, you can 'replace' x with anything, but you must graph y vs whatever that is in the brackets.
The data is not incorrect. Remember in essence your graphing y vs 1/x. So your points generated by those data values that you said will be (1/1, 60),(1/2, 30). If you take time = 3, you end up with the point (1/3, 20). Now just to check it's correct we can do m = (y2-y1)/(x2-x1), which gives us:
oh I think I understand now. So would it be y=60(1/time) right? but when I do it I get: 60(1/1) =60 but when I do time=2 I get 60(1/2)=30 which is incorrect
sorry I'm bothering you people
sorry I'm bothering you peopleNot at all, were here to help! =)
Yup. Transformations tend to change the graph, equation and coordinates quite drastically, so you’re on the money there.
So for the Q1c)i) I have gotten k=60 by doing the following: 30=k/2 (chose the point 2,30 and solved for k)
However, for part ii, the equation is avg speed= 1/time hence its no longer 60/time?
oh I think I understand now. So would it be y=60(1/time) right? but when I do it I get: 60(1/1) =60 but when I do time=2 I get 60(1/2)=30 which is incorrectReally close! You’re missing a divided sign somewhere...
sorry I'm bothering you people
Hi,What’s the reason you’re getting the VCAA questions wrong? Is it the wording, identifying what type of question it is, dumb mistakes or something else entirely? Perhaps if you could look into this, you’d know how to fix this issue.
The only subject I am worried about is math. I have done so many practice exams and have a really detailed summary book. It's weird because I answer all the textbook questions confidently and correct, but then on most of the vcaa practices I get them wrong or I don't understand in what what's to apply my knowledge. This is only for the data and finicancial math part.
Does any one have any notes or tips on how to get better?
Hi,That's normal. Doing just textbook questions wont help for the final exam. What you need to be doing is past papers as this is what will build your ability to problem solve. Most textbooks only have very niche questions so you can learn the content, whereas the exam questions require you to apply this knowledge in many different formats that just aren't usually in textbooks. Most of the time textbook questions are easier compared to the actual final. So far I only know of one textbook here in nsw that has questions as hard as the actual paper.
The only subject I am worried about is math. I have done so many practice exams and have a really detailed summary book. It's weird because I answer all the textbook questions confidently and correct, but then on most of the vcaa practices I get them wrong or I don't understand in what what's to apply my knowledge. This is only for the data and finicancial math part.
Does any one have any notes or tips on how to get better?
Hi,sorry but are you able to state what question this is for what exam? Just so I can get some context into what the question is asking.
Thank you for taking time out to help students, I love ATAR notes so so much.
Anyway, how does this work? I don't understand how they got the answer with this explanation.
Thank you (:
sorry but are you able to state what question this is for what exam? Just so I can get some context into what the question is asking.it was what is the maximum flow from the source to the sink? :)
Hi,
How do you find the equation of a line, from a graph?
Hefferman 2011 Q8
The graph does not begin at 0
Hey,
For these type of questions, i would choose two points from the regression line, in this case (75,68) and (85,60) and then put these points on your CAS or find the equation by hand, finding the gradient, then substituting two points into the equation to find the y-intercept.
Therefore, the answer is E
Another approach is by inspection, as the horizontal axis does not start at 0.
Hope this helps :)
Hi,
How do you find the equation of a line, from a graph?
Hefferman 2011 Q8
The graph does not begin at 0
Hey y'allIf you rearrange \(Q=mx+ny\) in terms of \(y\) you get, \(y=\frac{-m}{n}x+\frac{Q}{n}\). \(\frac{-m}{n}\) corresponds to the gradient of the profit equation so \(\frac{-m}{n}=-1\) therefore \(m=n\)
Im having trouble with this specific question from the VCAA 2017 Exam, question 3 Graphs and Relations module
I have read the examiners report (below), but i do not understand how m=n
Only 7% of the state got it fully right!!
If you rearrange \(Q=mx+ny\) in terms of \(y\) you get, \(y=\frac{-m}{n}x+\frac{Q}{n}\). \(\frac{-m}{n}\) corresponds to the gradient of the profit equation so \(\frac{-m}{n}=-1\) therefore \(m=n\)
Hopefully this helps!
