Help me please

[HERculina]

Tickets for a concert are available at two prices. The more expensive ticket is $30 more than the cheaper one. Find the cost of each type of ticket if a group can buy 10 more of the cheaper tickets than the expensive ones for $1800.

  

[InitialDRulz]

ummm....not sure about this but i'll try.

Lets call the ticket price X

So you know that it totals up for 1800 (=1800)
Expensive ticket is $30 more (X + 30)
If a group buys 10 more of the cheaper one than the expensive ones (x10 as a whole, where x is a multiply)

So my equation would be
10 (X+30) = 1800

X + 30 = 180

X = 150

So cheap ticket is $150, and Expensive Ticket is $180?

Not sure if thats right

[HERculina]

thanks for trying but the answer is $90 and $60 :/

the equation 10 ( X+30) = 1800 is incorrect. why are you multiplying it by 10, wouldnt it be plus? i think you have to use another pronumeral to represent the no. of tickets.

i got (y + 30) (x+10) + xy = 1800
where y = price of cheaper ticket and x = no. of cheaper tickets

but i dunno if its right or how to work out the rest 

[Water]

Tickets for a concert are available at two prices. The more expensive ticket is $30 more than the cheaper one. Find the cost of each type of ticket if a group can buy 10 more of the cheaper tickets than the expensive ones for $1800.

x + 30 = y           (y) is the expensive one

second equation.

1800\y   + 10  =  1800\x  




Not sure if this is right? Sorta guessedish

[InitialDRulz]

bleh, i just realised i didn't read the question right. Yeah Water is right with those two equations.

I'll just like finish this off or something.

Move the equation around to make
1800/x - 1800/y = 10

Simplify

180/x - 180/y = 1

Multiply both sides by x and y
180y - 180x = xy

sub y
180 (x + 30) - 180 x = (x+30) * x

Expand
180x + 5400 - 180x = x^2 + 30 x
x^2 + 30x - 5400 = 0

Through GQF or CTS

(x-60)(x+90)=0
As money can't be negative, $60 is the only possible answer

[HERculina]

:O correcto!
thanks so much

[donaldgillies]

This will drive you mad if you don't get what the person who wrote the question was trying to say. If you realise the cost of the expensive tickets is ALSO $1800, same as the cost of the cheap tickets, you will be able to solve it ok.  The solution given by InitialDrulz then makes sense.