Login

Welcome, Guest. Please login or register.

April 19, 2024, 08:51:55 am

Author Topic: Projectile Motion Launched From Above Ground  (Read 958 times)  Share 

0 Members and 1 Guest are viewing this topic.

BakerDad12

  • Trendsetter
  • **
  • Posts: 126
  • Respect: +1
Projectile Motion Launched From Above Ground
« on: November 03, 2019, 06:58:28 pm »
0
Hi guys, on the topic of the position of a projectile, Physics In Focus says: Sx = x0 + uxt and Sy = y = uyt +1/2ayt2.

What do the x0 and y 0 mean? I am struggling to understand this.

Thank you so much for your time guys!!
« Last Edit: November 03, 2019, 07:03:49 pm by BakerDad12 »

DrDusk

  • NSW MVP - 2019
  • Forum Leader
  • ****
  • Posts: 504
  • Respect: +130
Re: Projectile Motion Launched From Above Ground
« Reply #1 on: November 03, 2019, 07:28:54 pm »
+1
Hi guys, on the topic of the position of a projectile, Physics In Focus says: Sx = x0 + uxt and Sy = y = uyt +1/2ayt2.

What do the x0 and y 0 mean? I am struggling to understand this.

Thank you so much for your time guys!!
Well firstly I don't see any y0, and the x0 is what horizontal distance the projectile starts from with reference to your origin. For example in the x-y plane if you take (0,0) as the place of where displacement is measured and your projectile is launched from (1,0). Then it's total displacement from the reference point is 1 + uxt where '1' is  x0. Of course this would be different if say you were measuring from (2,0), then it would be (2)+uxt where (2) is  x0.
« Last Edit: November 03, 2019, 07:36:10 pm by DrDusk »