Hi again.These equations should be 16.75=2.55+8x+10y and 30.35=2.55+20x+18y
I was having a bit of confusion with q8 Graphs and Relations module 2018 exam 1.
My two equations were 16.75=2.25+8x+10y and 30.35=2.25+20x+18y
Solving this simultaneously I got x=0.36 and y=1.16 (rounded to two decimal places)
The examiners report tho showed 8x+10y=14.20 and 20x+18y=27.80 which is the same as mine but they got rid of the $2.55
However, these two equations gave them x=0.4 and y=1.1
And the question was asking the exact cost of a ride, not the closest.
These equations should be 16.75=2.55+8x+10y and 30.35=2.55+20x+18y
Hey guys!
With those descriptive questions, I wanted to clarify what exactly is needed for 2 marks.
For example, 2019 NHT Core Q5biii (attached), the examiners report says the following:
A statement that clearly indicated the contention is supported with a change or difference in one
category of likelihood of attack considered and a statement similar to one of the following using
column percentages was required. Approximate percentages were acceptable.
• The percentage of animals with low likelihood of attack decreases with increased exposure to
attack during sleep – low exposure 91%, medium exposure 89%, high exposure 11%
• The percentage of animals with medium likelihood of attack changes with increased exposure
to attack during sleep – low exposure 6%, medium exposure 0%, high exposure 11%
• The percentage of animals with high likelihood of attack increases with increased exposure to
attack during sleep – low exposure 3%, medium exposure 11%, high exposure 79%
Basically, what does the first statement have to be? Because the examples they've given are in addition to another statement, but I thought the ones they provided already indicate a change/difference?
Just wondering what would be the rough percentage required for further maths exam to get 40+?90% via https://twmpublications.com/statistics
i have done well with sacs and stuff - high A's and A+....
How do I attach a question ? PhotoHey!
I forgot to shade what modules I didSee here for a similar thread and my answer.
I’m so worried
Do you think they won’t mark it??? :'( :'(
I forgot to shade what modules I didSo did i in 2017 and my school got a phone call and i just had to confirm over the phone which 2 modules i completed!!
I’m so worried
Do you think they won’t mark it??? :'( :'(
are you sure it’s ok if I forgot to shade it I’m stressing out so muxh and if they don’t mark it I would be really upsetVCAA will try to contact you by phone. If they cannot get onto you, they will contact your school. You not only will have to tell them which modules you answered, but also in which order you answered them.
So you mean which one I did in the first set of modules and which one I did for the second set?You did two modules. Let's say they were matrices and Networks. They will need to know which module you answered in the first box.
Hey guys, I'm sort of freaking out rn...Close to 100%
I'm ranked highly in a strong cohort, but scored a mere 37/40... so many dumb mistakes
What score do you think I need on exam 2 to achieve a 45+?
Thanks for the help
Hey guys, I'm sort of freaking out rn...
I'm ranked highly in a strong cohort, but scored a mere 37/40... so many dumb mistakes
What score do you think I need on exam 2 to achieve a 45+?
Thanks for the help
I'm just wondering what the conventions are for answering questions in terms of units.Units are generally stated in the question. Your answer does not need to include the units.
For example, for 1 marks questions is it fine to write 15,000 instead of $15,000; 20 instead of 20 goals or 2 instead of 2mm. Etc
Cheers
Why is the LST of D 3? -thought it was 4
I got 4 as well. The only way I can think of it being 3 is if they went the wrong way against the dummy line when they were backwards scanning. So they have gone from activity E down the dummy line to activity D. But this shouldn't work?
Can someone please explain Q3 from matrices module NHT exam 2019?
How do I find the centre/median for a skewed histogram? A symmetric one is fine but I am unsure for a skewed, if someone could explain it to me it would be well appreciated. Thanks.
You would do the same as you would for any normal histogram. Just count from each side until you reach the middle numberEven if their are higher frequency values on one side compared to the other? If you count to the middle number it's not necessarily even on both sides?
Even if their are higher frequency values on one side compared to the other? If you count to the middle number it's not necessarily even on both sides?
