You just need to get used to it.
We get to the stage:
tan(2x) = -sqrt(3).
tan(x) equals sqrt(3) at pi/3, and tan is negative in the 2nd and 4th quadrants (ASTC).
Hence, we need pi-pi/3, 2pi-pi/3.
and we need solutions from 0 to 2pi .. (which is really 4pi because we have tan(
2x), so we change the domain)
pi - pi/3, 2pi - pi/3, 3pi - pi/3, 4pi - pi/3
so eventually we have:
2x = 2pi/3, 5pi/3, 8pi/3, 11pi/3
x = 2pi/6, 5pi/6, 8pi/6, 11pi/6
You just do pi-pi/3, 2pi-pi/3 until you consume all the required periods.
As far as exact values go, I just memorized the sin row, the cos row is sort of an inverse (easy to remember once you have sin down), and then tan is just division. I'll write out the table in the exam. But you should prolly go for the triangles