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March 29, 2024, 10:11:28 am

Author Topic: Mathematics Extension 1 Challenge Marathon  (Read 26609 times)  Share 

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RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #30 on: September 23, 2017, 08:39:54 pm »
+2



RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #31 on: December 03, 2017, 08:09:48 pm »
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RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #32 on: December 23, 2017, 12:40:04 am »
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RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #33 on: January 01, 2018, 12:21:06 pm »
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Opengangs

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #34 on: January 01, 2018, 01:58:40 pm »
+1

RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #35 on: January 14, 2018, 05:20:26 pm »
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Opengangs

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #36 on: January 14, 2018, 05:45:26 pm »
+1

RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #37 on: January 14, 2018, 05:55:17 pm »
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Possible soln



I guess I wasn't clear enough, sorry :(

That was the "algebraic" proof I had in mind. I was more of looking for one based off actual counting and enumeration.

Opengangs

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #38 on: January 14, 2018, 06:09:44 pm »
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oh my bad  :-[
Didn't read it properly aha

Opengangs

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #39 on: January 29, 2018, 09:54:19 am »
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Assumed knowledge
Calculus, Basic algebra, Exponential and Logarithms.

RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #40 on: February 15, 2018, 11:48:44 pm »
+1

You are welcome to use the notation \( f^{(n)}(x) \) for the \(n\)-th derivative of \(f\) with respect to \(x\)

RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #41 on: April 14, 2018, 10:40:37 pm »
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Opengangs

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #42 on: April 23, 2018, 11:28:11 am »
+1

« Last Edit: April 23, 2018, 11:37:54 am by Opengangs »

RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #43 on: April 23, 2018, 11:47:00 am »
+2


lol
\[ \int_0^{\pi/2} \frac{dx}{\frac{\cos x}{\sin x}+ \frac{\sin x}{\cos x}} = \int_0^{\pi/2} \frac{\sin x \cos x}{\cos^2 x + \sin^2 x}\,dx = \int_0^{\pi/2} \frac12 \sin 2x\,dx \]
Too lazy to figure out a 2U-only way though

RuiAce

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Re: Mathematics Extension 1 Challenge Marathon
« Reply #44 on: September 21, 2018, 05:00:00 pm »
+2
« Last Edit: September 21, 2018, 05:29:00 pm by RuiAce »