Is there any chance you can upload a picture of the question? I like to think of the histogram as a dot plot when finding medians. If you look at q3 from NHT 2018 Exam two for example, you would count the frequency of each bird weight if you wanted to find the median. Since there are 143 birds, and the weight of 0-1000 has a frequency of over 100, the median would be 0-1000 if you understand what I mean?This is a question from the further textbook, it is asking to find the "approximate location of the centre"
This is a question from the further textbook, it is asking to find the "approximate location of the centre"I think you should manually count the total number of whatever is on this histogram and then go from either the left or right-hand side of the graph to find the certain point that there is 50% of the data above and 50% of the data below that point. This will find the median.
This is a question from the further textbook, it is asking to find the "approximate location of the centre"
This is a question from the further textbook, it is asking to find the "approximate location of the centre"
Hey, everyone, I've been searching google but I can't seem to find anything
Could someone explain to me what this means
50 –< 55 seconds
thanks
For financial math-
Can someone distinguish for me when a question asks you to find the value of an investment or the interest earned "in" 2 years or "after" 2 years?
One question is that what is the total interest earned with an investment at $6000 with a simple interest rate of 3.5%p.a
a. in the first four years
b. after four years
Thank you - I hope this makes sense
Is it correct to say that:
V0 = first year
V1 = second year
V2 = third year
V3 = fourth year
V4 = fifth year
V5 = sixth year
thankyou
Anyone who did Methods 3/4 in yr 11 and chose Further/Spesh 3/4 in yr 12 reply with how you found it- interested to know what experiences people had with it
What is a hurdleIs this in reference to a test of some sort? If so it normally means that you're required to pass it to pass the subject.
Hey everyone, just wanting to double check the answers to the following questions:
1) Fiona borrowed $740 000 to purchase a property at 5.2% p.a.. The loan is to be repaid in monthly repayments over the course of 30 years.
a) Calculate the monthly repayment value
b) Evaluate the value of the interest Fiona would pay over the course of the mortgage.
Thanks in advance!
a) 4063.42 (~2 d.p)
b) 722831.39 (~2 d.p)
Thank you! I got the same answers but wasn't entirely certain as to whether Finance Solver could be used (since it is never explicitly mentioned that it is compounding).
You can use Finance solver since it's asking for "monthly repayments" which in this case would mean it is compounding! ;D (Compounding monthly really). Whenever you see repayments, just think Finance Solver as it makes the process so much easier. It would take quite a long time if you didn't use FS.
The stuff you would put in would be:
N = 360
I = 5.2
PV = 740,000
Pmt = (-4063.42) Answer.
FV = 0
Ppy/Cpy = 12
Hope that helps!
That helped a lot! Thank you!
Also, just another question. How would you go about solving the following:
1) Robert wants to borrow $50 000. He is offered two options by two different financial institutions
- Option 1 = 7.32% p.a. simple interest
- Option 2 = 7.32% p.a. compounded fortnightly
Both options have a 10 years loan term
Calculate the monthly repayment under both options.
does a hurdle effect the study score?Is this regarding a SAC your school has? I wasn't aware of schools making SACs with hurdle requirements. But if yes, then it would depend on your school's policy so best to ask them.
When you make a prediction from time-series data is it best to use the smoothed data or the original data? why why not??
Id say the blue is seasonal with a slighting increasing trend and the black reveals that there is no seasonality and with the trend perhaps being slightly increasing (or relatively constant not too sure!).
Hello!
I was wondering if someone could explain 5d to me? I got $993.41 but the answer was $319.41. Thanks!
In part d, they're asking for the depreciation IN the third year, meaning by how much did it reduce by in the third year (not throughout the three years)
Hey Guys,
What type of distribution do you think the attached boxplot is?
Much appreciated
Positively skewed. You should keep a diagram of each in your bound reference. Google 'Boxplot distributions' for diagrams
You wouldnt think it could be approximately symmetric?
Hi, I was wondering what the best software is to type up your bound reference. Need help please!!!!!
Word was my saviour for Further last year 8).Your BR looks amazing!! Would you mind sharing it with us if you still have it on your computer??
