can anyone please help me with these!
okay these are the questions.
Q1. if --> = 60mN , --> = 20 mS
A B
a) --> -->
A + B
Q2.
--> -->
A = 60 km-1 NE , B = 60 km-1 SE
Find --> -->
A + B
Q2.
--> -->
A = 40 km W , B = 40 km SW
a) find the south component of -->
B
b) find the west component of -->
B
c) find --> -->
A + B
THANKYOU
OMG lol caramel got it just before me
The resultant vector is achieved by placing two vectors head to tail and finding the displacement between the ends... soo... (look at attached image)
1. By making the 20m S vector negative, you reverse its direction. Now you have two vectors heading north, and adding them you get the resultant vector 40m N.
2. I don't know what you mean by km-1 so I'll just take it to mean km. Here we just move vector A so its head is at B's tail. As the angle between them is
, it's just a right triangle and
km E.
3. a) South component of B is found by trigonometry:
km S.
b) West component is also
km W.
c) The resultant vector is found using the
Law of Cosines.
km
The direction of the vector will be
where by the
Law of sines,
So the bearing of the resultant vector is