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March 29, 2024, 05:36:03 am

Author Topic: 4U Maths Question Thread  (Read 659888 times)  Share 

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VydekiE

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Re: 4U Maths Question Thread
« Reply #1020 on: March 25, 2017, 09:06:22 am »
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Hi, it would be great if I could get some help on this question
1) P(x1,y1) is a variable point on the hyperbola x2/a2 - y2/b2 =1 such that the tangent at P cuts the asymptotes at M and N.
a) Find the equation of the tangent at P (which I've already done)
b) Find the coordinates of M and N
Thank you!!

RuiAce

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Re: 4U Maths Question Thread
« Reply #1021 on: March 25, 2017, 09:19:18 am »
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Hi, it would be great if I could get some help on this question
1) P(x1,y1) is a variable point on the hyperbola x2/a2 - y2/b2 =1 such that the tangent at P cuts the asymptotes at M and N.
a) Find the equation of the tangent at P (which I've already done)
b) Find the coordinates of M and N
Thank you!!



VydekiE

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Re: 4U Maths Question Thread
« Reply #1022 on: March 25, 2017, 09:27:10 am »
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hanaacdr

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Re: 4U Maths Question Thread
« Reply #1023 on: March 26, 2017, 01:49:31 pm »
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Hi does anyone know how to do question 2
I am not sure how to approach it
Thanks


RuiAce

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Re: 4U Maths Question Thread
« Reply #1024 on: March 26, 2017, 01:59:03 pm »
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Hi does anyone know how to do question 2
I am not sure how to approach it
Thanks

(Image removed from quote.)
C, because the complementary event is just having none of the windows open, which can only be done in 1 way.

Note obviously that the total number of arrangements is 2^4 = 16, which is where we get 16-1=15 from.

hanaacdr

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Re: 4U Maths Question Thread
« Reply #1025 on: March 26, 2017, 02:10:41 pm »
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C, because the complementary event is just having none of the windows open, which can only be done in 1 way.

Note obviously that the total number of arrangements is 2^4 = 16, which is where we get 16-1=15 from.

ahhh true
thank you!

hanaacdr

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Re: 4U Maths Question Thread
« Reply #1026 on: March 27, 2017, 11:27:52 am »
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Not sure how to do b part 1 and 2

hanaacdr

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Re: 4U Maths Question Thread
« Reply #1027 on: March 27, 2017, 11:53:09 am »
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Also this question
It looks simple but i just cant get it
Thank you!



RuiAce

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Re: 4U Maths Question Thread
« Reply #1028 on: March 27, 2017, 12:42:52 pm »
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Also this question
It looks simple but i just cant get it
Thank you!


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Hint for the other one: There are 3 cases to consider. You have no E's in there, one E or two E's
« Last Edit: March 27, 2017, 12:46:52 pm by RuiAce »

cutiepie30

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Re: 4U Maths Question Thread
« Reply #1029 on: March 28, 2017, 09:18:04 pm »
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How would you do this question? (attached)

RuiAce

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Re: 4U Maths Question Thread
« Reply #1030 on: March 28, 2017, 10:10:15 pm »
+1
How would you do this question? (attached)

cutiepie30

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Re: 4U Maths Question Thread
« Reply #1031 on: March 29, 2017, 12:28:59 am »
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Thanks RuiAce  :)

could you please write a solution for me, i am kind of lost on where to go  :(

RuiAce

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Re: 4U Maths Question Thread
« Reply #1032 on: March 29, 2017, 07:10:25 am »
+1

It's really just a standard by parts question.
« Last Edit: March 29, 2017, 07:13:15 am by RuiAce »

chelseam

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Re: 4U Maths Question Thread
« Reply #1033 on: March 29, 2017, 08:10:43 pm »
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Hi! Can someone please help me with part b of this question? Thank you! :)
HSC 2017: Chemistry / English Advanced / English Extension 1 / Legal Studies (5th in NSW) / Math Extension 1 / Math Extension 2

dux99.95

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Re: 4U Maths Question Thread
« Reply #1034 on: March 29, 2017, 08:58:17 pm »
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Heey
I got part a by subbing z= i.
How do u solve part b?

You guys are awesome!!