Further is quite a wordy maths subject and I found that using Word with multiple tables seems to work well for me as it made it super easy to find something if I were to panic. You can insert equations into word or write using LaTeX too if that's your type of thing. (I currently have my Methods Bound reference on Word too and it's super handy as maths equations are easy to write into it. Plus you can convert it to a PDF when you are done for printing)
Some pictures of my old B.R are in the spoiler below if you want any ideas of how to go about constructing your own:Hope that helps! :DSpoiler(https://i.imgur.com/8Rn8HTy.jpg)
(https://i.imgur.com/pAONNmA.jpg)
Your BR looks amazing!! Would you mind sharing it with us if you still have it on your computer??
Does anyone know how the exam this year will look like considering we only need to complete one module? As in, will the time to complete the exam be reduced, or will there be more questions per module?
does anyone know whether further examiners would accept this as a 'show that' answer?
thanks XD
How would I solve this if I'm not given the initial state matrix?
Hello all!
I was wondering if there was any particular way to find out the amount of the last payment (like in part dii of the attached question)?
Is there some way on the finance solver or do you have to use recursion rules or any other ways?
Thanks!
Eloise
Good question! Do you know what happens if you raise a transition matrix to a stupidly high power (and in this case, even just to the power of 10 is enough, though you should typically do 50 for good measure)?Yes, but to do that don't you need multiply T^n times So? How do I find the So values when it's only given for the rose?
Yes, but to do that don't you need multiply T^n times So? How do I find the So values when it's only given for the rose?
does anyone know whether further examiners would accept this as a 'show that' answer?
Hello everyone!
I was completing the 2015 Further Exam 1 and I got a bit stumped on Networks Question 8, l found some worked solutions (not from VCAA as they were not on the examiners report) and saw that they were using something called a dominance matrix. I have not learnt this for the networks module and by a quick look of the study design, it is not in the Networks section either. Is this part of the 2020 study design I have missed or was it only part of the old study design (2006-2015)?
Thank you!
Matrix representations of networks and their application IS part of the current study design. So you could be asked something about a "dominance matrix", since that could be understood as an application of a matrix representation of a directed network.
What you are NOT required to know as part of the networks module is that if A is the one-step adjacency matrix (ie. where each entry gives the number of edges between the respective vertices), then A^n is the n-step adjacency matrix (where each entry gives the number of paths of n edges between the respective vertices).
Out of curiosity, have we seen dominance matrices asked about before in the current study design? Seems odd they'd mention it explicitly in the old design, but not this one, if they were still going to ask about them
Not that I recall. My advice would be that, even if it's unlikely to be asked, it still appears to be within the scope of the course.VCAA moved dominance matrices into the Matrices module starting 2016. Therefore no longer relevant in the Networks module.
Hello,
I am slightly confused with rounding. My teacher said that the rounding depends on the context of the situation; saying you would always round down in certain contexts. For example, let's say that you got an answer of 277.8 cars and the question did not specify rounding, my teacher would have rounded down to 277 cars.
However, according to the trial exams I am doing, they would have rounded normally - (in this case, rounding up 278 cars).
Can someone please tell me how VCAA expects our answers to be rounded?
And is rounding to the "nearest" whole number/car/month (etc.) the same as rounding to the "correct" whole number/car/month (etc.)?
It would be greatly appreciated if anyone could answer my questions with VCAA examples, feel free to ignore these questions.
Thank you
Hello,As has been pointed out, it does depend on the context of the question, but also on the wording.
I am slightly confused with rounding. My teacher said that the rounding depends on the context of the situation; saying you would always round down in certain contexts. For example, let's say that you got an answer of 277.8 cars and the question did not specify rounding, my teacher would have rounded down to 277 cars.
However, according to the trial exams I am doing, they would have rounded normally - (in this case, rounding up 278 cars).
Can someone please tell me how VCAA expects our answers to be rounded?
And is rounding to the "nearest" whole number/car/month (etc.) the same as rounding to the "correct" whole number/car/month (etc.)?
It would be greatly appreciated if anyone could answer my questions with VCAA examples, feel free to ignore these questions.
Thank you
Hi guys,
For further i am ranked 3-5, with the top end being extremely strong and was wondering would a 50 study score be possible if i were to get full marks or lose 1 mark in total across both exams? Or if i achieve such on the exam will my score still be dependent on hoping that those ranked higher than me full mark or get close to full marking the exam?
