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April 19, 2024, 11:53:19 am
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Author Topic: 2012 vce paper help  (Read 822 times)  Share 

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2012 vce paper help
« on: May 20, 2013, 07:50:11 pm »
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can someone help me with question 2 of the 2012 vce physics unit 3 exam? if not, no hard feelings but help will be greatly appreciated
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Will Sparks

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Re: 2012 vce paper help
« Reply #1 on: May 20, 2013, 08:42:24 pm »
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Whats the question? I don't have access to the exam
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English [14] Methods [19] Specialist [16] Chemistry [15] Physics [18]

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availn

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Re: 2012 vce paper help
« Reply #2 on: May 20, 2013, 08:48:42 pm »
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Put simply, the total momentum before is to the right. Therefore, the total momentum after must also be to the right. For this to be true, the block moving to the right must have a greater momentum than the block moving to the left.

I got 0.5/3 on this question ;_;
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Will Sparks

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Re: 2012 vce paper help
« Reply #3 on: May 20, 2013, 08:51:55 pm »
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Quote from: availn on May 20, 2013, 08:48:42 pm
Put simply, the total momentum before is to the right. Therefore, the total momentum after must also be to the right. For this to be true, the block moving to the right must have a greater momentum than the block moving to the left.

I got 0.5/3 on this question ;_;

I got 0.5/30 on one of my SACs
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English [14] Methods [19] Specialist [16] Chemistry [15] Physics [18]

ATAR: 33.60


You do realize that in order for us to get ATARs of 80-90+, there has to be people at the other end of the spectrum right?

Kiro Kompiro

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Re: 2012 vce paper help
« Reply #4 on: May 23, 2013, 10:15:59 pm »
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Quote from: Kiro Kompiro on May 23, 2013, 10:14:47 pm
1.  Momentum is a vector: opposite directions have opposite signs
2.  Momentum is ALWAYS conserved: Vector sum of momentums before collision must equal vector sum after collision
3.  take velocity to the RIGHT as +ve
 
Before the collision 1.2 kg is moving to the right.  It has +ve momentum. 

After, its moving to the left so it now has negative momentum. 

However the total momentum must remain as it was before the collision.  That means the -ve momentum of the 1.2 kg mass after the collision needs to be "cancelled" by the 2.4 kg mass +ve momentum, AND the 2.4 kg momentum be enough to equal the total momentum before the collision.  Therefore the momentum of the 2.4 kg it must be greater than the momentum of the 1.2 kg before the collision.
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