Thanks in advance
When we're asked to draw a reg line, do we alw start from 0 or where the first data on x value is given?- When sketching the regression line onto a graph, assuming its a scatterplot, identify where the y intercept is (it's not always at x=0!) and sub that x value into the equation to find the y intercept.
Do ALL time series plot have irregular fluctuations?
When the data provides both year and numbers, which do we use for IV? (eg 1 for 2000, 2 for 2001)
Thanks in advance!
Hey guys,The answer is 12.
Could someone tell me what the LST for activity D is? I believe its 6, but the answers and my friend (rank 1) say its 12. I can understand why it would be 12; however, wouldn't it affect the overall completion time?
Much appreciated
Hi Stick, i got a sac average of 98% in a strong cohort/high ranked, I think I dropped 2 marks on exam 1 and 3 marks on exam 2, can I still get 45+ in Further maths 2020
Hello 😀
I am a Mathematics teacher and actually teach 11 General Maths and the year 12 equivalent which is Further Mathematics. Year 11 General is actually easier than standard year 10 Mathematics and you will have no difficulty at all doing Further Mathematics without having completed General Mathematics.
I hope your Methods examinations went well and you get the score you hope for 👍👍
Hi, this year I accelerated in 3/4 methods and just completed the subject. I have picked up further as my fifth subject. How difficult will it be to pick up 3/4 further without having done units 1 and 2?
Thanks! ;D
Hi! I was wondering what exactly I need to know in this study design dot point:Hi homeworkisapotato!
population and sample, random numbers and their use to draw simple random samples from a population or
randomly allocate subjects to groups, the difference between population parameters (e.g., µ and σ), sample
statistics (e.g., mean and standard deviation of sample)
Do I need to know how to calculate the standard deviation of a population? I don't really understand what to know and how that is applied into math questions
Also, do you recommend any external resources to buy for additional practice questions?
Thank you so much in advance!
hey guys so basically im struggling in the question where its like how to find the median from the histogram like its not always that the middle of the histogram is the median and im having a hard time to figure it out by looking at the graph.
also for box plots how do i know how much of the data is there eg: if they give a boxplot of a sample of 48 children earning pocket money . how do i know in percentage how many children earned like more than $20 because there is no numbers on the boxplot to indicate that.
Ordinal, they all have a specific order such as 3000,3001,3002 and so on.
Someone please let me know, I recently royally screwed up my financial SAC ( I don't even know if I'll pass tbh). I scored a 91 % on the first DATA SAC. So my question is, if I do mess up my financial SAC but get 90+ on all the upcoming network and matrices SAC and then do relatively well in the exam. Does that still mean I am able to reach 45+ or at least in the mid 40 range for further? Or is that it for my goals and dreams in further?You can still score very highly as long as you ace your future SACs and the exam, which I know you will since you seem so committed. All the best :)
What’s the difference between bias and confounding in statistics
How do you do this question
A 95% confidence interval for the population mean based on a sample 109 observations is 48.26 to 52.39. Which of the following is most likely the 99% confidence interval?
A 48. 60 to 52.05
B 52.39 to 56.85
C 47.59 to 53.06
How do you work this out it’s 47.59 to 53.06
Thanks
If x is from a normal distribution with mean 5 and standard deviation 2 find
p( -2.3< x < 8.5) to 4 decimal places . Use r commander to answer this question.
How would you do this question . The answer is 0.9598
You know the normal distribution has this formula:**** This discussion about Confidence intervals and formula for a normal curve does not belong in this thread !
https://www.thoughtco.com/thmb/8teul80x5qdrwyFNdvv_ATs_mJY=/1250x0/filters:no_upscale():max_bytes(150000):strip_icc()/bellformula-56b749555f9b5829f8380dc8.jpg
Plug in your values for standard deviation and mean, then use a definite integral with terminals of 8.5 on top and -2.3 on bottom to find the area under the normal distribution function
Hi, is time considered a discrete or continuous variable?
Can someone help me with what a "three-median line" is and how this is different to median smoothing? There was a question about 3-median line in the vcaa 2011 exam but I'm not sure if it's still relevant to the current study design. Thanks
Hi, is time considered a discrete or continuous variable?Continuous, as is evident in the sweeping second hand on an analog clock.
Can someone help me with what a "three-median line" is and how this is different to median smoothing? There was a question about 3-median line in the vcaa 2011 exam but I'm not sure if it's still relevant to the current study design. ThanksThe three median line is not in the current study design that commenced in 2016. You can ignore it. It is not the same as tmedian smoothing.
Looking for sols or answers for Further Maths NHT 2021 Anyone?
Looking for sols or answers for Further Maths NHT 2021 Anyone?
Our school only though us cores and modules 1(matrices) and 2(network).
However, I found module 3(geometry and measurement) easier than module 2(network).
Am I allow to complete modules 1 and 3 instead of module 2?
I asked my school teacher and they say that I should stick with the modules that I learned because it will stuff everyone's score. I don't get why that will stuff everyone's score.
Can somebody tell me the reasons and why I should stick with modules I learned at school? (I'm 100% sure I will do better if I do module 3 because I always get 100% on the practice exam if I pick modules 1 and 3.)
Looking for sols or answers for Further Maths NHT 2021 Anyone?
Can someone tell me why distance is a continuous variable? In 2016 vcaa sample exam 1 (question 4), the distance was recorded to the nearest tenth (?) of a kilometre e.g. 4.2, 0.8, 3.9 however this did not count as a discrete variable and I don't understand why? I thought that the type of variable depends on HOW it's recorded and not the nature of the variable itself. Any help would be appreciated, thanksDiscrete = can be counted (e.g. number of steps walked)
Hi what study score am i likely to get with these scoresHi tannicholas!
93/100 sac prob around rank 5-10
40/40 exam 1
58/60 exam 2
Edit: didn't see this question
Discrete = can be counted (e.g. number of steps walked)
Continuous = can be measured
With the unit of kilometers, it can be measured (as a bit of a silly example, you can get a really long ruler and measure the distance).
Hope this helps.
Thanks! But what about height to the nearest cm? or weight to the nearest kg? you're technically still "measuring" these values but it's discrete...(a bit silly that I'm struggling with this haha but I wanna make sure I understand it properly)
Hi,
I can be wrong but it does not matter if it says "nearest Kg" or "nearest cm" it would still be continuous. As the person earlier said Discrete is counting. In this case you are measuring someone weight thus it has to still be continuous does not matter if it is full number or in decimal.
Hi tannicholas!It was 93 for both units.
Just wondering, what were your SAC averages for Unit 3 and 4 separately?
Yeah ig that makes sense aHH but my teachers said it'd be discrete ://
Hi,
I can be wrong but it does not matter if it says "nearest Kg" or "nearest cm" it would still be continuous. As the person earlier said Discrete is counting. In this case you are measuring someone weight thus it has to still be continuous does not matter if it is full number or in decimal.
Yeah ig that makes sense aHH but my teachers said it'd be discrete ://I've had a similar question about petrol prices
Hi what study score am i likely to get with these scoresAmazing scores! You’re looking at around a 48 raw (and scaled), but, as I always say, it really depends on your rank and overall strength of the cohort. All the best for the exams!
93/100 sac prob around rank 5-10
40/40 exam 1
58/60 exam 2
As I posted above earlier, classifications of data is relative to how the data is recorded. Statements like "weight and height are always continuous because you measure it" are misleading. The same quantity / variable can be any of the four types, depending on how it is measured / or how the data is recorded. I suppose the only thing that could be said is that weight / height / distance are continuous if no information about how they are recorded is given, then perhaps it might be implied that they are being recorded in the most precise way possible.
For instance, take distance.
(1) If measured in cm with infinite precision - ie, if conceivably you could record a value of 3.1415926... - then it is continuous.
(2) If measured in cm but rounded to the nearest whole number - ie. only numbers like 2, 6, 11, 13 etc are recorded in your data - then it is discrete.
(3) If recorded as "really short", "short", "long", "really long" then it is categorical ordinal.
(4) Silly example, but if recorded as "exhausting" "fun" "satisfying", then it is categorical nominal.
VCAA exam questions will always specify how the data is recorded.
A good example of this is 2017 Exam 1, Question 7, where students had to classify the variable number of moths, which is being recorded as "less than 250", "250-500", or "more than 500". 36% of students incorrectly classified this as numerical when in fact it is ordinal (the possible data values "less than 250", "250-500", or "more than 500" are not numerical values, they are categories with an implied ranking).
I've had a similar question about petrol prices
The question went like this, "is petrol prices discrete or continuous?"
I knew that petrol prices were rounded to 2 d.p because the previous bit of that question said so. The petrol price is rounded to a terminating decimal and therefore discrete is the correct.
Continuous also doesn't exclusively mean can be measured. It just means that the value of something can change continuously as the word suggests and that the decimal doesn't terminate.
Yes, hence my confusion. My question in the first place was about distance that was recorded to ONE decimal place e.g. 4.9km, 0.8km, 3.5km etc. (i.e. the distances weren't recorded with "infinite precision" [which is said to be continuous] nor to the nearest km [which would be discrete]). But, from what I've read in this thread, this would make it a DISCRETE variable, regardless of whether the distance was rounded to the nearest tenth of a kilometre OR if it was EXACTLY 4.9km, 0.8km and so forth (whether it was exact or rounded was not specified in the premise). However, in the solutions this was classified as a CONTINUOUS variable instead ... is there something fundamental that I'm missing or??? Are the answers wrong lmao
Yes, hence my confusion. My question in the first place was about distance that was recorded to ONE decimal place e.g. 4.9km, 0.8km, 3.5km etc. (i.e. the distances weren't recorded with "infinite precision" [which is said to be continuous] nor to the nearest km [which would be discrete]). But, from what I've read in this thread, this would make it a DISCRETE variable, regardless of whether the distance was rounded to the nearest tenth of a kilometre OR if it was EXACTLY 4.9km, 0.8km and so forth (whether it was exact or rounded was not specified in the premise). However, in the solutions this was classified as a CONTINUOUS variable instead ... is there something fundamental that I'm missing or??? Are the answers wrong lmao
Could you please send or give the details of the question? Usually there's subtle differences in question wording which change a lot about what they're looking for.
Yeah sure - also thank you to everyone for the help, I really appreciate it!!!!!!!!!!!! :)In this question, it didn't specifically say that distance is rounded to 1 dp so it's assumed that this variable is continuous. Please correct me if I'm wrong this is just my reasoning based on my teacher feedback.
In this question, it didn't specifically say that distance is rounded to 1 dp so it's assumed that this variable is continuous. Please correct me if I'm wrong this is just my reasoning based on my teacher feedback.
is it just me or are the exams for further maths getting harder since 2019?
If someone could help with this questionNo because a sample doesn't represent an entire population of women so your conclusion would be inaccurate. Also, is this actually a further maths question?
Hypertension is commonly defined as a systolic blood pressure above 140mmHg. If a physician is given a report stating that a sample of 4women has an average systolic blood pressure below 140mmHg, can the physician conclude that none of the women has hypertension? Justify your answer
No because a sample doesn't represent an entire population of women so your conclusion would be inaccurate. Also, is this actually a further maths question?
This doesn't answer the question. The question implies that we should be checking if the doctor can conclude that none of the women they've tested has hypertension, not some purported entire population. There is no mention of a population. Good attempt thoughright makes sense i thought this was a science prac question instead of a medical question.
I purposefully left my response open-ended because we'd like to see more working out appended to any question.
Since an answer has now been posted up, I may as well: the answer is no, you cannot conclude that none of the women has hypertension. A simple counterexample can be found by letting the blood pressure of three of the women be 139mmHg and the other be 141mmHg. The average is clearly below 140mmHg, yet one is above 140mmHg (implying that said woman has hypertension).
Hope this helps
Yeah ig the implication is that all 15 students are going on the helicopter so there's a minimum of 15 seats required ... a bit ambiguous though, anyways thanks!Yep, I don't think VCAA would be this ambiguous.
for this question i don't get why this is the answer isn't it just 0.42 x 0.17. for independent events you x them and disjoint you add them
for this question int it just 0.69+ 0.4
Does anyone know strategies about how to guarantee full marks on exam 2 without making careless mistakes?Unfortunately, there isn't really a way to guarantee full marks on exam 2 but I'd suggest checking your answers as you go and after you do them. By this, I mean check that you've entered numbers correctly into your CAS, the signs are correct on financial solver, you've put enough zeros in a calculation (I lost a mark on a SAC for writing 200 instead of 2000 - the epitome of careless mistakes :( ). If time permits, go through questions you found difficult first and then the rest of the questions.
Unfortunately, there isn't really a way to guarantee full marks on exam 2 but I'd suggest checking your answers as you go and after you do them. By this, I mean check that you've entered numbers correctly into your CAS, the signs are correct on financial solver, you've put enough zeros in a calculation (I lost a mark on a SAC for writing 200 instead of 2000 - the epitome of careless mistakes :( ). If time permits, go through questions you found difficult first and then the rest of the questions.thank you good news is that I haven't done some of these yet so there's still hope
Hope this helps :)
for this question ii
i don't understand why its 8.606 i thought it had to be less than 7.5358
i dont understand the answer for this question can someone explain and where did the 0.48 come from
Can someone please solve this question and tell me what they got?
Can someone please solve this question and tell me what they got?
Also can someone please tell me what you got for this question?
I'd be inclined to say that it is 36% (because I usually assume between is exclusive, as inclusivity is usually stated); but it should be made clear by the question. If in doubt, ask.Yeah that's what the solution said but "between" isn't really explicit because if we're talking about between 1 standard deviation and 2 standard deviation, we're including both the value at the 1 standard dev and the value at standard dev.
This is really blurry and hard to read - if you have another picture I'd be happy to take a look at it later.
There are 9 numbers between 3 and 7 (4, 4, 4, 4, 5, 5, 5, 6, 6)Hey,
9 / 25 x 100 = 36%
deseasonalised temp = 23.71 + 0.457 x month
= 23.71 + 0.457 x 13
= 29.651
predicted temp = 29.651 x 1.13
= 33.5 degrees
= 34 degrees
Hope that helps... ;D
someone has posted the answerswhere?
Hey, does anyone have any tips on how to use reading time in Exam 2? What’s the most effective way to use it?hey! tbh I don't really think there's anything like the "most effective" way to use reading time. I would take 30secs-1min to just flick through the entire exam once and get a gist of how long it is. Then I personally prefer to read it in chronological order; if you know you take more time to do a particular section of the exam or you struggle with a module more than other sections then I'd probably suggest spending the majority of your reading time on those questions so you have a better idea of how to approach them when writing time starts. It's really just about doing what you feel comfortable with.
Does anyone know if I need to pass the unit 2 General Maths exam? For reference I am not doing Further Maths next year and I failed 1 of the 3 SACs this semester. My exam is tomorrow
Hello,
I am looking for confirmation of my working or correction of errors.
For A, I got 0.75%
For B, I got t(0) = 55000, t(n+1) = 1.0075 x t(n)
For C, I got t(n) = ((1.0075)^n) x 55000
For D, the one I am stuck on, I got $86,112.46. I understand the question as that the rule in part C is for n months, not n years, so t(60) would give the value after 5 years.
Thanks
Hey there,
Does any one have practice SACS for further maths.
If So DM me Immediately on ATAR NOTES.
THANKS
What is the difference, if any, between a question asking for "the first five recursions" and "the first five terms"?
Graphs and relations question:
In the exam does it matter if you don't use the formula (y-y1)=m(x-x1)?
As I would prefer to work with y=mx+c but don't want to be losing marks if the other is necessary for the exam working out.
Thanks :)
G'day,
I am a tutor in Further Mathematics, but have a question for fellow experts and students.
The picture attached is of a question my student attempted. The content is on chapter 3 of cambridge, so is on least squares regression. A few issues:
- The original data has a massive outlier, so shouldn't even be subject to least squares regression per the assumptions
- The picture is of the residual plot, which to me has no real observable pattern given the outlier, however perhaps the definition of "pattern" is not so clear cut? I imagine the pattern being non-linear or curved or some such, so how do we distinguish between pattern and non pattern?
Thanks for the help. Hopefully someone more zen than I can help me understand why we'd approach this question despite the outlier being present!
Cheers